{"id":14,"date":"2023-06-27T19:33:24","date_gmt":"2023-06-27T19:33:24","guid":{"rendered":"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/"},"modified":"2023-06-27T19:33:24","modified_gmt":"2023-06-27T19:33:24","slug":"componentes-de-uma-forca","status":"publish","type":"post","link":"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/","title":{"rendered":"Componentes de uma for\u00e7a"},"content":{"rendered":"<p>Este artigo explica quais s\u00e3o os componentes de uma for\u00e7a e como s\u00e3o calculados. Al\u00e9m disso, voc\u00ea poder\u00e1 ver exemplos resolvidos de c\u00e1lculo de componentes de for\u00e7a. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-son-las-componentes-de-una-fuerza\"><\/span> Quais s\u00e3o os componentes de uma for\u00e7a?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Os <strong>componentes de uma for\u00e7a<\/strong> s\u00e3o as proje\u00e7\u00f5es de uma for\u00e7a nos eixos de refer\u00eancia. Se trabalharmos no sistema de coordenadas cartesianas, uma for\u00e7a tem duas componentes: a componente ao longo do eixo X e a componente ao longo do eixo Y.<\/p>\n<p> Normalmente, as for\u00e7as s\u00e3o aplicadas no sistema de coordenadas cartesianas, portanto os dois componentes de uma for\u00e7a no plano s\u00e3o geralmente chamados <strong>de componente horizontal<\/strong> e <strong>componente vertical<\/strong> da for\u00e7a. <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/composantes-dune-force.png\" alt=\"componentes de uma for\u00e7a\" class=\"wp-image-237\" width=\"252\" height=\"253\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/composantes-dune-force-300x300.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/composantes-dune-force-150x150.png 150w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/composantes-dune-force.png 627w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<p> Tenha em mente que unir vetores<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0b35266aff72392f18054a3ee0726b72_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{i}\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"6\" style=\"vertical-align: 0px;\"><\/p>\n<p> E<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e64160920c9450edf06e8f621fe04ba2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{j}\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"9\" style=\"vertical-align: -4px;\"><\/p>\n<p> \u00e0s vezes s\u00e3o usados para expressar os componentes retangulares de uma for\u00e7a de outra maneira: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-94172e0b2af1621d2a6288b24e221779_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{F}=\\vv{F_x}+\\vv{F_y}=F_x\\cdot \\vv{i}+F_y\\cdot \\vv{j}\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"223\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Como-calcular-las-componentes-de-una-fuerza\"><\/span> Como calcular os componentes de uma for\u00e7a<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Os componentes retangulares de uma for\u00e7a s\u00e3o calculados usando as raz\u00f5es trigonom\u00e9tricas de seno e cosseno.<\/strong><\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:12px\"> <span style=\"color:#101010;font-weight: normal;\">A componente horizontal de uma for\u00e7a \u00e9 igual \u00e0 magnitude da for\u00e7a vezes o cosseno do \u00e2ngulo de inclina\u00e7\u00e3o da for\u00e7a.<\/span><\/li>\n<li> <span style=\"color:#101010;font-weight: normal;\">A componente vertical de uma for\u00e7a \u00e9 igual \u00e0 magnitude da for\u00e7a vezes o seno do \u00e2ngulo de inclina\u00e7\u00e3o da for\u00e7a.<\/span> <\/li>\n<\/ul>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/decomposition-vectorielle-dune-force.png\" alt=\"decomposi\u00e7\u00e3o vetorial de uma for\u00e7a\" class=\"wp-image-184\" width=\"340\" height=\"273\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/decomposition-vectorielle-dune-force-300x242.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/decomposition-vectorielle-dune-force-768x619.