{"id":46,"date":"2023-06-26T20:26:33","date_gmt":"2023-06-26T20:26:33","guid":{"rendered":"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/"},"modified":"2023-06-26T20:26:33","modified_gmt":"2023-06-26T20:26:33","slug":"fiziksel-agirlik","status":"publish","type":"post","link":"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/","title":{"rendered":"A\u011f\u0131rl\u0131k (fiziksel)"},"content":{"rendered":"

Bu makale a\u011f\u0131rl\u0131\u011f\u0131n fizikteki anlam\u0131n\u0131 a\u00e7\u0131klamaktad\u0131r. Burada a\u011f\u0131rl\u0131\u011f\u0131n tan\u0131m\u0131n\u0131, bir nesnenin a\u011f\u0131rl\u0131\u011f\u0131n\u0131n nas\u0131l hesapland\u0131\u011f\u0131n\u0131 ve a\u011f\u0131rl\u0131k ile k\u00fctle aras\u0131ndaki fark\u0131n ne oldu\u011funu bulacaks\u0131n\u0131z. Son olarak ad\u0131m ad\u0131m v\u00fccut geli\u015ftirme egzersizleriyle antrenman yapabilirsiniz. <\/p>\n

<\/span> Fizikte a\u011f\u0131rl\u0131k nedir?<\/span><\/h2>\n

Fizikte bir cismin a\u011f\u0131rl\u0131\u011f\u0131<\/strong> , s\u00f6z konusu cisme etki eden yer\u00e7ekimi kuvvetidir. Genel olarak a\u011f\u0131rl\u0131k kavram\u0131, D\u00fcnya’n\u0131n belirli bir nesneye uygulad\u0131\u011f\u0131 yer\u00e7ekimi kuvvetini ifade eder, ancak ayn\u0131 zamanda ba\u015fka herhangi bir gezegenin kuvvetini de ifade edebilir.<\/p>\n

Yani a\u011f\u0131rl\u0131k bir kuvvet oldu\u011fundan mod\u00fcl\u00fc, y\u00f6n\u00fc, y\u00f6n\u00fc ve uygulama noktas\u0131 olan bir vekt\u00f6rd\u00fcr. A\u015fa\u011f\u0131da a\u011f\u0131rl\u0131k de\u011ferinin nas\u0131l bulunaca\u011f\u0131n\u0131 g\u00f6rece\u011fiz ancak y\u00f6n her zaman dikey, y\u00f6n a\u015fa\u011f\u0131 do\u011fru olacak ve uygulama noktas\u0131 v\u00fccudun a\u011f\u0131rl\u0131k merkezine kar\u015f\u0131l\u0131k gelecektir.<\/p>\n

G\u00f6rd\u00fc\u011f\u00fcn\u00fcz gibi fizikte a\u011f\u0131rl\u0131k ve k\u00fctleyi birbirinden ay\u0131rmal\u0131y\u0131z<\/strong> \u00e7\u00fcnk\u00fc bu iki terimin anlam\u0131 g\u00fcnl\u00fck ya\u015famda yanl\u0131\u015f kullan\u0131lmaktad\u0131r. A\u015fa\u011f\u0131da bir cismin a\u011f\u0131rl\u0131\u011f\u0131 ile k\u00fctlesi aras\u0131ndaki farklar\u0131 ayr\u0131nt\u0131l\u0131 olarak a\u00e7\u0131klad\u0131n\u0131z.<\/p>\n

Fizikte a\u011f\u0131rl\u0131\u011f\u0131n sembol\u00fc P harfidir, dolay\u0131s\u0131yla bir cismin a\u011f\u0131rl\u0131\u011f\u0131n\u0131n kuvvetini temsil eden ok, yan\u0131na P harfi konularak g\u00f6sterilir.<\/p>\n

Bir kuvvet oldu\u011fundan a\u011f\u0131rl\u0131\u011f\u0131n \u00f6l\u00e7\u00fc birimi newtondur ve N harfiyle ifade edilir. \u00d6rne\u011fin 50 kg a\u011f\u0131rl\u0131\u011f\u0131ndaki bir ki\u015finin a\u011f\u0131rl\u0131\u011f\u0131 yakla\u015f\u0131k 490 N’dir. <\/p>\n

