{"id":251,"date":"2023-06-23T07:32:36","date_gmt":"2023-06-23T07:32:36","guid":{"rendered":"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/"},"modified":"2023-06-23T07:32:36","modified_gmt":"2023-06-23T07:32:36","slug":"surtunme-kuvveti-veya-surtunme-kuvveti","status":"publish","type":"post","link":"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/","title":{"rendered":"S\u00fcrt\u00fcnme kuvveti (veya s\u00fcrt\u00fcnme kuvveti)"},"content":{"rendered":"<p>Bu makale fizikte s\u00fcrt\u00fcnme kuvvetinin (veya s\u00fcrt\u00fcnme kuvvetinin) ne oldu\u011funu ve nas\u0131l hesapland\u0131\u011f\u0131n\u0131 a\u00e7\u0131klamaktad\u0131r. Bu nedenle s\u00fcrt\u00fcnme kuvvetinin \u00f6zelliklerini, var olan iki s\u00fcrt\u00fcnme kuvveti t\u00fcr\u00fcn\u00fc ve ayr\u0131ca uygulamaya y\u00f6nelik \u00f6zel egzersizleri bulacaks\u0131n\u0131z. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-la-fuerza-de-rozamiento\"><\/span> S\u00fcrt\u00fcnme kuvveti nedir?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>S\u00fcrt\u00fcnme<\/strong> <strong>kuvveti olarak da adland\u0131r\u0131lan s\u00fcrt\u00fcnme kuvveti<\/strong> , bir cismi ba\u015fka bir cismin y\u00fczeyi boyunca hareket ettirmeye \u00e7al\u0131\u015f\u0131rken ortaya \u00e7\u0131kan bir temas kuvvetidir.<\/p>\n<p> Daha do\u011frusu s\u00fcrt\u00fcnme kuvveti harekete paralel ve z\u0131t y\u00f6nde uygulanan bir kuvvettir. <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-de-friction-ou-force-de-friction.png\" alt=\"\" class=\"wp-image-4319\" width=\"293\" height=\"292\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-de-friction-ou-force-de-friction-300x300.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-de-friction-ou-force-de-friction-150x150.png 150w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-de-friction-ou-force-de-friction.png 625w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<p> \u0130ki t\u00fcr s\u00fcrt\u00fcnme kuvveti vard\u0131r: Statik s\u00fcrt\u00fcnme kuvveti ve dinamik s\u00fcrt\u00fcnme kuvveti. Duruma g\u00f6re biri veya di\u011feri hareket eder. A\u015fa\u011f\u0131da aralar\u0131ndaki fark\u0131 g\u00f6rece\u011fiz.<\/p>\n<p> Genel olarak s\u00fcrt\u00fcnme kuvveti F <sub>R<\/sub> sembol\u00fcyle temsil edilir. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Caracteristicas-de-la-fuerza-de-rozamiento\"><\/span> S\u00fcrt\u00fcnme kuvveti \u00f6zellikleri<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Art\u0131k s\u00fcrt\u00fcnme kuvvetinin (veya s\u00fcrt\u00fcnme kuvvetinin) tan\u0131m\u0131n\u0131 bildi\u011fimize g\u00f6re, bu t\u00fcr kuvvetin \u00f6zelliklerinin neler oldu\u011funa bakal\u0131m:<\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\">S\u00fcrt\u00fcnme kuvveti bir temas kuvvetidir, yani yaln\u0131zca iki y\u00fczey temas halinde oldu\u011funda etki eder.<\/span><\/li>\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\">Dahas\u0131, s\u00fcrt\u00fcnme kuvveti yaln\u0131zca bir cisim hareket etti\u011finde veya di\u011ferinin \u00fczerinde hareket etmeye \u00e7al\u0131\u015ft\u0131\u011f\u0131nda ortaya \u00e7\u0131kar.<\/span><\/li>\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\">S\u00fcrt\u00fcnme kuvvetinin y\u00f6n\u00fc hareket y\u00f6n\u00fcne paraleldir.<\/span><\/li>\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\">S\u00fcrt\u00fcnme kuvvetinin y\u00f6n\u00fc harekete z\u0131tt\u0131r.<\/span><\/li>\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\">S\u00fcrt\u00fcnme kuvveti cisimlerin kayma h\u0131z\u0131na ba\u011fl\u0131 de\u011fildir.<\/span><\/li>\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\">S\u00fcrt\u00fcnme kuvveti temas eden y\u00fczeyin b\u00fcy\u00fckl\u00fc\u011f\u00fcne ba\u011fl\u0131 de\u011fildir.<\/span><\/li>\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\">Ancak s\u00fcrt\u00fcnme kuvveti temas halindeki malzemelere, y\u00fczeylerine ve s\u0131cakl\u0131\u011fa ba\u011fl\u0131d\u0131r.<\/span><\/li>\n<li> <span style=\"color:#101010;font-weight: normal;\">S\u00fcrt\u00fcnme kuvveti normal kuvvetle do\u011fru orant\u0131l\u0131d\u0131r.