{"id":246,"date":"2023-06-23T10:01:11","date_gmt":"2023-06-23T10:01:11","guid":{"rendered":"https:\/\/physigeek.com\/tr\/itme-kuvveti\/"},"modified":"2023-06-23T10:01:11","modified_gmt":"2023-06-23T10:01:11","slug":"itme-kuvveti","status":"publish","type":"post","link":"https:\/\/physigeek.com\/tr\/itme-kuvveti\/","title":{"rendered":"I\u0307ti\u015f kuvveti"},"content":{"rendered":"<p>Bu makalede itme kuvvetinin ne oldu\u011fu a\u00e7\u0131klanmaktad\u0131r. Bu nedenle, bu t\u00fcr kuvvetlerin kararl\u0131 bir uygulamas\u0131 olan kald\u0131rma kuvvetinin nas\u0131l hesaplanaca\u011f\u0131n\u0131 ve bunun ak\u0131\u015fkanlar mekani\u011finin \u00f6nemli bir kavram\u0131 olan kald\u0131rma kuvveti ile ili\u015fkisini ke\u015ffedeceksiniz.<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-la-fuerza-de-empuje\"><\/span> \u0130tme kuvveti nedir?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Kald\u0131rma kuvveti,<\/strong> bir cisim i\u00e7ine dald\u0131r\u0131ld\u0131\u011f\u0131nda bir s\u0131v\u0131n\u0131n uygulad\u0131\u011f\u0131 yukar\u0131ya do\u011fru dikey bir kuvvettir. Daha kesin olarak, kald\u0131rma kuvveti, batan cisim taraf\u0131ndan yer de\u011fi\u015ftiren hacmin a\u011f\u0131rl\u0131\u011f\u0131na e\u015fittir.<\/p>\n<p> Bu nedenle itme kuvveti Ar\u015fimed ilkesine dayanmaktad\u0131r. Bu nedenle kald\u0131rma kuvvetine bazen kald\u0131rma kuvveti veya Ar\u015fimet kald\u0131rma kuvveti de denir.<\/p>\n<p> \u0130tme kuvveti, bir s\u0131v\u0131n\u0131n suya batm\u0131\u015f herhangi bir cismin y\u00fczeylerine uygulad\u0131\u011f\u0131 bas\u0131n\u00e7la \u00fcretilir. Bas\u0131n\u00e7 derinlikle do\u011fru orant\u0131l\u0131 oldu\u011fundan, cismin derin k\u0131sm\u0131 \u00fcst k\u0131sm\u0131na g\u00f6re daha fazla bas\u0131n\u00e7 al\u0131r ve dolay\u0131s\u0131yla ak\u0131\u015fkan cisme yukar\u0131 do\u011fru bir kuvvet uygular. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Formula-de-la-fuerza-de-empuje\"><\/span> \u0130tme kuvveti form\u00fcl\u00fc<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> \u0130tme kuvveti, s\u0131v\u0131ya (k\u0131smen veya tamamen) dald\u0131r\u0131lan cisim taraf\u0131ndan yer de\u011fi\u015ftiren s\u0131v\u0131 hacminin a\u011f\u0131rl\u0131\u011f\u0131na e\u015fittir. Bu nedenle itme kuvveti, s\u0131v\u0131 yo\u011funlu\u011funun yer\u00e7ekimi ile yer de\u011fi\u015ftiren s\u0131v\u0131 hacmiyle \u00e7arp\u0131lmas\u0131yla hesaplan\u0131r.<\/p>\n<p> Yani <strong>itme kuvvetinin form\u00fcl\u00fc<\/strong> \u015fu \u015fekildedir:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d74e9528f5afcbcfab4ad839d3d20607_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E=\\rho_f \\cdot g\\cdot V\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"104\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p style=\"margin-bottom:5px\"> Alt\u0131n: <\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-638a7387bd72763290cc777a9b509c38_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"14\" style=\"vertical-align: 0px;\"><\/p>\n<p> Newton cinsinden ifade edilen itme kuvvetidir. <\/span><\/li>\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6da7d3aab222e3315c9879e9a2e42bdd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\rho_f\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"17\" style=\"vertical-align: -6px;\"><\/p>\n<p> kg\/ <sup>m3<\/sup> cinsinden ifade edilen s\u0131v\u0131n\u0131n yo\u011funlu\u011fudur. <\/span><\/li>\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e88010d25c51c0c42c505ee1004ed182_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"g\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"9\" style=\"vertical-align: -4px;\"><\/p>\n<p> yer \u00e7ekimi ivmesinin de\u011feridir.