<\/span> Fizikte a\u011f\u0131rl\u0131k nas\u0131l hesaplan\u0131r<\/span><\/h2>\n

Fizikte bir cismin a\u011f\u0131rl\u0131\u011f\u0131n\u0131n form\u00fcl\u00fc, s\u00f6z konusu cismin k\u00fctlesi ile \u00e7ekim kuvvetini uygulayan y\u0131ld\u0131z\u0131n yer\u00e7ekiminin \u00e7arp\u0131m\u0131na e\u015fittir. Bu nedenle, bir gezegenin bir cismi \u00e7ekti\u011fi a\u011f\u0131rl\u0131k kuvvetini hesaplamak<\/strong> i\u00e7in cismin k\u00fctlesinin gezegenin yer\u00e7ekimi ile \u00e7arp\u0131lmas\u0131 gerekir.<\/p>\n

Yani bir nesnenin a\u011f\u0131rl\u0131\u011f\u0131n\u0131 hesaplamak i\u00e7in kullan\u0131lan form\u00fcl \u015f\u00f6yledir: <\/p>\n

\n
\"fiziksel<\/figure>\n<\/div>\n

D\u00fcnyadaki yer \u00e7ekiminin 9,81 m\/ s2<\/sup> oldu\u011funu unutmay\u0131n. <\/p>\n

\n
A\u011f\u0131rl\u0131k form\u00fcl\u00fc g\u00f6sterimini g\u00f6r\u00fcnt\u00fcleyin<\/strong><\/div>\n<\/div>\n

A\u011f\u0131rl\u0131k kuvvetinin form\u00fcl\u00fcn\u00fc g\u00f6stermek i\u00e7in, herhangi bir cismin ba\u015fka herhangi bir cisme uygulad\u0131\u011f\u0131 yer\u00e7ekimi kuvvetini hesaplamam\u0131z\u0131 sa\u011flayan cebirsel ifadeyle ba\u015flayaca\u011f\u0131z:<\/p>\n

\n

\"F=G\\cdot<\/p>\n<\/p>\n

Bununla birlikte, yer\u00e7ekimi form\u00fcl\u00fc tam olarak evrensel yer\u00e7ekimi sabitinin (G) g\u00f6k cisminin k\u00fctlesiyle (M) \u00e7arp\u0131m\u0131, g\u00f6k cisminin merkezi ile y\u00fczeyi aras\u0131ndaki mesafenin karesine ( r2<\/sup> ) b\u00f6l\u00fcnmesiyle elde edilir:<\/p>\n

\n

\"g=\\cfrac{G\\cdot<\/p>\n<\/p>\n

B\u00f6ylece, bir ifadeyi di\u011feriyle de\u011fi\u015ftirerek a\u011f\u0131rl\u0131k form\u00fcl\u00fcne ula\u015f\u0131r\u0131z:<\/p>\n

\n

\"F=G\\cdot<\/p>\n<\/p>\n

\n

\"F=\\cfrac{G\\cdot<\/p>\n<\/p>\n

\n

\"F=g\\cdot<\/p>\n<\/p>\n

<\/div>\n

<\/span> A\u011f\u0131rl\u0131k ve k\u00fctle aras\u0131ndaki fark<\/span><\/h2>\n

A\u011f\u0131rl\u0131k ve k\u00fctle<\/strong> fizikte iki farkl\u0131 kavramd\u0131r. K\u00fctle, bir cismin sahip oldu\u011fu madde miktar\u0131d\u0131r ve kilogram (kg) cinsinden \u00f6l\u00e7\u00fcl\u00fcr; a\u011f\u0131rl\u0131k ise bir y\u0131ld\u0131z\u0131n bir cisme uygulad\u0131\u011f\u0131 \u00e7ekim kuvvetidir ve \u00f6l\u00e7\u00fc birimi newton (N)’dur.<\/p>\n

\u00d6rne\u011fin 70 kg a\u011f\u0131rl\u0131\u011f\u0131ndaki bir ki\u015finin D\u00fcnya’daki a\u011f\u0131rl\u0131\u011f\u0131 686,7 N’dir. Ancak ayn\u0131 ki\u015finin Ay’daki a\u011f\u0131rl\u0131\u011f\u0131 113,4 N’dir, ancak k\u00fctlesi ayn\u0131 kal\u0131r.<\/p>\n

