{"id":254,"date":"2023-06-23T05:53:04","date_gmt":"2023-06-23T05:53:04","guid":{"rendered":"https:\/\/physigeek.com\/pt\/coeficiente-de-atrito-ou-coeficiente-de-atrito\/"},"modified":"2023-06-23T05:53:04","modified_gmt":"2023-06-23T05:53:04","slug":"coeficiente-de-atrito-ou-coeficiente-de-atrito","status":"publish","type":"post","link":"https:\/\/physigeek.com\/pt\/coeficiente-de-atrito-ou-coeficiente-de-atrito\/","title":{"rendered":"Coeficiente de atrito (ou coeficiente de atrito)"},"content":{"rendered":"<p>Este artigo explica o que \u00e9 o coeficiente de atrito (ou coeficiente de atrito) na f\u00edsica. Assim voc\u00ea descobrir\u00e1 como calcular o coeficiente de atrito, quais s\u00e3o os tipos de coeficientes de atrito e, al\u00e9m disso, exerc\u00edcios resolvidos passo a passo. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-el-coeficiente-de-friccion\"><\/span> Qual \u00e9 o coeficiente de atrito?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> O <strong>coeficiente de atrito<\/strong> , tamb\u00e9m chamado <strong>de coeficiente de atrito<\/strong> , \u00e9 um coeficiente que indica o atrito entre as superf\u00edcies de dois corpos quando um pretende mover-se sobre o outro.<\/p>\n<p> Assim, o coeficiente de atrito \u00e9 usado para calcular a for\u00e7a de atrito (ou for\u00e7a de atrito), que \u00e9 a for\u00e7a que dificulta o movimento de um corpo sobre outro. Portanto, quanto maior o coeficiente de atrito, maior ser\u00e1 a for\u00e7a de atrito.<\/p>\n<p> O coeficiente de atrito \u00e9 um coeficiente adimensional, ou seja, n\u00e3o possui unidade. Da mesma forma, a letra grega \u03bc \u00e9 frequentemente usada como s\u00edmbolo para representar o coeficiente de atrito. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Formula-del-coeficiente-de-friccion\"><\/span> F\u00f3rmula do coeficiente de atrito<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> O coeficiente de atrito \u00e9 igual \u00e0 raz\u00e3o entre a for\u00e7a de atrito (ou for\u00e7a de atrito) e a for\u00e7a normal. Portanto, o coeficiente de atrito \u00e9 calculado dividindo a for\u00e7a de atrito pela for\u00e7a normal.<\/p>\n<p> Em outras palavras, a <strong>f\u00f3rmula do coeficiente de atrito<\/strong> \u00e9 a seguinte:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-2bee3710c7506bf8ff2456662a57f279_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\mu=\\cfrac{F_R}{N}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"59\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p style=\"margin-bottom:5px\"> Ouro: <\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-05d9eae892416bd34247a25207f8b718_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\mu\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"11\" style=\"vertical-align: -4px;\"><\/p>\n<p> \u00e9 o coeficiente de atrito, que n\u00e3o tem unidade. <\/span><\/li>\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-5b005ac29604de5f2904d2da7ade0238_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_R\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"22\" style=\"vertical-align: -3px;\"><\/p>\n<p> \u00e9 a <a href=\"https:\/\/physigeek.com\/pt\/forca-de-atrito-ou-forca-de-atrito\/\">for\u00e7a de atrito<\/a> , expressa em newtons.<\/span><\/li>\n<li><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7354bae77b50b7d1faed3e8ea7a3511a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"16\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a for\u00e7a normal, expressa em newtons.<\/span><\/li>\n<\/ul>\n<p> Lembre-se que o coeficiente de atrito \u00e9 um coeficiente que n\u00e3o possui unidade porque \u00e9 calculado dividindo duas grandezas que possuem as mesmas unidades. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Coeficiente-de-friccion-estatico-y-dinamico\"><\/span> Coeficiente de atrito est\u00e1tico e din\u00e2mico<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> O valor da for\u00e7a de atrito depende se o corpo est\u00e1 em repouso ou em movimento. Por exemplo, voc\u00ea provavelmente tentou arrastar um corpo muito pesado e foi dif\u00edcil mov\u00ea-lo no in\u00edcio, mas depois que conseguiu mover um pouco o corpo, \u00e9 mais f\u00e1cil continuar arrastando o objeto.