{"id":21,"date":"2023-06-27T12:59:55","date_gmt":"2023-06-27T12:59:55","guid":{"rendered":"https:\/\/physigeek.com\/tr\/ilk-denge-kosulu\/"},"modified":"2023-06-27T12:59:55","modified_gmt":"2023-06-27T12:59:55","slug":"ilk-denge-kosulu","status":"publish","type":"post","link":"https:\/\/physigeek.com\/tr\/ilk-denge-kosulu\/","title":{"rendered":"Dengenin ilk \u015fart\u0131"},"content":{"rendered":"<p>Bu makale ilk denge ko\u015fulunun nelerden olu\u015ftu\u011funu a\u00e7\u0131klamaktad\u0131r. Ayr\u0131ca ilk denge ko\u015fulunun ger\u00e7ek \u00f6rneklerini de bulacaks\u0131n\u0131z ve son olarak bu konuyla ilgili \u00e7\u00f6z\u00fcml\u00fc al\u0131\u015ft\u0131rmalarla pratik yapabileceksiniz. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFCual-es-la-primera-condicion-de-equilibrio\"><\/span> \u0130lk denge ko\u015fulu nedir?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Fizikte <strong>dengenin ilk ko\u015fulu<\/strong> , bir cisme uygulanan kuvvetlerin toplam\u0131 s\u0131f\u0131ra e\u015fitse, s\u00f6z konusu cismin \u00f6teleme dengesinde olmas\u0131d\u0131r.<\/p>\n<p> Bu nedenle, bir sistemin bile\u015fke kuvveti s\u0131f\u0131r oldu\u011funda dengenin ilk ko\u015fulu kar\u015f\u0131lan\u0131r. Ba\u015fka bir deyi\u015fle, a\u015fa\u011f\u0131daki form\u00fcl sa\u011fland\u0131\u011f\u0131nda birinci denge ko\u015fulu kar\u015f\u0131lan\u0131r:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-b6be8a8a29e6933d96cdf943ceb09119_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\sum \\vv{F}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"25\" width=\"75\" style=\"vertical-align: -8px;\"><\/p>\n<\/p>\n<p> Ayr\u0131ca, ilk denge ko\u015fulu sa\u011fland\u0131\u011f\u0131nda v\u00fccut hareketsizdir veya sabit h\u0131zla hareket etmektedir. \u00c7\u00fcnk\u00fc kuvvetlerin toplam\u0131 s\u0131f\u0131r ise cisim ivmelenemez.<\/p>\n<p> Mant\u0131ksal olarak, ilk denge ko\u015fulunun do\u011frulanmas\u0131 i\u00e7in kuvvetlerin mod\u00fcller de\u011fil vekt\u00f6rel olarak eklenmesi gerekir. Ba\u015fka bir deyi\u015fle, e\u011fer her eksene etkiyen kuvvetlerin toplam\u0131 s\u0131f\u0131r ise kat\u0131 cisim mekanik dengededir.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-9d6873586b63ccddf575a8ee1c7f5137_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\sum\\vv{F_x}=0\\qquad\\sum\\vv{F_y}=0\\qquad\\sum\\vv{F_z}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"25\" width=\"319\" style=\"vertical-align: -8px;\"><\/p>\n<\/p>\n<p> Dolay\u0131s\u0131yla, ilk denge ko\u015fulunun kar\u015f\u0131lan\u0131p kar\u015f\u0131lanmad\u0131\u011f\u0131n\u0131 kontrol etmenin bir y\u00f6ntemi, her eksendeki t\u00fcm kuvvetleri ayr\u0131 ayr\u0131 toplamakt\u0131r ve e\u011fer t\u00fcm toplamlar s\u0131f\u0131ra e\u015fitse, cisim \u00f6teleme dengesindedir. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/premiere-condition-dequilibre.png\" alt=\"dengenin ilk ko\u015fulu\" class=\"wp-image-368\" width=\"307\" height=\"307\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/premiere-condition-dequilibre-300x300.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/premiere-condition-dequilibre-150x150.png 150w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/premiere-condition-dequilibre-768x766.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/premiere-condition-dequilibre.png 1006w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p> \u0130ki t\u00fcr \u00f6teleme dengesi oldu\u011funa dikkat edin:<\/p>\n<ul>\n<li> <strong>Statik \u00f6teleme dengesi<\/strong> : \u0130lk denge ko\u015fulu kar\u015f\u0131land\u0131\u011f\u0131nda ve v\u00fccut da hareketsiz oldu\u011funda.