{"id":22,"date":"2023-06-27T12:43:20","date_gmt":"2023-06-27T12:43:20","guid":{"rendered":"https:\/\/physigeek.com\/tr\/ikinci-denge-kosulu\/"},"modified":"2023-06-27T12:43:20","modified_gmt":"2023-06-27T12:43:20","slug":"ikinci-denge-kosulu","status":"publish","type":"post","link":"https:\/\/physigeek.com\/tr\/ikinci-denge-kosulu\/","title":{"rendered":"I\u0307kinci denge ko\u015fulu"},"content":{"rendered":"<p>Bu makalede ikinci denge ko\u015fulunun ne oldu\u011fu ve nelerden olu\u015ftu\u011fu a\u00e7\u0131klanmaktad\u0131r. Ayr\u0131ca ikinci denge durumunun ger\u00e7ek \u00f6rneklerini de bulacaks\u0131n\u0131z ve son olarak ad\u0131m ad\u0131m \u00e7\u00f6z\u00fclen egzersizlerle antrenman yapabileceksiniz. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFCual-es-la-segunda-condicion-de-equilibrio\"><\/span> \u0130kinci denge ko\u015fulu nedir?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Fizikte <strong>ikinci denge ko\u015fulu<\/strong> , bir cismin kendisine uygulanan momentlerin toplam\u0131 s\u0131f\u0131ra e\u015fitse d\u00f6nme dengesinde oldu\u011funu s\u00f6yleyen bir kurald\u0131r.<\/p>\n<p> Dolay\u0131s\u0131yla ikinci denge ko\u015fulu, ortaya \u00e7\u0131kan moment s\u0131f\u0131r oldu\u011funda kar\u015f\u0131lan\u0131r. Matematiksel olarak ikinci denge ko\u015fulu a\u015fa\u011f\u0131daki form\u00fclle ifade edilir:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d8a19d84c103481347db47c0b8a6d2a8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\somme \\vv{M}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"52\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Farkl\u0131 eksenlere etki eden momentler toplanamayaca\u011f\u0131ndan momentlerin vekt\u00f6rel olarak eklenmesi gerekti\u011fine dikkat edin. Moment her zaman ayn\u0131 y\u00f6nde gitti\u011fi i\u00e7in e\u015f d\u00fczlemli kuvvetlerle (iki boyutta) \u00e7al\u0131\u015f\u0131ld\u0131\u011f\u0131nda bu durum sorun te\u015fkil etmez, ancak \u00fc\u00e7 boyutta \u00e7al\u0131\u015f\u0131rken bunun fark\u0131nda olunmas\u0131 gerekir.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-ec7e37abbe42c976a3809c9e0f2724f2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\sum\\vv{M_x}=0\\qquad\\sum\\vv{M_y}=0\\qquad\\sum\\vv{M_z}=0\\qquad\" title=\"Rendered by QuickLaTeX.com\" height=\"25\" width=\"336\" style=\"vertical-align: -8px;\"><\/p>\n<\/p>\n<p> Bir noktadaki kuvvetin momentinin (veya torkunun), kuvvetin de\u011ferinin, kuvvetin o noktaya dik mesafesiyle \u00e7arp\u0131lmas\u0131yla hesapland\u0131\u011f\u0131n\u0131 unutmay\u0131n.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-765ae97c83695144c85bb65446416345_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M=F\\cdot d\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"79\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> O halde, ikinci denge ko\u015fulunun denklemini sa\u011flamak i\u00e7in, cismin a\u00e7\u0131sal ivmesinin s\u0131f\u0131r olmas\u0131 gerekir, ba\u015fka bir deyi\u015fle, bu durumdaki bir cisim d\u00f6nm\u00fcyor (durgun durumda) veya a\u00e7\u0131sal h\u0131z sabitinde d\u00f6nm\u00fcyor.<\/p>\n<p> B\u00f6ylece d\u00f6nme dengesi t\u00fcrlerini ay\u0131rt edebiliriz:<\/p>\n<ul>\n<li> <strong>Statik d\u00f6nme dengesi<\/strong> : Momentlerin toplam\u0131 s\u0131f\u0131r ve cismin a\u00e7\u0131sal h\u0131z\u0131 s\u0131f\u0131r oldu\u011funda.<\/li>\n<li> <strong>Dinamik d\u00f6nme dengesi<\/strong> : Momentlerin toplam\u0131 s\u0131f\u0131r oldu\u011funda ve cismin a\u00e7\u0131sal h\u0131z\u0131 sabit oldu\u011funda (s\u0131f\u0131rdan farkl\u0131). <\/li>\n<\/ul>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejemplos-de-la-segunda-condicion-de-equilibrio\"><\/span> \u0130kinci denge ko\u015fulu \u00f6rnekleri<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Dengenin ikinci ko\u015fulunun tan\u0131m\u0131na bakt\u0131\u011f\u0131m\u0131zda, kavram\u0131n anla\u015f\u0131lmas\u0131n\u0131 tamamlamak i\u00e7in art\u0131k g\u00fcnl\u00fck hayattan bir\u00e7ok \u00f6rnek g\u00f6rece\u011fiz.