{"id":418,"date":"2023-06-18T22:56:38","date_gmt":"2023-06-18T22:56:38","guid":{"rendered":"https:\/\/physigeek.com\/pt\/o-movimento-retilineo-acelera-uniformemente-mrua\/"},"modified":"2023-06-18T22:56:38","modified_gmt":"2023-06-18T22:56:38","slug":"o-movimento-retilineo-acelera-uniformemente-mrua","status":"publish","type":"post","link":"https:\/\/physigeek.com\/pt\/o-movimento-retilineo-acelera-uniformemente-mrua\/","title":{"rendered":"Movimento retil\u00edneo uniformemente acelerado (mrua)"},"content":{"rendered":"<p>Este artigo explica o que \u00e9 o movimento retil\u00edneo uniformemente acelerado (UNIR), tamb\u00e9m conhecido como movimento retil\u00edneo uniformemente variado (MRUV), e quais s\u00e3o suas caracter\u00edsticas. Voc\u00ea tamb\u00e9m encontrar\u00e1 todas as f\u00f3rmulas para movimento retil\u00edneo uniformemente acelerado e um exemplo concreto deste tipo de movimento. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-el-movimiento-rectilineo-uniformemente-acelerado-MRUA\"><\/span> O que \u00e9 movimento retil\u00edneo uniformemente acelerado (MRUA)?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Movimento retil\u00edneo uniformemente acelerado (MRUA)<\/strong> , ou <strong>movimento retil\u00edneo uniformemente variado (MRUV)<\/strong> , \u00e9 aquele movimento descrito por um corpo que se move em linha reta e sua acelera\u00e7\u00e3o \u00e9 constante.<\/p>\n<p> Por exemplo, um corpo em <a href=\"https:\/\/physigeek.com\/pt\/queda-livre\/\">queda livre<\/a> descreve um movimento retil\u00edneo uniformemente acelerado (MRUA). A trajet\u00f3ria de um corpo em queda livre \u00e9 uma linha reta e a acelera\u00e7\u00e3o da gravidade \u00e9 constante, portanto \u00e9 um exemplo claro de movimento retil\u00edneo uniformemente acelerado (MRUA). <\/p>\n<figure class=\"wp-block-image aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/mouvement-rectiligne-uniformement-accelere-mrua.png\" alt=\"movimento retil\u00edneo uniformemente acelerado (MRUA)\" class=\"wp-image-8014\" width=\"620\" height=\"395\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/mouvement-rectiligne-uniformement-accelere-mrua-300x191.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/mouvement-rectiligne-uniformement-accelere-mrua-1024x652.png 1024w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/mouvement-rectiligne-uniformement-accelere-mrua-768x489.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/mouvement-rectiligne-uniformement-accelere-mrua.png 1039w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<div style=\"background-color:#FFFDE7; padding-top: 10px; padding-bottom: 10px; padding-right: 10px; padding-left: 20px; border: 2.5px dashed #FFB74D; border-radius:20px;\"> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Veja:<\/strong> <a href=\"https:\/\/physigeek.com\/pt\/aceleracao-fisica\/\">Acelera\u00e7\u00e3o (f\u00edsica)<\/a> <\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Caracteristicas-del-movimiento-rectilineo-uniformemente-acelerado-MRUA\"><\/span> Caracter\u00edsticas do movimento retil\u00edneo uniformemente acelerado (MRUA)<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Depois de vermos a defini\u00e7\u00e3o de movimento retil\u00edneo uniformemente acelerado (MRUA) na f\u00edsica, veremos quais s\u00e3o as caracter\u00edsticas desse tipo de movimento.<\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:20px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>A principal caracter\u00edstica do movimento retil\u00edneo uniformemente acelerado (MRUA)<\/strong> \u00e9 que a acelera\u00e7\u00e3o do corpo \u00e9 constante durante todo o movimento.<\/span><\/li>\n<li style=\"margin-bottom:20px\"> <span style=\"color:#101010;font-weight: normal;\">Outra caracter\u00edstica do movimento retil\u00edneo uniformemente acelerado \u00e9 que a trajet\u00f3ria do corpo em movimento \u00e9 uma linha reta.<\/span><\/li>\n<li style=\"margin-bottom:20px\"> <span style=\"color:#101010;font-weight: normal;\">Como a acelera\u00e7\u00e3o do movimento retil\u00edneo uniformemente acelerado \u00e9 constante, isso significa que a velocidade neste tipo de movimento varia uniformemente. Ou seja, a velocidade aumenta ou diminui seu valor em fun\u00e7\u00e3o do tempo de forma linear.