{"id":254,"date":"2023-06-23T05:53:04","date_gmt":"2023-06-23T05:53:04","guid":{"rendered":"https:\/\/physigeek.com\/tr\/surtunme-katsayisi-veya-surtunme-katsayisi\/"},"modified":"2023-06-23T05:53:04","modified_gmt":"2023-06-23T05:53:04","slug":"surtunme-katsayisi-veya-surtunme-katsayisi","status":"publish","type":"post","link":"https:\/\/physigeek.com\/tr\/surtunme-katsayisi-veya-surtunme-katsayisi\/","title":{"rendered":"S\u00fcrt\u00fcnme katsay\u0131s\u0131 (veya s\u00fcrt\u00fcnme katsay\u0131s\u0131)"},"content":{"rendered":"<p>Bu makale fizikte s\u00fcrt\u00fcnme katsay\u0131s\u0131n\u0131n (veya s\u00fcrt\u00fcnme katsay\u0131s\u0131n\u0131n) ne oldu\u011funu a\u00e7\u0131klamaktad\u0131r. B\u00f6ylece s\u00fcrt\u00fcnme katsay\u0131s\u0131n\u0131n nas\u0131l hesaplanaca\u011f\u0131n\u0131, s\u00fcrt\u00fcnme katsay\u0131s\u0131 t\u00fcrlerinin neler oldu\u011funu ve ayr\u0131ca ad\u0131m ad\u0131m \u00e7\u00f6z\u00fclen al\u0131\u015ft\u0131rmalar\u0131 \u00f6\u011freneceksiniz. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-el-coeficiente-de-friccion\"><\/span> S\u00fcrt\u00fcnme katsay\u0131s\u0131 nedir?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>S\u00fcrt\u00fcnme katsay\u0131s\u0131<\/strong> olarak da adland\u0131r\u0131lan <strong>s\u00fcrt\u00fcnme<\/strong> katsay\u0131s\u0131, iki cisimden biri di\u011ferinin \u00fczerinde hareket etmek istedi\u011finde y\u00fczeyleri aras\u0131ndaki s\u00fcrt\u00fcnmeyi g\u00f6steren bir katsay\u0131d\u0131r.<\/p>\n<p> Dolay\u0131s\u0131yla s\u00fcrt\u00fcnme katsay\u0131s\u0131, bir cismin di\u011ferinin \u00fczerinde hareket etmesini zorla\u015ft\u0131ran kuvvet olan s\u00fcrt\u00fcnme kuvvetini (veya s\u00fcrt\u00fcnme kuvvetini) hesaplamak i\u00e7in kullan\u0131l\u0131r. Yani s\u00fcrt\u00fcnme katsay\u0131s\u0131 ne kadar y\u00fcksek olursa s\u00fcrt\u00fcnme kuvveti de o kadar b\u00fcy\u00fck olur.<\/p>\n<p> S\u00fcrt\u00fcnme katsay\u0131s\u0131 boyutsuz bir katsay\u0131d\u0131r, yani birimi yoktur. Benzer \u015fekilde, Yunan harfi \u03bc s\u0131kl\u0131kla s\u00fcrt\u00fcnme katsay\u0131s\u0131n\u0131 temsil eden bir sembol olarak kullan\u0131l\u0131r. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Formula-del-coeficiente-de-friccion\"><\/span> S\u00fcrt\u00fcnme katsay\u0131s\u0131 form\u00fcl\u00fc<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> S\u00fcrt\u00fcnme katsay\u0131s\u0131, s\u00fcrt\u00fcnme kuvveti (veya s\u00fcrt\u00fcnme kuvveti) ile normal kuvvet aras\u0131ndaki orana e\u015fittir. Bu nedenle s\u00fcrt\u00fcnme katsay\u0131s\u0131, s\u00fcrt\u00fcnme kuvvetinin normal kuvvete b\u00f6l\u00fcnmesiyle hesaplan\u0131r.<\/p>\n<p> Ba\u015fka bir deyi\u015fle <strong>s\u00fcrt\u00fcnme katsay\u0131s\u0131n\u0131n form\u00fcl\u00fc<\/strong> \u015fu \u015fekildedir:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-2bee3710c7506bf8ff2456662a57f279_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\mu=\\cfrac{F_R}{N}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"59\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p style=\"margin-bottom:5px\"> Alt\u0131n: <\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-05d9eae892416bd34247a25207f8b718_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\mu\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"11\" style=\"vertical-align: -4px;\"><\/p>\n<p> birimi olmayan s\u00fcrt\u00fcnme katsay\u0131s\u0131d\u0131r. <\/span><\/li>\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-5b005ac29604de5f2904d2da7ade0238_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_R\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"22\" style=\"vertical-align: -3px;\"><\/p>\n<p> Newton cinsinden ifade edilen <a href=\"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/\">s\u00fcrt\u00fcnme kuvvetidir<\/a> .