{"id":39,"date":"2023-06-26T23:01:22","date_gmt":"2023-06-26T23:01:22","guid":{"rendered":"https:\/\/physigeek.com\/pt\/primeira-lei-de-newton-lei-da-inercia\/"},"modified":"2023-06-26T23:01:22","modified_gmt":"2023-06-26T23:01:22","slug":"primeira-lei-de-newton-lei-da-inercia","status":"publish","type":"post","link":"https:\/\/physigeek.com\/pt\/primeira-lei-de-newton-lei-da-inercia\/","title":{"rendered":"Primeira lei de newton (lei da in\u00e9rcia)"},"content":{"rendered":"<p>Este artigo explica o que diz a primeira lei de Newton, tamb\u00e9m conhecida como lei da in\u00e9rcia. Al\u00e9m da afirma\u00e7\u00e3o da primeira lei de Newton, voc\u00ea ver\u00e1 exemplos desta lei e sua f\u00f3rmula matem\u00e1tica. Finalmente, voc\u00ea poder\u00e1 praticar exerc\u00edcios resolvidos passo a passo da primeira lei de Newton. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFCual-es-la-primera-ley-de-Newton\"><\/span> Qual \u00e9 a primeira lei de Newton?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>A declara\u00e7\u00e3o da primeira lei de Newton<\/strong> , tamb\u00e9m chamada de lei da in\u00e9rcia, afirma o seguinte: <\/p>\n<div style=\"background:linear-gradient(to bottom, #FFFFFF 0%, #E1F5FE 100%);  padding-right: 27px; padding-left: 30px; padding-top: 23px; padding-bottom: 0.5px; border: 2px dashed #4FC3F7; border-radius:25px;\">\n<p> Um corpo permanece em repouso ou com velocidade constante se nenhuma for\u00e7a externa atuar sobre ele. Em outras palavras, uma for\u00e7a deve ser aplicada a um corpo para alterar seu estado de movimento ou repouso.<\/p>\n<\/div>\n<p> Por exemplo, um objeto em repouso no solo n\u00e3o se mover\u00e1 at\u00e9 que uma for\u00e7a atue sobre ele.<\/p>\n<p> Portanto, a primeira lei de Newton implica que se um corpo se move em movimento retil\u00edneo uniforme, significa que nenhuma for\u00e7a externa atua sobre ele ou que a for\u00e7a resultante de todo o sistema \u00e9 zero.<\/p>\n<p> No total existem tr\u00eas leis de Newton, aquela que acabamos de ver que tamb\u00e9m \u00e9 chamada de princ\u00edpio da in\u00e9rcia, a segunda lei ou princ\u00edpio fundamental da din\u00e2mica e a terceira lei ou princ\u00edpio de a\u00e7\u00e3o e rea\u00e7\u00e3o.<\/p>\n<p> Logicamente, as tr\u00eas leis recebem o nome do f\u00edsico Isaac Newton porque ele foi o primeiro a explic\u00e1-las em sua obra <em>Princ\u00edpios Matem\u00e1ticos da Filosofia Natural<\/em> . Esta publica\u00e7\u00e3o \u00e9 considerada um dos pilares da f\u00edsica. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejemplos-de-la-primera-ley-de-Newton\"><\/span> Exemplos da Primeira Lei de Newton<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Considerando a defini\u00e7\u00e3o da primeira lei de Newton (ou lei da in\u00e9rcia), analisaremos a seguir v\u00e1rios exemplos desta regra.<\/p>\n<ol style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:25px\"> <span style=\"color:#101010;font-weight: normal;\">Um exemplo claro da primeira lei de Newton \u00e9 um sof\u00e1 apoiado no ch\u00e3o. Se nenhuma for\u00e7a for exercida sobre o sof\u00e1, ele n\u00e3o se mover\u00e1 e permanecer\u00e1 parado. Mas se o sof\u00e1 for empurrado com uma for\u00e7a suficientemente grande, o sof\u00e1 adquirir\u00e1 velocidade e, portanto, mudar\u00e1 o seu estado de movimento.<\/span><\/li>\n<li style=\"margin-bottom:25px\"> <span style=\"color:#101010;font-weight: normal;\">Outro exemplo da primeira lei de Newton \u00e9 a de uma sonda espacial movendo-se a uma velocidade constante atrav\u00e9s do espa\u00e7o. Uma vez superada a influ\u00eancia gravitacional dos planetas, n\u00e3o h\u00e1 atrito ou qualquer outra for\u00e7a no espa\u00e7o. Portanto, uma sonda espacial se move a uma velocidade constante atrav\u00e9s do espa\u00e7o porque n\u00e3o h\u00e1 for\u00e7a atuando sobre ela.<\/span><\/li>\n<li> <span style=\"color:#101010;font-weight: normal;\">Um carro movendo-se com velocidade constante tamb\u00e9m \u00e9 um exemplo da primeira lei de Newton (ou lei da in\u00e9rcia), pois para se mover sem acelera\u00e7\u00e3o a for\u00e7a resultante deve ser zero. Quando o carro avan\u00e7a, uma for\u00e7a de atrito atua sobre ele contra o movimento; portanto, para se mover a uma velocidade constante, o motor do carro deve exercer uma for\u00e7a de mesma magnitude e dire\u00e7\u00e3o, mas na dire\u00e7\u00e3o oposta. Desta forma, as duas for\u00e7as se op\u00f5em e o carro se move na mesma velocidade.<\/span> <\/li>\n<\/ol>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Formula-de-la-primera-ley-de-Newton\"><\/span> Primeira f\u00f3rmula da lei de Newton<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Para aprofundar o conceito da primeira lei de Newton, nesta se\u00e7\u00e3o veremos a f\u00f3rmula com a qual essa lei pode ser expressa.<\/p>\n<p> Matematicamente, a <strong>f\u00f3rmula da primeira lei de Newton<\/strong> afirma que se a soma das for\u00e7as de um sistema for zero, a acelera\u00e7\u00e3o desse sistema tamb\u00e9m ser\u00e1 zero. O oposto tamb\u00e9m \u00e9 verdade.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-798449d310a6591fae0659a9d9319bc8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\sum F=0 \\ \\Leftrightarrow \\ \\frac{dv}{dt}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"36\" width=\"169\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Da mesma forma, se a soma das for\u00e7as for zero, isso implica que o momento (ou momento linear) \u00e9 constante.