{"id":19,"date":"2023-06-27T14:57:01","date_gmt":"2023-06-27T14:57:01","guid":{"rendered":"https:\/\/physigeek.com\/tr\/oteleme-dengesi\/"},"modified":"2023-06-27T14:57:01","modified_gmt":"2023-06-27T14:57:01","slug":"oteleme-dengesi","status":"publish","type":"post","link":"https:\/\/physigeek.com\/tr\/oteleme-dengesi\/","title":{"rendered":"\u00c7eviri dengesi"},"content":{"rendered":"<p>Bu makale \u00f6teleme dengesinin ne oldu\u011funu a\u00e7\u0131klamaktad\u0131r. \u00d6teleme dengesi ile ilk denge ko\u015fulu (ya da eylemsizlik ilkesi) aras\u0131ndaki ili\u015fkiyi bulacaks\u0131n\u0131z. Ayr\u0131ca \u00f6teleme dengelerine ili\u015fkin birka\u00e7 \u00f6rnek g\u00f6rebileceksiniz ve son olarak konuyla ilgili \u00e7\u00f6z\u00fcml\u00fc bir al\u0131\u015ft\u0131rma yapacaks\u0131n\u0131z. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-el-equilibrio-traslacional\"><\/span> \u00d6teleme dengesi nedir?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Translasyonel denge,<\/strong> v\u00fccudun hareketsiz veya sabit h\u0131zda oldu\u011fu fiziksel bir durumdur. Translasyonel denge, v\u00fccuda etki eden kuvvetlerin toplam\u0131 s\u0131f\u0131ra e\u015fit oldu\u011funda ortaya \u00e7\u0131kar.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-022c7518a0834669c82cb9a1e2208ce2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\sum\\vv{F} =0\" title=\"Rendered by QuickLaTeX.com\" height=\"25\" width=\"75\" style=\"vertical-align: -8px;\"><\/p>\n<\/p>\n<p> Bu nedenle, kat\u0131 bir cisim \u00f6teleme dengesinde oldu\u011funda, bu onun ivmesinin s\u0131f\u0131r oldu\u011fu anlam\u0131na gelir. Benzer \u015fekilde, e\u011fer bir kuvvetler sistemi \u00f6teleme dengesindeyse, sistem \u00fczerindeki bile\u015fke kuvvet s\u0131f\u0131rd\u0131r.<\/p>\n<p> Fizikte \u00e7evirinin bir nesnenin konumunun de\u011fi\u015ftirildi\u011fi bir hareket oldu\u011funu hat\u0131rlay\u0131n. Bu nedenle \u00e7eviri dengesi, \u00e7evirinin dengeli bir \u015fekilde (sabit bir h\u0131zda) ger\u00e7ekle\u015fti\u011fi veya \u00e7evirinin olmad\u0131\u011f\u0131 anlam\u0131na gelir.<\/p>\n<p> \u0130ki t\u00fcr \u00f6teleme dengesi vard\u0131r:<\/p>\n<ul>\n<li> <strong>Statik \u00f6teleme dengesi<\/strong> : Kuvvetlerin toplam\u0131 s\u0131f\u0131r olan ve ayn\u0131 zamanda hareketsiz olan cisim.<\/li>\n<li> <strong>Dinamik \u00f6teleme dengesi<\/strong> : Kuvvetlerin vekt\u00f6r toplam\u0131 s\u0131f\u0131r olan ve sabit h\u0131zla hareket eden bir cisim. <\/li>\n<\/ul>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Primera-condicion-de-equilibrio\"><\/span> Dengenin ilk \u015fart\u0131<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Bir cisim \u00f6teleme dengesinde oldu\u011funda, <strong>birinci denge ko\u015fulunun<\/strong> sa\u011fland\u0131\u011f\u0131 s\u00f6ylenir.<\/p>\n<p> Bu nedenle, bir sistemin kuvvetlerinin toplam\u0131 s\u0131f\u0131r oldu\u011funda ilk denge ko\u015fulu sa\u011flan\u0131r. Kuvvetlerin mod\u00fcllerinin toplanmamas\u0131, vekt\u00f6r olarak eklenmesi gerekti\u011fini, yani her eksen i\u00e7in kuvvetlerin toplam\u0131n\u0131n s\u0131f\u0131r olmas\u0131 gerekti\u011fini unutmay\u0131n.<\/p>\n<p> Yani e\u015f d\u00fczlemli kuvvetlerle (iki boyut) \u00e7al\u0131\u015f\u0131yorsak, bir cismin \u00f6teleme dengesinde olmas\u0131 i\u00e7in yatay kuvvetler (X ekseni) ve dikey kuvvetler (Y ekseni) ayr\u0131 ayr\u0131 eklenmeli ve iki toplam\u0131n 0 vermesi gerekir. . <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-45b0a8d2ba38c7f5141d9122c85b4363_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\sum \\vv{F_x}=0 \\qquad \\sum\\vv{F_y}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"25\" width=\"200\" style=\"vertical-align: -8px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Equilibrio-traslacional-y-rotacional\"><\/span> \u00d6teleme ve d\u00f6nme dengesi<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Rijit bir cisim, kuvvetlerin toplam\u0131 ve momentlerin toplam\u0131 s\u0131f\u0131ra e\u015fit oldu\u011funda \u00f6teleme ve d\u00f6nme dengesindedir.<\/strong> Veya ba\u015fka bir deyi\u015fle, bile\u015fke kuvvet ve bile\u015fke moment s\u0131f\u0131r oldu\u011funda bir cisim \u00f6teleme ve d\u00f6nme dengesindedir.