{"id":236,"date":"2023-06-23T14:44:52","date_gmt":"2023-06-23T14:44:52","guid":{"rendered":"https:\/\/physigeek.com\/pt\/campo-gravitacional-ou-campo-gravitacional\/"},"modified":"2023-06-23T14:44:52","modified_gmt":"2023-06-23T14:44:52","slug":"campo-gravitacional-ou-campo-gravitacional","status":"publish","type":"post","link":"https:\/\/physigeek.com\/pt\/campo-gravitacional-ou-campo-gravitacional\/","title":{"rendered":"Campo gravitacional (ou campo gravitacional)"},"content":{"rendered":"<p>Este artigo explica o que \u00e9 o campo gravitacional, tamb\u00e9m chamado de campo gravitacional. Assim, voc\u00ea encontrar\u00e1 a defini\u00e7\u00e3o do campo gravitacional, sua f\u00f3rmula e um exemplo de seu c\u00e1lculo. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-el-campo-gravitatorio-o-campo-gravitacional\"><\/span> Qual \u00e9 o campo gravitacional (ou campo gravitacional)?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> O <strong>campo gravitacional<\/strong> , ou <strong>campo gravitacional<\/strong> , \u00e9 o campo de for\u00e7a que representa a gravidade. Em outras palavras, o campo gravitacional \u00e9 a extens\u00e3o do espa\u00e7o em que um corpo com massa atrai outro.<\/p>\n<p> Portanto, o campo gravitacional de uma massa \u00e9 a regi\u00e3o do espa\u00e7o em que essa massa atrai todas as outras massas pela for\u00e7a gravitacional.<\/p>\n<p> Logicamente, quanto maior a massa de um corpo, maior ser\u00e1 o seu campo gravitacional. \u00c9 por isso que corpos contendo muita mat\u00e9ria, por exemplo planetas, exercem for\u00e7as gravitacionais significativas. Em contraste, objetos de baixa massa, como um l\u00e1pis, quase n\u00e3o t\u00eam for\u00e7a gravitacional (s\u00e3o negligenciados). A seguir veremos como \u00e9 calculada a intensidade de um campo gravitacional.<\/p>\n<p> Observe que o campo gravitacional \u00e9 considerado um campo vetorial na f\u00edsica newtoniana ou cl\u00e1ssica, enquanto na f\u00edsica relativ\u00edstica \u00e9 um campo tensorial. Assim, para resolver os problemas fundamentais relativos ao campo gravitacional, ele deve ser tratado como um campo vetorial. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Formula-del-campo-gravitatorio\"><\/span> F\u00f3rmula do campo gravitacional<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> A intensidade do campo gravitacional (ou campo gravitacional) de um corpo \u00e9 igual \u00e0 constante gravitacional universal multiplicada pela massa do corpo dividida pelo quadrado da dist\u00e2ncia entre o ponto em quest\u00e3o e o centro do corpo.<\/p>\n<p> A <strong>f\u00f3rmula para calcular a intensidade do campo gravitacional<\/strong> \u00e9, portanto, a seguinte:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-278bac151b8b02af9dbca5a377d8823e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"g=\\cfrac{G\\cdot M}{r^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"81\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p style=\"margin-bottom:5px\"> Ouro: <\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e88010d25c51c0c42c505ee1004ed182_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"g\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"9\" style=\"vertical-align: -4px;\"><\/p>\n<p> \u00e9 o campo gravitacional. <\/span><\/li>\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-1e40206e25474f738eeb7ca968031abf_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"G\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"14\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a constante gravitacional universal, cujo valor \u00e9<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-9d75ef18969b22581b72ad88a7def60c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"6,674\\cdot 10^{-11} \\ N\\cdot m^2\/kg^2\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"192\" style=\"vertical-align: -5px;\"><\/p>\n<p> . <\/span><\/li>\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-27d6692c77760dc1111628e74a6d272f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"19\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a massa do corpo que cria o campo gravitacional, expressa em quilogramas.<\/span><\/li>\n<li><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-01bcf7e9e043561da78fecf715c8a46e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"r\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"8\" style=\"vertical-align: 0px;\"><\/p>\n<p> \u00e9 a dist\u00e2ncia entre o corpo que cria o campo gravitacional e o corpo atra\u00eddo, expressa em metros.<\/span><\/li>\n<\/ul>\n<p> Portanto, o s\u00edmbolo do campo gravitacional \u00e9 um g min\u00fasculo e suas unidades s\u00e3o m\/s <sup>2<\/sup> , pois \u00e9 uma acelera\u00e7\u00e3o. Mais precisamente, \u00e9 a acelera\u00e7\u00e3o com que o corpo que exerce o campo gravitacional atrai outro corpo. <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/champ-gravitationnel.png\" alt=\"campo gravitacional\" class=\"wp-image-3922\" width=\"244\" height=\"206\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/champ-gravitationnel-300x253.