<\/span><\/li>\n<li><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-54e215a7a583b4f357a5a627420bcf2f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"V\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"14\" style=\"vertical-align: 0px;\"><\/p>\n<p> bat\u0131k cisim taraf\u0131ndan yer de\u011fi\u015ftiren hacimdir.<\/span><\/li>\n<\/ul>\n<p> Dikkat ederseniz s\u0131v\u0131n\u0131n yo\u011funlu\u011fu ile yer \u00e7ekiminin \u00e7arp\u0131m\u0131 s\u0131v\u0131n\u0131n \u00f6zg\u00fcl a\u011f\u0131rl\u0131\u011f\u0131na e\u015fittir. B\u00f6ylece itme kuvveti a\u015fa\u011f\u0131daki ifadeyle de belirlenebilir:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-a87e1a57e5f55acdbdf8b216be6cbff8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E=P_e\\cdot V\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"83\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p> Normal ko\u015fullar alt\u0131nda itme kuvveti yukar\u0131ya do\u011fru dikeydir ve uygulama noktas\u0131 bat\u0131k cismin a\u011f\u0131rl\u0131k merkezidir. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejemplo-del-calculo-de-la-fuerza-de-empuje\"><\/span> \u0130tme kuvvetinin hesaplanmas\u0131na \u00f6rnek<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> \u0130tki kuvvetinin tan\u0131m\u0131n\u0131 ve form\u00fcl\u00fcn\u00fc g\u00f6rd\u00fckten sonra bu b\u00f6l\u00fcmde bu t\u00fcr kuvvetin nas\u0131l hesapland\u0131\u011f\u0131na dair bir \u00f6rnek g\u00f6sterilmektedir.<\/p>\n<ul>\n<li> Kenar uzunlu\u011fu 50 cm olan bir k\u00fcp i\u00e7i su (\u03c1=1000 kg\/m <sup>3<\/sup> ) dolu bir kaba at\u0131l\u0131yor. K\u00fcp kab\u0131n i\u00e7ine tamamen bat\u0131r\u0131lm\u0131\u015fsa, s\u0131v\u0131n\u0131n k\u00fcp \u00fczerine uygulad\u0131\u011f\u0131 Ar\u015fimet itme kuvvetinin de\u011feri nedir? Veri: g=9,81 m\/ <sup>s2<\/sup> .<\/li>\n<\/ul>\n<p> K\u00fcp\u00fcn t\u00fcm g\u00f6vdesi suya bat\u0131r\u0131l\u0131rsa, bu, yer de\u011fi\u015ftiren s\u0131v\u0131n\u0131n hacminin k\u00fcp\u00fcn hacmine e\u015fit olaca\u011f\u0131 anlam\u0131na gelir. Bu nedenle \u00f6nce k\u00fcp\u00fcn hacmini hesapl\u0131yoruz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c9925f0bb2d8ab9801ca09f91391ef8b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"V=0,5\\cdot 0,5\\cdot 0,5 = 0,125 \\ m^3\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"236\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p> Bu y\u00fczden de\u011ferini bulmak i\u00e7in itme kuvveti form\u00fcl\u00fcn\u00fc kullan\u0131r\u0131z:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d74e9528f5afcbcfab4ad839d3d20607_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E=\\rho_f \\cdot g\\cdot V\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"104\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p> Son olarak verileri form\u00fclde yerine koyuyoruz ve itme kuvvetini hesapl\u0131yoruz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fd52db67a009ea87141e6dbc02f71479_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E=1000 \\cdot 9,81\\cdot 0,125=1226,25 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"283\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"La-fuerza-de-empuje-y-la-flotabilidad\"><\/span> kald\u0131rma kuvveti ve itme kuvveti<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Bu son b\u00f6l\u00fcmde, fizikte birbiriyle yak\u0131ndan ili\u015fkili iki kavram oldu\u011fundan, itme kuvveti ile kald\u0131rma kuvveti aras\u0131ndaki ili\u015fkiyi g\u00f6rece\u011fiz.