{"id":245,"date":"2023-06-23T10:06:26","date_gmt":"2023-06-23T10:06:26","guid":{"rendered":"https:\/\/physigeek.com\/tr\/elastik-kuvvet-veya-geri-getirme-kuvveti\/"},"modified":"2023-06-23T10:06:26","modified_gmt":"2023-06-23T10:06:26","slug":"elastik-kuvvet-veya-geri-getirme-kuvveti","status":"publish","type":"post","link":"https:\/\/physigeek.com\/tr\/elastik-kuvvet-veya-geri-getirme-kuvveti\/","title":{"rendered":"Elastik kuvvet (veya geri getirme kuvveti)"},"content":{"rendered":"<p>Bu makale elastik kuvvetin (veya onar\u0131c\u0131 kuvvetin) ne oldu\u011funu a\u00e7\u0131klamaktad\u0131r. B\u00f6ylece elastik kuvvetin nas\u0131l hesaplanaca\u011f\u0131n\u0131, \u00f6zelliklerini ve \u00e7\u00f6z\u00fclm\u00fc\u015f elastik kuvvet egzersizlerini ke\u015ffedeceksiniz. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-la-fuerza-elastica\"><\/span> Elastik kuvvet nedir?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Geri y\u00fckleme kuvveti<\/strong> olarak da adland\u0131r\u0131lan <strong>elastik kuvvet<\/strong> , elastik bir malzeme deforme oldu\u011funda uygulad\u0131\u011f\u0131 kuvvettir. Daha do\u011frusu elastik kuvvet, elastik cismi deforme eden kuvvetle ayn\u0131 b\u00fcy\u00fckl\u00fck ve y\u00f6ne sahiptir ancak y\u00f6n\u00fc z\u0131tt\u0131r.<\/p>\n<p> Ayr\u0131ca elastik g\u00f6vde ne kadar \u00e7ok deformasyona u\u011frarsa, yani elastik g\u00f6vde ne kadar \u00e7ok uzat\u0131l\u0131r veya s\u0131k\u0131\u015ft\u0131r\u0131l\u0131rsa, elastik kuvvetin mod\u00fcl\u00fc de o kadar b\u00fcy\u00fck olur. <\/p>\n<figure class=\"wp-block-image aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elastique.png\" alt=\"elastik kuvvet\" class=\"wp-image-4161\" width=\"640\" height=\"318\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elastique-300x150.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elastique-1024x511.png 1024w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elastique-768x383.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elastique-1536x767.png 1536w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elastique.png 1585w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<p> B\u00f6ylece bir yay her zaman kendisine uygulanan d\u0131\u015f kuvvetin tersi y\u00f6nde elastik kuvvet uygular.<\/p>\n<p> Fizikte yaylarla ilgili problemler genellikle elastik kuvvet kavram\u0131n\u0131 anlamak i\u00e7in ele al\u0131n\u0131r. Daha sonra elastik kuvvetin nas\u0131l hesapland\u0131\u011f\u0131n\u0131 ve bu gibi problemlerin nas\u0131l \u00e7\u00f6z\u00fclece\u011fini g\u00f6rece\u011fiz. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Formula-de-la-fuerza-elastica\"><\/span>Elastik kuvvet form\u00fcl\u00fc<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Bir yay\u0131n uygulad\u0131\u011f\u0131 elastik kuvvet eksi yay\u0131n elastik sabitinin yer de\u011fi\u015ftirmesiyle \u00e7arp\u0131m\u0131na e\u015fittir.<\/p>\n<p> Bu nedenle <strong>elastik kuvvetin form\u00fcl\u00fc<\/strong> a\u015fa\u011f\u0131daki gibidir:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-b886155aaf78dae4ad0a70c38f91d77f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_e=-k\\cdot \\Delta x\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"104\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p style=\"margin-bottom:5px\"> Alt\u0131n: <\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-88df03c55e081c7cd9da4e7d74ba7265_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"14\" style=\"vertical-align: 0px;\"><\/p>\n<p> Newton cinsinden ifade edilen elastik kuvvettir. <\/span><\/li>\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d42bc2203d6f76ad01b27ac9acc0bee1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"k\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"9\" style=\"vertical-align: 0px;\"><\/p>\n<p> birimi N\/m olan yay\u0131n elastik sabitidir.