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/champ-gravitationnel.png 520w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:12px\"> <span style=\"color:#101010;font-weight: normal;\">Observe que o campo gravitacional n\u00e3o depende da massa do objeto atra\u00eddo, mas da massa que cria o campo e da dist\u00e2ncia entre os dois corpos.<\/span><\/li>\n<li style=\"margin-bottom:12px\"> <span style=\"color:#101010;font-weight: normal;\">Al\u00e9m disso, a dire\u00e7\u00e3o do campo gravitacional \u00e9 a linha imagin\u00e1ria que passa entre a massa que cria o campo e a massa atra\u00edda pelo campo.<\/span><\/li>\n<li> <span style=\"color:#101010;font-weight: normal;\">Finalmente, ao considerar o campo gravitacional como um campo vetorial, a dire\u00e7\u00e3o do vetor \u00e9 em dire\u00e7\u00e3o ao centro de massa que cria o campo.<\/span> <\/li>\n<\/ul>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Campo-gravitatorio-de-la-Tierra\"><\/span> Campo gravitacional da Terra<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Agora que sabemos o significado do campo gravitacional, vamos calcular a intensidade do campo gravitacional da Terra para que voc\u00ea veja como isso \u00e9 feito.<\/p>\n<p> Para fazer isso, devemos aplicar a f\u00f3rmula do campo gravitacional:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-2d7d5f61b9b8b498cdb664565d2c0b59_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" g=G\\cdot \\cfrac{M}{R^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"83\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Os valores da constante gravitacional universal, da massa da Terra e do raio do centro do planeta \u00e0 sua superf\u00edcie s\u00e3o:<\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:8px\"> <span style=\"color:#101010;font-weight: normal;\">G = 6,674 \u00b7 10 <sup>-11<\/sup> N\u00b7m <sup>2<\/sup> \/kg <sup>2<\/sup><\/span><\/li>\n<li style=\"margin-bottom:8px\"> <span style=\"color:#101010;font-weight: normal;\">M = 5,972 10 <sup>24kg<\/sup><\/span><\/li>\n<li> <span style=\"color:#101010;font-weight: normal;\">R = 6371000m<\/span><\/li>\n<\/ul>\n<p class=\"has-text-align-left\"> Assim, substitu\u00edmos os dados na f\u00f3rmula e calculamos o valor do campo gravitacional na superf\u00edcie da Terra:<\/p>\n<p class=\"has-text-align-center\"> [l\u00e1tex] g=6,674\\cdot 10^{-11}\\cdot \\cfrac{5,972\\cdot 10^{24}}{6371000^2}=9,81 \\\\cfrac{m}{s^2}[\/l\u00e1tex]<\/p>\n<p> Resumindo, o valor do campo gravitacional na superf\u00edcie da Terra \u00e9 9,81 m\/s <sup>2<\/sup> . <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Campo-gravitatorio-y-campo-electrico\"><\/span> Campo gravitacional e campo el\u00e9trico<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Por fim, veremos qual a diferen\u00e7a entre o campo gravitacional e o campo el\u00e9trico, pois s\u00e3o dois tipos de campos vetoriais normalmente trabalhados na f\u00edsica.<\/p>\n<p> A principal <strong>diferen\u00e7a entre o campo gravitacional e o campo el\u00e9trico<\/strong> \u00e9 que o campo gravitacional sempre existe para todos os corpos, enquanto o campo el\u00e9trico s\u00f3 existe quando os corpos est\u00e3o eletricamente carregados.<\/p>\n<p> Assim, qualquer objeto com massa exerce sempre uma for\u00e7a gravitacional, embora, logicamente, se a sua massa for muito pequena, a for\u00e7a gravitacional que exerce tamb\u00e9m ser\u00e1 pequena. enquanto um corpo s\u00f3 exercer\u00e1 uma for\u00e7a el\u00e9trica quando estiver carregado com eletricidade.<\/p>\n<p> Al\u00e9m disso, o campo el\u00e9trico pode ser atrativo ou repulsivo, uma vez que dois corpos eletricamente carregados podem se atrair (se estiverem carregados com sinais diferentes) ou se repelirem (se estiverem carregados com o mesmo sinal). Por\u00e9m, o campo gravitacional ainda \u00e9 um campo de atra\u00e7\u00e3o, pois a for\u00e7a da gravidade atrai um corpo em dire\u00e7\u00e3o a outro.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Este artigo explica o que \u00e9 o campo gravitacional, tamb\u00e9m chamado de campo gravitacional. Assim, voc\u00ea encontrar\u00e1 a defini\u00e7\u00e3o do campo gravitacional, sua f\u00f3rmula e um exemplo de seu c\u00e1lculo. Qual \u00e9 o campo gravitacional (ou campo gravitacional)? O campo gravitacional , ou campo gravitacional , \u00e9 o campo de for\u00e7a que representa a gravidade. &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/pt\/campo-gravitacional-ou-campo-gravitacional\/\"> <span class=\"screen-reader-text\">Campo gravitacional (ou campo gravitacional)<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-236","post","type-post","status-publish","format-standard","hentry","category-dinamico"],"yoast_head":"<!-- This site is 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