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/decomposition-vectorielle-dune-force.png 814w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>veja a demonstra\u00e7\u00e3o<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Qualquer for\u00e7a vetorial forma um tri\u00e2ngulo ret\u00e2ngulo com seus componentes vetoriais. Podemos, portanto, relacionar o m\u00f3dulo aos componentes aplicando raz\u00f5es trigonom\u00e9tricas.<\/p>\n<p class=\"has-text-align-left\"> O cosseno de um \u00e2ngulo \u00e9 igual ao ramo cont\u00ednuo dividido pela hipotenusa do tri\u00e2ngulo ret\u00e2ngulo, no nosso caso a hipotenusa \u00e9 o m\u00f3dulo da for\u00e7a e a componente horizontal \u00e9 o lado cont\u00ednuo:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c6586c2f16a4d9f38abfa1da91156abb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{cos}(\\alpha)=\\cfrac{F_x}{F}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"95\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Assim, a partir da rela\u00e7\u00e3o matem\u00e1tica anterior, podemos resolver a componente X da for\u00e7a:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-56c5cd1e545655a07c011ff5f7c07005_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_x=F\\cdot \\text{cos}(\\alpha)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"118\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Por outro lado, podemos aplicar o mesmo racioc\u00ednio para obter a f\u00f3rmula da componente Y da for\u00e7a, mas utilizando o seno.<\/p>\n<p class=\"has-text-align-left\"> O seno de um \u00e2ngulo \u00e9 igual ao ramo oposto dividido pela hipotenusa do tri\u00e2ngulo ret\u00e2ngulo, no nosso caso a hipotenusa \u00e9 o m\u00f3dulo da for\u00e7a e a componente vertical \u00e9 o lado oposto ao \u00e2ngulo:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d8a9790805082b3dc429cac7728b4085_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\text{sin}(\\alpha)=\\cfrac{F_y}{F}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"93\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> E finalmente, resolvemos a componente Y da for\u00e7a: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-33e91f744879940077c4bb29e56103a1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_y=F\\cdot \\text{sin}(\\alpha)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"116\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<p> O processo de determina\u00e7\u00e3o dos componentes vetoriais de uma for\u00e7a \u00e9 denominado <strong>decomposi\u00e7\u00e3o vetorial de uma for\u00e7a<\/strong> .<\/p>\n<p> Tenha em mente que se o \u00e2ngulo que conhecemos n\u00e3o for o \u00e2ngulo que a for\u00e7a faz com o eixo horizontal, as f\u00f3rmulas mudar\u00e3o. Por exemplo, se conhecermos apenas o \u00e2ngulo que a for\u00e7a faz com o eixo vertical, devemos usar cosseno para a componente vertical e seno para a componente horizontal. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejemplos-de-componentes-de-fuerzas\"><\/span> Exemplos de componentes de for\u00e7a<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Agora que conhecemos a defini\u00e7\u00e3o, veremos dois exerc\u00edcios resolvidos sobre como determinar as componentes de uma for\u00e7a.<\/p>\n<h3 class=\"wp-block-heading\"> Exemplo 1<\/h3>\n<p> Quais s\u00e3o as componentes cartesianas de uma for\u00e7a de 8 N inclinada 35\u00ba em rela\u00e7\u00e3o ao eixo horizontal? <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-dangle-de-force.png\" alt=\"exemplo resolvido de decomposi\u00e7\u00e3o vetorial de uma for\u00e7a\" class=\"wp-image-244\" width=\"181\" height=\"131\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-dangle-de-force-300x218.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-dangle-de-force.png 477w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<p class=\"has-text-align-left\"> Para vetorizar a for\u00e7a, basta usar as f\u00f3rmulas de seno e cosseno vistas acima.