Bu nedenle \u201cKa\u00e7 kilosunuz?\u201d \u00bb Birinin k\u00fctlesini bilmek i\u00e7in asl\u0131nda “K\u00fctleniz nedir?” diye sormal\u0131y\u0131z. \u00bb<\/p>\n

A\u011f\u0131rl\u0131k ve k\u00fctle aras\u0131ndaki bir di\u011fer fark, \u00f6zelli\u011fi \u00f6l\u00e7mek i\u00e7in gereken alettir. A\u011f\u0131rl\u0131k dinamometre ile, k\u00fctle ise terazi ile \u00f6l\u00e7\u00fcl\u00fcr.<\/p>\n

Ayr\u0131ca k\u00fctle basit bir say\u0131d\u0131r ama a\u011f\u0131rl\u0131k bir kuvvet oldu\u011fu i\u00e7in vekt\u00f6rd\u00fcr. Dolay\u0131s\u0131yla her vekt\u00f6r gibi a\u011f\u0131rl\u0131\u011f\u0131n da bir y\u00f6n\u00fc, anlam\u0131, b\u00fcy\u00fckl\u00fc\u011f\u00fc ve uygulama noktas\u0131 vard\u0131r. <\/p>\n

<\/span>\u00c7\u00f6z\u00fclm\u00fc\u015f A\u011f\u0131rl\u0131k Egzersizleri<\/span><\/h2>\n

1. Egzersiz<\/h3>\n

K\u00fctlesi 45 kg olan bir cismin D\u00fcnya \u00fczerindeki a\u011f\u0131rl\u0131\u011f\u0131n\u0131 hesaplay\u0131n\u0131z. D\u00fcnyan\u0131n yer\u00e7ekimi olarak g=9,81 m\/ s2<\/sup> de\u011ferini kullan\u0131n. <\/p>\n

\n
\u00e7\u00f6z\u00fcm\u00fc g\u00f6r<\/strong><\/div>\n<\/div>\n

Bir nesnenin a\u011f\u0131rl\u0131\u011f\u0131n\u0131 belirlemek i\u00e7in ilgili form\u00fcl\u00fc uygulaman\u0131z yeterlidir:<\/p>\n

\n

\"P=m\\cdot<\/p>\n<\/p>\n

\u015eimdi cismin k\u00fctlesi ve d\u00fcnyan\u0131n yer\u00e7ekimi verilerini form\u00fclde yerine koyup a\u011f\u0131rl\u0131\u011f\u0131 hesapl\u0131yoruz: <\/p>\n

\n

\"P=45\\cdot<\/p>\n<\/p>\n

<\/div>\n

Al\u0131\u015ft\u0131rma 2<\/h3>\n

Bir cismin D\u00fcnya’daki a\u011f\u0131rl\u0131\u011f\u0131 650 N’dur, bu a\u011f\u0131rl\u0131\u011f\u0131n Mars’taki e\u015fde\u011fer k\u00fctlesi nedir? Ger\u00e7ekler: Mars’ta yer \u00e7ekimi 3721 m\/ s2’dir<\/sup> . <\/p>\n

\n
\u00e7\u00f6z\u00fcm\u00fc g\u00f6r<\/strong><\/div>\n<\/div>\n

A\u011f\u0131rl\u0131kla ilgili bu fiziksel sorunu \u00e7\u00f6zmek i\u00e7in yukar\u0131da a\u00e7\u0131klanan form\u00fcl\u00fc kullanmal\u0131y\u0131z:<\/p>\n

\n

\"P=m\\cdot<\/p>\n<\/p>\n

Bu durumda a\u011f\u0131rl\u0131\u011f\u0131n ve yer \u00e7ekiminin de\u011ferini biliyoruz ve cismin k\u00fctlesini de bilmek istiyoruz, bu nedenle \u00f6nce k\u00fctleyi a\u015fa\u011f\u0131daki form\u00fclden \u00e7\u00f6z\u00fcyoruz:<\/p>\n