<\/span> <\/li>\n<\/ul>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Formula-de-la-fuerza-de-rozamiento\"><\/span> S\u00fcrt\u00fcnme kuvveti form\u00fcl\u00fc<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> S\u00fcrt\u00fcnme kuvveti, s\u00fcrt\u00fcnme katsay\u0131s\u0131n\u0131n normal kuvvetle \u00e7arp\u0131m\u0131na e\u015fittir. Bu nedenle s\u00fcrt\u00fcnme kuvvetini hesaplamak i\u00e7in \u00f6nce normal kuvvet bulunmal\u0131, daha sonra bu kuvvet iki temas y\u00fczeyi aras\u0131ndaki s\u00fcrt\u00fcnme katsay\u0131s\u0131yla \u00e7arp\u0131lmal\u0131d\u0131r.<\/p>\n<p> <strong>S\u00fcrt\u00fcnme kuvvetinin (veya s\u00fcrt\u00fcnme kuvvetinin) form\u00fcl\u00fc<\/strong> bu nedenle a\u015fa\u011f\u0131daki gibidir:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-a865b1cd2e263b944debf58666ec1269_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_R=\\mu\\cdot N\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"86\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p style=\"margin-bottom:5px\"> Alt\u0131n: <\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-5b005ac29604de5f2904d2da7ade0238_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_R\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"22\" style=\"vertical-align: -3px;\"><\/p>\n<p> Newton cinsinden ifade edilen s\u00fcrt\u00fcnme veya s\u00fcrt\u00fcnme kuvvetidir. <\/span><\/li>\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-05d9eae892416bd34247a25207f8b718_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\mu\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"11\" style=\"vertical-align: -4px;\"><\/p>\n<p> birimi olmayan s\u00fcrt\u00fcnme katsay\u0131s\u0131d\u0131r.<\/span><\/li>\n<li><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7354bae77b50b7d1faed3e8ea7a3511a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"16\" style=\"vertical-align: 0px;\"><\/p>\n<p> Newton cinsinden ifade edilen normal kuvvettir. <\/span><\/li>\n<\/ul>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Fuerza-de-rozamiento-estatico-y-dinamico\"><\/span> Statik ve dinamik s\u00fcrt\u00fcnme kuvveti<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> S\u00fcrt\u00fcnme kuvvetinin de\u011feri cismin hareketsiz veya hareket halinde olmas\u0131na ba\u011fl\u0131d\u0131r. \u00d6rne\u011fin, elbette \u00e7ok a\u011f\u0131r bir cismi s\u00fcr\u00fcklemeye \u00e7al\u0131\u015ft\u0131n\u0131z ve ilk ba\u015fta onu hareket ettirmek zor oldu, ancak bedeni biraz hareket ettirmeyi ba\u015fard\u0131ktan sonra nesneyi s\u00fcr\u00fcklemeye devam etmek daha kolay hale geliyor.<\/p>\n<p> Ger\u00e7ekten de, genel olarak, cisim sabitken s\u00fcrt\u00fcnme kuvveti, cismin hareket halindeki s\u00fcrt\u00fcnme kuvvetinden daha fazlad\u0131r.<\/p>\n<p> B\u00f6ylece iki t\u00fcr s\u00fcrt\u00fcnme kuvvetini (veya s\u00fcrt\u00fcnme kuvvetini) ay\u0131rt ederiz:<\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Statik s\u00fcrt\u00fcnme kuvveti<\/strong> : V\u00fccut hen\u00fcz hareket halinde de\u011filken etki eden s\u00fcrt\u00fcnme kuvvetidir.<\/span><\/li>\n<li> <span style=\"color:#101010;font-weight: normal;\"><strong>Dinamik (veya kinetik) s\u00fcrt\u00fcnme kuvveti<\/strong> : Bu, v\u00fccut harekete ba\u015flad\u0131\u011f\u0131nda etki eden s\u00fcrt\u00fcnme kuvvetidir.<\/span><\/li>\n<\/ul>\n<p> Benzer \u015fekilde statik s\u00fcrt\u00fcnme katsay\u0131s\u0131, s\u0131ras\u0131yla statik s\u00fcrt\u00fcnme kuvvetini ve dinamik s\u00fcrt\u00fcnme kuvvetini belirlemek i\u00e7in kullan\u0131lan dinamik s\u00fcrt\u00fcnme katsay\u0131s\u0131ndan da ayr\u0131l\u0131r.<\/p>\n<p> Son olarak s\u00fcrt\u00fcnme kuvvetinin de\u011feri a\u015fa\u011f\u0131daki grafikte g\u00f6sterildi\u011fi gibi de\u011fi\u015fir: <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/graphique-force-statique-et-dynamique-friction.png\" alt=\"Statik ve dinamik s\u00fcrt\u00fcnme kuvveti\" class=\"wp-image-4356\" width=\"381\" height=\"261\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/graphique-force-statique-et-dynamique-friction-300x205.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/graphique-force-statique-et-dynamique-friction.png 725w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<p> Statik s\u00fcrt\u00fcnme kuvveti, cismi hareket ettirmek i\u00e7in uygulanan kuvvete e\u015fittir ancak y\u00f6n\u00fc z\u0131tt\u0131r. Maksimum de\u011feri, statik s\u00fcrt\u00fcnme katsay\u0131s\u0131 ile normal kuvvet aras\u0131ndaki \u00e7arp\u0131md\u0131r. Uygulanan kuvvet bu de\u011feri a\u015ft\u0131\u011f\u0131nda v\u00fccut hareket etmeye ba\u015flar.