{"id":20,"date":"2023-06-27T14:15:28","date_gmt":"2023-06-27T14:15:28","guid":{"rendered":"https:\/\/physigeek.com\/tr\/donme-dengesi\/"},"modified":"2023-06-27T14:15:28","modified_gmt":"2023-06-27T14:15:28","slug":"donme-dengesi","status":"publish","type":"post","link":"https:\/\/physigeek.com\/tr\/donme-dengesi\/","title":{"rendered":"D\u00f6nme dengesi"},"content":{"rendered":"<p>Bu makale bir cismin d\u00f6nme dengesinde olmas\u0131n\u0131n ne anlama geldi\u011fini a\u00e7\u0131klamaktad\u0131r. Ayr\u0131ca d\u00f6nme dengesi ile ikinci denge ko\u015fulu aras\u0131ndaki ili\u015fkiyi de bulacaks\u0131n\u0131z. Ayn\u0131 \u015fekilde rotasyonel denge \u00f6rne\u011fini de g\u00f6rebileceksiniz ve son olarak ad\u0131m ad\u0131m \u00e7\u00f6z\u00fclen bir egzersizle pratik yapabileceksiniz. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-el-equilibrio-rotacional\"><\/span> D\u00f6nme dengesi nedir?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Fizikte <strong>d\u00f6nme dengesi<\/strong> , v\u00fccudun d\u00f6nmedi\u011fi veya sabit bir d\u00f6n\u00fc\u015fe sahip oldu\u011fu, yani v\u00fccudun hareketsiz oldu\u011fu veya sabit bir a\u00e7\u0131sal h\u0131zda d\u00f6nd\u00fc\u011f\u00fc bir durumdur.<\/p>\n<p> D\u00f6nme dengesi, cisme etki eden momentlerin (veya torklar\u0131n) toplam\u0131 s\u0131f\u0131ra e\u015fit oldu\u011funda ortaya \u00e7\u0131kar.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-68e425c6419a56b8acdfd0805f80b077_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\somme M=0\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"52\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Bir cismin d\u00f6nme dengesinde olmas\u0131 a\u00e7\u0131sal h\u0131z\u0131n\u0131n s\u0131f\u0131r veya sabit oldu\u011fu anlam\u0131na gelir. Dolay\u0131s\u0131yla bu durumda a\u00e7\u0131sal ivme her zaman s\u0131f\u0131rd\u0131r.<\/p>\n<p> Fizikte d\u00f6nmenin, cismin y\u00f6n\u00fcn\u00fc de\u011fi\u015ftirdi\u011fi, b\u00f6ylece bir nesnenin ayn\u0131 noktada kalarak kendi ekseni etraf\u0131nda d\u00f6nebildi\u011fi bir hareket oldu\u011funu unutmay\u0131n.<\/p>\n<p> D\u00f6nme dengesi t\u00fcrlerini ay\u0131rt edebiliriz:<\/p>\n<ul>\n<li> <strong>Statik d\u00f6nme dengesi<\/strong> : Momentlerin toplam\u0131 s\u0131f\u0131r ve cismin a\u00e7\u0131sal h\u0131z\u0131 s\u0131f\u0131r oldu\u011funda.<\/li>\n<li> <strong>Dinamik d\u00f6nme dengesi<\/strong> : Momentlerin toplam\u0131 s\u0131f\u0131r oldu\u011funda ve cismin a\u00e7\u0131sal h\u0131z\u0131 sabit oldu\u011funda (s\u0131f\u0131rdan farkl\u0131). <\/li>\n<\/ul>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Segunda-condicion-de-equilibrio\"><\/span> \u0130kinci denge ko\u015fulu<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Bir cisim d\u00f6nme dengesinde oldu\u011funda, <strong>ikinci denge ko\u015fulunun<\/strong> sa\u011fland\u0131\u011f\u0131 s\u00f6ylenir.<\/p>\n<p> B\u00f6ylece ikinci denge ko\u015fulu, bir sistemin momentlerinin (veya \u00e7iftlerinin) toplam\u0131 s\u0131f\u0131r oldu\u011funda do\u011frulan\u0131r. Kuvvetlerin moment mod\u00fcllerinin toplanmamas\u0131 gerekti\u011fini, bunun yerine momentlerin vekt\u00f6rel olarak eklenmesi gerekti\u011fini, dolay\u0131s\u0131yla momentlerin toplam\u0131n\u0131n her eksen i\u00e7in s\u0131f\u0131r olmas\u0131 gerekti\u011fini unutmay\u0131n.<\/p>\n<p> Ba\u015fka bir deyi\u015fle, bir cismin d\u00f6nme dengesinde oldu\u011funu do\u011frulamak i\u00e7in her eksenin momentlerinin ayr\u0131 ayr\u0131 toplanmas\u0131 gerekir ve her eksenin toplam\u0131 s\u0131f\u0131rsa kat\u0131 cisim d\u00f6nme dengesindedir. <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-afbd9140b106ab074dab6852a6dc7f4b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\sum \\vv{M_x}=0 \\qquad \\sum\\vv{M_y}=0\\qquad \\sum\\vv{M_z}\" title=\"Rendered by QuickLaTeX.com\" height=\"25\" width=\"303\" style=\"vertical-align: -8px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Equilibrio-rotacional-y-traslacional\"><\/span> D\u00f6nme ve \u00f6teleme dengesi<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Momentlerin toplam\u0131 ve kuvvetlerin toplam\u0131 s\u0131f\u0131ra e\u015fit oldu\u011funda kat\u0131 bir cisim d\u00f6nme ve \u00f6teleme dengesindedir.