{"id":293,"date":"2023-06-22T09:55:32","date_gmt":"2023-06-22T09:55:32","guid":{"rendered":"https:\/\/physigeek.com\/pt\/alavanca\/"},"modified":"2023-06-22T09:55:32","modified_gmt":"2023-06-22T09:55:32","slug":"alavanca","status":"publish","type":"post","link":"https:\/\/physigeek.com\/pt\/alavanca\/","title":{"rendered":"Elevador"},"content":{"rendered":"<p>Este artigo explica o que s\u00e3o alavancas. Assim, voc\u00ea descobrir\u00e1 em que consiste uma alavanca na f\u00edsica, os diferentes tipos de alavancas e a f\u00f3rmula que permite resolver problemas de alavancas. Al\u00e9m disso, voc\u00ea pode praticar a teoria com exerc\u00edcios de alavanca resolvidos passo a passo.<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-una-palanca\"><\/span> O que \u00e9 um elevador?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Uma <strong>alavanca<\/strong> \u00e9 uma m\u00e1quina simples que transmite for\u00e7a e movimento. Em outras palavras, uma alavanca \u00e9 um dispositivo mec\u00e2nico que serve para aumentar uma for\u00e7a aplicada a um objeto, sua velocidade ou a dist\u00e2ncia que ele percorre.<\/p>\n<p> Em geral, as alavancas consistem em uma barra r\u00edgida que pode girar em torno de um fulcro, denominado fulcro.<\/p>\n<p> A alavanca \u00e9 muito antiga, na verdade pensa-se que tenha sido inventada em tempos pr\u00e9-hist\u00f3ricos. Na verdade, o mecanismo de alavanca \u00e9 muito simples de fazer e tamb\u00e9m muito \u00fatil porque permite aumentar consideravelmente a for\u00e7a exercida sobre um objeto. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Caracteristicas-de-las-palancas\"><\/span> Recursos de alavanca<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Dada a defini\u00e7\u00e3o de alavanca, vejamos quais s\u00e3o as diferentes partes deste tipo de m\u00e1quina simples:<\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:14px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Ponto de apoio ou fulcro (F)<\/strong> : \u00e9 a parte da alavanca sobre a qual permanece. Portanto, ela suporta todo o peso da barra, bem como dos corpos acima dela.<\/span><\/li>\n<li style=\"margin-bottom:14px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Esfor\u00e7o ou pot\u00eancia (P)<\/strong> : \u00e9 a for\u00e7a aplicada \u00e0 alavanca para neutralizar a carga do outro lado.<\/span><\/li>\n<li style=\"margin-bottom:14px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Carga ou resist\u00eancia (R)<\/strong> : esta \u00e9 a for\u00e7a que deve ser superada.<\/span><\/li>\n<li style=\"margin-bottom:14px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Bra\u00e7o de for\u00e7a (BP)<\/strong> : \u00e9 a dist\u00e2ncia entre a for\u00e7a e o fulcro.<\/span><\/li>\n<li style=\"margin-bottom:14px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Bra\u00e7o de resist\u00eancia (BR)<\/strong> : \u00e9 a dist\u00e2ncia entre a resist\u00eancia e o fulcro.<\/span> <\/li>\n<\/ul>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/parties-dun-levier-de-premiere-qualite.png\" alt=\"caracter\u00edsticas de uma alavanca\" class=\"wp-image-4733\" width=\"342\" height=\"255\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/parties-dun-levier-de-premiere-qualite-300x224.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/parties-dun-levier-de-premiere-qualite.png 606w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ley-de-la-palanca\"><\/span> lei da alavanca<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Para que uma alavanca de primeiro grau esteja em equil\u00edbrio, deve-se cumprir a equa\u00e7\u00e3o de que a pot\u00eancia vezes o bra\u00e7o de pot\u00eancia \u00e9 igual \u00e0 resist\u00eancia vezes o bra\u00e7o de resist\u00eancia.<\/p>\n<p> A <strong>f\u00f3rmula para a lei da alavancagem<\/strong> \u00e9, portanto, a seguinte:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-f6834df9d4ef006d7a868d9f1df7af56_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P\\cdot BP=R\\cdot BR\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"133\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p style=\"margin-bottom:5px\"> Ouro: <\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fda1e51b12ba3624074fcbebad72b1fc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"14\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 o poder (ou esfor\u00e7o). <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fc8acbc9d0331ce1b64fef220d307f4a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"BP\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"28\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a arma do poder. <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d6abdd487c56e5efbb2c9522ed4b9360_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"R\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"14\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a resist\u00eancia (ou carga). <\/span><\/li>\n<li style=\"margin-bottom:5px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-47cb9c1f3d49c4064a8ea053f28ba5f8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"BR\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"28\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 o bra\u00e7o da resist\u00eancia.