<\/p>\n<p> B\u00f6ylece, cisim hareket halindeyken, uygulanan kuvvetin de\u011feri ne olursa olsun, dinamik s\u00fcrt\u00fcnme kuvveti, dinamik s\u00fcrt\u00fcnme katsay\u0131s\u0131 ile normal kuvvet aras\u0131ndaki \u00e7arp\u0131ma e\u015fde\u011fer sabit bir de\u011fere sahiptir. Ayr\u0131ca bu de\u011fer statik s\u00fcrt\u00fcnme kuvvetinin maksimum de\u011ferinden biraz daha d\u00fc\u015f\u00fckt\u00fcr. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicios-resueltos-de-la-fuerza-de-rozamiento\"><\/span> S\u00fcrt\u00fcnme kuvveti ile ilgili \u00e7\u00f6z\u00fclm\u00fc\u015f al\u0131\u015ft\u0131rmalar<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> 1. Egzersiz<\/h3>\n<p> K\u00fctlesi m=12 kg olan bir blo\u011fun d\u00fcz bir y\u00fczey \u00fczerinde hareket ettirilmesi ama\u00e7lan\u0131yor ve blok 35 N&#8217;luk bir kuvvet uyguland\u0131\u011f\u0131nda hareket etmeye ba\u015fl\u0131yor. Zemin ile blok aras\u0131ndaki statik s\u00fcrt\u00fcnme katsay\u0131s\u0131 nedir? Veri: g=10 m\/ <sup>s2<\/sup> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-statique.png\" alt=\"Statik s\u00fcrt\u00fcnme katsay\u0131s\u0131 problemini \u00e7\u00f6zd\u00fc\" class=\"wp-image-4302\" width=\"285\" height=\"125\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-statique-300x132.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-statique.png 650w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>\u00c7\u00f6z\u00fcm\u00fc g\u00f6r\u00fcn<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> \u00d6ncelikle blo\u011fa etki eden t\u00fcm kuvvetlerin grafi\u011fini \u00e7iziyoruz: <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-statique.png\" alt=\"Statik s\u00fcrt\u00fcnme katsay\u0131s\u0131 veya statik s\u00fcrt\u00fcnme katsay\u0131s\u0131 ile ilgili \u00e7\u00f6z\u00fclm\u00fc\u015f al\u0131\u015ft\u0131rma\" class=\"wp-image-4303\" width=\"269\" height=\"359\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-statique-225x300.png 225w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-statique.png 670w\" sizes=\"auto, (max-width: 225px) 100vw, 225px\"><\/figure>\n<p class=\"has-text-align-left\"> Denge limit durumunda a\u015fa\u011f\u0131daki iki denklem sa\u011flan\u0131r:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-318d3aaff48777c13e5ac24cb775f6b0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N=P\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"54\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-b2d0fc9325264d9c3dceae21b529d2c5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_R=F\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"60\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> B\u00f6ylece s\u00fcrt\u00fcnme kuvveti cisme uygulanan yatay kuvvete e\u015fit olacakt\u0131r:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-f433d79addb4c8cfc17c71cf797f4905_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_R=F=35 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"123\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> \u00d6te yandan normal kuvvetin de\u011ferini a\u011f\u0131rl\u0131k kuvveti form\u00fcl\u00fcn\u00fc kullanarak hesaplayabiliriz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fdd5a10090733132a78410e57a059c2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{l}N=P\\\\[3ex] N=m\\cdot g\\\\[3ex] N=12\\cdot 10 \\\\[3ex] N=120 \\ N\\end{array }\" title=\"Rendered by QuickLaTeX.com\" height=\"147\" width=\"88\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Son olarak, s\u00fcrt\u00fcnme kuvvetinin ve normal kuvvetin de\u011ferini \u00f6\u011frendikten sonra de\u011ferini belirlemek i\u00e7in statik s\u00fcrt\u00fcnme katsay\u0131s\u0131 form\u00fcl\u00fcn\u00fc uygular\u0131z: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-20cdd7c8dcf9b6af55e1fe95eedf8da2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\mu_e=\\cfrac{F_R}{N}=\\cfrac{35}{120}=0.29\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"174\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Al\u0131\u015ft\u0131rma 2<\/h3>\n<p> E\u011fimi 45\u00b0 olan bir d\u00fczlemin tepesine m=6 kg