{"id":242,"date":"2023-06-23T11:50:51","date_gmt":"2023-06-23T11:50:51","guid":{"rendered":"https:\/\/physigeek.com\/tr\/hooke-yasasi\/"},"modified":"2023-06-23T11:50:51","modified_gmt":"2023-06-23T11:50:51","slug":"hooke-yasasi","status":"publish","type":"post","link":"https:\/\/physigeek.com\/tr\/hooke-yasasi\/","title":{"rendered":"Hook kanunu"},"content":{"rendered":"<p>Bu yaz\u0131da Hooke yasas\u0131n\u0131n nelerden olu\u015ftu\u011funu, form\u00fcl\u00fcn\u00fcn ne oldu\u011funu ve Hooke yasas\u0131yla ilgili ad\u0131m ad\u0131m \u00e7\u00f6z\u00fclm\u00fc\u015f \u00e7e\u015fitli al\u0131\u015ft\u0131rmalar\u0131 ke\u015ffedeceksiniz. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-la-ley-de-Hooke\"><\/span> Hooke Yasas\u0131 Nedir?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Hooke&#8217;un<\/strong> <strong>esneklik yasas\u0131<\/strong> olarak da adland\u0131r\u0131lan Hooke yasas\u0131, bir yaya uygulanan kuvveti onun uzamas\u0131yla ili\u015fkilendiren fiziksel bir yasad\u0131r. Daha spesifik olarak Hooke yasas\u0131, yay\u0131n uzamas\u0131n\u0131n uygulanan kuvvetin b\u00fcy\u00fckl\u00fc\u011f\u00fcyle do\u011fru orant\u0131l\u0131 oldu\u011funu belirtir.<\/p>\n<p> Hooke kanunu \u0130ngiliz fizik\u00e7i Robert Hooke taraf\u0131ndan ke\u015ffedildi. \u0130lgin\u00e7 bir \u015fekilde, Hooke, bulu\u015funu ilk \u00f6nce ba\u015fkas\u0131n\u0131n yay\u0131nlayaca\u011f\u0131ndan korktu\u011fu i\u00e7in yasay\u0131 ilk olarak 1676&#8217;da anagram olarak yay\u0131nlad\u0131, ard\u0131ndan 1678&#8217;de yasay\u0131 resmi olarak yay\u0131nlad\u0131.<\/p>\n<p> Hooke yasas\u0131n\u0131n m\u00fchendislik, in\u015faat ve malzeme ara\u015ft\u0131rmalar\u0131nda bir\u00e7ok uygulamas\u0131 vard\u0131r, Hooke yasas\u0131 yayg\u0131n olarak kullan\u0131lmaktad\u0131r. \u00d6rne\u011fin dinamometrelerin \u00e7al\u0131\u015fmas\u0131 Hooke kanununa dayanmaktad\u0131r. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Formula-de-la-ley-de-Hooke\"><\/span> Hooke Yasas\u0131 Form\u00fcl\u00fc<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Hooke kanunu, bir yaya uygulanan kuvvet ile uzamas\u0131n\u0131n do\u011fru orant\u0131l\u0131 oldu\u011funu belirtir.<\/p>\n<p> Dolay\u0131s\u0131yla <strong>Hooke yasas\u0131n\u0131n form\u00fcl\u00fc<\/strong> , yaya uygulanan kuvvetin yay\u0131n elastik sabiti ile uzamas\u0131n\u0131n \u00e7arp\u0131m\u0131na e\u015fit oldu\u011funu belirtir.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7059f0a7fb501304d4de6360520575d6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=k\\cdot\\Delta x\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"85\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p style=\"margin-bottom:5px\"> Alt\u0131n: <\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-88df03c55e081c7cd9da4e7d74ba7265_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"14\" style=\"vertical-align: 0px;\"><\/p>\n<p> yaya uygulanan kuvvetin Newton cinsinden ifadesidir. <\/span><\/li>\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d42bc2203d6f76ad01b27ac9acc0bee1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"k\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"9\" style=\"vertical-align: 0px;\"><\/p>\n<p> birimi N\/m olan yay\u0131n elastik sabitidir.<\/span><\/li>\n<li><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e936d3a449e3ecae93ebb5ae1e61feac_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\Delta x\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"25\" style=\"vertical-align: 0px;\"><\/p>\n<p> kuvvet uyguland\u0131\u011f\u0131nda yay\u0131n ya\u015fad\u0131\u011f\u0131 uzama metre cinsinden ifade edilir.