<\/span><\/li>\n<li><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e936d3a449e3ecae93ebb5ae1e61feac_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\Delta x\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"25\" style=\"vertical-align: 0px;\"><\/p>\n<p> metre cinsinden ifade edilen, harici bir kuvvet uyguland\u0131\u011f\u0131nda yay\u0131n ya\u015fad\u0131\u011f\u0131 uzamad\u0131r.<\/span><\/li>\n<\/ul>\n<p> <strong>Not<\/strong> : Negatif i\u015faret, elastik kuvvetin y\u00f6n\u00fcn\u00fcn, yaya uygulanan d\u0131\u015f kuvvetin tersi oldu\u011funu belirtmek i\u00e7indir. \u00d6nemli olan elastik kuvvet mod\u00fcl\u00fcn\u00fcn elastik sabitin yer de\u011fi\u015ftirme ile \u00e7arp\u0131m\u0131na e\u015fit olmas\u0131d\u0131r.<\/p>\n<p> Bu nedenle elastik kuvvet form\u00fcl\u00fc <a href=\"https:\/\/physigeek.com\/tr\/hooke-yasasi\/\">Hooke&#8217;un esneklik yasas\u0131yla<\/a> tan\u0131mlan\u0131r.<\/p>\n<p> \u00d6te yandan yay gerildi\u011finde veya s\u0131k\u0131\u015ft\u0131r\u0131ld\u0131\u011f\u0131nda potansiyel enerji depolan\u0131r. Dolay\u0131s\u0131yla elastik potansiyel enerjinin hesaplanmas\u0131na y\u00f6nelik form\u00fcl a\u015fa\u011f\u0131daki gibidir: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-3bd6ff61b959af0bf6c8061037ba754e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_p=\\cfrac{1}{2}\\cdot k \\cdot \\Delta x^2\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"123\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejemplo-de-la-fuerza-elastica\"><\/span>Elastik kuvvet \u00f6rne\u011fi<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Elastik kuvvetin tan\u0131m\u0131n\u0131 g\u00f6rd\u00fckten sonra bu t\u00fcr kuvvetin nas\u0131l hesapland\u0131\u011f\u0131na dair \u00e7\u00f6z\u00fcml\u00fc bir \u00f6rnek g\u00f6rece\u011fiz.<\/p>\n<ul>\n<li> Elastikiyet sabiti 170 N\/m olan bir yay 45 cm uzat\u0131l\u0131yor. Yay\u0131n uygulayaca\u011f\u0131 elastik kuvvet nedir?<\/li>\n<\/ul>\n<p> Elastik kuvveti belirlemek i\u00e7in yukar\u0131da g\u00f6rd\u00fc\u011f\u00fcm\u00fcz form\u00fcl\u00fc kullanmal\u0131y\u0131z:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-b886155aaf78dae4ad0a70c38f91d77f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_e=-k\\cdot \\Delta x\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"104\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p> Ancak form\u00fcl\u00fc kullanmadan \u00f6nce uzakl\u0131\u011f\u0131n uzunlu\u011funu metreye d\u00f6n\u00fc\u015ft\u00fcrmeniz gerekir:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-311621c96c01a4535b15801b7164ee17_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"45 \\ cm \\div 100 =0,45 \\ m\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"174\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p> Son olarak elastik sabiti ve yay yer de\u011fi\u015ftirme verilerini form\u00fclde yerine koyar\u0131z ve elastik kuvveti hesaplar\u0131z: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-f6aa371674edfdd6c42d7e3bcb64383e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_e=-170\\cdot 0,45=-76,5 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"224\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicios-resueltos-de-la-fuerza-elastica\"><\/span> Elastik kuvvetle ilgili \u00e7\u00f6z\u00fclm\u00fc\u015f al\u0131\u015ft\u0131rmalar<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> 1. Egzersiz<\/h3>\n<p> K\u00fctlesi 8 kg olan bir cisim dikey bir yay \u00fczerinde as\u0131l\u0131 duruyor. Elastik sabiti 350 N\/m ise yay ne kadar uzar? (g=10 m\/ <sup>s2<\/sup> ) <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-de-la-loi-de-hooke.png\" alt=\"Hooke