k\u00fctleli bir cisim yerle\u015ftiriyoruz. E\u011fer cisim e\u011fik d\u00fczlem \u00fczerinde 4 m\/s <sup>2<\/sup> ivmeyle kay\u0131yorsa, e\u011fik d\u00fczlem y\u00fczeyi ile cismin y\u00fczeyi aras\u0131ndaki dinamik s\u00fcrt\u00fcnme katsay\u0131s\u0131 nedir? Veri: g=10 m\/ <sup>s2<\/sup> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-dynamique.png\" alt=\"S\u00fcrt\u00fcnme katsay\u0131s\u0131 veya dinamik s\u00fcrt\u00fcnme sorunu\" class=\"wp-image-4281\" width=\"203\" height=\"205\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-dynamique-298x300.png 298w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-dynamique-150x150.png 150w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-dynamique.png 479w\" sizes=\"auto, (max-width: 298px) 100vw, 298px\"><\/figure>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>\u00c7\u00f6z\u00fcm\u00fc g\u00f6r\u00fcn<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Dinamik ile ilgili herhangi bir fizik problemini \u00e7\u00f6zmek i\u00e7in yapmam\u0131z gereken ilk \u015fey serbest cisim diyagram\u0131n\u0131 \u00e7izmektir. Yani sisteme etki eden t\u00fcm kuvvetler \u015funlard\u0131r: <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-dynamique.png\" alt=\"S\u00fcrt\u00fcnme katsay\u0131s\u0131 veya dinamik s\u00fcrt\u00fcnmenin \u00e7\u00f6z\u00fclm\u00fc\u015f egzersizi\" class=\"wp-image-4282\" width=\"248\" height=\"301\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-dynamique-247x300.png 247w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-dynamique.png 572w\" sizes=\"auto, (max-width: 247px) 100vw, 247px\"><\/figure>\n<p class=\"has-text-align-left\"> Cisim 1. eksen y\u00f6n\u00fcnde (e\u011fik d\u00fczleme paralel) bir ivmeye sahiptir, ancak 2. eksen y\u00f6n\u00fcnde (e\u011fik d\u00fczleme dik) cisim hareketsizdir. Bu bilgiden yola \u00e7\u0131karak sistem kuvvetlerinin denklemlerini \u00f6neriyoruz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d87a1ef6aaa3476891df5da8334cbc49_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_1-F_R=m\\cdot a\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"124\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6bdf90ed250934bf6cffbb110bc792a4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_2-N=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"90\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> B\u00f6ylece normal kuvveti ikinci denklemden hesaplayabiliriz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-59341555fe3d5fe315ceb1864547873b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{l}N=P_2\\\\[3ex]N=m\\cdot g\\cdot \\text{cos}(\\alpha) \\\\[3ex] N=6 \\cdot 10 \\cdot \\ text{cos}(45\u00ba)\\\\[3ex]N=42,43 \\ N\\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"151\" width=\"185\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> \u00d6te yandan s\u00fcrt\u00fcnme kuvvetinin (veya s\u00fcrt\u00fcnme kuvvetinin) de\u011ferini sunulan ilk denklemden hesapl\u0131yoruz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d8f2aff2a81d98ddcea04b1988282fda_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{l}P_1-F_R=m\\cdot a\\\\[3ex]F_R=P_1-m\\cdot a\\\\[3ex]F_R=m\\cdot g\\cdot \\text{sin} (\\alpha)-m\\cdot a\\\\[3ex]F_R=6\\cdot 10\\cdot \\text{sin}(45\u00ba)-6\\cdot 4\\\\[3ex]F_R=18.43 \\ N\\end{ array} \" title=\"Rendered by QuickLaTeX.com\" height=\"195\" width=\"204\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Normal kuvvetin ve s\u00fcrt\u00fcnme kuvvetinin de\u011ferini bildi\u011fimizde, buna kar\u015f\u0131l\u0131k gelen form\u00fcl\u00fc kullanarak dinamik s\u00fcrt\u00fcnme katsay\u0131s\u0131n\u0131 belirleyebiliriz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-31af78ef6e04fa66121d64aa3570f5a6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\mu_d=\\cfrac{F_R}{N}=\\cfrac{18.43}{43.43}=\\bm{0.42}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"187\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Al\u0131\u015ft\u0131rma 3<\/h3>\n<p> 70 kg&#8217;l\u0131k bir k\u0131zak 30\u00b0&#8217;lik bir e\u011fimden a\u015fa\u011f\u0131 2 m\/s&#8217;lik ba\u015flang\u0131\u00e7 h\u0131z\u0131yla kaymaktad\u0131r. K\u0131zak ile kar aras\u0131ndaki dinamik s\u00fcrt\u00fcnme katsay\u0131s\u0131 0,2 oldu\u011funa g\u00f6re