<\/p>\n<p> \u0130kinci denge ko\u015fulunun yayg\u0131n bir \u00f6rne\u011fi \u00f6l\u00e7ektir. Sistem stabil hale geldi\u011finde denge kolu d\u00f6nmeyi b\u0131rak\u0131r ve dolay\u0131s\u0131yla momentlerin toplam\u0131 s\u0131f\u0131r olur ve sistem d\u00f6nme dengesinde olur. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/deuxieme-condition-dequilibre.png\" alt=\"ikinci denge ko\u015fulu\" class=\"wp-image-430\" width=\"303\" height=\"303\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/deuxieme-condition-dequilibre-300x300.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/deuxieme-condition-dequilibre-150x150.png 150w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/deuxieme-condition-dequilibre-768x768.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/deuxieme-condition-dequilibre.png 781w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p> Bir ba\u015fka somut \u00f6rnek ise D\u00fcnya&#8217;d\u0131r. Gezegen s\u00fcrekli olarak kendi ekseni etraf\u0131nda d\u00f6nmektedir ancak sabit a\u00e7\u0131sal h\u0131zla d\u00f6nd\u00fc\u011f\u00fc kabul edilir, dolay\u0131s\u0131yla ikinci denge ko\u015fulunu kar\u015f\u0131lar.<\/p>\n<p> Son olarak, bir nesneyi tavana ast\u0131\u011f\u0131m\u0131zda ve onu hareketsiz tuttu\u011fumuzda, nesne \u00f6teleme dengesinde ve \u00f6teleme dengesinde oldu\u011fundan hem ikinci denge ko\u015fulunu hem de birinci denge ko\u015fulunu yerine getirir. rotasyon.<\/p>\n<p> \u0130lk denge ko\u015fulunun nelerden olu\u015ftu\u011funu net olarak anlayam\u0131yorsan\u0131z detayl\u0131 bir \u015fekilde anlat\u0131ld\u0131\u011f\u0131 a\u015fa\u011f\u0131daki makaleye ba\u015fvurabilirsiniz: <\/p>\n<div style=\"background-color:#FFFDE7; padding-top: 10px; padding-bottom: 10px; padding-right: 10px; padding-left: 20px; border: 2.5px dashed #FFB74D; border-radius:20px;\"> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Bak\u0131n\u0131z:<\/strong> <a href=\"https:\/\/physigeek.com\/tr\/ilk-denge-kosulu\/\">ilk denge ko\u015fulu nedir<\/a> <\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicios-resueltos-de-la-segunda-condicion-de-equilibrio\"><\/span>\u0130kinci denge ko\u015fulunun \u00e7\u00f6z\u00fclm\u00fc\u015f al\u0131\u015ft\u0131rmalar\u0131<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> 1. Egzersiz<\/h3>\n<p> A\u015fa\u011f\u0131daki kiri\u015fin deste\u011finin d\u00f6nme dengesinde olmas\u0131 i\u00e7in yapmas\u0131 gereken momenti hesaplay\u0131n: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-deuxieme-condition-dequilibre.png\" alt=\"ikinci denge ko\u015fulunun \u00e7\u00f6z\u00fcmlenmi\u015f uygulamas\u0131\" class=\"wp-image-397\" width=\"237\" height=\"203\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-deuxieme-condition-dequilibre-300x257.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-deuxieme-condition-dequilibre.png 643w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>\u00e7\u00f6z\u00fcm\u00fc g\u00f6r<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Kiri\u015fin d\u00f6nme dengesinde olmas\u0131 ve dolay\u0131s\u0131yla ikinci denge ko\u015fulunun kar\u015f\u0131lanmas\u0131 i\u00e7in, deste\u011fin kuvvet taraf\u0131ndan \u00fcretilen burulma momentine kar\u015f\u0131 koymas\u0131 gerekir, dolay\u0131s\u0131yla momentlerin toplam\u0131 s\u0131f\u0131r olacakt\u0131r.