<\/span><\/li>\n<li style=\"margin-bottom:20px\"> <span style=\"color:#101010;font-weight: normal;\">Al\u00e9m disso, a acelera\u00e7\u00e3o centr\u00edpeta (ou acelera\u00e7\u00e3o normal) de movimentos retil\u00edneos uniformemente acelerados \u00e9 sempre zero, uma vez que a trajet\u00f3ria n\u00e3o muda de dire\u00e7\u00e3o.<\/span> <\/li>\n<\/ul>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Formulas-del-movimiento-rectilineo-uniformemente-acelerado-MRUA\"><\/span> F\u00f3rmulas para movimento retil\u00edneo uniformemente acelerado (MRUA)<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> A seguir veremos quais s\u00e3o as f\u00f3rmulas para o movimento retil\u00edneo uniformemente acelerado (MRUA), tamb\u00e9m conhecido como movimento retil\u00edneo uniformemente variado (MRUV). Estas f\u00f3rmulas permitir\u00e3o resolver problemas deste tipo de movimentos retil\u00edneos.<\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Posicion\"><\/span> Posi\u00e7\u00e3o<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p> No movimento retil\u00edneo uniformemente acelerado (MRUA), a posi\u00e7\u00e3o de um corpo \u00e9 igual \u00e0 posi\u00e7\u00e3o inicial (x <sub>0<\/sub> ) mais o produto da velocidade inicial (v <sub>0<\/sub> ) vezes o tempo decorrido (\u0394t) mais metade da acelera\u00e7\u00e3o (a) pelo quadrado do tempo decorrido (x=x <sub>0<\/sub> +v <sub>0<\/sub> \u00b7\u0394t+a\u00b7\u0394t <sup>2<\/sup> \/2).<\/p>\n<p> Assim, a <strong>f\u00f3rmula para calcular a posi\u00e7\u00e3o do corpo que descreve o movimento retil\u00edneo uniformemente acelerado (MRUA)<\/strong> \u00e9:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-12ff67c6c64f8517159c4c2274aa980e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x=x_0+v_0\\cdot (t-t_0) +\\cfrac{1}{2}\\cdot a \\cdot (t-t_0)^2\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"289\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p style=\"margin-bottom:5px\"> Ouro: <\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7e5fbfa0bbbd9f3051cd156a0f1b5e31_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"10\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a posi\u00e7\u00e3o do corpo que segue um movimento retil\u00edneo uniformemente acelerado. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e6e1c3611728e9db0e52bb6485e06068_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x_0\" title=\"Rendered by QuickLaTeX.com\" height=\"11\" width=\"17\" style=\"vertical-align: -3px;\"><\/p>\n<p> \u00e9 a posi\u00e7\u00e3o inicial do corpo. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-033c1c43e83708a4a975dedd88f197a8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"v_0\" title=\"Rendered by QuickLaTeX.com\" height=\"11\" width=\"16\" style=\"vertical-align: -3px;\"><\/p>\n<p> \u00e9 a velocidade inicial do corpo. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fd9cb27edab3f0a8a249bc80cc9c6ee2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"t\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"6\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 o instante de tempo durante o qual a posi\u00e7\u00e3o do corpo \u00e9 calculada. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c1a3f4a217f20d31e6f72a2f42a2e7dd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"t_0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"13\" style=\"vertical-align: -3px;\"><\/p>\n<p> \u00e9 o momento inicial. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0e55b0b3943237ccfc96979505679274_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"9\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a acelera\u00e7\u00e3o do corpo.<\/span><\/li>\n<\/ul>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Velocidad\"><\/span> Velocidade<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p> No movimento retil\u00edneo uniformemente acelerado, a velocidade varia uniformemente com o tempo. Assim, a velocidade num instante (v) \u00e9 igual \u00e0 velocidade inicial (v <sub>0<\/sub> ) mais a acelera\u00e7\u00e3o do corpo (a) multiplicada pelo tempo decorrido (\u0394t). Portanto, a f\u00f3rmula da velocidade \u00e9 v=v <sub>0<\/sub> + a\u00b7\u0394t.