k\u0131za\u011f\u0131n 20 metre gittikten sonra elde edece\u011fi h\u0131z\u0131 hesaplay\u0131n\u0131z. Veri: g=10 m\/ <sup>s2<\/sup> . <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>\u00c7\u00f6z\u00fcm\u00fc g\u00f6r\u00fcn<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> \u00d6ncelikle k\u0131za\u011f\u0131n serbest cisim diyagram\u0131n\u0131 yap\u0131yoruz: <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-plan-incline.png\" alt=\"e\u011fik bir d\u00fczlem \u00fczerinde s\u00fcrt\u00fcnme kuvvetinin kararl\u0131 bir \u015fekilde uygulanmas\u0131\" class=\"wp-image-4345\" width=\"305\" height=\"355\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-plan-incline-258x300.png 258w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-plan-incline.png 706w\" sizes=\"auto, (max-width: 258px) 100vw, 258px\"><\/figure>\n<p class=\"has-text-align-left\"> K\u0131zak, eksen 1 y\u00f6n\u00fcnde (e\u011fik d\u00fczleme paralel) bir ivmeye sahiptir ancak eksen 2 y\u00f6n\u00fcnde (e\u011fik d\u00fczleme dik) hareketsiz kal\u0131r, dolay\u0131s\u0131yla kuvvet denklemleri \u015f\u00f6yledir: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d87a1ef6aaa3476891df5da8334cbc49_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_1-F_R=m\\cdot a\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"124\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6bdf90ed250934bf6cffbb110bc792a4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_2-N=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"90\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> \u0130kinci denklemden k\u0131za\u011fa etki eden normal kuvveti hesaplayabiliriz.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-90b32b903f8be520ec73748b3de9b8b3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{l}N=P_2\\\\[3ex]N=m\\cdot g\\cdot \\text{cos}(\\alpha) \\\\[3ex] N=70 \\cdot 10 \\cdot \\ text{cos}(30\u00ba)\\\\[3ex]N=606,22 \\ N\\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"151\" width=\"194\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Art\u0131k normal kuvvetin de\u011ferini ve dinamik s\u00fcrt\u00fcnme katsay\u0131s\u0131n\u0131 bildi\u011fimize g\u00f6re, s\u00fcrt\u00fcnme kuvvetini ilgili form\u00fcl\u00fc uygulayarak hesaplayabiliriz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e0a32cc7650b33325233258788c218d4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_R=\\mu\\cdot N=0,2 \\cdot 606,22=121,24 \\ N \" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"298\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dolay\u0131s\u0131yla son h\u0131z\u0131 belirlemek i\u00e7in \u00f6ncelikle k\u0131za\u011f\u0131n ivmesini bulmal\u0131y\u0131z ve bu, sunulan ilk kuvvet denkleminden hesaplanabilir: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d87a1ef6aaa3476891df5da8334cbc49_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_1-F_R=m\\cdot a\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"124\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fa13e0490f51e32ac03b455043f6f32d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a=\\cfrac{P_1-F_R}{m}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"99\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-a6274d836af5618f7ef99e7f179c3902_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a=\\cfrac{m\\cdot g\\cdot \\text{sin}(\\alpha)-F_R}{m}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"177\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-a3a9db70462cd187d50b851ede83983f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a=\\cfrac{70\\cdot 10\\cdot \\text{sin}(30\u00ba)-121.24}{70}\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"221\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-ba0d7325efa059351cc3d9aef838a9e2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a=3,27 \\ \\cfrac{m}{s^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"34\" width=\"92\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> K\u0131za\u011f\u0131n ivmesini bildi\u011fimizde, sabit ivmede do\u011frusal hareket denklemi ile 20 metrelik yolu kat etmek i\u00e7in gereken s\u00fcreyi hesaplar\u0131z: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-69f632cd171007df0f5bd6f0fa458a5c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x=v_0\\cdot