{"id":30,"date":"2023-06-27T05:31:34","date_gmt":"2023-06-27T05:31:34","guid":{"rendered":"https:\/\/physigeek.com\/pt\/balanca-mecanica\/"},"modified":"2023-06-27T05:31:34","modified_gmt":"2023-06-27T05:31:34","slug":"balanca-mecanica","status":"publish","type":"post","link":"https:\/\/physigeek.com\/pt\/balanca-mecanica\/","title":{"rendered":"Balan\u00e7a mec\u00e2nica"},"content":{"rendered":"<p>Este artigo explica o que \u00e9 equil\u00edbrio mec\u00e2nico com v\u00e1rios exemplos. Voc\u00ea tamb\u00e9m encontrar\u00e1 os diferentes tipos de equil\u00edbrio e, al\u00e9m disso, poder\u00e1 praticar com um exerc\u00edcio resolvido passo a passo. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-el-equilibrio-mecanico\"><\/span> O que \u00e9 equil\u00edbrio mec\u00e2nico?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>O equil\u00edbrio mec\u00e2nico<\/strong> \u00e9 um estado estacion\u00e1rio em que um corpo se encontra quando a soma das for\u00e7as e momentos aplicados a ele \u00e9 igual a zero.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-441bf2d412ef3319b082457d569ae4ea_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\sum\\vv{F}=0\\qquad\\sum\\vv{M}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"25\" width=\"194\" style=\"vertical-align: -8px;\"><\/p>\n<\/p>\n<p> <strong>Um sistema deve, portanto, atender a duas condi\u00e7\u00f5es para estar em equil\u00edbrio<\/strong> . A primeira condi\u00e7\u00e3o de equil\u00edbrio estabelece que a soma das for\u00e7as de cada eixo deve ser zero.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-880d0e2ca3e0dc28c37888e1cc160968_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\sum\\vv{F_x}=0\\quad\\sum\\vv{F_y}=0\\quad\\sum\\vv{F_z}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"25\" width=\"283\" style=\"vertical-align: -8px;\"><\/p>\n<\/p>\n<p> Da mesma forma, a segunda condi\u00e7\u00e3o de equil\u00edbrio diz que a soma dos momentos de cada eixo deve ser zero para que o sistema seja considerado em equil\u00edbrio.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-ecdea042f883d6816356e84c5ead485b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\sum\\vv{M_x}=0\\quad\\sum\\vv{M_y}=0\\quad\\sum\\vv{M_z}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"25\" width=\"301\" style=\"vertical-align: -8px;\"><\/p>\n<\/p>\n<p> Quando estas duas regras de equil\u00edbrio s\u00e3o respeitadas, significa que o corpo n\u00e3o tem acelera\u00e7\u00e3o linear nem angular. Portanto, o corpo est\u00e1 em repouso, movendo-se com velocidade linear constante ou girando com velocidade angular constante.<\/p>\n<p> Na f\u00edsica, quando um corpo est\u00e1 em equil\u00edbrio mec\u00e2nico, dizemos tamb\u00e9m que est\u00e1 em equil\u00edbrio translacional e rotacional ou simplesmente que est\u00e1 em equil\u00edbrio.<\/p>\n<p> Esta \u00e9 uma forma de explicar o que \u00e9 equil\u00edbrio mec\u00e2nico, a mais simples do meu ponto de vista, mas a seguir veremos outra forma de definir equil\u00edbrio mec\u00e2nico. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejemplos-de-equilibrio-mecanico\"><\/span> Exemplos de equil\u00edbrio mec\u00e2nico<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Considerando a defini\u00e7\u00e3o de balan\u00e7a mec\u00e2nica, abaixo voc\u00ea pode ver v\u00e1rios exemplos de balan\u00e7as mec\u00e2nicas para entender melhor o conceito.<\/p>\n<ol style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:25px\"> <span style=\"color:#101010;font-weight: normal;\">Um exemplo de equil\u00edbrio mec\u00e2nico \u00e9 uma l\u00e2mpada pendurada no teto. A l\u00e2mpada est\u00e1 em repouso porque a for\u00e7a que \u00e9 aplicada para apoi\u00e1-la contraria a for\u00e7a do seu peso, estando portanto numa posi\u00e7\u00e3o de equil\u00edbrio mec\u00e2nico.<\/span><\/li>\n<li style=\"margin-bottom:25px\"> <span style=\"color:#101010;font-weight: normal;\">Outro exemplo de balan\u00e7a mec\u00e2nica \u00e9 uma balan\u00e7a. Quando o bra\u00e7o de equil\u00edbrio para de girar isso significa que a soma dos momentos aplicados a ele \u00e9 zero, portanto est\u00e1 em equil\u00edbrio mec\u00e2nico.<\/span><\/li>\n<li> <span style=\"color:#101010;font-weight: normal;\">Como \u00faltimo exemplo de equil\u00edbrio mec\u00e2nico, podemos usar um carro que se move a uma velocidade constante. Se o carro estiver se movendo com velocidade constante, significa que sua acelera\u00e7\u00e3o \u00e9 zero e, portanto, a soma das for\u00e7as e momentos \u00e9 zero. Est\u00e1, portanto, em equil\u00edbrio mec\u00e2nico.<\/span> <\/li>\n<\/ol>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Tipos-de-equilibrios\"><\/span> Tipos de escalas<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Dentro da balan\u00e7a mec\u00e2nica, existem tr\u00eas tipos diferentes de equil\u00edbrio: equil\u00edbrio est\u00e1vel, equil\u00edbrio inst\u00e1vel e equil\u00edbrio indiferente.<\/p>\n<ul>\n<li> <strong>Equil\u00edbrio est\u00e1vel<\/strong> : Um corpo est\u00e1 em equil\u00edbrio est\u00e1vel quando retorna \u00e0 sua posi\u00e7\u00e3o inicial ap\u00f3s ser movido. Por exemplo, um p\u00eandulo.