<\/span><\/li>\n<li><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7354bae77b50b7d1faed3e8ea7a3511a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"16\" style=\"vertical-align: 0px;\"><\/p>\n<p> Newton cinsinden ifade edilen normal kuvvettir.<\/span><\/li>\n<\/ul>\n<p> S\u00fcrt\u00fcnme katsay\u0131s\u0131n\u0131n birimi olmayan bir katsay\u0131 oldu\u011funu unutmay\u0131n \u00e7\u00fcnk\u00fc ayn\u0131 birimlere sahip iki niceli\u011fin b\u00f6l\u00fcnmesiyle hesaplan\u0131r. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Coeficiente-de-friccion-estatico-y-dinamico\"><\/span> Statik ve dinamik s\u00fcrt\u00fcnme katsay\u0131s\u0131<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> S\u00fcrt\u00fcnme kuvvetinin de\u011feri cismin hareketsiz veya hareket halinde olmas\u0131na ba\u011fl\u0131d\u0131r. \u00d6rne\u011fin, muhtemelen \u00e7ok a\u011f\u0131r bir g\u00f6vdeyi s\u00fcr\u00fcklemeye \u00e7al\u0131\u015ft\u0131n\u0131z ve ilk ba\u015fta onu hareket ettirmek zor oldu, ancak g\u00f6vdeyi biraz hareket ettirmeyi ba\u015fard\u0131ktan sonra nesneyi s\u00fcr\u00fcklemeye devam etmek daha kolay olacakt\u0131r.<\/p>\n<p> Ger\u00e7ekten de, genel olarak, cisim sabitken s\u00fcrt\u00fcnme kuvveti, cismin hareket halindeki s\u00fcrt\u00fcnme kuvvetinden daha fazlad\u0131r. Bu nedenle iki t\u00fcr s\u00fcrt\u00fcnme kuvveti vard\u0131r:<\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Statik s\u00fcrt\u00fcnme kuvveti<\/strong> : V\u00fccut hen\u00fcz hareket halinde de\u011filken etki eden s\u00fcrt\u00fcnme kuvvetidir.<\/span><\/li>\n<li> <span style=\"color:#101010;font-weight: normal;\"><strong>Dinamik (veya kinetik) s\u00fcrt\u00fcnme kuvveti<\/strong> : Bu, v\u00fccut harekete ba\u015flad\u0131\u011f\u0131nda etki eden s\u00fcrt\u00fcnme kuvvetidir.<\/span><\/li>\n<\/ul>\n<p> Dolay\u0131s\u0131yla iki t\u00fcr s\u00fcrt\u00fcnme katsay\u0131s\u0131 da vard\u0131r:<\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Statik s\u00fcrt\u00fcnme katsay\u0131s\u0131 (\u03bc <sub>E<\/sub> )<\/strong> : Statik s\u00fcrt\u00fcnme kuvvetini hesaplamak i\u00e7in kullan\u0131l\u0131r. Hareketin hen\u00fcz ba\u015flamad\u0131\u011f\u0131, yani hareketsiz durumdaki iki cismin y\u00fczeyleri aras\u0131ndaki s\u00fcrt\u00fcnmeyi belirtir.<\/span><\/li>\n<li> <span style=\"color:#101010;font-weight: normal;\"><strong>Dinamik s\u00fcrt\u00fcnme katsay\u0131s\u0131 (\u03bc <sub>D<\/sub> )<\/strong> : Dinamik s\u00fcrt\u00fcnme kuvvetini hesaplamak i\u00e7in kullan\u0131l\u0131r. Biri di\u011ferinin \u00fczerinde kayarken iki cismin y\u00fczeyleri aras\u0131ndaki s\u00fcrt\u00fcnmeyi g\u00f6sterir.<\/span><\/li>\n<\/ul>\n<p> Ek olarak s\u00fcrt\u00fcnme kuvvetinin de\u011feri a\u015fa\u011f\u0131daki grafikte g\u00f6sterildi\u011fi gibi de\u011fi\u015fir: <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/graphique-force-statique-et-dynamique-friction.png\" alt=\"Statik ve dinamik s\u00fcrt\u00fcnme kuvveti\" class=\"wp-image-4356\" width=\"381\" height=\"261\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/graphique-force-statique-et-dynamique-friction-300x205.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/graphique-force-statique-et-dynamique-friction.png 725w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<p> Statik s\u00fcrt\u00fcnme kuvveti, cismi hareket ettirmek i\u00e7in uygulanan kuvvete e\u015fittir ancak y\u00f6n\u00fc z\u0131tt\u0131r. Maksimum de\u011feri, statik s\u00fcrt\u00fcnme katsay\u0131s\u0131 ile normal kuvvet aras\u0131ndaki \u00e7arp\u0131md\u0131r. Uygulanan kuvvet bu de\u011feri a\u015ft\u0131\u011f\u0131nda v\u00fccut hareket etmeye ba\u015flar.<\/p>\n<p> B\u00f6ylece, cisim hareket halindeyken, uygulanan kuvvetin de\u011feri ne olursa olsun, dinamik s\u00fcrt\u00fcnme kuvveti, dinamik s\u00fcrt\u00fcnme katsay\u0131s\u0131 ile normal kuvvet aras\u0131ndaki \u00e7arp\u0131ma e\u015fde\u011fer sabit bir de\u011fere sahiptir. Ayr\u0131ca bu de\u011fer statik s\u00fcrt\u00fcnme kuvvetinin maksimum de\u011ferinden biraz daha d\u00fc\u015f\u00fckt\u00fcr.