<\/span><\/li>\n<\/ul>\n<p> Hooke yasas\u0131n\u0131n yaln\u0131zca yay\u0131n elastik b\u00f6lgesinde ge\u00e7erli oldu\u011funu, yani kuvvet durdu\u011funda yay\u0131n orijinal \u015fekline d\u00f6nd\u00fc\u011f\u00fcn\u00fc unutmay\u0131n. <\/p>\n<figure class=\"wp-block-image aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/la-loi-de-hooke.png\" alt=\"Hook kanunu\" class=\"wp-image-4058\" width=\"464\" height=\"474\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/la-loi-de-hooke-293x300.png 293w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/la-loi-de-hooke-1002x1024.png 1002w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/la-loi-de-hooke-768x785.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/la-loi-de-hooke.png 1475w\" sizes=\"auto, (max-width: 293px) 100vw, 293px\"><\/figure>\n<p> Yaya bir d\u0131\u015f kuvvet uyguland\u0131\u011f\u0131nda, yay ayn\u0131 b\u00fcy\u00fckl\u00fck ve y\u00f6nde fakat z\u0131t y\u00f6nde bir tepki kuvveti uygular (etki-tepki prensibi). Bu nedenle yay her zaman denge konumuna d\u00f6nmek i\u00e7in bir kuvvet uygulayacakt\u0131r.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-f90e909ce2ba85406d2bf43cb0922b17_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{spring}=-k\\cdot \\Delta x\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"137\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p> \u00d6te yandan yaya uygulanan kuvvet nedeniyle potansiyel enerji depolan\u0131r. Yani elastik potansiyel enerjiyi hesaplama form\u00fcl\u00fc \u015f\u00f6yledir: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-23275e7a75b34506284c2ecb992e2844_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"U=\\cfrac{1}{2}\\cdot k \\cdot \\Delta x^2\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"115\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejemplo-de-la-ley-de-Hooke\"><\/span> Hooke Yasas\u0131 \u00d6rne\u011fi<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Art\u0131k Hooke yasas\u0131n\u0131n tan\u0131m\u0131n\u0131 bildi\u011fimize g\u00f6re, kavram\u0131 tam olarak anlamak i\u00e7in a\u015fa\u011f\u0131da bu fiziksel yasan\u0131n somut bir \u00f6rne\u011fini verece\u011fiz.<\/p>\n<ul>\n<li> Bir yaya 30 N kuvvet uygulan\u0131yor ve yay 0,15 m uzuyor. Bu yay\u0131n elastik sabiti nedir?<\/li>\n<\/ul>\n<p> Bu durumda bir yay\u0131n uzamas\u0131n\u0131 inceledi\u011fimiz i\u00e7in bu bir Hooke yasas\u0131 problemidir, dolay\u0131s\u0131yla yukar\u0131da g\u00f6r\u00fclen form\u00fcl\u00fc kullanmam\u0131z gerekir:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7059f0a7fb501304d4de6360520575d6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=k\\cdot\\Delta x\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"85\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Art\u0131k yay esnekli\u011fi sabitini form\u00fclden \u00e7\u0131kar\u0131yoruz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e23986b61dc1996f4d3bce1279bd11d7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"k=\\cfrac{F}{\\Delta x}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"60\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Son olarak problem verilerini form\u00fcle yerle\u015ftirip hesaplamay\u0131 ger\u00e7ekle\u015ftiriyoruz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-162a0e44c922480a2815fea3a80e76ba_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"k=\\cfrac{F}{\\Delta x}=\\cfrac{30}{0.15}=200 \\ \\cfrac{N}{m}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"192\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicios-resueltos-de-la-ley-de-Hooke\"><\/span> Hooke yasas\u0131n\u0131n \u00e7\u00f6z\u00fclm\u00fc\u015f sorunlar\u0131<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> 1. Egzersiz<\/h3>\n<p> K\u00fctlesi 8 kg olan bir