<\/span><\/li>\n<\/ul>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Tipos-de-palancas\"><\/span> tipos de alavancas<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Existem tr\u00eas tipos de alavancas com base na posi\u00e7\u00e3o relativa de pot\u00eancia, resist\u00eancia e fulcro. Portanto, cada tipo de alavanca \u00e9 explicado a seguir.<\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Palanca-de-primer-grado\"><\/span> alavanca premium<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p> A <strong>alavanca de primeiro grau<\/strong> , tamb\u00e9m chamada de <strong>alavanca de primeira classe<\/strong> , \u00e9 aquela alavanca que possui um peso em cada uma de suas extremidades e que, em posi\u00e7\u00e3o intermedi\u00e1ria, \u00e9 o fulcro.<\/p>\n<p> Portanto, a principal caracter\u00edstica das alavancas de primeiro grau \u00e9 que elas possuem o fulcro (ou fulcro) entre o esfor\u00e7o (ou pot\u00eancia) e a carga (ou resist\u00eancia).<\/p>\n<p> Por exemplo, o balancim, a tesoura, a pin\u00e7a ou o alicate s\u00e3o alavancas principais. At\u00e9 o corpo humano pode funcionar como uma alavanca de primeiro grau quando tentamos levantar um peso.<\/p>\n<p> Al\u00e9m disso, tr\u00eas classes diferentes de alavancas de primeiro grau podem ser analisadas:<\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:18px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Alavanca de primeiro grau com fulcro centrado<\/strong> : o fulcro fica bem no meio da alavanca, ou seja, a dist\u00e2ncia do fulcro \u00e0 pot\u00eancia \u00e9 igual \u00e0 dist\u00e2ncia do ponto de apoio da resist\u00eancia.<\/span><\/li>\n<li style=\"margin-bottom:18px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Alavanca de primeiro grau com ponto de apoio pr\u00f3ximo \u00e0 resist\u00eancia<\/strong> : o ponto de apoio est\u00e1 mais pr\u00f3ximo da resist\u00eancia do que da pot\u00eancia. Portanto, o bra\u00e7o de pot\u00eancia \u00e9 mais longo que o bra\u00e7o de resist\u00eancia e, portanto, a pot\u00eancia \u00e9 menor que a resist\u00eancia.<\/span><\/li>\n<li style=\"margin-bottom:18px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Alavanca de primeiro grau com fulcro pr\u00f3ximo da pot\u00eancia<\/strong> : o fulcro est\u00e1 mais pr\u00f3ximo da pot\u00eancia do que da resist\u00eancia. Portanto, o bra\u00e7o de resist\u00eancia \u00e9 mais longo que o bra\u00e7o de pot\u00eancia e, portanto, a pot\u00eancia \u00e9 maior que a resist\u00eancia.<\/span> <\/li>\n<\/ul>\n<div class=\"wp-block-columns is-layout-flex wp-container-4 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/levier-de-premier-degre-a-point-dappui-centre.png\" alt=\"fulcro centrado na alavanca de primeiro grau\" class=\"wp-image-4744\" width=\"250\" height=\"274\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/levier-de-premier-degre-a-point-dappui-centre-273x300.png 273w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/levier-de-premier-degre-a-point-dappui-centre.png 604w\" sizes=\"auto, (max-width: 273px) 100vw, 273px\"><\/figure>\n<\/div>\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/point-dappui-du-levier-du-premier-degre-proche-de-la-resistance.png\" alt=\"fulcro da alavanca de primeiro grau pr\u00f3ximo \u00e0 resist\u00eancia\" class=\"wp-image-4746\" width=\"250\" height=\"276\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/point-dappui-du-levier-du-premier-degre-proche-de-la-resistance-271x300.png 271w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/point-dappui-du-levier-du-premier-degre-proche-de-la-resistance.png 606w\" sizes=\"auto, (max-width: 271px) 100vw, 271px\"><\/figure>\n<\/div>\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/levier-dappui-de-premiere-qualite-proche-de-la-puissance.png\" alt=\"fulcro da alavanca de primeiro grau pr\u00f3ximo ao poder\" class=\"wp-image-4747\" width=\"250\" height=\"276\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/levier-dappui-de-premiere-qualite-proche-de-la-puissance-271x300.png 271w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/levier-dappui-de-premiere-qualite-proche-de-la-puissance.png 606w\" sizes=\"auto, (max-width: 271px) 100vw, 271px\"><\/figure>\n<\/div>\n<\/div>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Palanca-de-segundo-grado\"><\/span> alavanca de segundo grau<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p> <strong>Alavanca de segundo grau<\/strong> , tamb\u00e9m chamada de <strong>alavanca de segunda classe<\/strong> , \u00e9 um tipo de alavanca em que a carga (ou resist\u00eancia) fica entre o fulcro (ou fulcro) e o esfor\u00e7o (ou pot\u00eancia).