\n

\"m=\\cfrac{P}{g}\"<\/p>\n<\/p>\n

Ve son olarak, Mars’taki 650 N’luk bir a\u011f\u0131rl\u0131\u011f\u0131n k\u00fctlesini bulmak i\u00e7in verileri form\u00fcle yerle\u015ftiriyoruz: <\/p>\n

\n

\"m=\\cfrac{650}{3.721}=174,68<\/p>\n<\/p>\n

<\/div>\n

Al\u0131\u015ft\u0131rma 3<\/h3>\n

A\u015fa\u011f\u0131daki \u015fekilde a\u00e7\u0131lar\u0131 g\u00f6sterilen iki ip ile as\u0131l\u0131 duran, k\u00fctlesi 12 kg olan kat\u0131 bir cisim verildi\u011finde, her bir ipin, cismi dengede tutmak i\u00e7in uygulamas\u0131 gereken kuvveti hesaplay\u0131n. <\/p>\n

\n
\"ilk<\/figure>\n<\/div>\n
\n
\u00e7\u00f6z\u00fcm\u00fc g\u00f6r<\/strong><\/div>\n<\/div>\n

Bu t\u00fcr problemleri \u00e7\u00f6zmek i\u00e7in yapmam\u0131z gereken ilk \u015fey, \u015feklin serbest cisim diyagram\u0131n\u0131 \u00e7izmektir: <\/p>\n

\n
\"dengenin<\/figure>\n<\/div>\n

As\u0131l\u0131 cisme etki eden yaln\u0131zca \u00fc\u00e7 kuvvetin oldu\u011funa dikkat edin: P a\u011f\u0131rl\u0131\u011f\u0131n\u0131n kuvveti ve T 1<\/sub> ve T 2<\/sub> tellerinin gerilmeleri. T 1x<\/sub> , T 1y<\/sub> , T 2x<\/sub> ve T 2y<\/sub> ile temsil edilen kuvvetler s\u0131ras\u0131yla T 1<\/sub> ve T 2’nin<\/sub> vekt\u00f6r bile\u015fenleridir.<\/p>\n

B\u00f6ylece iplerin e\u011fim a\u00e7\u0131lar\u0131n\u0131 bildi\u011fimiz i\u00e7in \u00e7ekme kuvvetlerinin vekt\u00f6r bile\u015fenleri i\u00e7in ifadeler bulabiliriz: <\/p>\n

\n

\"<\/p>\n<\/p>\n

\n

\"<\/p>\n<\/p>\n

\n

\"<\/p>\n<\/p>\n

\n

\"<\/p>\n<\/p>\n

\u00d6te yandan a\u011f\u0131rl\u0131k kuvvetini yer\u00e7ekimi kuvveti form\u00fcl\u00fcn\u00fc uygulayarak hesaplayabiliriz:<\/p>\n

\n

\"P=m\\cdot<\/p>\n<\/p>\n

Problem ifadesi bize v\u00fccudun dengede oldu\u011funu, dolay\u0131s\u0131yla dikey kuvvetlerin toplam\u0131n\u0131n ve yatay kuvvetlerin toplam\u0131n\u0131n s\u0131f\u0131ra e\u015fit olmas\u0131 gerekti\u011fini s\u00f6yler. B\u00f6ylece kuvvet denklemlerini olu\u015fturabilir ve bunlar\u0131 s\u0131f\u0131ra e\u015fitleyebiliriz: <\/p>\n

\n

\"-T_{1x}+T_{2x}=0\"<\/p>\n<\/p>\n

\n

\"T_{1y}+T_{2y}-P=0\"<\/p>\n<\/p>\n

\u015eimdi gerilimlerin bile\u015fenlerini daha \u00f6nce buldu\u011fumuz ifadelerle de\u011fi\u015ftiriyoruz: <\/p>\n

\n

\"-T_1\\cdot\\text{cos}(20\u00ba)+T_2\\cdot<\/p>\n<\/p>\n

\n

\"T_1\\cdot<\/p>\n<\/p>\n

Ve son olarak T 1<\/sub> ve T 2<\/sub> kuvvetlerinin de\u011ferini elde etmek i\u00e7in denklem sistemini \u00e7\u00f6z\u00fcyoruz: <\/p>\n