<\/li>\n<li> <strong>Dinamik \u00f6teleme dengesi<\/strong> : \u0130lk denge ko\u015fulu kar\u015f\u0131land\u0131\u011f\u0131nda ve v\u00fccut sabit bir h\u0131za sahip oldu\u011funda (s\u0131f\u0131rdan farkl\u0131). <\/li>\n<\/ul>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejemplos-de-la-primera-condicion-de-equilibrio\"><\/span> \u0130lk denge ko\u015fulu \u00f6rnekleri<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Birinci denge ko\u015fulunun tan\u0131m\u0131n\u0131 \u00f6\u011frendikten sonra, bunun ne anlama geldi\u011fini tam olarak anlayabilmek i\u00e7in a\u015fa\u011f\u0131da \u00fc\u00e7 farkl\u0131 \u00f6rne\u011fi g\u00f6rebilirsiniz.<\/p>\n<p> Trafik \u0131\u015f\u0131klar\u0131 g\u00fcnl\u00fck hayatta dengenin ilk ko\u015fulunun \u00f6rne\u011fidir. Sokakta as\u0131l\u0131 tabelalar\u0131 s\u0131kl\u0131kla g\u00f6r\u00fcyoruz ve bunlar her zaman hareketsiz (dik duruyor ve d\u00fc\u015fm\u00fcyor), dolay\u0131s\u0131yla dengede.<\/p>\n<p> Ayn\u0131 \u015fekilde yerde duran herhangi bir cisim de kuvvetler dengesindedir, yani dengenin ilk \u015fart\u0131n\u0131 kar\u015f\u0131lar. \u00c7\u00fcnk\u00fc v\u00fccuda uygulanan kuvvetler yaln\u0131zca a\u011f\u0131rl\u0131k ve normal kuvvettir ve iki kuvvet birbirine kar\u015f\u0131tt\u0131r. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/equilibre-des-forces.png\" alt=\"g\u00fc\u00e7 dengesi\" class=\"wp-image-294\" width=\"319\" height=\"252\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/equilibre-des-forces-300x238.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/equilibre-des-forces-768x610.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/equilibre-des-forces.png 852w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p> Son olarak, ilk denge ko\u015fulunun bir ba\u015fka \u00f6rne\u011fi, otoyolda sabit h\u0131zla giden bir arabad\u0131r. Sabit h\u0131zla hareket eden herhangi bir cisim, ivmesinin s\u0131f\u0131r oldu\u011fu ve dolay\u0131s\u0131yla ona uygulanan kuvvetlerin toplam\u0131n\u0131n da s\u0131f\u0131r oldu\u011fu anlam\u0131na gelir. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicios-resueltos-de-la-primera-condicion-de-equilibrio\"><\/span>Birinci denge ko\u015fulunun \u00e7\u00f6z\u00fclm\u00fc\u015f problemleri<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> 1. Egzersiz<\/h3>\n<p> A\u015fa\u011f\u0131daki \u015fekilde a\u00e7\u0131lar\u0131 g\u00f6sterilen iki ip ile as\u0131l\u0131 duran, k\u00fctlesi 12 kg olan kat\u0131 bir cisim verildi\u011finde, her bir ipin, cismi dengede tutmak i\u00e7in uygulamas\u0131 gereken kuvveti hesaplay\u0131n. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-de-premiere-condition-dequilibre.png\" alt=\"ilk denge ko\u015fulu problemi\" class=\"wp-image-372\" width=\"243\" height=\"243\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-de-premiere-condition-dequilibre-300x300.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-de-premiere-condition-dequilibre-150x150.png 150w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-de-premiere-condition-dequilibre.png 600w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>\u00c7\u00f6z\u00fcm\u00fc g\u00f6r\u00fcn<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Bu t\u00fcr problemleri \u00e7\u00f6zmek i\u00e7in yapmam\u0131z gereken ilk \u015fey, \u015feklin serbest cisim diyagram\u0131n\u0131 \u00e7izmektir: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-de-la-premiere-condition-dequilibre.png\" alt=\"Dengenin ilk ko\u015fulunun \u00e7\u00f6z\u00fclm\u00fc\u015f