{"id":26,"date":"2023-06-27T09:15:43","date_gmt":"2023-06-27T09:15:43","guid":{"rendered":"https:\/\/physigeek.com\/tr\/paralel-kuvvetler\/"},"modified":"2023-06-27T09:15:43","modified_gmt":"2023-06-27T09:15:43","slug":"paralel-kuvvetler","status":"publish","type":"post","link":"https:\/\/physigeek.com\/tr\/paralel-kuvvetler\/","title":{"rendered":"Paralel kuvvetler"},"content":{"rendered":"

Bu makale paralel kuvvetlerin ne oldu\u011funu a\u00e7\u0131klamaktad\u0131r. Ayr\u0131ca paralel kuvvet sistemlerinin \u00f6rneklerini de bulacaks\u0131n\u0131z. Son olarak, ayn\u0131 y\u00f6ndeki paralel kuvvetler sisteminden ve farkl\u0131 y\u00f6ndeki paralel kuvvetlerden olu\u015fan bir sistemden kaynaklanan kuvvetin nas\u0131l hesaplanaca\u011f\u0131n\u0131 g\u00f6rebileceksiniz. <\/p>\n

<\/span> Paralel kuvvetler nelerdir?<\/span><\/h2>\n

Paralel kuvvetler<\/strong> etki \u00e7izgileri paralel olan kuvvetlerdir. Ba\u015fka bir deyi\u015fle, iki veya daha fazla kuvvet ayn\u0131 y\u00f6ne sahip olduklar\u0131nda paraleldir.<\/p>\n

\u0130ki paralel kuvvet ayn\u0131 y\u00f6ne sahip olabilece\u011fi gibi z\u0131t y\u00f6nlere de sahip olabilir. Ancak \u00fczerine yans\u0131t\u0131ld\u0131klar\u0131 \u00e7izgiler paralel oldu\u011fu s\u00fcrece kuvvetler paralel kabul edilir. <\/p>\n

\n
\"\"<\/figure>\n<\/div>\n

Tan\u0131m gere\u011fi iki paralel kuvvetin e\u015f zamanl\u0131 kuvvetler<\/a> olamayaca\u011f\u0131n\u0131, ancak e\u015fdo\u011frusal kuvvetler<\/a><\/span> olabilece\u011fini unutmay\u0131n. <\/p>\n

<\/span>Paralel Kuvvet \u00d6rnekleri<\/span><\/h2>\n

Paralel kuvvet kavram\u0131n\u0131 tam olarak anlamak i\u00e7in, bu t\u00fcr kuvvete ili\u015fkin g\u00fcnl\u00fck hayattan al\u0131nan iki \u00f6rne\u011fi burada bulabilirsiniz.<\/p>\n

\u00d6rne\u011fin, iki ki\u015fi \u00e7ok a\u011f\u0131r bir nesneyi ayn\u0131 anda yatay olarak hareket ettirmeye \u00e7al\u0131\u015ft\u0131\u011f\u0131nda, her iki ki\u015fi de nesneyi ayn\u0131 tarafa hareket ettirmek istedi\u011finden, ayn\u0131 y\u00f6nde iki paralel kuvvet uyguluyorlar. <\/p>\n

\n
\"paralel<\/figure>\n<\/div>\n

\u0130ki paralel kuvvete bir ba\u015fka \u00f6rnek de her iki aya\u011f\u0131m\u0131zla ayn\u0131 anda z\u0131plamam\u0131zd\u0131r. Atlamak i\u00e7in her bacak yere dikey bir kuvvet uygular.<\/p>\n

A\u015fa\u011f\u0131daki b\u00f6l\u00fcmlerde iki paralel kuvvetin nas\u0131l bir sonu\u00e7 kuvvetiyle de\u011fi\u015ftirildi\u011fini g\u00f6rece\u011fiz. Ancak a\u015fa\u011f\u0131daki paralel kuvvetler egzersizlerini anlayabilmek i\u00e7in \u00f6ncelikle denge ko\u015fullar\u0131n\u0131n ne oldu\u011funu<\/a><\/span> bilmeniz gerekir. <\/p>\n

<\/span> Ayn\u0131 y\u00f6ndeki paralel kuvvetler<\/span><\/h2>\n

Ayn\u0131 y\u00f6ndeki iki paralel kuvvetten<\/strong> kaynaklanan kuvvet, de\u011feri paralel kuvvetlerin mod\u00fcllerinin toplam\u0131 olan bir kuvvettir ve uygulama noktas\u0131 a\u015fa\u011f\u0131daki ili\u015fkiye yan\u0131t verir: <\/p>\n

\n
\"Ayn\u0131<\/figure>\n<\/div>\n

Ortaya \u00e7\u0131kan kuvvetin uygulama noktas\u0131n\u0131 elde etmek i\u00e7in kullan\u0131lan denklem, moment denge ko\u015fulunun, yani ikinci denge ko\u015fulunun uygulanmas\u0131ndan gelir.<\/p>\n

\u00d6rne\u011fin, ayn\u0131 y\u00f6nde 12 m uzunlukla ayr\u0131lm\u0131\u015f iki paralel kuvveti toplamak istersek, ortaya \u00e7\u0131kan kuvvetin de\u011ferini bulmak i\u00e7in \u00f6nce kuvvetlerin yo\u011funluklar\u0131n\u0131 toplamam\u0131z gerekir:<\/p>\n

\n

\"R=F_1+F_2=9+15=24\\N\"<\/p>\n<\/p>\n

Art\u0131k kuvvetin uygulama noktas\u0131n\u0131 belirlemek kal\u0131yor. Bunu yapmak i\u00e7in a\u015fa\u011f\u0131daki denklemi \u00e7\u00f6zmeliyiz:<\/p>\n