\n

\"\\left.\\begin{array}{l}-T_1\\cdot<\/div>\n

Exercice 4<\/h3>\n

Comme le montre la figure suivante, deux objets sont reli\u00e9s par une corde et une poulie de masses n\u00e9gligeables. Si l’objet 2 a une masse de 7 kg et que l’inclinaison de la rampe est de 50\u00ba, calculez la masse de l’objet 1 pour que l’ensemble du syst\u00e8me soit dans des conditions d’\u00e9quilibre. Dans ce cas, la force de frottement peut \u00eatre n\u00e9glig\u00e9e. <\/p>\n

\n
"probl\u00e8me<\/figure>\n<\/div>\n
\n
Voir la solution<\/strong><\/div>\n<\/div>\n

Le corps 1 est sur une pente inclin\u00e9e, donc la premi\u00e8re chose \u00e0 faire est de vectoriser la force de son poids pour avoir les forces sur les axes de la pente : [latex]P_{1x}=P_1\\cdot \\text{sin}(\\alpha)” title=”Rendered by QuickLaTeX.com” height=”340″ width=”2918″ style=”vertical-align: 0px;”><\/p>\n<\/p>\n

\n

\"P_{1y}=P_1\\cdot<\/p>\n<\/p>\n

B\u00f6ylece sistemin tamam\u0131na etki eden kuvvetler k\u00fcmesi \u015fu \u015fekildedir: <\/p>\n

\n
\"\u00f6teleme<\/figure>\n<\/div>\n

Problem ifadesi bize kuvvetler sisteminin dengede oldu\u011funu, dolay\u0131s\u0131yla iki cismin de dengede olmas\u0131 gerekti\u011fini s\u00f6yler. Bu bilgiden iki cismin denge denklemlerini \u00f6nerebiliriz: <\/p>\n

\n

\"1\\<\/p>\n<\/p>\n

\n

\"P_1\\cdot<\/p>\n<\/p>\n

\u015eimdi yer \u00e7ekimi kuvveti form\u00fcl\u00fcn\u00fc uygulay\u0131p denklemi basitle\u015ftiriyoruz: <\/p>\n

\n

\"m_1\\cdot<\/p>\n<\/p>\n

\n

\"m_1<\/p>\n<\/p>\n

Son olarak verileri yerine koyuyoruz ve 1. cismin k\u00fctlesini buluyoruz: <\/p>\n

\n

\"m_1<\/p>\n<\/p>\n

\n

\"m_1<\/p>\n<\/p>\n

\n

\"m_1=9,14<\/p>\n<\/p>\n

<\/div>\n","protected":false},"excerpt":{"rendered":"

Bu makale a\u011f\u0131rl\u0131\u011f\u0131n fizikteki anlam\u0131n\u0131 a\u00e7\u0131klamaktad\u0131r. Burada a\u011f\u0131rl\u0131\u011f\u0131n tan\u0131m\u0131n\u0131, bir nesnenin a\u011f\u0131rl\u0131\u011f\u0131n\u0131n nas\u0131l hesapland\u0131\u011f\u0131n\u0131 ve a\u011f\u0131rl\u0131k ile k\u00fctle aras\u0131ndaki fark\u0131n ne oldu\u011funu bulacaks\u0131n\u0131z. Son olarak ad\u0131m ad\u0131m v\u00fccut geli\u015ftirme egzersizleriyle antrenman yapabilirsiniz. Fizikte a\u011f\u0131rl\u0131k nedir? Fizikte bir cismin a\u011f\u0131rl\u0131\u011f\u0131 , s\u00f6z konusu cisme etki eden yer\u00e7ekimi kuvvetidir. Genel olarak a\u011f\u0131rl\u0131k kavram\u0131, D\u00fcnya’n\u0131n belirli bir nesneye …<\/p>\n

