{"id":246,"date":"2023-06-23T10:01:11","date_gmt":"2023-06-23T10:01:11","guid":{"rendered":"https:\/\/physigeek.com\/pt\/forca-de-empurrao\/"},"modified":"2023-06-23T10:01:11","modified_gmt":"2023-06-23T10:01:11","slug":"forca-de-empurrao","status":"publish","type":"post","link":"https:\/\/physigeek.com\/pt\/forca-de-empurrao\/","title":{"rendered":"For\u00e7a de impulso"},"content":{"rendered":"<p>Este artigo explica o que \u00e9 for\u00e7a de impulso. Voc\u00ea descobrir\u00e1, portanto, como calcular o empuxo, um exerc\u00edcio resoluto deste tipo de for\u00e7as e sua rela\u00e7\u00e3o com o empuxo, um conceito importante na mec\u00e2nica dos fluidos.<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-la-fuerza-de-empuje\"><\/span> O que \u00e9 for\u00e7a de impulso?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> A <strong>for\u00e7a de empuxo<\/strong> \u00e9 uma for\u00e7a vertical ascendente exercida por um fluido quando um corpo est\u00e1 imerso nele. Mais precisamente, o empuxo \u00e9 igual ao peso do volume deslocado pelo corpo submerso.<\/p>\n<p> A for\u00e7a de impulso baseia-se, portanto, no princ\u00edpio de Arquimedes. \u00c9 por isso que a for\u00e7a de empuxo \u00e9 \u00e0s vezes chamada de for\u00e7a de empuxo ou for\u00e7a de empuxo de Arquimedes.<\/p>\n<p> A for\u00e7a de impulso \u00e9 produzida pela press\u00e3o exercida por um fluido nas faces de qualquer corpo submerso. Como a press\u00e3o \u00e9 diretamente proporcional \u00e0 profundidade, a parte mais profunda do corpo recebe maior press\u00e3o que a parte superior e, portanto, o fluido exerce uma for\u00e7a ascendente sobre o corpo. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Formula-de-la-fuerza-de-empuje\"><\/span> F\u00f3rmula de for\u00e7a de impulso<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> A for\u00e7a de impulso \u00e9 igual ao peso do volume de l\u00edquido deslocado pelo corpo imerso (parcial ou totalmente) no fluido. Portanto, a for\u00e7a de impulso \u00e9 calculada multiplicando a densidade do fluido pela gravidade pelo volume de fluido deslocado.<\/p>\n<p> Portanto, a <strong>f\u00f3rmula da for\u00e7a de impulso<\/strong> \u00e9:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d74e9528f5afcbcfab4ad839d3d20607_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E=\\rho_f \\cdot g\\cdot V\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"104\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p style=\"margin-bottom:5px\"> Ouro: <\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-638a7387bd72763290cc777a9b509c38_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"14\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a for\u00e7a de impulso, expressa em newtons. <\/span><\/li>\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6da7d3aab222e3315c9879e9a2e42bdd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\rho_f\" title=\"Rendered by QuickLaTeX.com\" height=\"14\" width=\"17\" style=\"vertical-align: -6px;\"><\/p>\n<p> \u00e9 a densidade do fluido, expressa em kg\/m <sup>3<\/sup> . <\/span><\/li>\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e88010d25c51c0c42c505ee1004ed182_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"g\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"9\" style=\"vertical-align: -4px;\"><\/p>\n<p> \u00e9 o valor da acelera\u00e7\u00e3o da gravidade.<\/span><\/li>\n<li><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-54e215a7a583b4f357a5a627420bcf2f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"V\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"14\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 o volume deslocado pelo corpo submerso.<\/span><\/li>\n<\/ul>\n<p> Se voc\u00ea notar, o produto da densidade do fluido pela gravidade \u00e9 equivalente ao peso espec\u00edfico do fluido. Assim, a for\u00e7a de impulso tamb\u00e9m pode ser determinada pela seguinte express\u00e3o:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-a87e1a57e5f55acdbdf8b216be6cbff8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E=P_e\\cdot V\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"83\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p> Em condi\u00e7\u00f5es normais, a for\u00e7a de impulso \u00e9 vertical para cima e o seu ponto de aplica\u00e7\u00e3o \u00e9 o centro de gravidade do corpo submerso. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejemplo-del-calculo-de-la-fuerza-de-empuje\"><\/span> Exemplo de c\u00e1lculo da for\u00e7a de impulso<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Depois de vermos a defini\u00e7\u00e3o de for\u00e7a de impulso e qual \u00e9 sua f\u00f3rmula, esta se\u00e7\u00e3o mostra um exemplo de como esse tipo de for\u00e7a \u00e9 calculado.<\/p>\n<ul>\n<li> Um cubo cuja aresta mede 50 cm \u00e9 introduzido num recipiente cheio de \u00e1gua (\u03c1=1000 kg\/m <sup>3<\/sup> ). Se o cubo estiver completamente imerso no recipiente, qual ser\u00e1 o valor do impulso de Arquimedes aplicado pelo l\u00edquido ao cubo? Dados: g=9,81 m\/ <sup>s2<\/sup> .