t +\\cfrac{1}{2}\\cdot a \\cdot t^2\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"150\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-b97ac72bf22d70273fece0cce195f4ca_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"20=2\\cdot t +\\cfrac{1}{2}\\cdot 3.27 \\cdot t^2\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"172\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-11a99cb686bf68cbcca594d0d60f801b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"0=1,64t^2+2t-20\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"158\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7aa7e01e70b4199d597d05e261c970df_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle t=\\cfrac{-2\\pm \\sqrt{2^2-4\\cdot 1.64\\cdot (-20)}}{2\\cdot 1.64}=\\cfrac{-2\\ pm 11.63}{ 3.28}=\\begin{cases}2.94\\\\[2ex]-4.15 \\ \\color{red}\\bm{\\times}\\end{cases}\" title=\"Rendered by QuickLaTeX.com\" height=\"65\" width=\"507\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Mant\u0131ksal olarak, zaman negatif olamayacak fiziksel bir nicelik oldu\u011fundan negatif \u00e7\u00f6z\u00fcm\u00fc ekarte ederiz.<\/p>\n<p class=\"has-text-align-left\"> Son olarak, sabit ivme form\u00fcl\u00fcn\u00fc kullanarak son h\u0131z\u0131 hesapl\u0131yoruz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-5ace98bfb166f5b813f593760fcfa048_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a=\\cfrac{v_f-v_0}{t_f-t_0}\\quad \\longrightarrow \\quad v_f=a\\cdot (t_f-t_0)+v_0\" title=\"Rendered by QuickLaTeX.com\" height=\"40\" width=\"330\" style=\"vertical-align: -18px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e7b1fffc78a1f3be82ead78bf2635dc0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"v_f=3,27\\cdot (2,94-0)+2=11,61 \\ \\cfrac{m}{s}\" title=\"Rendered by QuickLaTeX.com\" height=\"34\" width=\"288\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Bu makale fizikte s\u00fcrt\u00fcnme kuvvetinin (veya s\u00fcrt\u00fcnme kuvvetinin) ne oldu\u011funu ve nas\u0131l hesapland\u0131\u011f\u0131n\u0131 a\u00e7\u0131klamaktad\u0131r. Bu nedenle s\u00fcrt\u00fcnme kuvvetinin \u00f6zelliklerini, var olan iki s\u00fcrt\u00fcnme kuvveti t\u00fcr\u00fcn\u00fc ve ayr\u0131ca uygulamaya y\u00f6nelik \u00f6zel egzersizleri bulacaks\u0131n\u0131z. S\u00fcrt\u00fcnme kuvveti nedir? S\u00fcrt\u00fcnme kuvveti olarak da adland\u0131r\u0131lan s\u00fcrt\u00fcnme kuvveti , bir cismi ba\u015fka bir cismin y\u00fczeyi boyunca hareket ettirmeye \u00e7al\u0131\u015f\u0131rken ortaya \u00e7\u0131kan &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/\"> <span class=\"screen-reader-text\">S\u00fcrt\u00fcnme kuvveti (veya s\u00fcrt\u00fcnme kuvveti)<\/span> Devam\u0131 &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-251","post","type-post","status-publish","format-standard","hentry","category-dinamik"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.3 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 S\u00fcrt\u00fcnme kuvveti (veya s\u00fcrt\u00fcnme kuvveti)<\/title>\n<meta name=\"description\" content=\"Burada s\u00fcrt\u00fcnme kuvvetinin (veya s\u00fcrt\u00fcnme kuvvetinin) ne oldu\u011funu, nas\u0131l hesapland\u0131\u011f\u0131n\u0131 (form\u00fcl) \u00f6\u011frenecek ve s\u00fcrt\u00fcnme kuvveti ile ilgili al\u0131\u015ft\u0131rmalar\u0131 \u00e7\u00f6zeceksiniz.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/\" \/>\n<meta property=\"og:locale\" content=\"tr_TR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u25b7 S\u00fcrt\u00fcnme kuvveti (veya s\u00fcrt\u00fcnme kuvveti)\" \/>\n<meta property=\"og:description\" content=\"Burada s\u00fcrt\u00fcnme kuvvetinin (veya s\u00fcrt\u00fcnme kuvvetinin) ne oldu\u011funu, nas\u0131l hesapland\u0131\u011f\u0131n\u0131 (form\u00fcl) \u00f6\u011frenecek ve s\u00fcrt\u00fcnme kuvveti ile ilgili al\u0131\u015ft\u0131rmalar\u0131 \u00e7\u00f6zeceksiniz.