<\/p>\n<p class=\"has-text-align-left\"> Bu nedenle destek seviyesinde kuvvet taraf\u0131ndan \u00fcretilen momenti (veya torku) hesapl\u0131yoruz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e172a3bbd51bb42bd229d9a88df0a167_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M_{force}=13\\cdot 9 = 117 \\ Nm\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"202\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> \u015eimdi momentlerin denge denklemini \u00f6neriyoruz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fdac8512edbbe2c1b6396ee43a776261_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M_{support}+M_{force}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"170\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kuvveti olu\u015fturan an ekran\u0131n i\u00e7inden ge\u00e7ti\u011fi i\u00e7in i\u015fareti negatiftir:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-b654ae9d3ab78a23e2f7235a7742a503_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M_{support}-117=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"145\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Ve son olarak denklemdeki bilinmeyeni \u00e7\u00f6z\u00fcyoruz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-772409bbbd945be3fc433e503b43e540_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M_{support}=117 \\ Nm\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"152\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Elde edilen darbe pozitif bir i\u015farete sahiptir ve dolay\u0131s\u0131yla y\u00f6n\u00fc ekran\u0131n d\u0131\u015f\u0131na do\u011frudur.<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\"> Al\u0131\u015ft\u0131rma 2<\/h3>\n<p> A\u015fa\u011f\u0131daki \u015fekilde g\u00f6r\u00fcld\u00fc\u011f\u00fc gibi 10 m&#8217;lik yatay \u00e7ubuk k\u00fctlesi 8 kg olan bir cismi desteklemektedir. Mesnetler ile asma cisim aras\u0131ndaki mesafeler bilindi\u011finde, sistemin d\u00f6nme ve \u00f6telenme dengesinde olmas\u0131 durumunda mesnetlerin uygulad\u0131\u011f\u0131 kuvvetlerin de\u011ferleri nelerdir? <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-de-rotation.png\" alt=\"d\u00f6nme dengesi sorunu\" class=\"wp-image-355\" width=\"339\" height=\"120\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-de-rotation-300x107.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-de-rotation.png 643w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>\u00e7\u00f6z\u00fcm\u00fc g\u00f6r<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> \u0130lk olarak yatay \u00e7ubu\u011fun desteklemesi gereken a\u011f\u0131rl\u0131\u011f\u0131 hesaplamak i\u00e7in yer \u00e7ekimi kuvveti form\u00fcl\u00fcn\u00fc kullan\u0131r\u0131z:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-eb480f5d32a9e25cefacd5f89d407580_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=m\\cdot g=8\\cdot 9,81 =78,48 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"244\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Buna g\u00f6re sistemin serbest cisim diyagram\u0131 \u015fu \u015fekildedir: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-rotation-equilibre.png\" alt=\"D\u00f6nme dengesi egzersizi \u00e7\u00f6z\u00fcld\u00fc\" class=\"wp-image-356\" width=\"340\" height=\"297\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-rotation-equilibre-300x261.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-rotation-equilibre.png 654w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Problem ifadesi bize sistemin kuvvetler dengesinde oldu\u011funu, dolay\u0131s\u0131yla t\u00fcm bu kuvvetlerin toplam\u0131n\u0131n s\u0131f\u0131r olmas\u0131 gerekti\u011fini s\u00f6yler. Bu denge ko\u015fulunu kullanarak a\u015fa\u011f\u0131daki denklemi form\u00fcle edebiliriz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-635096a57ce10781254f283c9807f64c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_A+F_B-P=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"136\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> \u00d6te