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-94c8a25629b1104e0690373d70fa9a4c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle \\sum \\vv{F}=0 \\ \\Leftrightarrow \\ \\vv{p}=\\text{constant}\" title=\"Rendered by QuickLaTeX.com\" height=\"25\" width=\"212\" style=\"vertical-align: -8px;\"><\/p>\n<\/p>\n<p> Em qualquer caso, estas express\u00f5es servem apenas para expressar a lei atrav\u00e9s da \u00e1lgebra. O importante \u00e9 que voc\u00ea entenda o significado da primeira lei de Newton e que a soma de todas as for\u00e7as deve ser zero para que ela seja verdadeira. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicios-resueltos-de-la-primera-ley-de-Newton\"><\/span> Exerc\u00edcios resolvidos da primeira lei de Newton<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 1<\/h3>\n<p> Quanta for\u00e7a um elevador deve exercer para levantar um objeto de 7 kg? <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> A primeira coisa que precisamos fazer para resolver este problema \u00e9 calcular a for\u00e7a da gravidade que a Terra exerce sobre o objeto. Para fazer isso, usamos a f\u00f3rmula da for\u00e7a peso:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0180c5a990cc4c86131732dc83b2e98b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=m\\cdot g=7\\cdot 9,81=68,67 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"244\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Assim, de acordo com a primeira lei de Newton, se o elevador exercer uma for\u00e7a vertical de 68,67 N para cima, o objeto permanecer\u00e1 estacion\u00e1rio, pois a for\u00e7a resultante ser\u00e1 zero. O elevador deve, portanto, exercer uma for\u00e7a superior a 68,67 N para poder come\u00e7ar a subir.<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 2<\/h3>\n<p> Um elevador levanta um corpo cuja massa \u00e9 100 kg. A qualquer momento, a for\u00e7a de atrito que se op\u00f5e ao movimento \u00e9 de 300 N e a for\u00e7a ascendente exercida pelo cabo \u00e9 de 1100 N. O elevador est\u00e1 acelerando, desacelerando ou movendo-se a uma velocidade constante? <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Primeiro, calculamos a for\u00e7a gravitacional que a Terra exerce sobre o corpo com a f\u00f3rmula do peso:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-8967bd64872be26930c9d96806eb907b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=m\\cdot g=100\\cdot 9,81=981 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"245\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Portanto, a soma total de todas as for\u00e7as que puxam o elevador para baixo \u00e9:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-590875c04c7d7898b42966b5f4c2b6fa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{\\text{down}}=300+981=1281 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"223\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Por outro lado, a \u00fanica for\u00e7a que empurra o elevador para cima \u00e9 a do cabo.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-942d287388bd1536af62f73fdda4c356_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{\\text{up}}=1100 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"109\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Portanto, a soma das for\u00e7as descendentes \u00e9 maior que as for\u00e7as ascendentes, de modo que o elevador desacelera nesse ponto. <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-8fa755aed0a89cc4ba13df28bc54056f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{\\text{down}}>F_{\\text{up}} \\ \\longrightarrow \\ \\text{freins d&#8217;ascenseur}&#8221; title=&#8221;Rendered by QuickLaTeX.com&#8221; height=&#8221;19&#8243; width=&#8221;282&#8243; style=&#8221;vertical-align: -6px;&#8221;><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 3<\/h3>\n<p> Uma caixa de massa 60 kg \u00e9 arrastada por uma corda que forma um \u00e2ngulo de 30\u00ba com o solo. Se uma for\u00e7a de 120 N \u00e9 necess\u00e1ria sobre a corda para mover a caixa com uma velocidade constante de 10 m\/s, qual \u00e9 o valor aproximado do coeficiente de atrito cin\u00e9tico entre a caixa e o solo? <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-de-la-premiere-loi-de-newton.png\" alt=\"primeiro problema da lei de Newton\" class=\"wp-image-683\" width=\"310\" height=\"148\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-de-la-premiere-loi-de-newton-300x143.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-de-la-premiere-loi-de-newton.png 716w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Como conhecemos o \u00e2ngulo de inclina\u00e7\u00e3o da for\u00e7a aplicada, podemos dividi-lo em uma for\u00e7a vertical e uma for\u00e7a horizontal usando raz\u00f5es trigonom\u00e9tricas:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-ca8b091dde12db0c8ca49c760300a2c3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_x=120\\cdot \\text{cos}(30\u00ba)=103,92 \\N \" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"213\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-25f281fa8a4950c719d8c437d43a2ad0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_y=120\\cdot \\text{sin}(30\u00ba)=60 \\N \" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"177\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Por outro lado, calculamos a for\u00e7a do peso que a Terra exerce sobre a caixa:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-ea67ee8904c4125d742b69e19d73888f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=m\\cdot g=60\\cdot 9,81=588,6 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"252\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> O diagrama de corpo livre do sistema \u00e9, portanto: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-de-la-premiere-loi-de-newton.png\" alt=\"exerc\u00edcio resolvido da primeira lei de Newton\" class=\"wp-image-685\" width=\"380\" height=\"330\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-de-la-premiere-loi-de-newton-300x260.