{"id":243,"date":"2023-06-23T11:17:07","date_gmt":"2023-06-23T11:17:07","guid":{"rendered":"https:\/\/physigeek.com\/pt\/energia-potencial-elastica\/"},"modified":"2023-06-23T11:17:07","modified_gmt":"2023-06-23T11:17:07","slug":"energia-potencial-elastica","status":"publish","type":"post","link":"https:\/\/physigeek.com\/pt\/energia-potencial-elastica\/","title":{"rendered":"Energia potencial el\u00e1stica"},"content":{"rendered":"<p>Neste artigo voc\u00ea descobrir\u00e1 o que \u00e9 energia potencial el\u00e1stica, como calcular a energia potencial el\u00e1stica e, al\u00e9m disso, diversos exerc\u00edcios resolvidos passo a passo para praticar. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-la-energia-potencial-elastica\"><\/span> O que \u00e9 energia potencial el\u00e1stica?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Energia potencial el\u00e1stica<\/strong> , ou simplesmente <strong>energia el\u00e1stica<\/strong> , \u00e9 a energia acumulada no interior de um corpo deform\u00e1vel pelo trabalho realizado por uma for\u00e7a el\u00e1stica.<\/p>\n<p> Ou seja, a energia potencial el\u00e1stica \u00e9 um tipo de energia potencial associada \u00e0 for\u00e7a el\u00e1stica (ou for\u00e7a de recupera\u00e7\u00e3o).<\/p>\n<p> Por exemplo, quando uma mola \u00e9 comprimida ou alongada, a energia potencial el\u00e1stica \u00e9 armazenada. Na verdade, em f\u00edsica, problemas de molas s\u00e3o frequentemente resolvidos para aprender o conceito de energia potencial el\u00e1stica. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Formula-de-la-energia-potencial-elastica\"><\/span> F\u00f3rmula para energia potencial el\u00e1stica<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> A energia potencial el\u00e1stica de uma mola \u00e9 igual \u00e0 metade da constante el\u00e1stica da mola vezes o quadrado do deslocamento da mola.<\/p>\n<p> Portanto, a <strong>f\u00f3rmula da energia potencial el\u00e1stica<\/strong> \u00e9: <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique.png\" alt=\"energia potencial el\u00e1stica\" class=\"wp-image-4110\" width=\"289\" height=\"289\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique-300x300.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique-150x150.png 150w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique.png 525w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<p style=\"margin-bottom:5px\"> Ouro: <\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-09b2ab0fbfe1c76e7f3bf527fc17889c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_p\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"20\" style=\"vertical-align: -6px;\"><\/p>\n<p> \u00e9 a energia potencial el\u00e1stica, cuja unidade no Sistema Internacional \u00e9 o joule (J). <\/span><\/li>\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d42bc2203d6f76ad01b27ac9acc0bee1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"k\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"9\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a constante el\u00e1stica da mola, cujas unidades s\u00e3o N\/m.<\/span><\/li>\n<li><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7e5fbfa0bbbd9f3051cd156a0f1b5e31_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"10\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a dist\u00e2ncia at\u00e9 a posi\u00e7\u00e3o de equil\u00edbrio, expressa em metros. <\/span><\/li>\n<\/ul>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Energia-potencial-elastica-y-trabajo\"><\/span> Energia potencial el\u00e1stica e trabalho<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> O trabalho realizado por uma for\u00e7a el\u00e1stica \u00e9 calculado multiplicando-se a metade da f\u00f3rmula da for\u00e7a el\u00e1stica, definida pela <a href=\"https:\/\/physigeek.com\/pt\/lei-de-hooke\/\">lei de Hooke<\/a> , pelo deslocamento realizado. Assim, o trabalho de uma for\u00e7a el\u00e1stica \u00e9 equivalente \u00e0 \u00e1rea do seguinte tri\u00e2ngulo: <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elasticite-travail.png\" alt=\"energia potencial el\u00e1stica e trabalho\" class=\"wp-image-4115\" width=\"313\" height=\"263\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elasticite-travail-300x252.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elasticite-travail.png 454w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<p> Da mesma forma, o trabalho da for\u00e7a el\u00e1stica \u00e9 igual \u00e0 varia\u00e7\u00e3o negativa da energia potencial el\u00e1stica:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-b9ec4024e50b6145e2b40308562d3245_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"W_p=-\\Delta E_p \" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"97\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0534be0cea1bfe9a5658cafa6a63f09f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"W_p=-\\left(E_{p_{final}}-E_{p_{initial}}\\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"209\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p> Por\u00e9m, se a mola parte da