<\/strong> Ba\u015fka bir deyi\u015fle, bile\u015fke kuvvet ve bile\u015fke moment s\u0131f\u0131r oldu\u011funda bir cisim \u00f6teleme ve d\u00f6nme dengesindedir.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6c79e87aef62838b71a11567cc9a620f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\sum \\vv{F}=0 \\qquad \\sum\\vv{M}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"180\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Bu durumda cismin do\u011frusal h\u0131z\u0131 s\u0131f\u0131r veya sabit, a\u00e7\u0131sal h\u0131z\u0131 da s\u0131f\u0131r veya sabit olaca\u011f\u0131ndan ne do\u011frusal ivmesi ne de a\u00e7\u0131sal ivmesi olacakt\u0131r.<\/p>\n<p> Bir cisim hem kuvvetler dengesinde hem de momentler dengesinde oldu\u011funda <strong>, cismin dengede oldu\u011funun s\u00f6ylendi\u011fine<\/strong> dikkat edilmelidir.<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejemplo-de-equilibrio-rotacional\"><\/span> D\u00f6nme Dengesi \u00d6rne\u011fi<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Art\u0131k d\u00f6nme dengesinin tan\u0131m\u0131n\u0131 bildi\u011finize g\u00f6re, kavram\u0131n anla\u015f\u0131lmas\u0131n\u0131 tamamlamak i\u00e7in burada bir \u00f6rnek a\u00e7\u0131klanmaktad\u0131r.<\/p>\n<p> D\u00f6nme dengesinin tipik bir \u00f6rne\u011fi denge sistemidir. Terazinin her iki taraf\u0131na da tam olarak ayn\u0131 a\u011f\u0131rl\u0131k yerle\u015ftirildi\u011finde denge kolunun d\u00f6nmesi durur ve dolay\u0131s\u0131yla sistem d\u00f6nme dengesinde olur. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-dequilibre-de-rotation.png\" alt=\"d\u00f6nme dengesi\" class=\"wp-image-354\" width=\"233\" height=\"233\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-dequilibre-de-rotation-208x300.png 208w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-dequilibre-de-rotation.png 610w\" sizes=\"auto, (max-width: 208px) 100vw, 208px\"><\/figure>\n<\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicio-resuelto-equilibrio-rotalcional\"><\/span> Egzersiz d\u00f6nme dengesini \u00e7\u00f6zd\u00fc<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<ul>\n<li> A\u015fa\u011f\u0131daki \u015fekilde g\u00f6r\u00fcld\u00fc\u011f\u00fc gibi 10 m&#8217;lik yatay \u00e7ubuk k\u00fctlesi 8 kg olan bir cismi desteklemektedir. Destekler ile as\u0131l\u0131 cisim aras\u0131ndaki mesafeler bilindi\u011finde, sistem d\u00f6nme ve \u00f6telenme dengesinde ise desteklerin uygulad\u0131\u011f\u0131 kuvvetlerin de\u011feri nedir? <\/li>\n<\/ul>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-de-rotation.png\" alt=\"d\u00f6nme dengesi sorunu\" class=\"wp-image-355\" width=\"339\" height=\"120\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-de-rotation-300x107.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-de-rotation.png 643w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>\u00c7\u00f6z\u00fcm\u00fc g\u00f6r\u00fcn<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> \u00d6ncelikle yatay \u00e7ubu\u011fun desteklemesi gereken a\u011f\u0131rl\u0131\u011f\u0131 hesaplamak i\u00e7in yer \u00e7ekimi kuvveti form\u00fcl\u00fcn\u00fc kullan\u0131r\u0131z:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-eb480f5d32a9e25cefacd5f89d407580_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=m\\cdot g=8\\cdot 9,81 =78,48 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"244\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Buna g\u00f6re sistemin serbest cisim diyagram\u0131 \u015fu \u015fekildedir: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-rotation-equilibre.png\" alt=\"D\u00f6nme dengesi egzersizi \u00e7\u00f6z\u00fcld\u00fc\" class=\"wp-image-356\" width=\"340\" height=\"297\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-rotation-equilibre-300x261.