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/\" \/>\n<meta property=\"article:published_time\" content=\"2023-06-23T07:32:36+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-de-friction-ou-force-de-friction.png\" \/>\n<meta name=\"author\" content=\"Jonathan Reynolds\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Yazan:\" \/>\n\t<meta name=\"twitter:data1\" content=\"Jonathan Reynolds\" \/>\n\t<meta name=\"twitter:label2\" content=\"Tahmini okuma s\u00fcresi\" \/>\n\t<meta name=\"twitter:data2\" content=\"6 dakika\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/\"},\"author\":{\"name\":\"Jonathan Reynolds\",\"@id\":\"https:\/\/physigeek.com\/tr\/#\/schema\/person\/b49369b8bed2d27dbd13757330e431a5\"},\"headline\":\"S\u00fcrt\u00fcnme kuvveti (veya s\u00fcrt\u00fcnme kuvveti)\",\"datePublished\":\"2023-06-23T07:32:36+00:00\",\"dateModified\":\"2023-06-23T07:32:36+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/\"},\"wordCount\":1268,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\/\/physigeek.com\/tr\/#organization\"},\"articleSection\":[\"Dinamik\"],\"inLanguage\":\"tr\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/#respond\"]}]},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/\",\"url\":\"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/\",\"name\":\"\u25b7 S\u00fcrt\u00fcnme kuvveti (veya s\u00fcrt\u00fcnme kuvveti)\",\"isPartOf\":{\"@id\":\"https:\/\/physigeek.com\/tr\/#website\"},\"datePublished\":\"2023-06-23T07:32:36+00:00\",\"dateModified\":\"2023-06-23T07:32:36+00:00\",\"description\":\"Burada s\u00fcrt\u00fcnme kuvvetinin (veya s\u00fcrt\u00fcnme kuvvetinin) ne oldu\u011funu, nas\u0131l hesapland\u0131\u011f\u0131n\u0131 (form\u00fcl) \u00f6\u011frenecek ve s\u00fcrt\u00fcnme kuvveti ile ilgili al\u0131\u015ft\u0131rmalar\u0131 \u00e7\u00f6zeceksiniz.\",\"breadcrumb\":{\"@id\":\"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/#breadcrumb\"},\"inLanguage\":\"tr\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Ev\",\"item\":\"https:\/\/physigeek.com\/tr\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"S\u00fcrt\u00fcnme kuvveti (veya s\u00fcrt\u00fcnme kuvveti)\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/physigeek.com\/tr\/#website\",\"url\":\"https:\/\/physigeek.com\/tr\/\",\"name\":\"Physigeek\",\"description\":\"Fizi\u011fi kolay yoldan \u00f6\u011frenin!\",\"publisher\":{\"@id\":\"https:\/\/physigeek.com\/tr\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/physigeek.com\/tr\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"tr\"},{\"@type\":\"Organization\",\"@id\":\"https:\/\/physigeek.com\/tr\/#organization\",\"name\":\"Physigeek\",\"url\":\"https:\/\/physigeek.com\/tr\/\",\"logo\":{\"@type\":\"ImageObject\",\"inLanguage\":\"tr\",\"@id\":\"https:\/\/physigeek.com\/tr\/#\/schema\/logo\/image\/\",\"url\":\"https:\/\/physigeek.com\/tr\/wp-content\/uploads\/2023\/10\/physigeek-logos.png\",\"contentUrl\":\"https:\/\/physigeek.com\/tr\/wp-content\/uploads\/2023\/10\/physigeek-logos.png\",\"width\":180,\"height\":42,\"caption\":\"Physigeek\"},\"image\":{\"@id\":\"https:\/\/physigeek.com\/tr\/#\/schema\/logo\/image\/\"}},{\"@type\":\"Person\",\"@id\":\"https:\/\/physigeek.com\/tr\/#\/schema\/person\/b49369b8bed2d27dbd13757330e431a5\",\"name\":\"Jonathan Reynolds\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"tr\",\"@id\":\"https:\/\/physigeek.com\/tr\/#\/schema\/person\/image\/\",\"url\":\"http:\/\/physigeek.com\/tr\/wp-content\/uploads\/2023\/10\/Jonathan-Reynolds-96x96.jpg\",\"contentUrl\":\"http:\/\/physigeek.com\/tr\/wp-content\/uploads\/2023\/10\/Jonathan-Reynolds-96x96.jpg\",\"caption\":\"Jonathan Reynolds\"},\"sameAs\":[\"http:\/\/physigeek.com\/tr\"]}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"\u25b7 S\u00fcrt\u00fcnme kuvveti (veya s\u00fcrt\u00fcnme kuvveti)","description":"Burada s\u00fcrt\u00fcnme kuvvetinin (veya s\u00fcrt\u00fcnme kuvvetinin) ne oldu\u011funu, nas\u0131l hesapland\u0131\u011f\u0131n\u0131 (form\u00fcl) \u00f6\u011frenecek ve s\u00fcrt\u00fcnme kuvveti ile ilgili al\u0131\u015ft\u0131rmalar\u0131 \u00e7\u00f6zeceksiniz.