<\/p>\n<p> Portanto, as alavancas de segundo grau t\u00eam o fulcro em uma extremidade da alavanca e na outra extremidade uma for\u00e7a vertical ascendente deve ser aplicada para levantar a carga.<\/p>\n<p> Por exemplo, carrinhos de m\u00e3o, quebra-nozes e abridores de garrafas s\u00e3o alavancas de segundo grau. <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/caracteristiques-du-levier-du-deuxieme-degre.png\" alt=\"caracter\u00edsticas de uma alavanca de segundo grau\" class=\"wp-image-4933\" width=\"282\" height=\"354\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/caracteristiques-du-levier-du-deuxieme-degre-239x300.png 239w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/caracteristiques-du-levier-du-deuxieme-degre.png 558w\" sizes=\"auto, (max-width: 239px) 100vw, 239px\"><\/figure>\n<p> Portanto, nas alavancas de segundo grau, o bra\u00e7o de pot\u00eancia \u00e9 sempre maior que o bra\u00e7o de resist\u00eancia. Portanto, nas alavancas de segundo grau, a pot\u00eancia \u00e9 sempre menor que a resist\u00eancia.<\/p>\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Palanca-de-tercer-grado\"><\/span> alavanca de terceiro grau<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p> A <strong>alavanca de terceiro grau<\/strong> , tamb\u00e9m conhecida como <strong>alavanca de terceira classe<\/strong> , \u00e9 a alavanca que exerce o esfor\u00e7o (ou pot\u00eancia) entre o fulcro (ou fulcro) e a carga (ou resist\u00eancia).<\/p>\n<p> Ou seja, as alavancas de terceiro grau t\u00eam o fulcro em uma extremidade, a resist\u00eancia na outra extremidade e a pot\u00eancia em algum lugar entre as duas extremidades da alavanca.<\/p>\n<p> Por exemplo, varas de pescar, pin\u00e7as e cortadores de unhas s\u00e3o alavancas de terceiro grau. <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/caracteristiques-du-levier-de-troisieme-annee.png\" alt=\"caracter\u00edsticas de uma alavanca de terceiro grau\" class=\"wp-image-5009\" width=\"280\" height=\"377\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/caracteristiques-du-levier-de-troisieme-annee-223x300.png 223w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/caracteristiques-du-levier-de-troisieme-annee.png 525w\" sizes=\"auto, (max-width: 223px) 100vw, 223px\"><\/figure>\n<p> Portanto, como a resist\u00eancia estar\u00e1 sempre mais distante do fulcro do que a pot\u00eancia, nas alavancas de terceiro grau o bra\u00e7o de resist\u00eancia \u00e9 sempre maior que o bra\u00e7o de pot\u00eancia. Portanto, o poder a ser realizado tamb\u00e9m \u00e9 maior que a resist\u00eancia.<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicios-resueltos-de-palancas\"><\/span> Exerc\u00edcios resolvidos sobre alavancas<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 1<\/h3>\n<p> Um corpo de 50 kg \u00e9 colocado pr\u00f3ximo a uma alavanca de primeiro grau feita de uma barra r\u00edgida de 300 cm. Se a dist\u00e2ncia entre a carga e o fulcro \u00e9 de 180 cm, quanto deve pesar o corpo colocado do outro lado da alavanca para que esteja em equil\u00edbrio? <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> A alavanca neste problema \u00e9 de primeiro grau e conhecemos apenas a resist\u00eancia (50 kg) e o bra\u00e7o de resist\u00eancia (180 cm). No entanto, como sabemos o comprimento da barra, podemos calcular o bra\u00e7o de pot\u00eancia subtraindo o comprimento total da barra menos o comprimento do bra\u00e7o de resist\u00eancia:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d8009cd38409af0152df783ad89f3f36_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"BP=300-180=120 \\text{ cm}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"206\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Assim, podemos determinar o valor da pot\u00eancia aplicando a regra da alavanca:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-f6834df9d4ef006d7a868d9f1df7af56_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P\\cdot BP=R\\cdot BR\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"133\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Substitu\u00edmos os dados na f\u00f3rmula:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-5959be827849cceb2665451a56d8ff0a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P\\cdot 120=50\\cdot 180\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"134\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E finalmente, resolvemos a inc\u00f3gnita na