<\/li>\n<li> <strong>Equil\u00edbrio inst\u00e1vel<\/strong> : Um corpo est\u00e1 em equil\u00edbrio inst\u00e1vel quando n\u00e3o consegue encontrar nenhuma posi\u00e7\u00e3o de equil\u00edbrio ap\u00f3s ser empurrado para o lado por uma for\u00e7a. Por exemplo, um l\u00e1pis segurado verticalmente.<\/li>\n<li> <strong>Equil\u00edbrio indiferente<\/strong> (ou equil\u00edbrio neutro): um corpo est\u00e1 em equil\u00edbrio indiferente se, ao perder sua posi\u00e7\u00e3o de equil\u00edbrio, encontrar uma nova posi\u00e7\u00e3o de equil\u00edbrio diferente. Por exemplo, uma bola de gude colocada no ch\u00e3o. <\/li>\n<\/ul>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Relacion-del-equilibrio-mecanico-con-la-energia-potencial\"><\/span> Rela\u00e7\u00e3o entre equil\u00edbrio mec\u00e2nico e energia potencial<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Como veremos a seguir, o equil\u00edbrio mec\u00e2nico est\u00e1 matematicamente relacionado \u00e0 energia potencial. Assim, o significado do equil\u00edbrio mec\u00e2nico tamb\u00e9m pode ser explicado pela energia potencial, embora seja um pouco mais dif\u00edcil de entender.<\/p>\n<p> <strong>Um sistema est\u00e1 em equil\u00edbrio mec\u00e2nico num ponto<\/strong> onde a primeira derivada da energia potencial nesse ponto \u00e9 igual a zero.<\/p>\n<p> Da mesma forma, dependendo do sinal da segunda derivada, podemos distinguir que tipo de equil\u00edbrio se trata:<\/p>\n<ul>\n<li> <strong>Equil\u00edbrio est\u00e1vel<\/strong> : Um ponto est\u00e1 em equil\u00edbrio est\u00e1vel se a segunda derivada da energia potencial nesse ponto for positiva. Isto \u00e9, se a fun\u00e7\u00e3o energia potencial tiver um m\u00ednimo neste ponto.<\/li>\n<li> <strong>Equil\u00edbrio inst\u00e1vel<\/strong> : Um ponto est\u00e1 em equil\u00edbrio inst\u00e1vel quando a segunda derivada da energia potencial nesse ponto \u00e9 negativa. Isto \u00e9, se a fun\u00e7\u00e3o energia potencial tiver um m\u00e1ximo neste ponto.<\/li>\n<li> <strong>Equil\u00edbrio indiferente<\/strong> : um ponto est\u00e1 em equil\u00edbrio indiferente quando a segunda derivada da energia potencial neste ponto \u00e9 zero. <\/li>\n<\/ul>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicio-resuelto-del-equilibrio-mecanico\"><\/span> Exerc\u00edcio de equil\u00edbrio mec\u00e2nico resolvido<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Calcule a for\u00e7a que cada plano inclinado deve exercer para sustentar o pr\u00f3ximo cilindro de massa 25 kg em equil\u00edbrio mec\u00e2nico. Despreze o atrito durante todo o exerc\u00edcio. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-balance-mecanique.png\" alt=\"problema de equil\u00edbrio mec\u00e2nico resolvido\" class=\"wp-image-512\" width=\"261\" height=\"145\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-balance-mecanique-300x167.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-balance-mecanique.png 495w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Como em todos os problemas est\u00e1ticos, para resolver um problema voc\u00ea deve primeiro criar o diagrama de corpo livre do sistema: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-equilibre-mecanique.png\" alt=\"equil\u00edbrio resolvido do equil\u00edbrio mec\u00e2nico\" class=\"wp-image-513\" width=\"302\" height=\"209\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-equilibre-mecanique-300x208.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-equilibre-mecanique.png 516w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Observe que as for\u00e7as mostradas N <sub>1x<\/sub> , N <sub>1y<\/sub> e N <sub>2x<\/sub> , N <sub>2y<\/sub> s\u00e3o as componentes das for\u00e7as N <sub>1<\/sub> e N <sub>2<\/sub> respectivamente.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-23643671c6a4042138594c9445ed1c69_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N_{1x}=N_1\\cdot \\text{sin}(40\u00ba)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"141\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-8a22b8153b07362045e842df78bf1889_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N_{1y}=N_1\\cdot \\text{cos}(40\u00ba)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"142\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-a3500d29bd3aa0cd7c3c1d1e5db5cfe9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N_{2x}=N_2\\cdot \\text{sin}(55\u00ba)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"141\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-4b9cafb2c9c9fc5edcd519e6179ebd0a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N_{2y}=N_2\\cdot \\text{cos}(55\u00ba)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"142\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Portanto, para que o sistema esteja em equil\u00edbrio mec\u00e2nico, as duas equa\u00e7\u00f5es a seguir devem ser