yandan bu ifade bize ayn\u0131 zamanda sistemin momentum dengesinde oldu\u011funu da s\u00f6ylemektedir. Yani sistemin herhangi bir noktas\u0131ndaki momentlerin toplam\u0131n\u0131 dikkate al\u0131rsak sonu\u00e7 s\u0131f\u0131r olmal\u0131d\u0131r ve iki destekten birinin referans noktas\u0131n\u0131 al\u0131rsak tek bilinmeyenli bir denklem elde ederiz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-f1a6d56c3426e8d6c2e890b5e8f4a873_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M(A)=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"79\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-922d5ff929e034db7a9e80d732b0b893_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-P\\cdot 6.5+F_B\\cdot (6.5+3.5)=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"233\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Art\u0131k denklemdeki bilinmeyeni \u00e7\u00f6zerek B deste\u011finin uygulad\u0131\u011f\u0131 kuvveti hesaplayabiliriz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-95596edf27bb6086c35473f55465416d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-78.48\\cdot 6.5+F_B\\cdot 10=0\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"197\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-953185a6ad4824b654b8a40e259bbd71_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_B=\\cfrac{78.48\\cdot 6.5}{10}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"125\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c5459080e5aa468fa3d77a16a2b0d9b9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_B=51.01\\N\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"87\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Ve son olarak, elde edilen de\u011feri dikey kuvvetlerin y\u00fcksek denklemine koyarak di\u011fer deste\u011fe uygulanan kuvvetin yo\u011funlu\u011funu bilebiliriz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-635096a57ce10781254f283c9807f64c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_A+F_B-P=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"136\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-36325128977806ddaca1436ffb68dcd4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_A+51,01-78,48=0\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"185\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-5ecd2d608e61435093289d17c242e21f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_A=27,47\\N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"90\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Bu makalede ikinci denge ko\u015fulunun ne oldu\u011fu ve nelerden olu\u015ftu\u011fu a\u00e7\u0131klanmaktad\u0131r. Ayr\u0131ca ikinci denge durumunun ger\u00e7ek \u00f6rneklerini de bulacaks\u0131n\u0131z ve son olarak ad\u0131m ad\u0131m \u00e7\u00f6z\u00fclen egzersizlerle antrenman yapabileceksiniz. \u0130kinci denge ko\u015fulu nedir? Fizikte ikinci denge ko\u015fulu , bir cismin kendisine uygulanan momentlerin toplam\u0131 s\u0131f\u0131ra e\u015fitse d\u00f6nme dengesinde oldu\u011funu s\u00f6yleyen bir kurald\u0131r. Dolay\u0131s\u0131yla ikinci denge ko\u015fulu, &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/tr\/ikinci-denge-kosulu\/\"> <span class=\"screen-reader-text\">I\u0307kinci denge ko\u015fulu<\/span> Devam\u0131 &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-22","post","type-post","status-publish","format-standard","hentry","category-dinamik"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.3 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 \u0130kinci denge ko\u015fulu<\/title>\n<meta name=\"description\" content=\"\u0130kinci denge ko\u015fulunun ne oldu\u011funu ve nelerden olu\u015ftu\u011funu a\u00e7\u0131kl\u0131yoruz. 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