egzersizi\" class=\"wp-image-375\" width=\"282\" height=\"335\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-de-la-premiere-condition-dequilibre-252x300.png 252w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-de-la-premiere-condition-dequilibre.png 600w\" sizes=\"auto, (max-width: 252px) 100vw, 252px\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> As\u0131l\u0131 cisme etki eden yaln\u0131zca \u00fc\u00e7 kuvvetin oldu\u011funa dikkat edin: P a\u011f\u0131rl\u0131\u011f\u0131n\u0131n kuvveti ve T <sub>1<\/sub> ve T <sub>2<\/sub> tellerinin gerilmeleri. T <sub>1x<\/sub> , T <sub>1y<\/sub> , T <sub>2x<\/sub> ve T <sub>2y<\/sub> ile temsil edilen kuvvetler s\u0131ras\u0131yla T <sub>1<\/sub> ve T <sub>2&#8217;nin<\/sub> vekt\u00f6r bile\u015fenleridir.<\/p>\n<p class=\"has-text-align-left\"> B\u00f6ylece iplerin e\u011fim a\u00e7\u0131lar\u0131n\u0131 bildi\u011fimiz i\u00e7in \u00e7ekme kuvvetlerinin vekt\u00f6r bile\u015fenleri i\u00e7in ifadeler bulabiliriz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-bc09423d2d10435101c7d6b087add524_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" T_{1x}=T_1\\cdot \\text{cos}(20\u00ba)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"135\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0603d4b02835532dcefe2290484067fb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" T_{1y}=T_1\\cdot \\text{sin}(20\u00ba)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"133\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0b10a6fc64a1a84b9f4f2c47b7990766_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" T_{2x}=T_2\\cdot \\text{cos}(55\u00ba)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"135\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-3e7a1dc2ffa7eb20e5e2d9346f0b96a2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" T_{2y}=T_2\\cdot \\text{sin}(55\u00ba)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"133\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> \u00d6te yandan yer\u00e7ekimi kuvveti form\u00fcl\u00fcn\u00fc uygulayarak a\u011f\u0131rl\u0131\u011f\u0131n kuvvetini hesaplayabiliriz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-da2fc72dc768050ef84d2a3c9ee4a281_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=m\\cdot g=12\\cdot 9,81 =117,72 \\N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"239\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Problem ifadesi bize v\u00fccudun dengede oldu\u011funu, dolay\u0131s\u0131yla dikey kuvvetlerin toplam\u0131n\u0131n ve yatay kuvvetlerin toplam\u0131n\u0131n s\u0131f\u0131ra e\u015fit olmas\u0131 gerekti\u011fini s\u00f6yler. B\u00f6ylece kuvvet denklemlerini olu\u015fturabilir ve bunlar\u0131 s\u0131f\u0131ra e\u015fitleyebiliriz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6532044e76d6b9246f64624159b08c33_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-T_{1x}+T_{2x}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"119\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-52aadf04437252b1f9c17107dfc16a84_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"T_{1y}+T_{2y}-P=0\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"140\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> \u015eimdi k\u0131s\u0131tlamalar\u0131n bile\u015fenlerini daha \u00f6nce buldu\u011fumuz ifadelerle de\u011fi\u015ftiriyoruz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-4a4993c55ab7f27b6c0b67793ee5ff8a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-T_1\\cdot\\text{cos}(20\u00ba)+T_2\\cdot \\text{cos}(55\u00ba)=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"239\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-204773c167037418680872592d118315_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"T_1\\cdot \\text{sin}(20\u00ba)+T_2\\cdot \\text{sin}(55\u00ba)-117.72=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"293\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Ve son olarak T <sub>1<\/sub> ve T <sub>2<\/sub> kuvvetlerinin de\u011ferini elde etmek i\u00e7in denklem sistemini \u00e7\u00f6z\u00fcyoruz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-5ce6dd2d7dce6ba9d2e8c66e50e628b6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left.\\begin{array}{l}-T_1\\cdot 0,94+T_2\\cdot 0,57=0\\\\[2ex]T_1\\cdot 0,34+T_2\\cdot 0,82-117 .72=0\\end{array }\\right\\} \\longrightarrow \\ \\begin{array}{c}T_1=69,56 \\ N\\\\[2ex]T_2=114,74 \\ N\\end{array}[\/ latex] \n\n<div class=&quot;wp-block-otfm-box-spoiler-end otfm-sp_end&quot;><\/div>\n<h3 class=&quot;wp-block-heading&quot;> Exercice 2<\/h3>\n<p> Comme le montre la figure suivante, deux objets sont reli\u00e9s par une corde et une poulie de masses n\u00e9gligeables. Si l&#8217;objet 2 a une masse de 7 kg et que la pente de la rampe est de 50\u00ba, calculez la masse de l&#8217;objet 1 pour que l&#8217;ensemble du syst\u00e8me soit dans des conditions d&#8217;\u00e9quilibre. Dans ce cas, la force de frottement peut \u00eatre n\u00e9glig\u00e9e. <\/p>\n<div class=&quot;wp-block-image&quot;>\n<figure class=&quot;aligncenter size-full is-resized&quot;><img decoding=&quot;async&quot; loading=&quot;lazy&quot; src=&quot;https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-des-forces.png&quot; alt=&quot;probl\u00e8me d'\u00e9quilibre translationnel&quot; class=&quot;wp-image-295&quot; width=&quot;299&quot; height=&quot;240&quot; srcset=&quot;https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-des-forces-300x241.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-des-forces.png 718w&quot; sizes=&quot;(max-width: 300px) 100vw, 300px&quot;><\/figure>\n<\/div>\n<div class=&quot;wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1&quot; role=&quot;button&quot; tabindex=&quot;0&quot; aria-expanded=&quot;false&quot; data-otfm-spc=&quot;#FFF8E1&quot; style=&quot;text-align:center&quot;>\n<div class=&quot;otfm-sp__title&quot;> <strong>Voir la solution<\/strong><\/div>\n<\/div>\n<p> Le corps 1 est sur une pente inclin\u00e9e, donc la premi\u00e8re chose \u00e0 faire est de d\u00e9composer vectoriellement la force de son poids pour avoir les forces dans les axes de la pente : [latex]P_{1x}=P_1\\cdot \\text{sin}(\\alpha)&#8221; title=&#8221;Rendered by QuickLaTeX.com&#8221; height=&#8221;340&#8243; width=&#8221;2876&#8243; style=&#8221;vertical-align: 0px;&#8221;><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-1a0b77602980cc17cce9b3baef744df8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_{1y}=P_1\\cdot \\text{cos}(\\alpha)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"130\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> B\u00f6ylece sistemin tamam\u0131na etki eden kuvvetler k\u00fcmesi \u015fu \u015fekildedir: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-equilibre-des-forces.png\" alt=\"\u00f6teleme dengesi egzersizi \u00e7\u00f6z\u00fcld\u00fc\" class=\"wp-image-296\" width=\"338\" height=\"272\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-equilibre-des-forces-300x241.