A\u011f\u0131rl\u0131k (fiziksel)<\/span> Devam\u0131 »<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-46","post","type-post","status-publish","format-standard","hentry","category-dinamik"],"yoast_head":"\n\u25b7 A\u011f\u0131rl\u0131k (fizik): tan\u0131m, form\u00fcl, \u00e7\u00f6z\u00fclm\u00fc\u015f al\u0131\u015ft\u0131rmalar,...<\/title>\n<meta name=\"description\" content=\"Fizikte a\u011f\u0131rl\u0131\u011f\u0131n ne anlama geldi\u011fini a\u00e7\u0131kl\u0131yoruz. A\u011f\u0131rl\u0131\u011f\u0131n tan\u0131m\u0131, bir v\u00fccudun a\u011f\u0131rl\u0131\u011f\u0131n\u0131n nas\u0131l hesaplanaca\u011f\u0131 (form\u00fcl) ve v\u00fccut geli\u015ftirme egzersizleri \u00e7\u00f6z\u00fcld\u00fc.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u25b7 A\u011f\u0131rl\u0131k (fizik): tan\u0131m, form\u00fcl, \u00e7\u00f6z\u00fclm\u00fc\u015f al\u0131\u015ft\u0131rmalar,...\" \/>\n<meta property=\"og:description\" content=\"Fizikte a\u011f\u0131rl\u0131\u011f\u0131n ne anlama geldi\u011fini a\u00e7\u0131kl\u0131yoruz. A\u011f\u0131rl\u0131\u011f\u0131n tan\u0131m\u0131, bir v\u00fccudun a\u011f\u0131rl\u0131\u011f\u0131n\u0131n nas\u0131l hesaplanaca\u011f\u0131 (form\u00fcl) ve v\u00fccut geli\u015ftirme egzersizleri \u00e7\u00f6z\u00fcld\u00fc.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/\" \/>\n<meta property=\"article:published_time\" content=\"2023-06-26T20:26:33+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/poids-physique.png\" \/>\n<meta name=\"author\" content=\"Jonathan Reynolds\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Yazan:\" \/>\n\t<meta name=\"twitter:data1\" content=\"Jonathan Reynolds\" \/>\n\t<meta name=\"twitter:label2\" content=\"Tahmini okuma s\u00fcresi\" \/>\n\t<meta name=\"twitter:data2\" content=\"6 dakika\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/\"},\"author\":{\"name\":\"Jonathan Reynolds\",\"@id\":\"https:\/\/physigeek.com\/tr\/#\/schema\/person\/b49369b8bed2d27dbd13757330e431a5\"},\"headline\":\"A\u011f\u0131rl\u0131k (fiziksel)\",\"datePublished\":\"2023-06-26T20:26:33+00:00\",\"dateModified\":\"2023-06-26T20:26:33+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/\"},\"wordCount\":1116,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\/\/physigeek.com\/tr\/#organization\"},\"articleSection\":[\"Dinamik\"],\"inLanguage\":\"tr\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/#respond\"]}]},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/\",\"url\":\"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/\",\"name\":\"\u25b7 A\u011f\u0131rl\u0131k (fizik): tan\u0131m, form\u00fcl, \u00e7\u00f6z\u00fclm\u00fc\u015f al\u0131\u015ft\u0131rmalar,...\",\"isPartOf\":{\"@id\":\"https:\/\/physigeek.com\/tr\/#website\"},\"datePublished\":\"2023-06-26T20:26:33+00:00\",\"dateModified\":\"2023-06-26T20:26:33+00:00\",\"description\":\"Fizikte a\u011f\u0131rl\u0131\u011f\u0131n ne anlama geldi\u011fini a\u00e7\u0131kl\u0131yoruz. A\u011f\u0131rl\u0131\u011f\u0131n tan\u0131m\u0131, bir v\u00fccudun a\u011f\u0131rl\u0131\u011f\u0131n\u0131n nas\u0131l hesaplanaca\u011f\u0131 (form\u00fcl) ve v\u00fccut geli\u015ftirme egzersizleri \u00e7\u00f6z\u00fcld\u00fc.\",\"breadcrumb\":{\"@id\":\"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/#breadcrumb\"},\"inLanguage\":\"tr\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Ev\",\"item\":\"https:\/\/physigeek.com\/tr\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"A\u011f\u0131rl\u0131k (fiziksel)\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/physigeek.com\/tr\/#website\",\"url\":\"https:\/\/physigeek.com\/tr\/\",\"name\":\"Physigeek\",\"description\":\"Fizi\u011fi kolay yoldan \u00f6\u011frenin!