<\/p>\n<p> Sonu\u00e7 olarak statik s\u00fcrt\u00fcnme katsay\u0131s\u0131 dinamik s\u00fcrt\u00fcnme katsay\u0131s\u0131ndan daha b\u00fcy\u00fckt\u00fcr. Bu nedenle bir cismi hareket ettirmeye ba\u015flamak, hareket ba\u015flam\u0131\u015fken onu hareket ettirmekten daha zordur. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Valores-del-coeficiente-de-friccion\"><\/span> S\u00fcrt\u00fcnme katsay\u0131s\u0131 de\u011ferleri<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> A\u015fa\u011f\u0131daki tabloda statik s\u00fcrt\u00fcnme katsay\u0131s\u0131 ve dinamik s\u00fcrt\u00fcnme katsay\u0131s\u0131n\u0131n baz\u0131 ortak de\u011ferlerini g\u00f6rebilirsiniz:<\/p>\n<figure class=\"wp-block-table is-style-stripes\">\n<table>\n<thead>\n<tr>\n<th> Temas y\u00fczeyleri<\/th>\n<th class=\"has-text-align-center\" data-align=\"center\"> Statik s\u00fcrt\u00fcnme katsay\u0131s\u0131 (\u03bc <sub>e<\/sub> )<\/th>\n<th class=\"has-text-align-center\" data-align=\"center\"> Dinamik s\u00fcrt\u00fcnme katsay\u0131s\u0131 ( <sub>\u03bcd<\/sub> )<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td> \u00e7elik \u00fczerine bak\u0131r<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,53<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,36<\/td>\n<\/tr>\n<tr>\n<td> \u00e7elik \u00fczerine \u00e7elik<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,74<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,57<\/td>\n<\/tr>\n<tr>\n<td> \u00e7elik \u00fczerine al\u00fcminyum<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0.61<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,47<\/td>\n<\/tr>\n<tr>\n<td> \u00e7imento \u00fczerine kau\u00e7uk<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 1<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,8<\/td>\n<\/tr>\n<tr>\n<td> ah\u015fap \u00fczerine ah\u015fap<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,25-0,5<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,2<\/td>\n<\/tr>\n<tr>\n<td> Deri \u00fczerine ah\u015fap<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,5<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,4<\/td>\n<\/tr>\n<tr>\n<td> Teflon ve Teflon<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,04<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,04<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n<p> Bu de\u011ferlerin y\u00fczey p\u00fcr\u00fczl\u00fcl\u00fc\u011f\u00fc, s\u0131cakl\u0131k, y\u00fczeyler aras\u0131ndaki ba\u011f\u0131l h\u0131z gibi bir\u00e7ok fakt\u00f6re ba\u011fl\u0131 olarak de\u011fi\u015febilece\u011fini unutmay\u0131n. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicios-resueltos-del-coeficiente-de-friccion\"><\/span> \u00c7\u00f6z\u00fclm\u00fc\u015f S\u00fcrt\u00fcnme Katsay\u0131s\u0131 Sorunlar\u0131<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> 1. Egzersiz<\/h3>\n<p> K\u00fctlesi m=12 kg olan bir blo\u011fu d\u00fcz bir y\u00fczey \u00fczerinde hareket ettirmek istiyoruz ve blok tam 35 N&#8217;luk bir kuvvet uyguland\u0131\u011f\u0131nda hareket etmeye ba\u015fl\u0131yor. Zemin ile blok aras\u0131ndaki statik s\u00fcrt\u00fcnme katsay\u0131s\u0131 nedir? Veri: g=10 m\/ <sup>s2<\/sup> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-statique.png\" alt=\"Statik s\u00fcrt\u00fcnme katsay\u0131s\u0131 problemini \u00e7\u00f6zd\u00fc\" class=\"wp-image-4302\" width=\"285\" height=\"125\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-statique-300x132.