{"id":33,"date":"2023-06-27T03:01:24","date_gmt":"2023-06-27T03:01:24","guid":{"rendered":"https:\/\/physigeek.com\/pt\/forca-de-equilibrio\/"},"modified":"2023-06-27T03:01:24","modified_gmt":"2023-06-27T03:01:24","slug":"forca-de-equilibrio","status":"publish","type":"post","link":"https:\/\/physigeek.com\/pt\/forca-de-equilibrio\/","title":{"rendered":"For\u00e7a de equil\u00edbrio"},"content":{"rendered":"<p>Este artigo explica o que \u00e9 a for\u00e7a de equil\u00edbrio e como ela \u00e9 calculada. Al\u00e9m disso, voc\u00ea poder\u00e1 praticar exerc\u00edcios de for\u00e7a de equil\u00edbrio resolvidos. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-la-fuerza-equilibrante\"><\/span> Qual \u00e9 a for\u00e7a de equil\u00edbrio?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>For\u00e7a de equil\u00edbrio<\/strong> \u00e9 a for\u00e7a que neutraliza o efeito de todas as for\u00e7as de um sistema, ou seja, for\u00e7a de equil\u00edbrio \u00e9 a for\u00e7a capaz de equilibrar um sistema de for\u00e7as.<\/p>\n<p> Portanto, a for\u00e7a de equil\u00edbrio de um sistema tem a mesma magnitude, dire\u00e7\u00e3o e dire\u00e7\u00e3o oposta \u00e0 for\u00e7a resultante.<\/p>\n<p> Al\u00e9m disso, a for\u00e7a de equil\u00edbrio faz com que a soma de todas as for\u00e7as num sistema seja zero e, portanto, o sistema esteja em equil\u00edbrio.<\/p>\n<p> Por exemplo, a for\u00e7a normal \u00e9 a for\u00e7a que equilibra a for\u00e7a do peso, porque neutraliza o seu efeito e permite que um corpo se apoie no solo. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Como-calcular-la-fuerza-equilibrante\"><\/span> Como calcular a for\u00e7a de equil\u00edbrio<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Para calcular a for\u00e7a de equil\u00edbrio em um sistema, \u00e9 preciso primeiro encontrar a for\u00e7a resultante no sistema e depois negar seus componentes.<\/strong><\/p>\n<p> Como a for\u00e7a de equil\u00edbrio \u00e9 oposta \u00e0 for\u00e7a resultante, o processo para derivar a for\u00e7a de equil\u00edbrio \u00e9 simplesmente determinar a for\u00e7a resultante e depois alterar o sinal das suas coordenadas.<\/p>\n<p> Portanto, para encontrar a for\u00e7a de equil\u00edbrio de um sistema, \u00e9 essencial que voc\u00ea saiba como \u00e9 calculada a for\u00e7a resultante. Caso contr\u00e1rio, voc\u00ea dever\u00e1 ver a seguinte explica\u00e7\u00e3o: <\/p>\n<div style=\"background-color:#FFFDE7; padding-top: 10px; padding-bottom: 10px; padding-right: 10px; padding-left: 20px; border: 2.5px dashed #FFB74D; border-radius:20px;\"> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Veja:<\/strong> <a href=\"https:\/\/physigeek.com\/pt\/forca-resultante\/\">como calcular a for\u00e7a resultante<\/a><\/div>\n<p> Por exemplo, se a for\u00e7a resultante de um sistema for<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-56af5ee7c8addbbb008322d8d7a1b973_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{F_R}=(5,-9) \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"121\" style=\"vertical-align: -5px;\"><\/p>\n<p> , o c\u00e1lculo da for\u00e7a de equil\u00edbrio ser\u00e1:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-a0d97755676acf9aa70b81c95f2e5812_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{F_E}=-\\vv{F_R}\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"83\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-4b38f36424484cec6c3e0d03a9eaefb2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{F_E}=-(5,-9)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"113\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-ef7fc60f6acc6d952b2318ec8869e316_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{F_E}=(-5,9)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"99\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicios-resueltos-de-la-fuerza-equilibrante\"><\/span> Exerc\u00edcios de for\u00e7a de equil\u00edbrio resolvidos<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 1<\/h3>\n<p> Calcule a for\u00e7a de equil\u00edbrio das tr\u00eas for\u00e7as a seguir: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-forces-meme-direction-direction-differente.png\" alt=\"exemplo de for\u00e7as com mesma dire\u00e7\u00e3o e dire\u00e7\u00e3o diferente\" class=\"wp-image-206\" width=\"189\" height=\"150\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-forces-meme-direction-direction-differente-300x238.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-forces-meme-direction-direction-differente.png 452w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Todas as tr\u00eas for\u00e7as t\u00eam a mesma dire\u00e7\u00e3o, portanto a dire\u00e7\u00e3o da for\u00e7a resultante ser\u00e1 a mesma para essas for\u00e7as.<\/p>\n<p class=\"has-text-align-left\"> Neste exerc\u00edcio, temos duas for\u00e7as com a mesma dire\u00e7\u00e3o e dire\u00e7\u00e3o, portanto podemos som\u00e1-las diretamente. Por outro lado, temos outra for\u00e7a com a mesma dire\u00e7\u00e3o, mas com dire\u00e7\u00e3o diferente, ent\u00e3o esta for\u00e7a subtrair\u00e1 a intensidade da for\u00e7a resultante.<\/p>\n<p class=\"has-text-align-left\"> Al\u00e9m disso, o valor da soma das for\u00e7as direcionais para a direita \u00e9 maior que o valor da for\u00e7a direcional para a esquerda, portanto a for\u00e7a resultante deve ter uma dire\u00e7\u00e3o para a direita. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-de-somme-des-forces-resolues.png\" alt=\"exerc\u00edcio determinado da soma de for\u00e7as\" class=\"wp-image-208\" width=\"385\" height=\"173\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-de-somme-des-forces-resolues-300x135.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-de-somme-des-forces-resolues-768x346.