<\/p>\n<p> A componente horizontal \u00e9 o valor da for\u00e7a multiplicado pelo cosseno do \u00e2ngulo:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d571254931adef0fb7be9e89291dcd2a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{x}=F\\cdot \\text{cos}(\\alpha)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"118\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-b9a2b759f95332e4757b6eea399e2803_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{x}=8\\cdot \\text{cos}(35\u00ba)=6,55 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"201\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> E a componente vertical \u00e9 a intensidade da for\u00e7a multiplicada pelo seno do \u00e2ngulo:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-65831d656a918fcf2158e42f52bb40fe_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{y}=F\\cdot \\text{sin}(\\alpha)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"116\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fba01cc1bd3c5d903cb7a9f30745877b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{y}=8\\cdot \\text{sin}(35\u00ba)=4.59 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"195\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<h3 class=\"wp-block-heading\"> Exemplo 2<\/h3>\n<p> Encontre as componentes vetoriais da for\u00e7a gravitacional do peso que atua no pr\u00f3ximo corpo de 5 kg nos eixos 1-2 mostrados. <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/composants-forcer-lexercice-de-poids-resolu.png\" alt=\"exerc\u00edcio resolvido dos componentes de uma for\u00e7a\" class=\"wp-image-248\" width=\"282\" height=\"275\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/composants-forcer-lexercice-de-poids-resolu-300x292.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/composants-forcer-lexercice-de-poids-resolu.png 739w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<p> Em primeiro lugar, precisamos encontrar o valor da for\u00e7a do peso, por isso usamos a f\u00f3rmula correspondente:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-5f72110e8ae23e229d642d19404b5afb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=m\\cdot g= 5\\cdot 9,81=49,05 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"244\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p> E agora que sabemos o que \u00e9 a for\u00e7a, podemos determinar as suas componentes retangulares. O \u00e2ngulo entre a componente P <sub>2<\/sub> e a for\u00e7a P \u00e9 equivalente ao \u00e2ngulo de inclina\u00e7\u00e3o, portanto podemos utilizar as f\u00f3rmulas para as componentes com este \u00e2ngulo: <\/p>\n<p class=\"has-text-align-center\"><meta charset=\"utf-8\"><\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-5cc136ba4ebd72cc2abc20b8dd3e26f8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_{1}=P\\cdot \\text{sin}(25\u00ba)=49,05\\cdot \\text{sin}(25\u00ba)=20,73 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"345\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\"><meta charset=\"utf-8\"><\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-b19e0829ddabb1f6400983a90c3ab107_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_{2}=-P\\cdot \\text{cos}(25\u00ba)=-49.05\\cdot \\text{cos}(25\u00ba)=-44.45 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"384\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p> A componente P <sub>2<\/sub> \u00e9 negativa porque sua dire\u00e7\u00e3o \u00e9 oposta \u00e0 dire\u00e7\u00e3o do eixo.<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Composicion-de-una-fuerza\"><\/span>Composi\u00e7\u00e3o de uma for\u00e7a<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Se voc\u00ea chegou at\u00e9 aqui, significa que j\u00e1 sabe calcular os componentes de uma for\u00e7a. Bom, agora veremos o processo inverso, ou seja, como determinar o m\u00f3dulo de uma for\u00e7a a partir de suas componentes retangulares.<\/p>\n<p> Para encontrar a <strong>amplitude de uma for\u00e7a<\/strong> (ou m\u00f3dulo de uma for\u00e7a), deve-se calcular a raiz quadrada da soma dos quadrados dos componentes dessa for\u00e7a.