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-statique.png 650w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>\u00c7\u00f6z\u00fcm\u00fc g\u00f6r\u00fcn<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> \u00d6ncelikle blo\u011fa etki eden t\u00fcm kuvvetlerin grafi\u011fini \u00e7iziyoruz: <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-statique.png\" alt=\"Statik s\u00fcrt\u00fcnme katsay\u0131s\u0131 veya statik s\u00fcrt\u00fcnme katsay\u0131s\u0131n\u0131n \u00e7\u00f6z\u00fcml\u00fc al\u0131\u015ft\u0131rmas\u0131\" class=\"wp-image-4303\" width=\"269\" height=\"359\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-statique-225x300.png 225w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-statique.png 670w\" sizes=\"auto, (max-width: 225px) 100vw, 225px\"><\/figure>\n<p class=\"has-text-align-left\"> Denge limit durumunda a\u015fa\u011f\u0131daki iki denklem do\u011frulan\u0131r:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-318d3aaff48777c13e5ac24cb775f6b0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N=P\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"54\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-b2d0fc9325264d9c3dceae21b529d2c5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_R=F\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"60\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> B\u00f6ylece s\u00fcrt\u00fcnme kuvveti cisme uygulanan yatay kuvvete e\u015fit olacakt\u0131r:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-f433d79addb4c8cfc17c71cf797f4905_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_R=F=35 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"123\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> \u00d6te yandan normal kuvvetin de\u011ferini a\u011f\u0131rl\u0131k kuvveti form\u00fcl\u00fcn\u00fc kullanarak hesaplayabiliriz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fdd5a10090733132a78410e57a059c2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{l}N=P\\\\[3ex] N=m\\cdot g\\\\[3ex] N=12\\cdot 10 \\\\[3ex] N=120 \\ N\\end{array }\" title=\"Rendered by QuickLaTeX.com\" height=\"147\" width=\"88\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Son olarak, s\u00fcrt\u00fcnme kuvvetinin ve normal kuvvetin de\u011ferini \u00f6\u011frendikten sonra de\u011ferini belirlemek i\u00e7in statik s\u00fcrt\u00fcnme katsay\u0131s\u0131 form\u00fcl\u00fcn\u00fc uygular\u0131z: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-20cdd7c8dcf9b6af55e1fe95eedf8da2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\mu_e=\\cfrac{F_R}{N}=\\cfrac{35}{120}=0.29\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"174\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Al\u0131\u015ft\u0131rma 2<\/h3>\n<p> E\u011fimi 45\u00b0 olan bir d\u00fczlemin tepesine m=6 kg k\u00fctleli bir cisim yerle\u015ftiriyoruz. E\u011fer cisim e\u011fik d\u00fczlem \u00fczerinde 4 m\/s <sup>2<\/sup> ivmeyle kay\u0131yorsa, e\u011fik d\u00fczlem y\u00fczeyi ile cismin y\u00fczeyi aras\u0131ndaki dinamik s\u00fcrt\u00fcnme katsay\u0131s\u0131 nedir? Veri: g=10 m\/ <sup>s2<\/sup> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-dynamique.png\" alt=\"S\u00fcrt\u00fcnme katsay\u0131s\u0131 veya dinamik s\u00fcrt\u00fcnme sorunu\" class=\"wp-image-4281\" width=\"203\" height=\"205\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-dynamique-298x300.png 298w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-dynamique-150x150.png 150w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-dynamique.png 479w\" sizes=\"auto, (max-width: 298px) 100vw, 298px\"><\/figure>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>\u00c7\u00f6z\u00fcm\u00fc g\u00f6r\u00fcn<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Dinamik ile ilgili herhangi bir fizik problemini \u00e7\u00f6zmek i\u00e7in yapmam\u0131z gereken ilk \u015fey serbest cisim diyagram\u0131n\u0131 \u00e7izmektir. Buna g\u00f6re sisteme etki eden t\u00fcm kuvvetler \u015funlard\u0131r: <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-dynamique.png\" alt=\"S\u00fcrt\u00fcnme katsay\u0131s\u0131 veya dinamik s\u00fcrt\u00fcnmenin \u00e7\u00f6z\u00fclm\u00fc\u015f