<\/p>\n<p> Na verdade, em geral, a for\u00e7a de atrito quando o corpo est\u00e1 parado \u00e9 maior do que quando o corpo est\u00e1 em movimento. Existem, portanto, dois tipos de for\u00e7as de atrito:<\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>For\u00e7a de atrito est\u00e1tico<\/strong> : \u00c9 a for\u00e7a de atrito que atua quando o corpo ainda n\u00e3o est\u00e1 em movimento.<\/span><\/li>\n<li> <span style=\"color:#101010;font-weight: normal;\"><strong>For\u00e7a de atrito din\u00e2mica (ou cin\u00e9tica)<\/strong> : \u00e9 a for\u00e7a de atrito que atua quando o corpo j\u00e1 iniciou o movimento.<\/span><\/li>\n<\/ul>\n<p> Assim, existem tamb\u00e9m dois tipos de coeficiente de atrito:<\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Coeficiente de atrito est\u00e1tico (\u03bc <sub>E<\/sub> )<\/strong> : usado para calcular a for\u00e7a de atrito est\u00e1tico. Indica o atrito entre as superf\u00edcies de dois corpos quando o movimento ainda n\u00e3o foi iniciado, ou seja, quando ainda est\u00e3o em repouso.<\/span><\/li>\n<li> <span style=\"color:#101010;font-weight: normal;\"><strong>Coeficiente de atrito din\u00e2mico (\u03bc <sub>D<\/sub> )<\/strong> : usado para calcular a for\u00e7a de atrito din\u00e2mico. Indica o atrito entre as superf\u00edcies de dois corpos quando um j\u00e1 desliza sobre o outro.<\/span><\/li>\n<\/ul>\n<p> Al\u00e9m disso, o valor da for\u00e7a de atrito varia conforme mostrado no gr\u00e1fico a seguir: <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/graphique-force-statique-et-dynamique-friction.png\" alt=\"for\u00e7a de atrito est\u00e1tico e din\u00e2mico\" class=\"wp-image-4356\" width=\"381\" height=\"261\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/graphique-force-statique-et-dynamique-friction-300x205.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/graphique-force-statique-et-dynamique-friction.png 725w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<p> A for\u00e7a de atrito est\u00e1tico \u00e9 igual \u00e0 for\u00e7a aplicada para tentar mover o corpo, mas sua dire\u00e7\u00e3o \u00e9 oposta. Seu valor m\u00e1ximo \u00e9 o produto entre o coeficiente de atrito est\u00e1tico e a for\u00e7a normal. Quando a for\u00e7a aplicada ultrapassa esse valor, o corpo come\u00e7a a se mover.<\/p>\n<p> Assim, quando o corpo j\u00e1 est\u00e1 em movimento, a for\u00e7a de atrito din\u00e2mico tem valor constante equivalente ao produto entre o coeficiente de atrito din\u00e2mico e a for\u00e7a normal, qualquer que seja o valor da for\u00e7a aplicada. Al\u00e9m disso, este valor \u00e9 ligeiramente inferior ao valor m\u00e1ximo da for\u00e7a de atrito est\u00e1tico.<\/p>\n<p> Concluindo, o coeficiente de atrito est\u00e1tico \u00e9 maior que o coeficiente de atrito din\u00e2mico. \u00c9 portanto mais dif\u00edcil come\u00e7ar a mover um corpo do que mov\u00ea-lo quando o movimento j\u00e1 come\u00e7ou. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Valores-del-coeficiente-de-friccion\"><\/span> Valores do coeficiente de atrito<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Na tabela a seguir voc\u00ea pode ver alguns valores comuns de coeficiente de atrito est\u00e1tico e coeficiente de atrito din\u00e2mico:<\/p>\n<figure class=\"wp-block-table is-style-stripes\">\n<table>\n<thead>\n<tr>\n<th> Superf\u00edcies de contato<\/th>\n<th class=\"has-text-align-center\" data-align=\"center\"> Coeficiente de atrito est\u00e1tico (\u03bc <sub>e<\/sub> )<\/th>\n<th class=\"has-text-align-center\" data-align=\"center\"> Coeficiente de atrito din\u00e2mico ( <sub>\u03bcd<\/sub> )<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td> cobre em a\u00e7o<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,53<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,36<\/td>\n<\/tr>\n<tr>\n<td> a\u00e7o em a\u00e7o<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,74<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,57<\/td>\n<\/tr>\n<tr>\n<td> alum\u00ednio em a\u00e7o<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,61<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,47<\/td>\n<\/tr>\n<tr>\n<td> borracha em cimento<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 1<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,8<\/td>\n<\/tr>\n<tr>\n<td> madeira sobre