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-5efea5b1af1e668897135a5cd6a2f998_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{vmatrix}\\vv{F}\\end{vmatrix}=\\sqrt{F_x^2+F_y^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"32\" width=\"130\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> <span style=\"color:#4fd12f\">\u27a4<\/span> <strong>Veja:<\/strong> <span style=\"text-decoration: underline;\"><a href=\"https:\/\/physigeek.com\/pt\">qu\u00e3o grande \u00e9 uma for\u00e7a?<\/a><\/span><\/p>\n<p> Este processo \u00e9 denominado <strong>composi\u00e7\u00e3o de for\u00e7as<\/strong> .<\/p>\n<p> Por exemplo, se a componente horizontal de uma for\u00e7a for 6 N e a sua componente vertical for 8 N, a magnitude da for\u00e7a ser\u00e1:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-cacbf1bd54fa646a04b28d3613acce2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{aligned}\\begin{vmatrix}\\vv{F}\\end{vmatrix} &amp; =\\sqrt{F_x^2+F_y^2}\\\\[2ex]&amp; =\\sqrt{6^2+ 8^2}\\\\[2ex] &amp; = \\sqrt{100} \\\\[2ex] &amp; = 10 \\ N \\end{aligned}\" title=\"Rendered by QuickLaTeX.com\" height=\"160\" width=\"130\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> \u00c9 importante ter em mente que esta f\u00f3rmula s\u00f3 pode ser utilizada se as duas for\u00e7as formarem um \u00e2ngulo de 90\u00ba. Caso contr\u00e1rio, para encontrar a for\u00e7a resultante da uni\u00e3o de duas for\u00e7as com \u00e2ngulo diferente, outros m\u00e9todos devem ser aplicados (dependendo do caso), voc\u00ea pode ver como isso \u00e9 feito em nosso site.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Este artigo explica quais s\u00e3o os componentes de uma for\u00e7a e como s\u00e3o calculados. Al\u00e9m disso, voc\u00ea poder\u00e1 ver exemplos resolvidos de c\u00e1lculo de componentes de for\u00e7a. Quais s\u00e3o os componentes de uma for\u00e7a? Os componentes de uma for\u00e7a s\u00e3o as proje\u00e7\u00f5es de uma for\u00e7a nos eixos de refer\u00eancia. Se trabalharmos no sistema de coordenadas &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/\"> <span class=\"screen-reader-text\">Componentes de uma for\u00e7a<\/span> Leia mais &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-14","post","type-post","status-publish","format-standard","hentry","category-dinamico"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 Como calcular os componentes de uma for\u00e7a (exemplos)<\/title>\n<meta name=\"description\" content=\"Explicamos o que s\u00e3o os componentes de uma for\u00e7a e como s\u00e3o calculados (f\u00f3rmula). Com exemplos resolvidos de componentes de for\u00e7a.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/\" \/>\n<meta property=\"og:locale\" content=\"pt_BR\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u25b7 Como calcular os componentes de uma for\u00e7a (exemplos)\" \/>\n<meta property=\"og:description\" content=\"Explicamos o que s\u00e3o os componentes de uma for\u00e7a e como s\u00e3o calculados (f\u00f3rmula). Com exemplos resolvidos de componentes de for\u00e7a.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/\" \/>\n<meta property=\"article:published_time\" content=\"2023-06-27T19:33:24+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/composantes-dune-force.png\" \/>\n<meta name=\"author\" content=\"Jonathan Reynolds\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Escrito por\" \/>\n\t<meta name=\"twitter:data1\" content=\"Jonathan Reynolds\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. tempo de leitura\" \/>\n\t<meta name=\"twitter:data2\" content=\"4 minutos\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/\"},\"author\":{\"name\":\"Jonathan Reynolds\",\"@id\":\"https:\/\/physigeek.com\/pt\/#\/schema\/person\/dbb0dcefd6128273c4dc80a663ede0f7\"},\"headline\":\"Componentes de uma for\u00e7a\",\"datePublished\":\"2023-06-27T19:33:24+00:00\",\"dateModified\":\"2023-06-27T19:33:24+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/\"},\"wordCount\":820,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\/\/physigeek.com\/pt\/#organization\"},\"articleSection\":[\"Din\u00e2mico\"],\"inLanguage\":\"pt-BR\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/#respond\"]}]},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/\",\"url\":\"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/\",\"name\":\"\u25b7 