\",\"publisher\":{\"@id\":\"https:\/\/physigeek.com\/tr\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/physigeek.com\/tr\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"tr\"},{\"@type\":\"Organization\",\"@id\":\"https:\/\/physigeek.com\/tr\/#organization\",\"name\":\"Physigeek\",\"url\":\"https:\/\/physigeek.com\/tr\/\",\"logo\":{\"@type\":\"ImageObject\",\"inLanguage\":\"tr\",\"@id\":\"https:\/\/physigeek.com\/tr\/#\/schema\/logo\/image\/\",\"url\":\"https:\/\/physigeek.com\/tr\/wp-content\/uploads\/2023\/10\/physigeek-logos.png\",\"contentUrl\":\"https:\/\/physigeek.com\/tr\/wp-content\/uploads\/2023\/10\/physigeek-logos.png\",\"width\":180,\"height\":42,\"caption\":\"Physigeek\"},\"image\":{\"@id\":\"https:\/\/physigeek.com\/tr\/#\/schema\/logo\/image\/\"}},{\"@type\":\"Person\",\"@id\":\"https:\/\/physigeek.com\/tr\/#\/schema\/person\/b49369b8bed2d27dbd13757330e431a5\",\"name\":\"Jonathan Reynolds\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"tr\",\"@id\":\"https:\/\/physigeek.com\/tr\/#\/schema\/person\/image\/\",\"url\":\"http:\/\/physigeek.com\/tr\/wp-content\/uploads\/2023\/10\/Jonathan-Reynolds-96x96.jpg\",\"contentUrl\":\"http:\/\/physigeek.com\/tr\/wp-content\/uploads\/2023\/10\/Jonathan-Reynolds-96x96.jpg\",\"caption\":\"Jonathan Reynolds\"},\"sameAs\":[\"http:\/\/physigeek.com\/tr\"]}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"\u25b7 A\u011f\u0131rl\u0131k (fizik): tan\u0131m, form\u00fcl, \u00e7\u00f6z\u00fclm\u00fc\u015f al\u0131\u015ft\u0131rmalar,...","description":"Fizikte a\u011f\u0131rl\u0131\u011f\u0131n ne anlama geldi\u011fini a\u00e7\u0131kl\u0131yoruz. A\u011f\u0131rl\u0131\u011f\u0131n tan\u0131m\u0131, bir v\u00fccudun a\u011f\u0131rl\u0131\u011f\u0131n\u0131n nas\u0131l hesaplanaca\u011f\u0131 (form\u00fcl) ve v\u00fccut geli\u015ftirme egzersizleri \u00e7\u00f6z\u00fcld\u00fc.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/","og_locale":"tr_TR","og_type":"article","og_title":"\u25b7 A\u011f\u0131rl\u0131k (fizik): tan\u0131m, form\u00fcl, \u00e7\u00f6z\u00fclm\u00fc\u015f al\u0131\u015ft\u0131rmalar,...","og_description":"Fizikte a\u011f\u0131rl\u0131\u011f\u0131n ne anlama geldi\u011fini a\u00e7\u0131kl\u0131yoruz. A\u011f\u0131rl\u0131\u011f\u0131n tan\u0131m\u0131, bir v\u00fccudun a\u011f\u0131rl\u0131\u011f\u0131n\u0131n nas\u0131l hesaplanaca\u011f\u0131 (form\u00fcl) ve v\u00fccut geli\u015ftirme egzersizleri \u00e7\u00f6z\u00fcld\u00fc.","og_url":"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/","article_published_time":"2023-06-26T20:26:33+00:00","og_image":[{"url":"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/poids-physique.png"}],"author":"Jonathan Reynolds","twitter_card":"summary_large_image","twitter_misc":{"Yazan:":"Jonathan Reynolds","Tahmini okuma s\u00fcresi":"6 dakika"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/#article","isPartOf":{"@id":"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/"},"author":{"name":"Jonathan Reynolds","@id":"https:\/\/physigeek.com\/tr\/#\/schema\/person\/b49369b8bed2d27dbd13757330e431a5"},"headline":"A\u011f\u0131rl\u0131k (fiziksel)","datePublished":"2023-06-26T20:26:33+00:00","dateModified":"2023-06-26T20:26:33+00:00","mainEntityOfPage":{"@id":"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/"},"wordCount":1116,"commentCount":0,"publisher":{"@id":"https:\/\/physigeek.com\/tr\/#organization"},"articleSection":["Dinamik"],"inLanguage":"tr","potentialAction":[{"@type":"CommentAction","name":"Comment","target":["https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/#respond"]}]},{"@type":"WebPage","@id":"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/","url":"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/","name":"\u25b7 A\u011f\u0131rl\u0131k (fizik): tan\u0131m, form\u00fcl, \u00e7\u00f6z\u00fclm\u00fc\u015f al\u0131\u015ft\u0131rmalar,...","isPartOf":{"@id":"https:\/\/physigeek.com\/tr\/#website"},"datePublished":"2023-06-26T20:26:33+00:00","dateModified":"2023-06-26T20:26:33+00:00","description":"Fizikte a\u011f\u0131rl\u0131\u011f\u0131n ne anlama geldi\u011fini a\u00e7\u0131kl\u0131yoruz. A\u011f\u0131rl\u0131\u011f\u0131n tan\u0131m\u0131, bir v\u00fccudun a\u011f\u0131rl\u0131\u011f\u0131n\u0131n nas\u0131l hesaplanaca\u011f\u0131 (form\u00fcl) ve v\u00fccut geli\u015ftirme egzersizleri \u00e7\u00f6z\u00fcld\u00fc.","breadcrumb":{"@id":"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/#breadcrumb"},"inLanguage":"tr","potentialAction":[{"@type":"ReadAction","target":["https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/physigeek.com\/tr\/fiziksel-agirlik\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Ev","item":"https:\/\/physigeek.com\/tr\/"},{"@type":"ListItem","position":2,"name":"A\u011f\u0131rl\u0131k (fiziksel)"}]},{"@type":"WebSite","@id":"https:\/\/physigeek.com\/tr\/#website","url":"https:\/\/physigeek.com\/tr\/","name":"Physigeek","description":"Fizi\u011fi kolay yoldan \u00f6\u011frenin!","publisher":{"@id":"https:\/\/physigeek.com\/tr\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/physigeek.com\/tr\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"tr"},{"@type":"Organization","@id":"https:\/\/physigeek.com\/tr\/#organization","name":"Physigeek","url":"https:\/\/physigeek.com\/tr\/","logo":{"@type":"ImageObject","inLanguage":"tr","@id":"https:\/\/physigeek.com\/tr\/#\/schema\/logo\/image\/","url":"https:\/\/physigeek.com\/tr\/wp-content\/uploads\/2023\/10\/physigeek-logos.png","contentUrl":"https:\/\/physigeek.com\/tr\/wp-content\/uploads\/2023\/10\/physigeek-logos.png","width":180,"height":42,"caption":"Physigeek"},"image":{"@id":"https:\/\/physigeek.com\/tr\/#\/schema\/logo\/image\/"}},{"@type":"Person","@id":"https:\/\/physigeek.com\/tr\/#\/schema\/person\/b49369b8bed2d27dbd13757330e431a5","name":"Jonathan Reynolds","image":{"@type":"ImageObject","inLanguage":"tr","@id":"https:\/\/physigeek.com\/tr\/#\/schema\/person\/image\/","url":"http:\/\/physigeek.com\/tr\/wp-content\/uploads\/2023\/10\/Jonathan-Reynolds-96x96.jpg","contentUrl":"http:\/\/physigeek.com\/tr\/wp-content\/uploads\/2023\/10\/Jonathan-Reynolds-96x96.jpg","caption":"Jonathan Reynolds"},"sameAs":["http:\/\/physigeek.com\/tr"]}]}},"yoast_meta":{"yoast_wpseo_title":"","yoast_wpseo_metadesc":"","yoast_wpseo_canonical":""},"_links":{"self":[{"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/posts\/46","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/comments?post=46"}],"version-history":[{"count":0,"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/posts\/46\/revisions"}],"wp:attachment":[{"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/media?parent=46"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/categories?post=46"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/tags?post=46"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}