cisim dikey bir yay \u00fczerinde as\u0131l\u0131 duruyor. Elastikiyet sabiti 350 N\/m ise yay ne kadar uzar? (g=10m\/ <sup>s2<\/sup> ) <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-de-la-loi-de-hooke.png\" alt=\"Hooke yasas\u0131n\u0131n somut \u00f6rne\u011fi\" class=\"wp-image-4066\" width=\"118\" height=\"229\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-de-la-loi-de-hooke-154x300.png 154w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-de-la-loi-de-hooke.png 283w\" sizes=\"auto, (max-width: 154px) 100vw, 154px\"><\/figure>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>\u00e7\u00f6z\u00fcm\u00fc g\u00f6r<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> \u00d6ncelikle k\u00fctlenin yaya uygulad\u0131\u011f\u0131 a\u011f\u0131rl\u0131\u011f\u0131n kuvvetini hesaplamam\u0131z gerekir. Bunu yapmak i\u00e7in k\u00fctleyi yer\u00e7ekimiyle \u00e7arpman\u0131z yeterlidir:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-21b4daa2a5826fe5c1bffc3d93cb084a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=m\\cdot g = 8\\cdot 10=80 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"201\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Yaya uygulanan kuvveti bildi\u011fimizde Hooke yasas\u0131 form\u00fcl\u00fcn\u00fc kullanabiliriz.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7059f0a7fb501304d4de6360520575d6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=k\\cdot\\Delta x\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"85\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Uzant\u0131y\u0131 form\u00fclden siliyoruz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-accbd15bbecc5a9bc18444e2f79bb5bc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\Delta x=\\cfrac{F}{k}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"64\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Son olarak de\u011ferleri form\u00fclde yerine koyuyoruz ve yay\u0131n uzamas\u0131n\u0131 hesapl\u0131yoruz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-60fd28dc6582cf40cce90571aa87a066_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\Delta x=\\cfrac{F}{k}=\\cfrac{80}{350} =0,23 \\ m = 23 \\ cm\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"266\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Al\u0131\u015ft\u0131rma 2<\/h3>\n<p> Bir yaya 50 N&#8217;luk kuvvet uyguland\u0131\u011f\u0131nda yay 12 cm uzar. Yay \u00fczerine 78 N&#8217;luk bir kuvvet uyguland\u0131\u011f\u0131nda yay ne kadar uzar? <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>\u00e7\u00f6z\u00fcm\u00fc g\u00f6r<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Yay\u0131n uzamas\u0131n\u0131 hesaplamak i\u00e7in \u00f6ncelikle elastik sabitini belirlememiz gerekir. Bu nedenle yay sabitini Hooke yasas\u0131ndan ay\u0131r\u0131p de\u011ferini hesapl\u0131yoruz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c0583a84bd59386c9674aaa94aa7d6ba_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=k\\cdot \\Delta x \\quad \\longrightarrow \\quad k=\\cfrac{F}{\\Delta x}=\\cfrac{50}{0.12} =416.67 \\ \\cfrac{N} {m}[ \/latex] Maintenant que nous connaissons la valeur de la constante d'\u00e9lasticit\u00e9, nous pouvons calculer l'allongement du ressort en utilisant la loi de Hooke : [latex]F=k\\cdot \\Delta x \\quad \\longrightarrow \\quad \\Delta x=\\cfrac{F}{k}=\\cfrac{78}{416.67} =0,19 \\ m = 19 \\ cm \" title=\"Rendered by QuickLaTeX.com\" height=\"124\" width=\"1208\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Al\u0131\u015ft\u0131rma 3<\/h3>\n<p> Esneklik sabiti 560 N\/m olan yatay konumda bir yay\u0131n yan\u0131na yerle\u015ftirilmi\u015f m=7 kg k\u00fctleli bir topumuz var. Topu itip yay\u0131 8 cm s\u0131k\u0131\u015ft\u0131r\u0131rsak