yasas\u0131n\u0131n \u00e7\u00f6z\u00fclm\u00fc\u015f \u00f6rne\u011fi\" class=\"wp-image-4066\" width=\"118\" height=\"229\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-de-la-loi-de-hooke-154x300.png 154w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-de-la-loi-de-hooke.png 283w\" sizes=\"auto, (max-width: 154px) 100vw, 154px\"><\/figure>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>\u00c7\u00f6z\u00fcm\u00fc g\u00f6r\u00fcn<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> \u00d6ncelikle k\u00fctlenin yaya uygulad\u0131\u011f\u0131 a\u011f\u0131rl\u0131\u011f\u0131n kuvvetini hesaplamam\u0131z gerekir. Bunu yapmak i\u00e7in k\u00fctleyi yer\u00e7ekimiyle \u00e7arpman\u0131z yeterlidir:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-21b4daa2a5826fe5c1bffc3d93cb084a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=m\\cdot g = 8\\cdot 10=80 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"201\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Yaya uygulanan kuvveti bildi\u011fimizde elastik kuvvet form\u00fcl\u00fcn\u00fc kullanabiliriz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d289d95f4fbd3eaaa673f0217091347c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_e=k\\cdot \\Delta x\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"90\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Form\u00fcl\u00fcn uzant\u0131s\u0131n\u0131 \u00e7\u00f6z\u00fcyoruz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-dd49ebc50db3810f4c2d06bf3716663d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\Delta x=\\cfrac{F_e}{k}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"69\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Son olarak de\u011ferleri form\u00fclde yerine koyuyoruz ve yay\u0131n uzamas\u0131n\u0131 hesapl\u0131yoruz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-82d67ff2ea6c812a73f07308c0600014_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\Delta x=\\cfrac{F_e}{k}=\\cfrac{80}{350} =0,23 \\ m = 23 \\ cm\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"271\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Al\u0131\u015ft\u0131rma 2<\/h3>\n<p> Bir yaya 50 N&#8217;luk kuvvet uyguland\u0131\u011f\u0131nda yay 12 cm uzar. Yay 78 N&#8217;luk bir kuvvet uyguland\u0131\u011f\u0131nda ne kadar uzar? <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>\u00c7\u00f6z\u00fcm\u00fc g\u00f6r\u00fcn<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Yay\u0131n uzamas\u0131n\u0131 hesaplamak i\u00e7in \u00f6ncelikle elastik sabitini belirlememiz gerekir. Bu nedenle elastik sabiti elastik kuvvet form\u00fcl\u00fcnden \u00e7\u00f6z\u00fcyoruz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c0583a84bd59386c9674aaa94aa7d6ba_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=k\\cdot \\Delta x \\quad \\longrightarrow \\quad k=\\cfrac{F}{\\Delta x}=\\cfrac{50}{0.12} =416.67 \\ \\cfrac{N} {m}[ \/latex] Maintenant que nous connaissons la valeur de la constante d'\u00e9lasticit\u00e9, nous pouvons calculer l'allongement du ressort en utilisant la loi de Hooke : [latex]F=k\\cdot \\Delta x \\quad \\longrightarrow \\quad \\Delta x=\\cfrac{F}{k}=\\cfrac{78}{416.67} =0,19 \\ m = 19 \\ cm \" title=\"Rendered by QuickLaTeX.com\" height=\"124\" width=\"1208\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Al\u0131\u015ft\u0131rma 3<\/h3>\n<p> Esneklik sabiti 560 N\/m olan yatay konumda bir yay\u0131n yan\u0131na yerle\u015ftirilmi\u015f m=7 kg k\u00fctleli bir topumuz var. Topu itip yay\u0131 8 cm s\u0131k\u0131\u015ft\u0131r\u0131rsak o da topu iterek eski konumuna geri d\u00f6ner. Top yay ile temastan hangi h\u0131zla ayr\u0131lacakt\u0131r? Egzersiz boyunca s\u00fcrt\u00fcnmeyi