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-equilibre-des-forces.png 718w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Problem ifadesi bize kuvvetler sisteminin dengede oldu\u011funu, dolay\u0131s\u0131yla iki cismin de dengede olmas\u0131 gerekti\u011fini s\u00f6yler. Bu bilgiden iki cismin denge denklemlerini \u00f6nerebiliriz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-ed082b4f064316ab20fb0d26054d3010_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"1\\ \\rightarrow \\ \\begin{cases}P_{1x}=T\\\\[2ex]P_{1y}=N\\end{cases} \\qquad\\qquad 2 \\ \\rightarrow \\ T=P_2[\/latex ] Ainsi, la composante du poids de l'objet 1 inclin\u00e9 dans le sens de la pente doit \u00eatre \u00e9gale au poids de l'objet 2 : [latex]P_{1x}=P_2\" title=\"Rendered by QuickLaTeX.com\" height=\"87\" width=\"1160\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-4e1b75b6ba5d7bbe88d23e014eb011c5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_1\\cdot \\text{sin}(\\alpha)=P_2\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"120\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> \u015eimdi yer \u00e7ekimi kuvveti form\u00fcl\u00fcn\u00fc uygulay\u0131p denklemi basitle\u015ftiriyoruz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-06a53a846ad5bc034f69fa05488404c4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_1\\cdot g \\cdot \\text{sin}(\\alpha) =m_2 \\cdot g\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"174\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-802fde26f3388538d766a709d60cf48b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_1 \\cdot \\text{sin}(\\alpha) =m_2\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"130\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Son olarak verileri yerine koyuyoruz ve 1. cismin k\u00fctlesini buluyoruz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0457f85ca65afde96b2e575ce54869dd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_1 \\cdot \\text{sin}(50\u00ba) =7\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"122\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-9a26d132815a0ce878a6ad874c8b40b0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_1 =\\cfrac{7}{\\text{sin}(50\u00ba)}\" title=\"Rendered by QuickLaTeX.com\" height=\"44\" width=\"103\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6e80f0daabb2167ec2f6622b08001a97_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_1=9,14 \\ kg\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"106\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Bu makale ilk denge ko\u015fulunun nelerden olu\u015ftu\u011funu a\u00e7\u0131klamaktad\u0131r. Ayr\u0131ca ilk denge ko\u015fulunun ger\u00e7ek \u00f6rneklerini de bulacaks\u0131n\u0131z ve son olarak bu konuyla ilgili \u00e7\u00f6z\u00fcml\u00fc al\u0131\u015ft\u0131rmalarla pratik yapabileceksiniz. \u0130lk denge ko\u015fulu nedir? Fizikte dengenin ilk ko\u015fulu , bir cisme uygulanan kuvvetlerin toplam\u0131 s\u0131f\u0131ra e\u015fitse, s\u00f6z konusu cismin \u00f6teleme dengesinde olmas\u0131d\u0131r. Bu nedenle, bir sistemin bile\u015fke kuvveti s\u0131f\u0131r &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/tr\/ilk-denge-kosulu\/\"> <span class=\"screen-reader-text\">Dengenin ilk \u015fart\u0131<\/span> Devam\u0131 &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-21","post","type-post","status-publish","format-standard","hentry","category-dinamik"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.3 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 \u0130lk denge durumu (\u00e7\u00f6z\u00fcmlenmi\u015f al\u0131\u015ft\u0131rmalarla)<\/title>\n<meta name=\"description\" content=\"Birinci denge ko\u015fulunun ne oldu\u011funu ve nelerden olu\u015ftu\u011funu a\u00e7\u0131kl\u0131yoruz. 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