{"id":250,"date":"2023-06-23T08:09:09","date_gmt":"2023-06-23T08:09:09","guid":{"rendered":"https:\/\/physigeek.com\/pt\/peso-aparente\/"},"modified":"2023-06-23T08:09:09","modified_gmt":"2023-06-23T08:09:09","slug":"peso-aparente","status":"publish","type":"post","link":"https:\/\/physigeek.com\/pt\/peso-aparente\/","title":{"rendered":"Peso aparente"},"content":{"rendered":"<p>Neste artigo voc\u00ea aprender\u00e1 o que \u00e9 peso aparente, como calcular o peso aparente e um exerc\u00edcio resolvido sobre peso aparente. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-el-peso-aparente\"><\/span>Qual \u00e9 o peso aparente?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> O <strong>peso aparente<\/strong> de um corpo em um fluido \u00e9 a diferen\u00e7a entre o peso real do corpo e a for\u00e7a de empuxo exercida pelo fluido sobre o corpo.<\/p>\n<p> O peso aparente \u00e9, portanto, a for\u00e7a com a qual um corpo dentro de um fluido \u00e9 atra\u00eddo para o fundo do inv\u00f3lucro onde o fluido est\u00e1 localizado.<\/p>\n<p> Para entender o significado do peso aparente, voc\u00ea precisa ter clareza sobre o conceito de for\u00e7a de impulso. Ent\u00e3o voc\u00ea pode ver o que \u00e9 a for\u00e7a de impulso e como ela \u00e9 calculada no seguinte link: <\/p>\n<div style=\"background-color:#FFFDE7; padding-top: 10px; padding-bottom: 10px; padding-right: 10px; padding-left: 20px; border: 2.5px dashed #FFB74D; border-radius:20px;\"> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Veja:<\/strong> <a href=\"https:\/\/physigeek.com\/pt\/forca-de-empurrao\/\">O que \u00e9 for\u00e7a de impulso?<\/a> <\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Formula-del-peso-aparente\"><\/span> F\u00f3rmula de peso aparente<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> O peso aparente de um corpo \u00e9 igual \u00e0 diferen\u00e7a entre o peso real do corpo e a for\u00e7a de empuxo exercida pelo fluido sobre o corpo.<\/p>\n<p> A <strong>f\u00f3rmula do peso aparente<\/strong> \u00e9, portanto, a seguinte:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7b8736c539476a0c024e6448bae67c17_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_{apparent}=P_{r\u00e9el}-E\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"162\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p style=\"margin-bottom:5px\"> Ouro: <\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-8d83498b5889da421435b51a13fca7e5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_{apparent}\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"65\" style=\"vertical-align: -6px;\"><\/p>\n<p> \u00e9 o peso aparente do corpo, expresso em newtons. <\/span><\/li>\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-3b57a47305576c43737e66091c896613_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_{real}\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"35\" style=\"vertical-align: -3px;\"><\/p>\n<p> \u00e9 o peso real do corpo, expresso em newtons.<\/span><\/li>\n<li><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-638a7387bd72763290cc777a9b509c38_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"14\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a for\u00e7a de impulso, expressa em newtons.<\/span><\/li>\n<\/ul>\n<p> Por outro lado, lembre-se de que o peso \u00e9 igual \u00e0 massa corporal vezes a acelera\u00e7\u00e3o da gravidade.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-2e8bac7f5e595202312d9f0e2071ed10_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_{real}=m\\cdot g\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"98\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p> Da mesma forma, a for\u00e7a de impulso \u00e9 calculada multiplicando a densidade do fluido sob a gravidade pelo volume deslocado pelo corpo submerso. <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d74e9528f5afcbcfab4ad839d3d20607_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E=\\rho_f \\cdot g\\cdot V\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"104\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejemplo-resuelto-del-peso-aparente\"><\/span> Exemplo concreto de peso aparente<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Depois de vermos qual \u00e9 a defini\u00e7\u00e3o e a f\u00f3rmula do peso aparente, deixamos um exemplo concreto para que voc\u00eas possam ver como ele \u00e9 calculado.<\/p>\n<ul>\n<li> Um cubo cuja aresta mede 20 cm \u00e9 introduzido num recipiente cheio de \u00e1gua (\u03c1=1000 kg\/m <sup>3<\/sup> ) e fica completamente imerso. Se o cubo tem massa de 14 kg, qual \u00e9 o peso aparente do cubo? Dados: g=9,81 m\/ <sup>s2<\/sup> .<\/li>\n<\/ul>\n<p> Para determinar o peso aparente, devemos primeiro determinar o peso real e a for\u00e7a de impulso que o fluido aplica ao cubo.