madeira<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,25-0,5<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,2<\/td>\n<\/tr>\n<tr>\n<td> Madeira em couro<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,5<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,4<\/td>\n<\/tr>\n<tr>\n<td> Teflon em Teflon<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,04<\/td>\n<td class=\"has-text-align-center\" data-align=\"center\"> 0,04<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n<p> Tenha em mente que estes valores podem variar, pois dependem de muitos fatores como rugosidade da superf\u00edcie, temperatura, velocidade relativa entre superf\u00edcies, etc. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicios-resueltos-del-coeficiente-de-friccion\"><\/span> Problemas resolvidos de coeficiente de atrito<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 1<\/h3>\n<p> Pretendemos mover um bloco de massa m=12 kg sobre uma superf\u00edcie plana e ele come\u00e7a a se mover exatamente quando uma for\u00e7a de 35 N \u00e9 aplicada. Qual \u00e9 o coeficiente de atrito est\u00e1tico entre o solo e o bloco? Dados: g=10 m\/s <sup>2<\/sup> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-statique.png\" alt=\"problema resolvido de coeficiente de atrito est\u00e1tico\" class=\"wp-image-4302\" width=\"285\" height=\"125\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-statique-300x132.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-statique.png 650w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Primeiro, representamos graficamente todas as for\u00e7as que atuam no bloco: <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-statique.png\" alt=\"exerc\u00edcio resolvido do coeficiente de atrito est\u00e1tico ou coeficiente de atrito est\u00e1tico\" class=\"wp-image-4303\" width=\"269\" height=\"359\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-statique-225x300.png 225w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-statique.png 670w\" sizes=\"auto, (max-width: 225px) 100vw, 225px\"><\/figure>\n<p class=\"has-text-align-left\"> Na situa\u00e7\u00e3o limite de equil\u00edbrio, verificam-se as duas equa\u00e7\u00f5es a seguir:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-318d3aaff48777c13e5ac24cb775f6b0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N=P\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"54\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-b2d0fc9325264d9c3dceae21b529d2c5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_R=F\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"60\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Assim a for\u00e7a de atrito ser\u00e1 equivalente \u00e0 for\u00e7a horizontal aplicada ao corpo:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-f433d79addb4c8cfc17c71cf797f4905_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_R=F=35 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"123\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Por outro lado, podemos calcular o valor da for\u00e7a normal usando a f\u00f3rmula da for\u00e7a peso:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fdd5a10090733132a78410e57a059c2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{l}N=P\\\\[3ex] N=m\\cdot g\\\\[3ex] N=12\\cdot 10 \\\\[3ex] N=120 \\ N\\end{array }\" title=\"Rendered by QuickLaTeX.com\" height=\"147\" width=\"88\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Finalmente, uma vez conhecido o valor da for\u00e7a de atrito e da for\u00e7a normal, aplicamos a f\u00f3rmula do coeficiente de atrito est\u00e1tico para determinar o seu valor: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-20cdd7c8dcf9b6af55e1fe95eedf8da2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\mu_e=\\cfrac{F_R}{N}=\\cfrac{35}{120}=0.29\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"174\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 2<\/h3>\n<p> Colocamos um corpo de massa m=6 kg no topo de um plano inclinado de 45\u00ba. Se o corpo desliza sobre o plano inclinado com uma acelera\u00e7\u00e3o de 4 m\/s <sup>2<\/sup> , qual \u00e9 o coeficiente de atrito din\u00e2mico entre a superf\u00edcie do plano inclinado e a do corpo? Dados: g=10 m\/s <sup>2<\/sup> . <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-dynamique.png\" alt=\"problema