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-rotation-equilibre.png 654w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Problem ifadesi bize sistemin kuvvetler dengesinde oldu\u011funu, dolay\u0131s\u0131yla t\u00fcm bu kuvvetlerin toplam\u0131n\u0131n s\u0131f\u0131r olmas\u0131 gerekti\u011fini s\u00f6yler. Bu denge ko\u015fulunu kullanarak a\u015fa\u011f\u0131daki denklemi form\u00fcle edebiliriz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-635096a57ce10781254f283c9807f64c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_A+F_B-P=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"136\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> \u00d6te yandan bu ifade bize ayn\u0131 zamanda sistemin momentum dengesinde oldu\u011funu da s\u00f6ylemektedir. Yani sistemin herhangi bir noktas\u0131ndaki momentlerin toplam\u0131n\u0131 dikkate al\u0131rsak sonu\u00e7 s\u0131f\u0131r olmal\u0131d\u0131r ve iki destekten birinin referans noktas\u0131n\u0131 al\u0131rsak tek bilinmeyenli bir denklem elde ederiz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-f1a6d56c3426e8d6c2e890b5e8f4a873_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M(A)=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"79\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-922d5ff929e034db7a9e80d732b0b893_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-P\\cdot 6.5+F_B\\cdot (6.5+3.5)=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"233\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Art\u0131k denklemdeki bilinmeyeni \u00e7\u00f6zerek B deste\u011finin uygulad\u0131\u011f\u0131 kuvveti hesaplayabiliriz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-95596edf27bb6086c35473f55465416d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-78.48\\cdot 6.5+F_B\\cdot 10=0\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"197\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-953185a6ad4824b654b8a40e259bbd71_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_B=\\cfrac{78.48\\cdot 6.5}{10}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"125\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-11c77ae25a2807aee7370166ab0eaf25_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_B=51.01 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"109\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Ve son olarak, elde edilen de\u011feri d\u00fc\u015fey kuvvetlerin denkleminde yerine koyarak di\u011fer deste\u011fe uygulanan kuvvetin yo\u011funlu\u011funu bilebiliriz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-635096a57ce10781254f283c9807f64c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_A+F_B-P=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"136\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-db94d7dd9c18fdf7656ce98ee55f0c2b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_A+51.01-78.48=0\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"179\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-88d9c19a7f65d95a82b07e3a5e063322_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_A=27,47 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"111\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Bu makale bir cismin d\u00f6nme dengesinde olmas\u0131n\u0131n ne anlama geldi\u011fini a\u00e7\u0131klamaktad\u0131r. Ayr\u0131ca d\u00f6nme dengesi ile ikinci denge ko\u015fulu aras\u0131ndaki ili\u015fkiyi de bulacaks\u0131n\u0131z. Ayn\u0131 \u015fekilde rotasyonel denge \u00f6rne\u011fini de g\u00f6rebileceksiniz ve son olarak ad\u0131m ad\u0131m \u00e7\u00f6z\u00fclen bir egzersizle pratik yapabileceksiniz. D\u00f6nme dengesi nedir? Fizikte d\u00f6nme dengesi , v\u00fccudun d\u00f6nmedi\u011fi veya sabit bir d\u00f6n\u00fc\u015fe sahip oldu\u011fu, yani &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/tr\/donme-dengesi\/\"> <span class=\"screen-reader-text\">D\u00f6nme dengesi<\/span> Devam\u0131 &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-20","post","type-post","status-publish","format-standard","hentry","category-dinamik"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.3 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 D\u00f6nme dengesi nedir? 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