{"id":18,"date":"2023-06-27T16:03:03","date_gmt":"2023-06-27T16:03:03","guid":{"rendered":"https:\/\/physigeek.com\/tr\/cift\/"},"modified":"2023-06-27T16:03:03","modified_gmt":"2023-06-27T16:03:03","slug":"cift","status":"publish","type":"post","link":"https:\/\/physigeek.com\/tr\/cift\/","title":{"rendered":"\u00c7ift"},"content":{"rendered":"<p>Bu makalede kuvvet \u00e7iftlerinin ne oldu\u011fu ve kuvvet \u00e7iftlerinin momentinin nas\u0131l hesaplanaca\u011f\u0131 a\u00e7\u0131klanmaktad\u0131r. Ek olarak torkun \u00f6zelliklerini ve hesaplaman\u0131n nas\u0131l yap\u0131laca\u011f\u0131na dair somut bir \u00f6rnek bulacaks\u0131n\u0131z. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-un-par-de-fuerzas\"><\/span> G\u00fc\u00e7l\u00fc \u00e7ift nedir?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Kuvvet \u00e7ifti,<\/strong> ayn\u0131 b\u00fcy\u00fckl\u00fckte fakat z\u0131t y\u00f6nlerde iki paralel kuvvetin olu\u015fturdu\u011fu bir sistemdir. Ek olarak, birka\u00e7 kuvvetin kuvvetleri bir cisim \u00fczerinde d\u00f6nme hareketi \u00fcretir.<\/p>\n<p> \u00d6rne\u011fin bir araban\u0131n direksiyonunu iki elinizle \u00e7evirdi\u011finizde direksiyona bir miktar kuvvet uygulars\u0131n\u0131z. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/couple-de-forces.png\" alt=\"\u00e7ift\" class=\"wp-image-318\" width=\"270\" height=\"335\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/couple-de-forces-242x300.png 242w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/couple-de-forces.png 531w\" sizes=\"auto, (max-width: 242px) 100vw, 242px\"><\/figure>\n<\/div>\n<p> Bir kuvvet \u00e7iftinin \u00f6nemli bir \u00f6zelli\u011fi, uygulanan iki kuvvet ayn\u0131 y\u00f6n ve \u015fiddete sahip ancak y\u00f6nleri z\u0131t oldu\u011fundan sistemin sonu\u00e7ta ortaya \u00e7\u0131kan kuvvetinin s\u0131f\u0131r olmas\u0131d\u0131r. Bu nedenle sistem kuvvetler dengesindedir. <\/p>\n<div style=\"background-color:#FFFDE7; padding-top: 10px; padding-bottom: 10px; padding-right: 10px; padding-left: 20px; border: 2.5px dashed #FFB74D; border-radius:20px;\"> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Bak\u0131n\u0131z:<\/strong> <a href=\"https:\/\/physigeek.com\/tr\/ortaya-cikan-kuvvet\/\">bile\u015fke kuvvet nas\u0131l hesaplan\u0131r<\/a><\/div>\n<p> Fizikte kuvvet \u00e7iftine tork veya k\u0131saca tork da denir. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Momento-de-un-par-de-fuerzas\"><\/span> Baz\u0131 kuvvetlerin momenti<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Uygulanan birka\u00e7 kuvvet v\u00fccutta bir moment olu\u015fturur.<\/strong> Bir kuvvet \u00e7iftinin momenti, sistemdeki bir kuvvetin b\u00fcy\u00fckl\u00fc\u011f\u00fc ile iki kuvvet aras\u0131ndaki mesafenin \u00e7arp\u0131m\u0131na e\u015fittir.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-071d511105d77dd7d29e57da9c4efcfa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M=F_1\\cdot d=F_2\\cdot d\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"149\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p> Rijit cismin merkezindeki bir \u00e7ift kuvvetin toplam momenti (veya torku), bu iki kuvvet taraf\u0131ndan olu\u015fturulur. Ve iki kuvvet ayn\u0131 mod\u00fcle sahip fakat y\u00f6nleri z\u0131t oldu\u011fundan, her ikisi de ayn\u0131 b\u00fcy\u00fckl\u00fckte ve ayn\u0131 y\u00f6nde bir moment \u00fcretir.<\/p>\n<p> Bu nedenle birka\u00e7 kuvvetin form\u00fcl\u00fcn\u00fc g\u00f6stermek \u00e7ok basittir; kuvvetlerin \u00fcretti\u011fi iki momentin de\u011ferini eklemek yeterlidir:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-53292e4f614aab20c7e39bb481567ddc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" \\begin{aligned}M&amp;=F_1\\cdot \\cfrac{d}{2}+F_2\\cdot \\cfrac{d}{2} \\\\[1ex]&amp;=F_1 \\cdot \\cfrac{d}{2 }+F_1 \\cdot \\cfrac{d}{2}\\\\[2ex] &amp; = F_1\\cdot d \\\\[2ex] &amp;=F_2 \\cdot d\\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"175\" width=\"151\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Birka\u00e7 kuvvetin momenti cismin d\u00f6nme hareketini olu\u015fturur, dolay\u0131s\u0131yla cisim d\u00f6nme dengesinde de\u011fildir. Ba\u015fka bir deyi\u015fle kat\u0131 cisim kuvvet dengesindedir ancak moment dengesinde de\u011fildir. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejemplo-de-un-par-de-fuerzas\"><\/span> Baz\u0131 kuvvetlere \u00f6rnek<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Birka\u00e7 kuvvetin tan\u0131m\u0131 g\u00f6z \u00f6n\u00fcne al\u0131nd\u0131\u011f\u0131nda, kavram\u0131n \u00f6z\u00fcmsenmesini tamamlamak i\u00e7in birka\u00e7 kuvvetin momentinin nas\u0131l hesapland\u0131\u011f\u0131na dair bir \u00f6rnek g\u00f6rece\u011fiz.<\/p>\n<ul>\n<li> Aralar\u0131nda 3 m mesafe bulunan 16 N&#8217;luk kuvvet \u00e7iftinin olu\u015fturdu\u011fu momenti hesaplay\u0131n.<\/li>\n<\/ul>\n<p> Egzersizin kuvvet torkunun momentini belirlemek i\u00e7in yukar\u0131daki b\u00f6l\u00fcmde g\u00f6rd\u00fc\u011f\u00fcm\u00fcz form\u00fcl\u00fc uygulamal\u0131y\u0131z:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-df3773de0060e7b34a2f8732f8196e29_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M=F_1\\cdot d\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"85\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p> \u015eimdi problemdeki verileri form\u00fclde yerine koyuyoruz ve kuvvet \u00e7iftinin momentini hesapl\u0131yoruz: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-182ab8e1f2285ae7ad03cc6311d67b61_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M=16\\cdot 3=48 \\ Nm\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"161\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Propiedades-del-par-de-fuerzas\"><\/span> Tork \u00f6zelliklerini zorla<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Genel olarak kuvvet \u00e7iftleri a\u015fa\u011f\u0131daki \u00f6zelliklere sahiptir:<\/p>\n<ul>\n<li> Sistemdeki kuvvetlerin y\u00f6n\u00fcne g\u00f6re birka\u00e7 kuvvet aktar\u0131labilir ve yaratt\u0131\u011f\u0131 etki de\u011fi\u015fmez.<\/li>\n<li> \u00dcretilen etki ayn\u0131 olaca\u011f\u0131ndan, bir \u00e7ift kuvveti ba\u015fka bir paralel d\u00fczleme de aktarabilirsiniz.<\/li>\n<li> Kat\u0131 cisim orta nokta etraf\u0131nda d\u00f6nerken, bir \u00e7ift kuvvet, ayn\u0131 momenti \u00fcreten tek bir e\u015fde\u011fer kuvvete d\u00f6n\u00fc\u015ft\u00fcr\u00fclebilir.<\/li>\n<li> Matematiksel olarak, birka\u00e7 kuvvetin yerini, farkl\u0131 b\u00fcy\u00fckl\u00fckteki kuvvetlere ve farkl\u0131 uzunlukta bir kola sahip e\u015fde\u011fer bir sistem alabilir; bu, \u00fcretilen kuvvetin momentini korumak i\u00e7in yeterlidir.<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Bu makalede kuvvet \u00e7iftlerinin ne oldu\u011fu ve kuvvet \u00e7iftlerinin momentinin nas\u0131l hesaplanaca\u011f\u0131 a\u00e7\u0131klanmaktad\u0131r. Ek olarak torkun \u00f6zelliklerini ve hesaplaman\u0131n nas\u0131l yap\u0131laca\u011f\u0131na dair somut bir \u00f6rnek bulacaks\u0131n\u0131z. G\u00fc\u00e7l\u00fc \u00e7ift nedir? Kuvvet \u00e7ifti, ayn\u0131 b\u00fcy\u00fckl\u00fckte fakat z\u0131t y\u00f6nlerde iki paralel kuvvetin olu\u015fturdu\u011fu bir sistemdir. Ek olarak, birka\u00e7 kuvvetin kuvvetleri bir cisim \u00fczerinde d\u00f6nme hareketi \u00fcretir. \u00d6rne\u011fin bir &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/tr\/cift\/\"> <span class=\"screen-reader-text\">\u00c7ift<\/span> Devam\u0131 &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-18","post","type-post","status-publish","format-standard","hentry","category-dinamik"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.3 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 Kuvvet \u00e7ifti nedir? 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