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-de-somme-des-forces-resolues.png 927w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Portanto, como a for\u00e7a de equil\u00edbrio \u00e9 oposta \u00e0 for\u00e7a resultante, a for\u00e7a de equil\u00edbrio ser\u00e1 uma for\u00e7a de valor 5 N com a mesma dire\u00e7\u00e3o, mas para a esquerda.<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 2<\/h3>\n<p> Determine a for\u00e7a de equil\u00edbrio do sistema formado pelas duas for\u00e7as a seguir:<\/p>\n<ul>\n<li> For\u00e7a de 10 N com inclina\u00e7\u00e3o em rela\u00e7\u00e3o ao eixo horizontal de 45\u00ba.<\/li>\n<li> For\u00e7a de 7 N com inclina\u00e7\u00e3o em rela\u00e7\u00e3o ao eixo horizontal de 60\u00ba. <\/li>\n<\/ul>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> A defini\u00e7\u00e3o do problema nos diz que as for\u00e7as t\u00eam dire\u00e7\u00f5es diferentes, ent\u00e3o para encontrar a for\u00e7a resultante devemos primeiro decomp\u00f4-las vetorialmente usando as f\u00f3rmulas do seno e do cosseno:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d50341bac2e56c0bf8b052e5bdc69ff4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{1x}=10\\cdot \\text{cos}(45\u00ba)=7,71 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"216\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-487172781aca0e78793172956b5615d7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{1y}=10\\cdot \\text{sin}(45\u00ba)=7.71 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"211\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6f8c20f2affa0ed87fbe025c8d05be55_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{2x}=7\\cdot \\text{cos}(60\u00ba)=3,5 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"199\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fa287f252fc5fffdd78b33cc3a642485_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{2y}=7\\cdot \\text{sin}(60\u00ba)=6.06\\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"202\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E agora somamos as componentes das for\u00e7as que correspondem ao mesmo eixo:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c38ceddd5d93d2d83639cd83b5369e2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{Rx}=F_{1x}+F_{2x}=7,71+3,5=11,21 \\ N \" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"324\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-441effc100acf5a813f730815eca598c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{Ry}=F_{1y}+F_{2y}=7,71+6,06=13,77 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"331\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> A for\u00e7a resultante \u00e9 portanto:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-3050740d1257c084c15519680674e21e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{F_R}=(11.21 .13.77) \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"168\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Portanto, a for\u00e7a de equil\u00edbrio ser\u00e1: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-5d0a05a4bd596575b3da12bfaec277ab_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{F_E}=(-11.21 ,-13.77) \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"199\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 3<\/h3>\n<p> Encontre a for\u00e7a de equil\u00edbrio do seguinte sistema de for\u00e7as: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/sommes-de-forces-vectorielles.png\" alt=\"s\u00e3o for\u00e7as vetoriais\" class=\"wp-image-215\" width=\"331\" height=\"292\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/sommes-de-forces-vectorielles-300x264.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/sommes-de-forces-vectorielles.png 538w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Para obter a for\u00e7a resultante de todas as for\u00e7as vetoriais no gr\u00e1fico, precisamos aplicar o m\u00e9todo do pol\u00edgono: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/somme-des-forces-graphiquement.png\" alt=\"soma de for\u00e7as graficamente\" class=\"wp-image-216\" width=\"377\" height=\"292\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/somme-des-forces-graphiquement-300x233.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/somme-des-forces-graphiquement.png 610w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> A for\u00e7a resultante tem, portanto, as seguintes componentes:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-39e9675b94809f86add953c33ebddad9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{F_R}=(5,8)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"85\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> A for\u00e7a de equil\u00edbrio ser\u00e1, portanto, esta for\u00e7a com as mesmas componentes, mas com sinal alterado: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-2d5a91e70ece44aa0561f5af13520e94_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{F_E}=(-5,-8)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"113\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Este artigo explica o que \u00e9 a for\u00e7a de equil\u00edbrio e como ela \u00e9 calculada. Al\u00e9m disso, voc\u00ea poder\u00e1 praticar exerc\u00edcios de for\u00e7a de equil\u00edbrio resolvidos. Qual \u00e9 a for\u00e7a de equil\u00edbrio? For\u00e7a de equil\u00edbrio \u00e9 a for\u00e7a que neutraliza o efeito de todas as for\u00e7as de um sistema, ou seja, for\u00e7a de equil\u00edbrio \u00e9 &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/pt\/forca-de-equilibrio\/\"> <span class=\"screen-reader-text\">For\u00e7a de equil\u00edbrio<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-33","post","type-post","status-publish","format-standard","hentry","category-dinamico"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 For\u00e7a de equil\u00edbrio: defini\u00e7\u00e3o, c\u00e1lculo e exerc\u00edcios resolvidos<\/title>\n<meta name=\"description\" content=\"Explicamos o que \u00e9 a for\u00e7a de equil\u00edbrio e como ela \u00e9 calculada. 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