satisfeitas:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-a0317629d735caf1eea5b0cc5f628345_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N_{1x}-N_{2x}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"114\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-aac3d43e84c888bc44eaa971ba86ab8b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N_{1y}+N_{2y}-P=0\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"148\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Da primeira equa\u00e7\u00e3o podemos deduzir que as for\u00e7as dos dois planos t\u00eam a seguinte rela\u00e7\u00e3o:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-a0317629d735caf1eea5b0cc5f628345_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N_{1x}-N_{2x}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"114\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-666ce28dd9441d310bfc2332f91fa94c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N_{1x}=N_{2x}\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"82\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6f6d5654bb8b3230136251a4d0d83d9d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N_1\\cdot \\text{sin}(40\u00ba)=N_2\\cdot \\text{sin}(55\u00ba)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"199\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-8cc022d84ea1b54e979cdddfe833ca26_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N_1=\\cfrac{N_2\\cdot \\text{sin}(55\u00ba)}{\\text{sin}(40\u00ba)}\" title=\"Rendered by QuickLaTeX.com\" height=\"45\" width=\"137\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-ba903677b54cd02a6060d0f8fd05e0b8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N_1=1,27\\cdot N_2\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"114\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Agora vamos substituir as vari\u00e1veis na segunda equa\u00e7\u00e3o pelas suas express\u00f5es: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-aac3d43e84c888bc44eaa971ba86ab8b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N_{1y}+N_{2y}-P=0\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"148\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-8e40c0f5e4890cbf92cba43e37f1bc5d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N_1\\cdot \\text{cos}(40\u00ba)+N_2\\cdot \\text{cos}(55\u00ba)-m\\cdot g=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"293\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e3937cd826f192bc224dff97820dc6f4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N_1\\cdot 0,77+N_2\\cdot 0,57-25\\cdot 9,81=0\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"279\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e98d7fb02f7ae8bcc04e4814e7d05270_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"0,77\\cdot N_1+0,57\\cdot N_2-245,25=0\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"267\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E substitu\u00edmos a rela\u00e7\u00e3o encontrada na primeira equa\u00e7\u00e3o para encontrar o valor da for\u00e7a N <sub>2<\/sub> : <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c2e67a1cd5ea8a92a2db40c1763e6f6c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"0,77\\cdot 1,27\\cdot N_2+0,57\\cdot N_2-245,25=0\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"314\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-671d06ee81dab531cb66ade8e69bd747_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"0,98\\cdot N_2+0,57\\cdot N_2=245,25\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"235\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-da85ebb37019fad25bf3486ac83f79ed_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"1,55\\cdot N_2=245,25\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"143\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e8d486a3480f434c9e78a1189bb0e4ce_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N_2=\\cfrac{245,25}{1,55}=158,26 \\N\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"176\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E por fim, substitu\u00edmos o valor encontrado na rela\u00e7\u00e3o entre as for\u00e7as para determinar<meta charset=\"utf-8\"> N\u00ba <sub>1<\/sub> : <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-1bda6d097b084cf4c8caa0e7ebea9a53_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N_1=1,27\\cdot N_2=1,27\\cdot 158,26=200,95\\N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"313\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Este artigo explica o que \u00e9 equil\u00edbrio mec\u00e2nico com v\u00e1rios exemplos. Voc\u00ea tamb\u00e9m encontrar\u00e1 os diferentes tipos de equil\u00edbrio e, al\u00e9m disso, poder\u00e1 praticar com um exerc\u00edcio resolvido passo a passo. O que \u00e9 equil\u00edbrio mec\u00e2nico? O equil\u00edbrio mec\u00e2nico \u00e9 um estado estacion\u00e1rio em que um corpo se encontra quando a soma das for\u00e7as e &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/pt\/balanca-mecanica\/\"> <span class=\"screen-reader-text\">Balan\u00e7a mec\u00e2nica<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-30","post","type-post","status-publish","format-standard","hentry","category-dinamico"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 O que \u00e9 equil\u00edbrio mec\u00e2nico? 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