<\/p>\n<p> Assim, calculamos o peso real do cubo multiplicando sua massa pela gravidade:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-51b3474c32bed6a3f655525289081e42_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_{real}=m\\cdot g=14 \\cdot 9.81 =137.34\\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"278\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p> E por outro lado, calculamos a for\u00e7a de impulso. Se todo o corpo do cubo estiver imerso em \u00e1gua, isso significa que o volume de fluido deslocado ser\u00e1 equivalente ao volume do cubo:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7a31d9cd51fd2c8d9ef56ea0dd798773_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"V=0,2\\cdot 0,2\\cdot 0,2 = 0,008 \\ m^3\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"236\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p> Portanto, usamos a f\u00f3rmula para a for\u00e7a de impulso:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-4b97549c12905b01e6e86139202947e3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E=\\rho_f \\cdot g\\cdot V=1000 \\cdot 9,81\\cdot 0,008=78,48 \\N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"334\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p> Por fim, aplicamos a f\u00f3rmula do peso aparente para encontrar seu valor: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-4a69bbad1534d74632b9057d67d499aa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_{apparent}=P_{r\u00e9el}-E=137,34-78,48=58,86 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"392\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Peso-aparente-y-peso-real\"><\/span>Peso aparente e peso real<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> O peso aparente \u00e9 igual \u00e0 diferen\u00e7a entre o peso real do corpo e o impulso arquimediano exercido pelo fluido sobre o referido corpo.<\/p>\n<p> Portanto, <strong>a diferen\u00e7a entre o peso aparente e o peso real<\/strong> corresponde \u00e0 for\u00e7a de empuxo, que \u00e9 a for\u00e7a vertical ascendente que o fluido aplica ao corpo nele imerso.<\/p>\n<p> Al\u00e9m disso, dependendo do sinal do peso aparente, o corpo ir\u00e1 subir ou descer:<\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Peso aparente negativo<\/strong> : o corpo tende a subir dentro do fluido, ent\u00e3o a for\u00e7a de empuxo \u00e9 maior que a for\u00e7a do peso do corpo.<\/span><\/li>\n<p style=\"text-align:center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-3344d6711064a2ee12efc4f9d650c975_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E>P_{r\u00e9el}&#8221; title=&#8221;Rendered by QuickLaTeX.com&#8221; height=&#8221;15&#8243; width=&#8221;72&#8243; style=&#8221;vertical-align: -3px;&#8221;><\/p>\n<\/p>\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Peso aparente positivo<\/strong> : o corpo tende a descer no fluido, ou seja, o corpo afunda. Isso significa que a for\u00e7a de impulso \u00e9 menor que a for\u00e7a peso.<\/span><\/li>\n<p style=\"text-align:center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6f4091b8c09864f943d6f5d33193ecf0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" E\n\n<li style=&quot;margin-bottom:15px&quot;> <span style=&quot;color:#101010;font-weight: normal;&quot;><strong>Poids apparent nul<\/strong> : le corps est en \u00e9quilibre au sein du fluide, ou autrement dit, le corps reste suspendu au sein du fluide. Dans ce cas, la force de pouss\u00e9e appliqu\u00e9e par le fluide sur le corps est \u00e9quivalente \u00e0 son poids.<\/span><\/li>\n<p> [latex]E=P_{r\u00e9el}&#8221; title=&#8221;Rendered by QuickLaTeX.com&#8221; height=&#8221;106&#8243; width=&#8221;1417&#8243; style=&#8221;vertical-align: -5px;&#8221;><\/p>\n<\/p>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Neste artigo voc\u00ea aprender\u00e1 o que \u00e9 peso aparente, como calcular o peso aparente e um exerc\u00edcio resolvido sobre peso aparente. Qual \u00e9 o peso aparente? O peso aparente de um corpo em um fluido \u00e9 a diferen\u00e7a entre o peso real do corpo e a for\u00e7a de empuxo exercida pelo fluido sobre o corpo. &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/pt\/peso-aparente\/\"> <span class=\"screen-reader-text\">Peso aparente<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[12],"tags":[],"class_list":["post-250","post","type-post","status-publish","format-standard","hentry","category-mecanica-dos-fluidos"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 Qual \u00e9 o peso aparente? (f\u00f3rmula e exemplo)<\/title>\n<meta name=\"description\" content=\"Aqui voc\u00ea vai descobrir o que \u00e9 peso aparente, como calcular o peso aparente (f\u00f3rmula) e um exerc\u00edcio de peso aparente resolvido.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/physigeek.com\/pt\/peso-aparente\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u25b7 Qual \u00e9 o peso aparente? 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