do coeficiente de atrito ou atrito din\u00e2mico\" class=\"wp-image-4281\" width=\"203\" height=\"205\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-dynamique-298x300.png 298w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-dynamique-150x150.png 150w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-resolu-coefficient-de-frottement-dynamique.png 479w\" sizes=\"auto, (max-width: 298px) 100vw, 298px\"><\/figure>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> A primeira coisa que precisamos fazer para resolver qualquer problema de f\u00edsica relacionado \u00e0 din\u00e2mica \u00e9 desenhar o diagrama de corpo livre. Ent\u00e3o, todas as for\u00e7as que atuam no sistema s\u00e3o: <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-dynamique.png\" alt=\"exerc\u00edcio resolvido do coeficiente de atrito ou atrito din\u00e2mico\" class=\"wp-image-4282\" width=\"248\" height=\"301\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-dynamique-247x300.png 247w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-force-de-friction-dynamique.png 572w\" sizes=\"auto, (max-width: 247px) 100vw, 247px\"><\/figure>\n<p class=\"has-text-align-left\"> No sentido do eixo 1 (paralelo ao plano inclinado) o corpo apresenta uma acelera\u00e7\u00e3o, por\u00e9m, no sentido do eixo 2 (perpendicular ao plano inclinado) o corpo est\u00e1 em repouso. A partir dessas informa\u00e7\u00f5es, propomos as equa\u00e7\u00f5es das for\u00e7as do sistema:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d87a1ef6aaa3476891df5da8334cbc49_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_1-F_R=m\\cdot a\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"124\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6bdf90ed250934bf6cffbb110bc792a4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_2-N=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"90\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Ent\u00e3o, podemos calcular a for\u00e7a normal a partir da segunda equa\u00e7\u00e3o:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-59341555fe3d5fe315ceb1864547873b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{l}N=P_2\\\\[3ex]N=m\\cdot g\\cdot \\text{cos}(\\alpha) \\\\[3ex] N=6 \\cdot 10 \\cdot \\ text{cos}(45\u00ba)\\\\[3ex]N=42,43 \\ N\\end{array}\" title=\"Rendered by QuickLaTeX.com\" height=\"151\" width=\"185\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Por outro lado, calculamos o valor da for\u00e7a de atrito (ou for\u00e7a de atrito) a partir da primeira equa\u00e7\u00e3o apresentada:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d8f2aff2a81d98ddcea04b1988282fda_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{array}{l}P_1-F_R=m\\cdot a\\\\[3ex]F_R=P_1-m\\cdot a\\\\[3ex]F_R=m\\cdot g\\cdot \\text{sin} (\\alpha)-m\\cdot a\\\\[3ex]F_R=6\\cdot 10\\cdot \\text{sin}(45\u00ba)-6\\cdot 4\\\\[3ex]F_R=18.43 \\ N\\end{ array} \" title=\"Rendered by QuickLaTeX.com\" height=\"195\" width=\"204\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E uma vez conhecido o valor da for\u00e7a normal e da for\u00e7a de atrito, podemos determinar o coeficiente de atrito din\u00e2mico usando sua f\u00f3rmula correspondente: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-31af78ef6e04fa66121d64aa3570f5a6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\mu_d=\\cfrac{F_R}{N}=\\cfrac{18.43}{43.43}=\\bm{0.42}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"187\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Este artigo explica o que \u00e9 o coeficiente de atrito (ou coeficiente de atrito) na f\u00edsica. Assim voc\u00ea descobrir\u00e1 como calcular o coeficiente de atrito, quais s\u00e3o os tipos de coeficientes de atrito e, al\u00e9m disso, exerc\u00edcios resolvidos passo a passo. Qual \u00e9 o coeficiente de atrito? O coeficiente de atrito , tamb\u00e9m chamado de &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/pt\/coeficiente-de-atrito-ou-coeficiente-de-atrito\/\"> <span class=\"screen-reader-text\">Coeficiente de atrito (ou coeficiente de atrito)<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-254","post","type-post","status-publish","format-standard","hentry","category-dinamico"],"yoast_head":"<!-- This site is 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