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-56736742d1dc1fd0e737eca12cafe6b2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"v=v_0+a\\cdot (t-t_0)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"148\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p style=\"margin-bottom:5px\"> Ouro: <\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-796872219106704832bd95ce08640b7b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"v\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"9\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a velocidade do corpo em um determinado momento. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-033c1c43e83708a4a975dedd88f197a8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"v_0\" title=\"Rendered by QuickLaTeX.com\" height=\"11\" width=\"16\" style=\"vertical-align: -3px;\"><\/p>\n<p> \u00e9 a velocidade inicial do corpo. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0e55b0b3943237ccfc96979505679274_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"9\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a acelera\u00e7\u00e3o do corpo. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fd9cb27edab3f0a8a249bc80cc9c6ee2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"t\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"6\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 o instante de tempo durante o qual a velocidade do corpo \u00e9 calculada. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c1a3f4a217f20d31e6f72a2f42a2e7dd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"t_0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"13\" style=\"vertical-align: -3px;\"><\/p>\n<p> \u00e9 o momento inicial.<\/span><\/li>\n<\/ul>\n<p> Por outro lado, existe tamb\u00e9m outra f\u00f3rmula que relaciona a velocidade com a posi\u00e7\u00e3o e acelera\u00e7\u00e3o do corpo. Al\u00e9m disso, esta f\u00f3rmula tem a vantagem de n\u00e3o aparecer o tempo, pelo que pode ser \u00fatil na resolu\u00e7\u00e3o de determinados problemas.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-97aae78a0f54fd24e0b526dab1074fc8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"v^2=v_0^2+2\\cdot \u00e0 \\cdot (x-x_0)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"185\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p style=\"margin-bottom:5px\"> Ouro: <\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-796872219106704832bd95ce08640b7b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"v\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"9\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a velocidade do corpo. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-033c1c43e83708a4a975dedd88f197a8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"v_0\" title=\"Rendered by QuickLaTeX.com\" height=\"11\" width=\"16\" style=\"vertical-align: -3px;\"><\/p>\n<p> \u00e9 a velocidade inicial do corpo. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0e55b0b3943237ccfc96979505679274_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"9\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a acelera\u00e7\u00e3o do corpo. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7e5fbfa0bbbd9f3051cd156a0f1b5e31_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"10\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a posi\u00e7\u00e3o do corpo no momento em que a velocidade \u00e9 calculada. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e6e1c3611728e9db0e52bb6485e06068_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x_0\" title=\"Rendered by QuickLaTeX.com\" height=\"11\" width=\"17\" style=\"vertical-align: -3px;\"><\/p>\n<p> \u00e9 a posi\u00e7\u00e3o inicial do corpo.<\/span><\/li>\n<\/ul>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Aceleracion\"><\/span> Acelera\u00e7\u00e3o<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p> No movimento retil\u00edneo uniformemente acelerado (MRUA), a acelera\u00e7\u00e3o \u00e9 constante. Portanto, a acelera\u00e7\u00e3o \u00e9 calculada dividindo a mudan\u00e7a na velocidade (\u0394v) pela mudan\u00e7a no tempo (\u0394t). Portanto, a f\u00f3rmula da acelera\u00e7\u00e3o \u00e9 a=\u0394v\/\u0394t.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-2f2c6987b1994109ed1e24980e9b0bae_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a=\\cfrac{\\Delta v}{\\Delta t}=\\cfrac{v_f-v_i}{t_f-t_i}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"139\" style=\"vertical-align: -18px;\"><\/p>\n<\/p>\n<p style=\"margin-bottom:5px\"> Ouro: <\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0e55b0b3943237ccfc96979505679274_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"9\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a acelera\u00e7\u00e3o. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-94ac7e028a0584ad0183447f9c0fe2f9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\Delta v\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"24\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 o aumento da velocidade. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-819ab50990df5adf82bea9dfa75ffff2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\Delta t\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"21\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 um incremento de tempo. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-5d8e0d73e36f7ffd98c73baf4bec8be0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"v_f\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"17\" style=\"vertical-align: -6px;\"><\/p>\n<p> \u00e9 a velocidade final. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c9928f5e418ac3466349509fd03bdead_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"v_i\" title=\"Rendered by QuickLaTeX.com\" height=\"11\" width=\"14\" style=\"vertical-align: -3px;\"><\/p>\n<p> \u00e9 a velocidade inicial. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-82d36af17e232807e56da9ccdbbda0d8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"t_f\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"14\" style=\"vertical-align: -6px;\"><\/p>\n<p> \u00e9 o momento final. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-bf289b768173104db12fe7044c723db4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"t_i\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"11\" style=\"vertical-align: -3px;\"><\/p>\n<p> \u00e9 o momento inicial. <\/span><\/li>\n<\/ul>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Resumen-de-las-formulas-del-movimiento-rectilineo-uniformemente-acelerado-MRUA\"><\/span> Resumo das f\u00f3rmulas para movimento retil\u00edneo uniformemente acelerado (MRUA)<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p> Em resumo, deixamos abaixo uma tabela com todas as f\u00f3rmulas para movimento retil\u00edneo uniformemente acelerado (MRUA). <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/formules-mrua-a-mouvement-rectiligne-et-uniformement-accelere.png\" alt=\"movimento retil\u00edneo uniformemente acelerado (MRUA)\" class=\"wp-image-8033\" width=\"480\" height=\"330\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/formules-mrua-a-mouvement-rectiligne-et-uniformement-accelere-300x206.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/formules-mrua-a-mouvement-rectiligne-et-uniformement-accelere-768x527.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/formules-mrua-a-mouvement-rectiligne-et-uniformement-accelere.png 910w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicio-resuelto-del-movimiento-rectilineo-uniformemente-acelerado-MRUA\"><\/span> Exerc\u00edcio resolvido sobre movimento retil\u00edneo uniformemente acelerado (MRUA)<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<ul>\n<li> Um corpo que descreve um movimento retil\u00edneo uniformemente acelerado parte de uma velocidade inicial v <sub>0<\/sub> = 2 m\/s e de uma posi\u00e7\u00e3o inicial x <sub>0<\/sub> = 5 m. Se sabemos que ap\u00f3s 6 segundos sua velocidade \u00e9 de 11 m\/s, vamos calcular:\n<ol>\n<li> Acelera\u00e7\u00e3o do corpo.<\/li>\n<li> Posi\u00e7\u00e3o do corpo ap\u00f3s 6 segundos.<\/li>\n<\/ol>\n<\/li>\n<\/ul>\n<p> Neste caso, sabemos a velocidade final, a velocidade inicial e o intervalo de tempo decorrido, portanto podemos usar diretamente a f\u00f3rmula da acelera\u00e7\u00e3o para encontrar o seu valor:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-28204241c20bef26606f19bb83ab36e8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{aligned}a&amp;=\\cfrac{\\Delta v}{\\Delta t}\\\\[2ex]a&amp;=\\cfrac{v_f-v_i}{t_f-t_i}\\\\[2ex]a&amp;=\\cfrac {11-2}{6-0}\\\\[2ex]a&amp;=1.5 \\ \\cfrac{m}{s^2}\\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"234\" width=\"89\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> E uma vez conhecido o valor da acelera\u00e7\u00e3o, podemos determinar a posi\u00e7\u00e3o do corpo no tempo t=6 s aplicando a f\u00f3rmula da posi\u00e7\u00e3o: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fba7fbb044a6ca0d323d29e7d9762c0f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{aligned}x&amp;=x_0+v_0\\cdot (t-t_0) +\\cfrac{1}{2}\\cdot a \\cdot (t-t_0)^2\\\\[2ex]x&amp;=5+ 2\\cdot (6-0)+\\cfrac{1}{2}\\cdot 1.5\\cdot (6-0)^2\\\\[2ex]x&amp;=5+12+27 \\\\[2ex]x&amp;= 44\\ m\\end{align\u00e9}\" title=\"Rendered by QuickLaTeX.com\" height=\"180\" width=\"289\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Movimiento-rectilineo-uniformemente-acelerado-y-movimiento-rectilineo-uniforme\"><\/span> Movimento retil\u00edneo uniformemente acelerado e movimento retil\u00edneo uniforme<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Nesta se\u00e7\u00e3o, veremos a diferen\u00e7a entre movimento retil\u00edneo uniforme e movimento retil\u00edneo uniformemente acelerado, uma vez que estes s\u00e3o dois tipos de movimento retil\u00edneo amplamente utilizados na f\u00edsica.<\/p>\n<p> <strong>O movimento retil\u00edneo uniforme (MRU)<\/strong> , tamb\u00e9m chamado de movimento retil\u00edneo constante (MRC), \u00e9 aquele movimento que descreve um corpo que se move em linha reta e cuja velocidade \u00e9 constante.<\/p>\n<p> Portanto, a <strong>diferen\u00e7a entre o movimento retil\u00edneo uniformemente acelerado (MRUA) e o movimento retil\u00edneo uniforme (MRU)<\/strong> \u00e9 a quantidade que \u00e9 constante. No MRU, a acelera\u00e7\u00e3o \u00e9 constante, enquanto no MRU a velocidade \u00e9 constante. <\/p>\n<div style=\"background-color:#FFFDE7; padding-top: 10px; padding-bottom: 10px; padding-right: 10px; padding-left: 20px; border: 2.5px dashed #FFB74D; border-radius:20px;\"> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Veja:<\/strong> <a href=\"https:\/\/physigeek.com\/pt\/movimento-retilineo-uniforme-mru\/\">Caracter\u00edsticas do movimento retil\u00edneo uniforme (MRU)<\/a> <\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Movimiento-rectilineo-uniformemente-acelerado-y-movimiento-circular-uniformemente-acelerado\"><\/span> Movimento retil\u00edneo uniformemente acelerado e movimento circular uniformemente acelerado<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Finalmente, veremos qual \u00e9 a diferen\u00e7a entre o movimento retil\u00edneo uniformemente acelerado e o movimento circular uniformemente acelerado.<\/p>\n<p> <strong>O movimento circular uniformemente acelerado (MCUA)<\/strong> , tamb\u00e9m chamado de movimento circular uniformemente variado (MCUV), \u00e9 um movimento que descreve um corpo em movimento que gira em torno de um eixo com acelera\u00e7\u00e3o angular constante.<\/p>\n<p> Portanto, a <strong>diferen\u00e7a entre o movimento retil\u00edneo uniformemente acelerado (MRUA) e o movimento circular uniformemente acelerado (MCUA)<\/strong> \u00e9 que a trajet\u00f3ria e a amplitude s\u00e3o constantes. Num MRUA a trajet\u00f3ria \u00e9 reta e a acelera\u00e7\u00e3o \u00e9 constante, por outro lado num MCUA a trajet\u00f3ria \u00e9 circular e a acelera\u00e7\u00e3o angular \u00e9 constante. <\/p>\n<div style=\"background-color:#FFFDE7; padding-top: 10px; padding-bottom: 10px; padding-right: 10px; padding-left: 20px; border: 2.5px dashed #FFB74D; border-radius:20px;\"> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Veja:<\/strong> <a href=\"https:\/\/physigeek.com\/pt\/movimento-circular-acelera-uniformemente-mcua\/\">Caracter\u00edsticas do movimento circular uniformemente acelerado (MCUA)<\/a><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Este artigo explica o que \u00e9 o movimento retil\u00edneo uniformemente acelerado (UNIR), tamb\u00e9m conhecido como movimento retil\u00edneo uniformemente variado (MRUV), e quais s\u00e3o suas caracter\u00edsticas. Voc\u00ea tamb\u00e9m encontrar\u00e1 todas as f\u00f3rmulas para movimento retil\u00edneo uniformemente acelerado e um exemplo concreto deste tipo de movimento. O que \u00e9 movimento retil\u00edneo uniformemente acelerado (MRUA)? Movimento retil\u00edneo uniformemente &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/pt\/o-movimento-retilineo-acelera-uniformemente-mrua\/\"> <span class=\"screen-reader-text\">Movimento retil\u00edneo uniformemente acelerado (mrua)<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[3],"tags":[],"class_list":["post-418","post","type-post","status-publish","format-standard","hentry","category-cinematografico"],"yoast_head":"<!-- This site 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