\n

\"F_1\\cdot<\/p>\n<\/p>\n

\n

\"9\\cdot<\/p>\n<\/p>\n

\n

\"9a=180<\/p>\n<\/p>\n

\n

\"9<\/p>\n<\/p>\n

\n

\"24a=180\"<\/p>\n<\/p>\n

\n

\"a=\\cfrac{180}{24}=7,5<\/p>\n<\/p>\n

Sonu\u00e7 olarak, bu iki paralel kuvvetin olu\u015fturdu\u011fu sistemden kaynaklanan kuvvet 24 N b\u00fcy\u00fckl\u00fc\u011f\u00fcnde bir kuvvet olup, birinci kuvvetin uygulama noktas\u0131n\u0131n 7,5 m sa\u011f\u0131nda yer almaktad\u0131r. <\/p>\n

<\/span> Ters y\u00f6ndeki paralel kuvvetler<\/span><\/h2>\n

Z\u0131t y\u00f6ndeki iki paralel kuvvetin<\/strong> sonu\u00e7ta ortaya \u00e7\u0131kan kuvveti, de\u011feri paralel kuvvetlerin mod\u00fcllerindeki farka e\u015fit olan bir kuvvettir ve bunun uygulama noktas\u0131n\u0131 hesaplamak i\u00e7in a\u015fa\u011f\u0131daki ili\u015fkiyi uygulamak gerekir: <\/p>\n

\n
\"Kar\u015f\u0131t<\/figure>\n<\/div>\n

\u00d6rne\u011fin, 8 m uzunlukla ayr\u0131lan farkl\u0131 y\u00f6nlerdeki 11 N ve 7 N’lik iki paralel kuvveti bunlar\u0131n sonu\u00e7taki kuvvetiyle de\u011fi\u015ftirmek istersek, ortaya \u00e7\u0131kan kuvvetin de\u011ferini bulmak i\u00e7in \u00f6nce kuvvetlerin b\u00fcy\u00fckl\u00fc\u011f\u00fcn\u00fc \u00e7\u0131karmam\u0131z gerekir. :<\/p>\n

\n

\"R=F_1-F_7=11-7=4\\N\"<\/p>\n<\/p>\n

Ortaya \u00e7\u0131kan kuvvetin mod\u00fcl\u00fc hesapland\u0131ktan sonra geriye kalan tek \u015fey uygulama noktas\u0131n\u0131 bulmakt\u0131r, bu nedenle a\u015fa\u011f\u0131daki denklemi \u00f6neriyoruz ve \u00e7\u00f6z\u00fcyoruz:<\/p>\n

\n

\"F_1\\cdot<\/p>\n<\/p>\n

\n

\"11\\cdot<\/p>\n<\/p>\n

\n

\"11x=56+7x\"<\/p>\n<\/p>\n

\n

\"11x-7x=56\"<\/p>\n<\/p>\n

\n

\"4x=56\"<\/p>\n<\/p>\n

\n

\"x=\\cfrac{56}{4}=14<\/p>\n<\/p>\n

Bu paralel kuvvetler sisteminin sonu\u00e7ta ortaya \u00e7\u0131kan kuvveti, bu nedenle, 4 N b\u00fcy\u00fckl\u00fc\u011f\u00fcnde bir kuvvettir ve birinci kuvvetin uygulama noktas\u0131n\u0131n 14 m solunda bulunur.<\/p>\n

\u00d6te yandan, z\u0131t y\u00f6nlerdeki iki paralel kuvvetin \u015fiddeti ayn\u0131 oldu\u011funda fizikte bunlara bir kuvvet \u00e7ifti deriz. Birka\u00e7 kuvvetin \u00f6zelli\u011fi bir moment yaratmas\u0131 ve dolay\u0131s\u0131yla cismi d\u00f6nd\u00fcrmesidir. Baz\u0131 kuvvetlerin momentinin nas\u0131l hesapland\u0131\u011f\u0131n\u0131 buraya t\u0131klayarak g\u00f6rebilirsiniz: <\/p>\n

\u27a4<\/span> Bak\u0131n\u0131z:<\/strong> baz\u0131 kuvvetlerin momenti<\/a><\/div>\n","protected":false},"excerpt":{"rendered":"

Bu makale paralel kuvvetlerin ne oldu\u011funu a\u00e7\u0131klamaktad\u0131r. Ayr\u0131ca paralel kuvvet sistemlerinin \u00f6rneklerini de bulacaks\u0131n\u0131z. Son olarak, ayn\u0131 y\u00f6ndeki paralel kuvvetler sisteminden ve farkl\u0131 y\u00f6ndeki paralel kuvvetlerden olu\u015fan bir sistemden kaynaklanan kuvvetin nas\u0131l hesaplanaca\u011f\u0131n\u0131 g\u00f6rebileceksiniz. Paralel kuvvetler nelerdir? Paralel kuvvetler etki \u00e7izgileri paralel olan kuvvetlerdir. Ba\u015fka bir deyi\u015fle, iki veya daha fazla kuvvet ayn\u0131 y\u00f6ne sahip …<\/p>\n

Paralel kuvvetler<\/span> Devam\u0131 »<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-26","post","type-post","status-publish","format-standard","hentry","category-dinamik"],"yoast_head":"\nParalel kuvvetler: tan\u0131m, \u00f6rnekler ve \u00e7\u00f6z\u00fclm\u00fc\u015f al\u0131\u015ft\u0131rmalar<\/title>\n<meta name=\"description\" content=\"Paralel kuvvetler nelerdir - 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