<\/li>\n<\/ul>\n<p> Se todo o corpo do cubo estiver imerso em \u00e1gua, isso significa que o volume de fluido deslocado ser\u00e1 equivalente ao volume do cubo. Portanto, primeiro calculamos o volume do cubo:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c9925f0bb2d8ab9801ca09f91391ef8b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"V=0,5\\cdot 0,5\\cdot 0,5 = 0,125 \\ m^3\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"236\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p> Portanto, usamos a f\u00f3rmula da for\u00e7a de impulso para encontrar seu valor:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d74e9528f5afcbcfab4ad839d3d20607_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E=\\rho_f \\cdot g\\cdot V\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"104\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p> E finalmente, substitu\u00edmos os dados na f\u00f3rmula e calculamos a for\u00e7a de impulso: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fd52db67a009ea87141e6dbc02f71479_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E=1000 \\cdot 9,81\\cdot 0,125=1226,25 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"283\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"La-fuerza-de-empuje-y-la-flotabilidad\"><\/span> flutuabilidade e for\u00e7a de impulso<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Nesta se\u00e7\u00e3o final, veremos a rela\u00e7\u00e3o entre for\u00e7a de impulso e empuxo, pois s\u00e3o dois conceitos intimamente relacionados na f\u00edsica.<\/p>\n<p> <strong>Flutuabilidade<\/strong> \u00e9 a capacidade de um corpo permanecer em equil\u00edbrio dentro de um fluido. Assim, para que um objeto flutue em um fluido, a for\u00e7a de empuxo exercida pelo fluido sobre o corpo deve ser igual \u00e0 for\u00e7a do peso do corpo. Caso contr\u00e1rio, o corpo subir\u00e1 ou descer\u00e1 dependendo do caso.<\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Flutuabilidade positiva<\/strong> : o corpo tende a subir dentro do fluido, ent\u00e3o a for\u00e7a de empuxo \u00e9 maior que a for\u00e7a do peso do corpo.<\/span><\/li>\n<p style=\"text-align:center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0a6ca0343de89b85f96b0362baf565f3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E>P&#8221; title=&#8221;Rendered by QuickLaTeX.com&#8221; height=&#8221;14&#8243; width=&#8221;52&#8243; style=&#8221;vertical-align: -2px;&#8221;><\/p>\n<\/p>\n<li style=\"margin-bottom:15px\"> <span style=\"color:#101010;font-weight: normal;\"><strong>Flutuabilidade negativa<\/strong> : o corpo tende a descer no fluido, ou seja, o corpo afunda. Isso significa que a for\u00e7a de impulso \u00e9 menor que a for\u00e7a peso.<\/span> <\/li>\n<p style=\"text-align:center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-dd6bd6ffb5d967766330c165fc4cabe3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" E\n\n<li style=&quot;margin-bottom:15px&quot;> <span style=&quot;color:#101010;font-weight: normal;&quot;><strong>Flottabilit\u00e9 neutre<\/strong> : le corps est en \u00e9quilibre au sein du fluide, ou autrement dit, le corps reste suspendu au sein du fluide. Dans ce cas, la force de pouss\u00e9e appliqu\u00e9e par le fluide sur le corps est \u00e9quivalente \u00e0 son poids.<\/span><\/li>\n<p> [latex]E=P&#8221; title=&#8221;Rendered by QuickLaTeX.com&#8221; height=&#8221;106&#8243; width=&#8221;1417&#8243; style=&#8221;vertical-align: -5px;&#8221;><\/p>\n<\/p>\n<\/ul>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/types-de-flottabilite.png\" alt=\"for\u00e7a de impulso e flutuabilidade\" class=\"wp-image-1062\" width=\"389\" height=\"289\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/types-de-flottabilite-300x224.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/types-de-flottabilite-768x573.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/types-de-flottabilite.png 879w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Este artigo explica o que \u00e9 for\u00e7a de impulso. Voc\u00ea descobrir\u00e1, portanto, como calcular o empuxo, um exerc\u00edcio resoluto deste tipo de for\u00e7as e sua rela\u00e7\u00e3o com o empuxo, um conceito importante na mec\u00e2nica dos fluidos. O que \u00e9 for\u00e7a de impulso? A for\u00e7a de empuxo \u00e9 uma for\u00e7a vertical ascendente exercida por um fluido &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/pt\/forca-de-empurrao\/\"> <span class=\"screen-reader-text\">For\u00e7a de impulso<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[12],"tags":[],"class_list":["post-246","post","type-post","status-publish","format-standard","hentry","category-mecanica-dos-fluidos"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 O que \u00e9 for\u00e7a de impulso? 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