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6c79e87aef62838b71a11567cc9a620f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\sum \\vv{F}=0 \\qquad \\sum\\vv{M}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"180\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> Bu durumda cismin do\u011frusal h\u0131z\u0131 s\u0131f\u0131r veya sabit olaca\u011f\u0131 gibi a\u00e7\u0131sal h\u0131z\u0131 da s\u0131f\u0131r veya sabit olacakt\u0131r. Bu nedenle ne do\u011frusal ivmeye ne de a\u00e7\u0131sal ivmeye sahip olacakt\u0131r.<\/p>\n<p> Ek olarak, bir cisim hem kuvvetler dengesinde hem de momentler dengesinde oldu\u011funda <strong>, cismin dengede oldu\u011fu s\u00f6ylenir<\/strong> . <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejemplos-de-equilibrio-traslacional\"><\/span> \u00d6teleme dengesi \u00f6rnekleri<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> \u00d6teleme dengesinin tan\u0131m\u0131n\u0131 dikkate alarak bu terimin anlam\u0131n\u0131 anlamay\u0131 tamamlamak i\u00e7in \u00fc\u00e7 farkl\u0131 \u00f6rne\u011fi analiz edece\u011fiz.<\/p>\n<p> \u00d6rne\u011fin, iplere as\u0131l\u0131 olan a\u015fa\u011f\u0131daki nesne, t\u00fcm kuvvetler dengede oldu\u011fundan \u00f6teleme dengesindedir. A\u011f\u0131rl\u0131\u011f\u0131n kuvveti, <sub>T2<\/sub> kuvveti ve <sub>T1<\/sub> ve <sub>T3<\/sub> kuvvetlerinin dikey bile\u015fenleri taraf\u0131ndan telafi edilir. \u00d6te yandan T <sub>1<\/sub> ve T <sub>3<\/sub> kuvvetlerinin yatay bile\u015fenleri birbirini telafi etmektedir. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/equilibre-translationnel.png\" alt=\"\u00f6teleme dengesi\" class=\"wp-image-341\" width=\"360\" height=\"360\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/equilibre-translationnel-300x300.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/equilibre-translationnel-150x150.png 150w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/equilibre-translationnel-768x770.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/equilibre-translationnel.png 968w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p> Asl\u0131nda, hareketsiz halde yerde duran herhangi bir nesne, bir kuvvetler dengesi i\u00e7indedir, \u00e7\u00fcnk\u00fc ona uygulanan kuvvetler yaln\u0131zca a\u011f\u0131rl\u0131k ve normal kuvvettir ve iki kuvvet birbirine kar\u015f\u0131tt\u0131r. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/equilibre-des-forces.png\" alt=\"\u00e7eviride kuvvet dengesi\" class=\"wp-image-294\" width=\"319\" height=\"252\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/equilibre-des-forces-300x238.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/equilibre-des-forces-768x610.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/equilibre-des-forces.png 852w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p> \u00d6teleme dengesinin bir ba\u015fka \u00f6rne\u011fi, yol boyunca sabit bir h\u0131zla hareket eden bir arabad\u0131r. Sabit h\u0131zla hareket eden herhangi bir cisim, ivmesinin s\u0131f\u0131r oldu\u011fu ve dolay\u0131s\u0131yla kuvvetlerin toplam\u0131n\u0131n da s\u0131f\u0131r oldu\u011fu anlam\u0131na gelir. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicio-resuelto-del-equilibrio-traslacional\"><\/span> \u00c7\u00f6z\u00fclm\u00fc\u015f \u00e7evirisel denge egzersizi<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<ul>\n<li> A\u015fa\u011f\u0131daki \u015fekilde g\u00f6r\u00fcld\u00fc\u011f\u00fc gibi iki cisim k\u00fctleleri ihmal edilebilir bir halat ve bir makara ile birbirine ba\u011flanm\u0131\u015ft\u0131r. E\u011fer nesne 2&#8217;nin k\u00fctlesi 7 kg ise ve rampan\u0131n e\u011fimi 50\u00b0 ise, t\u00fcm sistem denge durumunda olacak \u015fekilde nesne 1&#8217;in k\u00fctlesini hesaplay\u0131n. Bu durumda s\u00fcrt\u00fcnme kuvveti ihmal edilebilir. <\/li>\n<\/ul>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-des-forces.png\" alt=\"\u00f6teleme dengesi problemi\" class=\"wp-image-295\" width=\"299\" height=\"240\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-des-forces-300x241.