ihmal edin. <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-loi-du-crochet.png\" alt=\"Hooke yasas\u0131n\u0131n kararl\u0131 bir \u015fekilde uygulanmas\u0131\" class=\"wp-image-4074\" width=\"295\" height=\"328\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-loi-du-crochet-270x300.png 270w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-loi-du-crochet.png 745w\" sizes=\"auto, (max-width: 270px) 100vw, 270px\"><\/figure>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>\u00c7\u00f6z\u00fcm\u00fc g\u00f6r\u00fcn<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> \u00d6ncelikle topu iterek ve yay\u0131 s\u0131k\u0131\u015ft\u0131rarak uygulanan kuvveti hesaplamal\u0131y\u0131z. Bunu yapmak i\u00e7in Hooke kanunundaki form\u00fcl\u00fc uyguluyoruz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-02824e33202a9d71a6964aba33e74849_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=k\\cdot \\Delta x=560 \\cdot 0,08 = 44,8 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"263\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Bu k\u0131sm\u0131 iyi anlamak i\u00e7in elastik kuvvet kavram\u0131 konusunda net olman\u0131z gerekir. Yay \u00fczerine bir kuvvet uyguland\u0131\u011f\u0131nda, yay ayn\u0131 b\u00fcy\u00fckl\u00fck ve y\u00f6nde fakat z\u0131t y\u00f6nde bir tepki kuvveti de \u00fcretir (etki-tepki prensibi). Dolay\u0131s\u0131yla yay\u0131n topa uygulad\u0131\u011f\u0131 kuvvet, yukar\u0131da hesaplanan kuvvetle ayn\u0131 b\u00fcy\u00fckl\u00fcktedir:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6b258ef25c5afc79b6401649152de803_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"|F_{ressort\\\u00e0 balle}|=|F|=44,8 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"219\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Son olarak topun ivmesini belirlemek i\u00e7in Newton&#8217;un ikinci yasas\u0131n\u0131 uygulamal\u0131y\u0131z:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-3121171800c187fa5cf1a980aa5e80cc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{spring\\to ball}=m_{ball}\\cdot a_{ball}\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"193\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dolay\u0131s\u0131yla ivmeyi form\u00fclden \u00e7\u00f6z\u00fcyoruz ve topun ivmesinin de\u011ferini bulmak i\u00e7in verileri de\u011fi\u015ftiriyoruz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-f4dfeca33dce4b76e142d1a6e41f26f3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" a_{ball}=\\cfrac{F_{spring\\to ball}}{m_{ball}}=\\cfrac{44,8}{7}=6,4 \\ \\cfrac{m}{s^2 }\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"279\" style=\"vertical-align: -15px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Bu makale elastik kuvvetin (veya onar\u0131c\u0131 kuvvetin) ne oldu\u011funu a\u00e7\u0131klamaktad\u0131r. B\u00f6ylece elastik kuvvetin nas\u0131l hesaplanaca\u011f\u0131n\u0131, \u00f6zelliklerini ve \u00e7\u00f6z\u00fclm\u00fc\u015f elastik kuvvet egzersizlerini ke\u015ffedeceksiniz. Elastik kuvvet nedir? Geri y\u00fckleme kuvveti olarak da adland\u0131r\u0131lan elastik kuvvet , elastik bir malzeme deforme oldu\u011funda uygulad\u0131\u011f\u0131 kuvvettir. Daha do\u011frusu elastik kuvvet, elastik cismi deforme eden kuvvetle ayn\u0131 b\u00fcy\u00fckl\u00fck ve y\u00f6ne sahiptir &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/tr\/elastik-kuvvet-veya-geri-getirme-kuvveti\/\"> <span class=\"screen-reader-text\">Elastik kuvvet (veya geri getirme kuvveti)<\/span> Devam\u0131 &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-245","post","type-post","status-publish","format-standard","hentry","category-dinamik"],"yoast_head":"<!-- This site is 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