posi\u00e7\u00e3o de equil\u00edbrio, o trabalho da for\u00e7a el\u00e1stica s\u00f3 \u00e9 equivalente \u00e0 energia potencial el\u00e1stica final, pois a energia potencial el\u00e1stica na posi\u00e7\u00e3o de equil\u00edbrio \u00e9 zero (o deslocamento \u00e9 nulo). <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-3410e455493de66bceb6b779165edfe0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"W_p=-\\left(E_{p_{final}}-\\cancelto{0}{E_{p_{equilibrium}}}\\right) =-E_{p_{final}}\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"334\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Energia-potencial-elastica-y-energia-cinetica\"><\/span> Energia potencial el\u00e1stica e energia cin\u00e9tica<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Quando uma mola \u00e9 comprimida ou alongada e liberada, a mola adquire velocidade. Portanto, uma mola pode ter energia potencial el\u00e1stica e energia cin\u00e9tica.<\/p>\n<p> Al\u00e9m disso, se n\u00e3o levarmos em conta o atrito, a energia da mola n\u00e3o se perde, mas sim transformada (princ\u00edpio da conserva\u00e7\u00e3o da energia). Assim, a energia potencial el\u00e1stica pode ser convertida em energia cin\u00e9tica e vice-versa, mas a energia total n\u00e3o ser\u00e1 reduzida.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-2aff47ab4f297de9c53f400a9eecd59d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_{p_i}+E_{c_i}=E_{p_f}+E_{c_f}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"173\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p> Assim, quando a energia potencial el\u00e1stica for m\u00e1xima, ou seja, quando a mola estiver completamente esticada ou comprimida, a energia cin\u00e9tica ser\u00e1 zero. Da mesma forma, quando a energia cin\u00e9tica for m\u00e1xima, ou seja, quando a mola estiver em posi\u00e7\u00e3o de equil\u00edbrio, a energia potencial el\u00e1stica ser\u00e1 zero. <\/p>\n<figure class=\"wp-block-image aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique-energie-cinetique.png\" alt=\"energia potencial el\u00e1stica e energia cin\u00e9tica\" class=\"wp-image-4139\" width=\"437\" height=\"525\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique-energie-cinetique-250x300.png 250w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique-energie-cinetique-852x1024.png 852w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique-energie-cinetique-768x923.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique-energie-cinetique.png 920w\" sizes=\"auto, (max-width: 250px) 100vw, 250px\"><\/figure>\n<p> Assim, a mola move-se continuamente da posi\u00e7\u00e3o m\u00e1xima para a posi\u00e7\u00e3o m\u00ednima, produzindo assim um movimento oscilat\u00f3rio. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicios-resueltos-de-la-energia-potencial-elastica\"><\/span> Exerc\u00edcios resolvidos sobre energia potencial el\u00e1stica<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 1<\/h3>\n<p> Calcule a energia potencial el\u00e1stica armazenada em uma mola comprimida em 60 cm cuja constante el\u00e1stica \u00e9 125 N\/m. <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Neste caso, para encontrar a energia potencial el\u00e1stica, basta utilizar a f\u00f3rmula correspondente, que \u00e9:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d2f4828b6b0f47984aaa21db09088c1a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_p=\\cfrac{1}{2}\\cdot k \\cdot x^2\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"108\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> A seguir, substitu\u00edmos os dados na f\u00f3rmula e calculamos a energia potencial el\u00e1stica: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6cb7cefbfa6fb113024875b9a74c0704_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_p=\\cfrac{1}{2}\\cdot 125 \\cdot 0,6^2=22,5 \\ J\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"217\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Exerc\u00edcio 2<\/h3>\n<p> Uma massa de 4 kg est\u00e1 presa a uma mola de constante 240 N\/m. Se a mola for esticada 35 cm, qual a velocidade m\u00e1xima que a massa adquire? E quando? Desprezamos o atrito e a massa da mola durante todo o exerc\u00edcio. <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Como vimos na teoria explicada ao longo do artigo, o valor da energia cin\u00e9tica m\u00e1xima de uma mola equivale ao valor da sua energia potencial el\u00e1stica m\u00e1xima. Ent\u00e3o primeiro calcularemos a energia potencial el\u00e1stica m\u00e1xima e a partir da\u00ed a velocidade m\u00e1xima.