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-des-forces.png 718w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>\u00e7\u00f6z\u00fcm\u00fc g\u00f6r<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Cisim 1 e\u011fimli bir e\u011fim \u00fczerindedir, dolay\u0131s\u0131yla yap\u0131lacak ilk \u015fey, kuvvetlerin e\u011fim eksenlerinde olmas\u0131n\u0131 sa\u011flamak i\u00e7in a\u011f\u0131rl\u0131\u011f\u0131n\u0131n kuvvetini vekt\u00f6rel olarak ayr\u0131\u015ft\u0131rmakt\u0131r:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c05811c44aa2d58295c811d612a54eee_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_{1x}=P_1\\cdot \\text{sin}(\\alpha)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"128\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-1a0b77602980cc17cce9b3baef744df8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_{1y}=P_1\\cdot \\text{cos}(\\alpha)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"130\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dolay\u0131s\u0131yla sistemin tamam\u0131na etki eden kuvvetler k\u00fcmesi \u015funlard\u0131r: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-equilibre-des-forces.png\" alt=\"\u00c7\u00f6z\u00fclm\u00fc\u015f \u00e7evirisel denge egzersizi\" class=\"wp-image-296\" width=\"338\" height=\"272\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-equilibre-des-forces-300x241.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-equilibre-des-forces.png 718w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Problem ifadesi bize kuvvetler sisteminin dengede oldu\u011funu, dolay\u0131s\u0131yla iki cismin de dengede olmas\u0131 gerekti\u011fini s\u00f6yler. Bu bilgiden iki cismin denge denklemlerini \u00f6nerebiliriz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-ed082b4f064316ab20fb0d26054d3010_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"1\\ \\rightarrow \\ \\begin{cases}P_{1x}=T\\\\[2ex]P_{1y}=N\\end{cases} \\qquad\\qquad 2 \\ \\rightarrow \\ T=P_2[\/latex ] Ainsi, la composante du poids de l'objet 1 inclin\u00e9 dans le sens de la pente doit \u00eatre \u00e9gale au poids de l'objet 2 : [latex]P_{1x}=P_2\" title=\"Rendered by QuickLaTeX.com\" height=\"87\" width=\"1160\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-9b5e757fb28e9dde3aed458f89a3ed53_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_1\\cdot \\text{sen}(\\alpha)=P_2\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"123\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> \u015eimdi yer\u00e7ekimi kuvveti form\u00fcl\u00fcn\u00fc uygulay\u0131p denklemi basitle\u015ftiriyoruz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-06a53a846ad5bc034f69fa05488404c4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_1\\cdot g \\cdot \\text{sin}(\\alpha) =m_2 \\cdot g\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"174\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-802fde26f3388538d766a709d60cf48b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_1 \\cdot \\text{sin}(\\alpha) =m_2\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"130\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Son olarak verileri yerine koyuyoruz ve 1. cismin k\u00fctlesini buluyoruz:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0457f85ca65afde96b2e575ce54869dd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_1 \\cdot \\text{sin}(50\u00ba) =7\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"122\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-9a26d132815a0ce878a6ad874c8b40b0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_1 =\\cfrac{7}{\\text{sin}(50\u00ba)}\" title=\"Rendered by QuickLaTeX.com\" height=\"44\" width=\"103\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-37d57b7e3c4a13f3c4dc4ae981f7d61f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_1=9,14\\kg\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"82\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Bu makale \u00f6teleme dengesinin ne oldu\u011funu a\u00e7\u0131klamaktad\u0131r. \u00d6teleme dengesi ile ilk denge ko\u015fulu (ya da eylemsizlik ilkesi) aras\u0131ndaki ili\u015fkiyi bulacaks\u0131n\u0131z. Ayr\u0131ca \u00f6teleme dengelerine ili\u015fkin birka\u00e7 \u00f6rnek g\u00f6rebileceksiniz ve son olarak konuyla ilgili \u00e7\u00f6z\u00fcml\u00fc bir al\u0131\u015ft\u0131rma yapacaks\u0131n\u0131z. \u00d6teleme dengesi nedir? Translasyonel denge, v\u00fccudun hareketsiz veya sabit h\u0131zda oldu\u011fu fiziksel bir durumdur. Translasyonel denge, v\u00fccuda etki eden &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/tr\/oteleme-dengesi\/\"> <span class=\"screen-reader-text\">\u00c7eviri dengesi<\/span> Devam\u0131 &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-19","post","type-post","status-publish","format-standard","hentry","category-dinamik"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.3 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 \u00d6teleme dengesi nedir? 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