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-de-la-premiere-loi-de-newton-768x667.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-de-la-premiere-loi-de-newton.png 858w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Tenha em mente que as for\u00e7as F <sub>x<\/sub> e F <sub>y<\/sub> mostradas s\u00e3o apenas a decomposi\u00e7\u00e3o da for\u00e7a de 120 N, portanto n\u00e3o atuam ao mesmo tempo, mas sim as duas for\u00e7as est\u00e3o substituindo a for\u00e7a de 120 N.<\/p>\n<p class=\"has-text-align-left\"> Como a caixa se move a uma velocidade constante, isso implica que est\u00e1 em equil\u00edbrio, pelo que podemos aplicar as condi\u00e7\u00f5es de equil\u00edbrio para resolver o exerc\u00edcio. Primeiro estabelecemos a equa\u00e7\u00e3o do equil\u00edbrio vertical para encontrar a for\u00e7a normal: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-cd141ea5ead6fddb72cef9f8fa7be69c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\somme F_y=0\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"52\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-8778dea9c0051935e9aaab0bac3ab68e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N+F_y-P=0\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"125\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-9dec190f1ff4a2bf5b073f5b169fe9c2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N=P-F_y\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"93\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6edfe781d454d3447d884e9cb3e6a6cc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N=588,6-60=528,6 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"211\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E finalmente notamos a equa\u00e7\u00e3o de equil\u00edbrio horizontal para determinar o coeficiente de atrito: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7bef12fab7ed21c7cc3b72174bdc17bd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\somme F_x=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"53\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fd006c9e3285f25e269d157af62c00b8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_x-F_{\\mu}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"95\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-4b7147d63bcf72d9f1d064a05c7605c4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_x-\\mu N=0\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"101\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d6478e911a77318f792371cce1fbbcae_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"103,92-\\mu \\cdot 528,6=0\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"172\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-44bb5b569ee86f7c867ab1d7f85394a5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"103,92=\\mu \\cdot 528,6\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"142\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7c066cd7c93e1f6b0e18f76b15dd676f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\mu=\\cfrac{103,92}{528,6}=0,20\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"147\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Este artigo explica o que diz a primeira lei de Newton, tamb\u00e9m conhecida como lei da in\u00e9rcia. Al\u00e9m da afirma\u00e7\u00e3o da primeira lei de Newton, voc\u00ea ver\u00e1 exemplos desta lei e sua f\u00f3rmula matem\u00e1tica. Finalmente, voc\u00ea poder\u00e1 praticar exerc\u00edcios resolvidos passo a passo da primeira lei de Newton. Qual \u00e9 a primeira lei de Newton? &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/pt\/primeira-lei-de-newton-lei-da-inercia\/\"> <span class=\"screen-reader-text\">Primeira lei de newton (lei da in\u00e9rcia)<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-39","post","type-post","status-publish","format-standard","hentry","category-dinamico"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 Primeira lei de Newton: afirma\u00e7\u00e3o, exemplos e exerc\u00edcios<\/title>\n<meta name=\"description\" content=\"O que diz a primeira lei de Newton (ou lei da in\u00e9rcia)? Enunciado, f\u00f3rmula, exemplos reais e exerc\u00edcios resolvidos da primeira lei de Newton.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/physigeek.com\/pt\/primeira-lei-de-newton-lei-da-inercia\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u25b7 Primeira lei de Newton: afirma\u00e7\u00e3o, exemplos e exerc\u00edcios\" \/>\n<meta property=\"og:description\" content=\"O que diz a primeira lei de Newton (ou lei da in\u00e9rcia)? 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