egzersizi\" class=\"wp-image-4282\" width=\"248\" height=\"301\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-dynamique-247x300.png 247w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-dynamique.png 572w\" sizes=\"auto, (max-width: 247px) 100vw, 247px\"><\/figure>\n<p class=\"has-text-align-left\"> Cisim 1. eksen y\u00f6n\u00fcnde (e\u011fik d\u00fczleme paralel) bir ivmeye sahiptir, ancak 2. eksen y\u00f6n\u00fcnde (e\u011fik d\u00fczleme dik) cisim hareketsizdir. Bu bilgiden yola \u00e7\u0131karak sistem kuvvetlerinin denklemlerini \u00f6neriyoruz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d87a1ef6aaa3476891df5da8334cbc49_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_1-F_R=m\\cdot a\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"124\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6bdf90ed250934bf6cffbb110bc792a4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_2-N=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"90\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> B\u00f6ylece normal kuvveti ikinci denklemden hesaplayabiliriz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-59341555fe3d5fe315ceb1864547873b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{l}N=P_2\\\\[3ex]N=m\\cdot g\\cdot \\text{cos}(\\alpha) \\\\[3ex] N=6 \\cdot 10 \\cdot \\ text{cos}(45\u00ba)\\\\[3ex]N=42,43 \\ N\\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"151\" width=\"185\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> \u00d6te yandan s\u00fcrt\u00fcnme kuvvetinin (veya s\u00fcrt\u00fcnme kuvvetinin) de\u011ferini sunulan ilk denklemden hesapl\u0131yoruz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d8f2aff2a81d98ddcea04b1988282fda_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{l}P_1-F_R=m\\cdot a\\\\[3ex]F_R=P_1-m\\cdot a\\\\[3ex]F_R=m\\cdot g\\cdot \\text{sin} (\\alpha)-m\\cdot a\\\\[3ex]F_R=6\\cdot 10\\cdot \\text{sin}(45\u00ba)-6\\cdot 4\\\\[3ex]F_R=18.43 \\ N\\end{ array} \" title=\"Rendered by QuickLaTeX.com\" height=\"195\" width=\"204\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Normal kuvvetin ve s\u00fcrt\u00fcnme kuvvetinin de\u011ferini bildi\u011fimizde, buna kar\u015f\u0131l\u0131k gelen form\u00fcl\u00fc kullanarak dinamik s\u00fcrt\u00fcnme katsay\u0131s\u0131n\u0131 belirleyebiliriz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-31af78ef6e04fa66121d64aa3570f5a6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\mu_d=\\cfrac{F_R}{N}=\\cfrac{18.43}{43.43}=\\bm{0.42}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"187\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Bu makale fizikte s\u00fcrt\u00fcnme katsay\u0131s\u0131n\u0131n (veya s\u00fcrt\u00fcnme katsay\u0131s\u0131n\u0131n) ne oldu\u011funu a\u00e7\u0131klamaktad\u0131r. B\u00f6ylece s\u00fcrt\u00fcnme katsay\u0131s\u0131n\u0131n nas\u0131l hesaplanaca\u011f\u0131n\u0131, s\u00fcrt\u00fcnme katsay\u0131s\u0131 t\u00fcrlerinin neler oldu\u011funu ve ayr\u0131ca ad\u0131m ad\u0131m \u00e7\u00f6z\u00fclen al\u0131\u015ft\u0131rmalar\u0131 \u00f6\u011freneceksiniz. S\u00fcrt\u00fcnme katsay\u0131s\u0131 nedir? S\u00fcrt\u00fcnme katsay\u0131s\u0131 olarak da adland\u0131r\u0131lan s\u00fcrt\u00fcnme katsay\u0131s\u0131, iki cisimden biri di\u011ferinin \u00fczerinde hareket etmek istedi\u011finde y\u00fczeyleri aras\u0131ndaki s\u00fcrt\u00fcnmeyi g\u00f6steren bir katsay\u0131d\u0131r. Dolay\u0131s\u0131yla s\u00fcrt\u00fcnme katsay\u0131s\u0131, &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/tr\/surtunme-katsayisi-veya-surtunme-katsayisi\/\"> <span class=\"screen-reader-text\">S\u00fcrt\u00fcnme katsay\u0131s\u0131 (veya s\u00fcrt\u00fcnme katsay\u0131s\u0131)<\/span> Devam\u0131 &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-254","post","type-post","status-publish","format-standard","hentry","category-dinamik"],"yoast_head":"<!-- This site is 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