<\/p>\n<p class=\"has-text-align-left\"> A energia potencial m\u00e1xima que a mola atingir\u00e1 ser\u00e1 no seu deslocamento m\u00e1ximo, ou seja, quando for esticada 35 cm. Portanto, calculamos a energia potencial el\u00e1stica nesta situa\u00e7\u00e3o:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-08e679b77dab99372b927bdf9e1ef672_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_{p_{m\\'ax}}=\\cfrac{1}{2}\\cdot k \\cdot x^2=\\cfrac{1}{2}\\cdot 240\\cdot 0,35^2= 14,7\\ J\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"338\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Assim, a energia cin\u00e9tica m\u00e1xima ser\u00e1 atingida em outro ponto, exatamente no momento em que a mola passa pela sua posi\u00e7\u00e3o de equil\u00edbrio. Mas o seu valor ser\u00e1 igual ao da energia potencial el\u00e1stica m\u00e1xima:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-4ef529c89fa2f18832b3326e13fe9b8d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_{c_{m\\'ax}}=E_{p_{m\\'ax}}=14,7 \\ J\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"190\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Por fim, basta calcular a velocidade que corresponde a esta energia cin\u00e9tica atrav\u00e9s da f\u00f3rmula correspondente: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d2ce3408631a61e46a1805d12f3ec1d7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle E_{c_{m\\'ax}}=\\cfrac{1}{2}\\cdot m \\cdot v_{m\\'ax}}^2 \\ \\longrightarrow \\ v_{m\\'ax} } =\\sqrt{\\frac{2\\cdot E_{c_{m\\'ax}}}{m}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"356\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-3d39d86532e99274a7b3e8812aec2d16_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle v_{m\\'ax}} =\\sqrt{\\frac{2\\cdot E_{c_{m\\'ax}}}{m}}=\\sqrt{\\frac{2\\cdot 14, 7}{4}}=2,71 \\ \\frac{m}{s}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"332\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Resumindo, a velocidade m\u00e1xima que a massa ir\u00e1 adquirir ser\u00e1 de 2,71 m\/s e ela a atingir\u00e1 cada vez que passar pela posi\u00e7\u00e3o de equil\u00edbrio.<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\"> Exerc\u00edcio 3<\/h3>\n<p> Suspendemos uma massa m = 2 kg em uma mola fixada no teto. Imediatamente, a mola \u00e9 esticada \u0394X=50 cm at\u00e9 que uma nova posi\u00e7\u00e3o de equil\u00edbrio seja obtida a uma altura de h=3 m do solo. Qual \u00e9 a energia potencial total armazenada? Dados: k=40 N\/m; g = 10m\/s. <\/p>\n<figure class=\"wp-block-image aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-energie-resolue-potentiel-elastique-ressort-ressort.png\" alt=\"problema resolvido de energia el\u00e1stica\" class=\"wp-image-4142\" width=\"133\" height=\"489\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-energie-resolue-potentiel-elastique-ressort-ressort-82x300.png 82w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-energie-resolue-potentiel-elastique-ressort-ressort-279x1024.png 279w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-energie-resolue-potentiel-elastique-ressort-ressort.png 358w\" sizes=\"auto, (max-width: 82px) 100vw, 82px\"><\/figure>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja a solu\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> A energia potencial el\u00e1stica total ser\u00e1 a soma da energia potencial el\u00e1stica da mola mais a energia potencial gravitacional da massa.<\/p>\n<p class=\"has-text-align-left\"> Ent\u00e3o, primeiro calculamos a energia potencial el\u00e1stica aplicando a f\u00f3rmula explicada no artigo:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7f1c525a7629730f7f6094e12ac7bb1d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_{p_{el\\'astica}}=\\cfrac{1}{2}\\cdot k \\cdot x^2=\\cfrac{1}{2}\\cdot 40\\cdot 0.5^2= 5 \\ J\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"311\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> A seguir, calculamos a energia potencial gravitacional usando a f\u00f3rmula correspondente:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-f16585ff1c7650cc38f0e69fa53e6034_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_{p_{hauteur}}=m\\cdot g \\cdot h =2 \\cdot 10 \\cdot 3 =60 \\ J\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"294\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> A energia potencial total \u00e9, portanto, a soma das duas energias potenciais calculadas: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-a60ec0c6fe0591fb20033ec30a2a4ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_{p_{Total}}=E_{p_{el\\'astica}}+E_{p_{hauteur}}=5+60=65 \\ J\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"358\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Neste artigo voc\u00ea descobrir\u00e1 o que \u00e9 energia potencial el\u00e1stica, como calcular a energia potencial el\u00e1stica e, al\u00e9m disso, diversos exerc\u00edcios resolvidos passo a passo para praticar. O que \u00e9 energia potencial el\u00e1stica? Energia potencial el\u00e1stica , ou simplesmente energia el\u00e1stica , \u00e9 a energia acumulada no interior de um corpo deform\u00e1vel pelo trabalho realizado &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/pt\/energia-potencial-elastica\/\"> <span class=\"screen-reader-text\">Energia potencial el\u00e1stica<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-243","post","type-post","status-publish","format-standard","hentry","category-dinamico"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - 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