equa\u00e7\u00e3o:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-78a4d183ce7fc344a8b0a34efc858751_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=\\cfrac{50\\cdot 180}{120}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"97\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7ace0a567aab127764f2007e8b8f0b3d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=75 \\text{ kg}\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"79\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 2<\/h3>\n<p> Num carrinho de m\u00e3o colocamos um objeto que pesa 70 kg a 50 cm do ponto de apoio. Se a parte onde fica o carrinho de m\u00e3o est\u00e1 a 140 cm do fulcro, qual o esfor\u00e7o que devemos fazer para poder transportar o objeto com o carrinho de m\u00e3o? <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> O carrinho de m\u00e3o \u00e9 uma alavanca de segundo grau, pois a resist\u00eancia est\u00e1 localizada entre o fulcro e a pot\u00eancia. Portanto, para resolver o problema devemos aplicar a lei da alavancagem:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-f6834df9d4ef006d7a868d9f1df7af56_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P\\cdot BP=R\\cdot BR\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"133\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Substitu\u00edmos os dados que conhecemos na equa\u00e7\u00e3o:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e71aa135e71ce25f9237d661b3656cd7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P\\cdot 140=70\\cdot 50\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"125\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E finalmente, resolvemos a inc\u00f3gnita na equa\u00e7\u00e3o: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-05e2c7e509587e806745d16426497be4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=\\cfrac{70\\cdot 50}{140}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"88\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-bda321058b63b34b706e280791fd6407_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=25 \\text{ kg}\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"79\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Voc\u00ea deve, portanto, fazer um esfor\u00e7o equivalente a levantar 25 kg.<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 3<\/h3>\n<p> Numa alavanca de terceiro grau, uma for\u00e7a equivalente a 60 N deve ser exercida para neutralizar uma resist\u00eancia de 15 N localizada a 80 cm do fulcro. Calcule a que dist\u00e2ncia do fulcro a energia \u00e9 aplicada. <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Neste problema de alavanca de terceiro grau, somos solicitados a determinar o bra\u00e7o do poder. Ent\u00e3o, para resolver o problema devemos aplicar a equa\u00e7\u00e3o da alavanca:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-f6834df9d4ef006d7a868d9f1df7af56_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P\\cdot BP=R\\cdot BR\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"133\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Substitu\u00edmos os dados que conhecemos na equa\u00e7\u00e3o:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-1dae5ba7078c412fbe57dd6d8fe0008f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"60\\cdot BP=15\\cdot 80\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"131\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E resolvemos a inc\u00f3gnita na equa\u00e7\u00e3o: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6c20589172f022b76c17eb055f14ab91_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"BP=\\cfrac{15\\cdot 80}{60}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"103\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-4b319952f3a57992cb5e4d229af26b5b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"BP=20 \\text{ cm}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"98\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> A pot\u00eancia deve, portanto, ser aplicada a 20 cm do fulcro.<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Este artigo explica o que s\u00e3o alavancas. Assim, voc\u00ea descobrir\u00e1 em que consiste uma alavanca na f\u00edsica, os diferentes tipos de alavancas e a f\u00f3rmula que permite resolver problemas de alavancas. Al\u00e9m disso, voc\u00ea pode praticar a teoria com exerc\u00edcios de alavanca resolvidos passo a passo. O que \u00e9 um elevador? Uma alavanca \u00e9 uma &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/pt\/alavanca\/\"> <span class=\"screen-reader-text\">Elevador<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-293","post","type-post","status-publish","format-standard","hentry","category-dinamico"],"yoast_head":"<!-- This site is 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