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/","og_locale":"tr_TR","og_type":"article","og_title":"\u25b7 S\u00fcrt\u00fcnme kuvveti (veya s\u00fcrt\u00fcnme kuvveti)","og_description":"Burada s\u00fcrt\u00fcnme kuvvetinin (veya s\u00fcrt\u00fcnme kuvvetinin) ne oldu\u011funu, nas\u0131l hesapland\u0131\u011f\u0131n\u0131 (form\u00fcl) \u00f6\u011frenecek ve s\u00fcrt\u00fcnme kuvveti ile ilgili al\u0131\u015ft\u0131rmalar\u0131 \u00e7\u00f6zeceksiniz.","og_url":"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/","article_published_time":"2023-06-23T07:32:36+00:00","og_image":[{"url":"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-de-friction-ou-force-de-friction.png"}],"author":"Jonathan Reynolds","twitter_card":"summary_large_image","twitter_misc":{"Yazan:":"Jonathan Reynolds","Tahmini okuma s\u00fcresi":"6 dakika"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/#article","isPartOf":{"@id":"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/"},"author":{"name":"Jonathan Reynolds","@id":"https:\/\/physigeek.com\/tr\/#\/schema\/person\/b49369b8bed2d27dbd13757330e431a5"},"headline":"S\u00fcrt\u00fcnme kuvveti (veya s\u00fcrt\u00fcnme kuvveti)","datePublished":"2023-06-23T07:32:36+00:00","dateModified":"2023-06-23T07:32:36+00:00","mainEntityOfPage":{"@id":"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/"},"wordCount":1268,"commentCount":0,"publisher":{"@id":"https:\/\/physigeek.com\/tr\/#organization"},"articleSection":["Dinamik"],"inLanguage":"tr","potentialAction":[{"@type":"CommentAction","name":"Comment","target":["https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/#respond"]}]},{"@type":"WebPage","@id":"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/","url":"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/","name":"\u25b7 S\u00fcrt\u00fcnme kuvveti (veya s\u00fcrt\u00fcnme kuvveti)","isPartOf":{"@id":"https:\/\/physigeek.com\/tr\/#website"},"datePublished":"2023-06-23T07:32:36+00:00","dateModified":"2023-06-23T07:32:36+00:00","description":"Burada s\u00fcrt\u00fcnme kuvvetinin (veya s\u00fcrt\u00fcnme kuvvetinin) ne oldu\u011funu, nas\u0131l hesapland\u0131\u011f\u0131n\u0131 (form\u00fcl) \u00f6\u011frenecek ve s\u00fcrt\u00fcnme kuvveti ile ilgili al\u0131\u015ft\u0131rmalar\u0131 \u00e7\u00f6zeceksiniz.","breadcrumb":{"@id":"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/#breadcrumb"},"inLanguage":"tr","potentialAction":[{"@type":"ReadAction","target":["https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/physigeek.com\/tr\/surtunme-kuvveti-veya-surtunme-kuvveti\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Ev","item":"https:\/\/physigeek.com\/tr\/"},{"@type":"ListItem","position":2,"name":"S\u00fcrt\u00fcnme kuvveti (veya s\u00fcrt\u00fcnme kuvveti)"}]},{"@type":"WebSite","@id":"https:\/\/physigeek.com\/tr\/#website","url":"https:\/\/physigeek.com\/tr\/","name":"Physigeek","description":"Fizi\u011fi kolay yoldan \u00f6\u011frenin!","publisher":{"@id":"https:\/\/physigeek.com\/tr\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/physigeek.com\/tr\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"tr"},{"@type":"Organization","@id":"https:\/\/physigeek.com\/tr\/#organization","name":"Physigeek","url":"https:\/\/physigeek.com\/tr\/","logo":{"@type":"ImageObject","inLanguage":"tr","@id":"https:\/\/physigeek.com\/tr\/#\/schema\/logo\/image\/","url":"https:\/\/physigeek.com\/tr\/wp-content\/uploads\/2023\/10\/physigeek-logos.png","contentUrl":"https:\/\/physigeek.com\/tr\/wp-content\/uploads\/2023\/10\/physigeek-logos.png","width":180,"height":42,"caption":"Physigeek"},"image":{"@id":"https:\/\/physigeek.com\/tr\/#\/schema\/logo\/image\/"}},{"@type":"Person","@id":"https:\/\/physigeek.com\/tr\/#\/schema\/person\/b49369b8bed2d27dbd13757330e431a5","name":"Jonathan Reynolds","image":{"@type":"ImageObject","inLanguage":"tr","@id":"https:\/\/physigeek.com\/tr\/#\/schema\/person\/image\/","url":"http:\/\/physigeek.com\/tr\/wp-content\/uploads\/2023\/10\/Jonathan-Reynolds-96x96.jpg","contentUrl":"http:\/\/physigeek.com\/tr\/wp-content\/uploads\/2023\/10\/Jonathan-Reynolds-96x96.jpg","caption":"Jonathan Reynolds"},"sameAs":["http:\/\/physigeek.com\/tr"]}]}},"yoast_meta":{"yoast_wpseo_title":"","yoast_wpseo_metadesc":"","yoast_wpseo_canonical":""},"_links":{"self":[{"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/posts\/251","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/comments?post=251"}],"version-history":[{"count":0,"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/posts\/251\/revisions"}],"wp:attachment":[{"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/media?parent=251"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/categories?post=251"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/physigeek.com\/tr\/wp-json\/wp\/v2\/tags?post=251"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}