{"id":26,"date":"2023-06-27T09:15:43","date_gmt":"2023-06-27T09:15:43","guid":{"rendered":"https:\/\/physigeek.com\/pt\/forcas-paralelas\/"},"modified":"2023-06-27T09:15:43","modified_gmt":"2023-06-27T09:15:43","slug":"forcas-paralelas","status":"publish","type":"post","link":"https:\/\/physigeek.com\/pt\/forcas-paralelas\/","title":{"rendered":"For\u00e7as paralelas"},"content":{"rendered":"<p>Este artigo explica o que s\u00e3o for\u00e7as paralelas. Voc\u00ea tamb\u00e9m encontrar\u00e1 exemplos de sistemas de for\u00e7as paralelos. Finalmente, voc\u00ea poder\u00e1 ver como calcular a for\u00e7a resultante de um sistema de for\u00e7as paralelas na mesma dire\u00e7\u00e3o e de um sistema de for\u00e7as paralelas em uma dire\u00e7\u00e3o diferente. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-son-las-fuerzas-paralelas\"><\/span> O que s\u00e3o for\u00e7as paralelas?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>For\u00e7as paralelas<\/strong> s\u00e3o for\u00e7as cujas linhas de a\u00e7\u00e3o s\u00e3o paralelas. Em outras palavras, duas ou mais for\u00e7as s\u00e3o paralelas quando t\u00eam a mesma dire\u00e7\u00e3o.<\/p>\n<p> Duas for\u00e7as paralelas podem ter a mesma dire\u00e7\u00e3o ou dire\u00e7\u00f5es opostas. Mas desde que as linhas nas quais s\u00e3o projetadas sejam paralelas, as for\u00e7as s\u00e3o consideradas paralelas. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/forces-paralleles.png\" alt=\"\" class=\"wp-image-463\" width=\"239\" height=\"239\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/forces-paralleles-300x300.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/forces-paralleles-150x150.png 150w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/forces-paralleles.png 514w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p> Observe que, por defini\u00e7\u00e3o, duas for\u00e7as paralelas n\u00e3o podem ser <a href=\"https:\/\/physigeek.com\/pt\/forcas-concorrentes\/\">for\u00e7as concorrentes<\/a> , mas podem ser <span style=\"text-decoration: underline;\"><a href=\"https:\/\/physigeek.com\/pt\/forcas-colineares\/\">for\u00e7as colineares<\/a><\/span> . <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejemplos-de-fuerzas-paralelas\"><\/span>Exemplos de for\u00e7as paralelas<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Para compreender totalmente o conceito de for\u00e7as paralelas, aqui est\u00e3o dois exemplos retirados do cotidiano desse tipo de for\u00e7a.<\/p>\n<p> Por exemplo, quando duas pessoas tentam mover horizontalmente um objeto muito pesado ao mesmo tempo, elas est\u00e3o exercendo duas for\u00e7as paralelas na mesma dire\u00e7\u00e3o, pois ambas as pessoas desejam mover o objeto para o mesmo lado. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-de-forces-paralleles.png\" alt=\"exemplo de for\u00e7as paralelas\" class=\"wp-image-464\" width=\"268\" height=\"163\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-de-forces-paralleles-300x183.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-de-forces-paralleles.png 481w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p> Outro exemplo de duas for\u00e7as paralelas \u00e9 quando saltamos com as duas pernas ao mesmo tempo. Para saltar, cada perna aplica uma for\u00e7a vertical contra o solo.<\/p>\n<p> Nas se\u00e7\u00f5es seguintes veremos como duas for\u00e7as paralelas s\u00e3o substitu\u00eddas por uma for\u00e7a resultante. Por\u00e9m, para compreender os seguintes exerc\u00edcios de for\u00e7as paralelas, primeiro voc\u00ea deve saber <span style=\"text-decoration: underline;\"><a href=\"https:\/\/physigeek.com\/pt\/condicoes-de-equilibrio\/\">quais s\u00e3o as condi\u00e7\u00f5es de equil\u00edbrio<\/a><\/span> . <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Fuerzas-paralelas-de-igual-sentido\"><\/span> For\u00e7as paralelas na mesma dire\u00e7\u00e3o<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> A for\u00e7a resultante de <strong>duas for\u00e7as paralelas na mesma dire\u00e7\u00e3o<\/strong> \u00e9 uma for\u00e7a cujo valor \u00e9 a soma dos m\u00f3dulos das for\u00e7as paralelas, e seu ponto de aplica\u00e7\u00e3o responde \u00e0 seguinte rela\u00e7\u00e3o: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/forces-paralleles-a-direction-egale.png\" alt=\"for\u00e7as paralelas na mesma dire\u00e7\u00e3o\" class=\"wp-image-466\" width=\"256\" height=\"373\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/forces-paralleles-a-direction-egale-206x300.png 206w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/forces-paralleles-a-direction-egale.png 466w\" sizes=\"auto, (max-width: 206px) 100vw, 206px\"><\/figure>\n<\/div>\n<p> A equa\u00e7\u00e3o utilizada para obter o ponto de aplica\u00e7\u00e3o da for\u00e7a resultante prov\u00e9m da aplica\u00e7\u00e3o da condi\u00e7\u00e3o de equil\u00edbrio de momentos, ou seja, da segunda condi\u00e7\u00e3o de equil\u00edbrio.<\/p>\n<p> Por exemplo, se quisermos somar duas for\u00e7as paralelas de 9 N e 15 N na mesma dire\u00e7\u00e3o separadas por um comprimento de 12 m, devemos primeiro somar as intensidades das for\u00e7as para encontrar o valor da for\u00e7a resultante:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7a60d278e210302b71dd7c54c7630014_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"R=F_1+F_2=9+15=24\\N\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"211\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p> Resta agora determinar o ponto de aplica\u00e7\u00e3o da for\u00e7a. Para fazer isso, devemos resolver a seguinte equa\u00e7\u00e3o:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e783273e2bf32ee2a65976d25c4493cc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_1\\cdot a = F_2\\cdot b\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"105\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0fc68dbe5c869e7c51c4159c0d71fbb4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"9\\cdot a = 15\\cdot (12 -a)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"146\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-54453cb4146f71f7f00d270cbdea216a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"9a=180 -15a\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"117\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6d71d7a01ca2ed48aae75972c0a80e49_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"9 ans + 15 ans = 180 \" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"156\" style=\"vertical-align: -2px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-b7610104491fb4024a8dbfebe2d0ebc1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"24a=180\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"78\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-2c04321053626aa16821552c7cd88bc6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a=\\cfrac{180}{24}=7,5 \\m\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"110\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Concluindo, a for\u00e7a resultante do sistema destas duas for\u00e7as paralelas \u00e9 uma for\u00e7a de magnitude 24 N e est\u00e1 localizada 7,5 m \u00e0 direita do ponto de aplica\u00e7\u00e3o da primeira for\u00e7a. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Fuerzas-paralelas-de-sentido-contrario\"><\/span> For\u00e7as paralelas na dire\u00e7\u00e3o oposta<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> A for\u00e7a resultante de <strong>duas for\u00e7as paralelas de sentido oposto<\/strong> \u00e9 uma for\u00e7a cujo valor \u00e9 igual \u00e0 diferen\u00e7a dos m\u00f3dulos das for\u00e7as paralelas, e para calcular o seu ponto de aplica\u00e7\u00e3o \u00e9 necess\u00e1rio aplicar a seguinte rela\u00e7\u00e3o: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/forces-paralleles-dans-direction-opposee.png\" alt=\"for\u00e7as paralelas opostas\" class=\"wp-image-470\" width=\"256\" height=\"403\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/forces-paralleles-dans-direction-opposee-191x300.png 191w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/forces-paralleles-dans-direction-opposee.png 470w\" sizes=\"auto, (max-width: 191px) 100vw, 191px\"><\/figure>\n<\/div>\n<p> Por exemplo, se quisermos substituir duas for\u00e7as paralelas de 11 N e 7 N em dire\u00e7\u00f5es diferentes separadas por um comprimento de 8 m pela sua for\u00e7a resultante, devemos primeiro subtrair os m\u00f3dulos das for\u00e7as para encontrar o valor da for\u00e7a resultante. :<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-5b45ff10e249df2a392c67e84223765b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"R=F_1-F_7=11-7=4\\N\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"202\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p> Uma vez calculado o m\u00f3dulo da for\u00e7a resultante, resta apenas encontrar o seu ponto de aplica\u00e7\u00e3o, por isso propomos a seguinte equa\u00e7\u00e3o e resolvemos:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e79e494c7049a7d1e5e9313fd3267cf0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_1\\cdot x = F_2\\cdot (d+x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"151\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-bc0954b27fb974b482c0ec45d57ac03d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"11\\cdot x = 7\\cdot (8+x)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"138\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-1c270fd705d150d0258f430560748f01_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"11x=56+7x\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"109\" style=\"vertical-align: -2px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-4043b5e370de2656eff9d3846dc8eb9b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"11x-7x=56\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"109\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-eaa26d51b2db58aecf5e193b70b8bfb9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"4x=56\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"61\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-bd823b476b2cd7c0da0d130f51905177_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x=\\cfrac{56}{4}=14 \\ m\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"116\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> A for\u00e7a resultante deste sistema de for\u00e7as paralelas \u00e9, portanto, uma for\u00e7a de magnitude 4 N e est\u00e1 localizada 14 m \u00e0 esquerda do ponto de aplica\u00e7\u00e3o da primeira for\u00e7a.<\/p>\n<p> Por outro lado, quando duas for\u00e7as paralelas em dire\u00e7\u00f5es opostas t\u00eam a mesma intensidade, em f\u00edsica dizemos que s\u00e3o um par de for\u00e7as. A caracter\u00edstica de um par de for\u00e7as \u00e9 que elas geram um momento e, portanto, giram o corpo. Voc\u00ea pode ver como \u00e9 calculado o momento de algumas for\u00e7as clicando aqui: <\/p>\n<div style=\"background-color:#FFFDE7; padding-top: 10px; padding-bottom: 10px; padding-right: 10px; padding-left: 20px; border: 2.5px dashed #FFB74D; border-radius:20px;\"> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Veja:<\/strong> <a href=\"https:\/\/physigeek.com\/pt\/casal\/\">momento de algumas for\u00e7as<\/a><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Este artigo explica o que s\u00e3o for\u00e7as paralelas. Voc\u00ea tamb\u00e9m encontrar\u00e1 exemplos de sistemas de for\u00e7as paralelos. Finalmente, voc\u00ea poder\u00e1 ver como calcular a for\u00e7a resultante de um sistema de for\u00e7as paralelas na mesma dire\u00e7\u00e3o e de um sistema de for\u00e7as paralelas em uma dire\u00e7\u00e3o diferente. O que s\u00e3o for\u00e7as paralelas? For\u00e7as paralelas s\u00e3o for\u00e7as &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/pt\/forcas-paralelas\/\"> <span class=\"screen-reader-text\">For\u00e7as paralelas<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-26","post","type-post","status-publish","format-standard","hentry","category-dinamico"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - 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