o da topu iterek eski konumuna geri d\u00f6ner. Top yay ile temastan hangi ivmeyle ayr\u0131lacakt\u0131r? Egzersiz boyunca s\u00fcrt\u00fcnmeyi ihmal edin. <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-loi-du-crochet.png\" alt=\"Hooke yasas\u0131n\u0131n kararl\u0131 bir \u015fekilde uygulanmas\u0131\" class=\"wp-image-4074\" width=\"295\" height=\"328\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-loi-du-crochet-270x300.png 270w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-loi-du-crochet.png 745w\" sizes=\"auto, (max-width: 270px) 100vw, 270px\"><\/figure>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>\u00e7\u00f6z\u00fcm\u00fc g\u00f6r<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> \u0130lk \u00f6nce topu iterek ve yay\u0131 s\u0131k\u0131\u015ft\u0131rarak uygulanan kuvveti hesaplamal\u0131y\u0131z. Bunu yapmak i\u00e7in Hooke kanunundaki form\u00fcl\u00fc uyguluyoruz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-02824e33202a9d71a6964aba33e74849_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=k\\cdot \\Delta x=560 \\cdot 0,08 = 44,8 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"263\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Bu k\u0131sm\u0131 iyi anlamak i\u00e7in Hooke yasas\u0131 kavram\u0131 konusunda net olman\u0131z gerekir. Yay \u00fczerine bir kuvvet uyguland\u0131\u011f\u0131nda, yay ayn\u0131 b\u00fcy\u00fckl\u00fckte ve y\u00f6nde fakat z\u0131t y\u00f6nde bir tepki kuvveti de \u00fcretir. Dolay\u0131s\u0131yla yay\u0131n topa uygulad\u0131\u011f\u0131 kuvvet, yukar\u0131da hesaplanan kuvvetle ayn\u0131 b\u00fcy\u00fckl\u00fcktedir:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6b258ef25c5afc79b6401649152de803_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"|F_{ressort\\\u00e0 balle}|=|F|=44,8 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"219\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Son olarak topun ivmesini belirlemek i\u00e7in Newton&#8217;un ikinci yasas\u0131n\u0131 uygulamal\u0131y\u0131z:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-3121171800c187fa5cf1a980aa5e80cc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{spring\\to ball}=m_{ball}\\cdot a_{ball}\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"193\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dolay\u0131s\u0131yla ivmeyi form\u00fclden \u00e7\u00f6z\u00fcyoruz ve topun ivmesinin de\u011ferini bulmak i\u00e7in verileri de\u011fi\u015ftiriyoruz:<\/p>\n<p class=\"has-text-align-center\"> [latex] a_{top}=\\cfrac{F_{yay\\topa}}{m_{top}}=\\cfrac{44.8}{7}=6.4 \\ \\cfrac{m}{s^2 }[\/latex ]<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Bu yaz\u0131da Hooke yasas\u0131n\u0131n nelerden olu\u015ftu\u011funu, form\u00fcl\u00fcn\u00fcn ne oldu\u011funu ve Hooke yasas\u0131yla ilgili ad\u0131m ad\u0131m \u00e7\u00f6z\u00fclm\u00fc\u015f \u00e7e\u015fitli al\u0131\u015ft\u0131rmalar\u0131 ke\u015ffedeceksiniz. Hooke Yasas\u0131 Nedir? Hooke&#8217;un esneklik yasas\u0131 olarak da adland\u0131r\u0131lan Hooke yasas\u0131, bir yaya uygulanan kuvveti onun uzamas\u0131yla ili\u015fkilendiren fiziksel bir yasad\u0131r. Daha spesifik olarak Hooke yasas\u0131, yay\u0131n uzamas\u0131n\u0131n uygulanan kuvvetin b\u00fcy\u00fckl\u00fc\u011f\u00fcyle do\u011fru orant\u0131l\u0131 oldu\u011funu belirtir. Hooke &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/tr\/hooke-yasasi\/\"> <span class=\"screen-reader-text\">Hook kanunu<\/span> Devam\u0131 &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-242","post","type-post","status-publish","format-standard","hentry","category-dinamik"],"yoast_head":"<!-- This site is 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