<\/p>\n<p> <strong>Y\u00fczd\u00fcrme<\/strong> , bir cismin s\u0131v\u0131 i\u00e7erisinde dengede kalma yetene\u011fidir. Yani bir cismin s\u0131v\u0131 i\u00e7inde y\u00fczebilmesi i\u00e7in s\u0131v\u0131n\u0131n cisme uygulad\u0131\u011f\u0131 kald\u0131rma kuvvetinin cismin a\u011f\u0131rl\u0131\u011f\u0131na e\u015fit olmas\u0131 gerekir. Aksi takdirde v\u00fccut duruma g\u00f6re y\u00fckselecek veya al\u00e7alacakt\u0131r.<\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Pozitif kald\u0131rma kuvveti<\/strong> : V\u00fccut s\u0131v\u0131 i\u00e7inde y\u00fckselme e\u011filimindedir, dolay\u0131s\u0131yla kald\u0131rma kuvveti v\u00fccut a\u011f\u0131rl\u0131\u011f\u0131n\u0131n kuvvetinden daha b\u00fcy\u00fckt\u00fcr.<\/span><\/li>\n<p style=\"text-align:center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0a6ca0343de89b85f96b0362baf565f3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E>P&#8221; title=&#8221;Rendered by QuickLaTeX.com&#8221; height=&#8221;14&#8243; width=&#8221;52&#8243; style=&#8221;vertical-align: -2px;&#8221;><\/p>\n<\/p>\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Negatif kald\u0131rma kuvveti<\/strong> : V\u00fccut s\u0131v\u0131 i\u00e7inde al\u00e7alma e\u011filimi g\u00f6sterir, yani v\u00fccut batar. Bu, itme kuvvetinin a\u011f\u0131rl\u0131k kuvvetinden daha az oldu\u011fu anlam\u0131na gelir.<\/span> <\/li>\n<p style=\"text-align:center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-dd6bd6ffb5d967766330c165fc4cabe3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" E\n\n<li style=&quot;margin-bottom:15px&quot;> <span style=&quot;color:#101010;font-weight: normal;&quot;><strong>Flottabilit\u00e9 neutre<\/strong> : le corps est en \u00e9quilibre au sein du fluide, ou autrement dit, le corps reste suspendu au sein du fluide. Dans ce cas, la force de pouss\u00e9e appliqu\u00e9e par le fluide sur le corps est \u00e9quivalente \u00e0 son poids.<\/span><\/li>\n<p> [latex]E=P&#8221; title=&#8221;Rendered by QuickLaTeX.com&#8221; height=&#8221;106&#8243; width=&#8221;1417&#8243; style=&#8221;vertical-align: -5px;&#8221;><\/p>\n<\/p>\n<\/ul>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/types-de-flottabilite.png\" alt=\"itme kuvveti ve kald\u0131rma kuvveti\" class=\"wp-image-1062\" width=\"389\" height=\"289\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/types-de-flottabilite-300x224.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/types-de-flottabilite-768x573.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/types-de-flottabilite.png 879w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Bu makalede itme kuvvetinin ne oldu\u011fu a\u00e7\u0131klanmaktad\u0131r. Bu nedenle, bu t\u00fcr kuvvetlerin kararl\u0131 bir uygulamas\u0131 olan kald\u0131rma kuvvetinin nas\u0131l hesaplanaca\u011f\u0131n\u0131 ve bunun ak\u0131\u015fkanlar mekani\u011finin \u00f6nemli bir kavram\u0131 olan kald\u0131rma kuvveti ile ili\u015fkisini ke\u015ffedeceksiniz. \u0130tme kuvveti nedir? Kald\u0131rma kuvveti, bir cisim i\u00e7ine dald\u0131r\u0131ld\u0131\u011f\u0131nda bir s\u0131v\u0131n\u0131n uygulad\u0131\u011f\u0131 yukar\u0131ya do\u011fru dikey bir kuvvettir. Daha kesin olarak, kald\u0131rma kuvveti, &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/tr\/itme-kuvveti\/\"> <span class=\"screen-reader-text\">I\u0307ti\u015f kuvveti<\/span> Devam\u0131 &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[12],"tags":[],"class_list":["post-246","post","type-post","status-publish","format-standard","hentry","category-akiskanlar-mekanigi"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.3 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 \u0130tme kuvveti nedir? 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