Como calcular os componentes de uma for\u00e7a (exemplos)\",\"isPartOf\":{\"@id\":\"https:\/\/physigeek.com\/pt\/#website\"},\"datePublished\":\"2023-06-27T19:33:24+00:00\",\"dateModified\":\"2023-06-27T19:33:24+00:00\",\"description\":\"Explicamos o que s\u00e3o os componentes de uma for\u00e7a e como s\u00e3o calculados (f\u00f3rmula). Com exemplos resolvidos de componentes de for\u00e7a.\",\"breadcrumb\":{\"@id\":\"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/#breadcrumb\"},\"inLanguage\":\"pt-BR\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Lar\",\"item\":\"https:\/\/physigeek.com\/pt\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Componentes de uma for\u00e7a\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/physigeek.com\/pt\/#website\",\"url\":\"https:\/\/physigeek.com\/pt\/\",\"name\":\"Physigeek\",\"description\":\"Aprenda f\u00edsica da maneira mais f\u00e1cil!\",\"publisher\":{\"@id\":\"https:\/\/physigeek.com\/pt\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/physigeek.com\/pt\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"pt-BR\"},{\"@type\":\"Organization\",\"@id\":\"https:\/\/physigeek.com\/pt\/#organization\",\"name\":\"Physigeek\",\"url\":\"https:\/\/physigeek.com\/pt\/\",\"logo\":{\"@type\":\"ImageObject\",\"inLanguage\":\"pt-BR\",\"@id\":\"https:\/\/physigeek.com\/pt\/#\/schema\/logo\/image\/\",\"url\":\"https:\/\/physigeek.com\/pt\/wp-content\/uploads\/2023\/10\/physigeek-logo.png\",\"contentUrl\":\"https:\/\/physigeek.com\/pt\/wp-content\/uploads\/2023\/10\/physigeek-logo.png\",\"width\":180,\"height\":42,\"caption\":\"Physigeek\"},\"image\":{\"@id\":\"https:\/\/physigeek.com\/pt\/#\/schema\/logo\/image\/\"}},{\"@type\":\"Person\",\"@id\":\"https:\/\/physigeek.com\/pt\/#\/schema\/person\/dbb0dcefd6128273c4dc80a663ede0f7\",\"name\":\"Jonathan Reynolds\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"pt-BR\",\"@id\":\"https:\/\/physigeek.com\/pt\/#\/schema\/person\/image\/\",\"url\":\"http:\/\/physigeek.com\/pt\/wp-content\/uploads\/2023\/10\/Jonathan-Reynolds-96x96.jpg\",\"contentUrl\":\"http:\/\/physigeek.com\/pt\/wp-content\/uploads\/2023\/10\/Jonathan-Reynolds-96x96.jpg\",\"caption\":\"Jonathan Reynolds\"},\"sameAs\":[\"http:\/\/physigeek.com\/pt\"]}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"\u25b7 Como calcular os componentes de uma for\u00e7a (exemplos)","description":"Explicamos o que s\u00e3o os componentes de uma for\u00e7a e como s\u00e3o calculados (f\u00f3rmula). Com exemplos resolvidos de componentes de for\u00e7a.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/","og_locale":"pt_BR","og_type":"article","og_title":"\u25b7 Como calcular os componentes de uma for\u00e7a (exemplos)","og_description":"Explicamos o que s\u00e3o os componentes de uma for\u00e7a e como s\u00e3o calculados (f\u00f3rmula). Com exemplos resolvidos de componentes de for\u00e7a.","og_url":"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/","article_published_time":"2023-06-27T19:33:24+00:00","og_image":[{"url":"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/composantes-dune-force.png"}],"author":"Jonathan Reynolds","twitter_card":"summary_large_image","twitter_misc":{"Escrito por":"Jonathan Reynolds","Est. tempo de leitura":"4 minutos"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/#article","isPartOf":{"@id":"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/"},"author":{"name":"Jonathan Reynolds","@id":"https:\/\/physigeek.com\/pt\/#\/schema\/person\/dbb0dcefd6128273c4dc80a663ede0f7"},"headline":"Componentes de uma for\u00e7a","datePublished":"2023-06-27T19:33:24+00:00","dateModified":"2023-06-27T19:33:24+00:00","mainEntityOfPage":{"@id":"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/"},"wordCount":820,"commentCount":0,"publisher":{"@id":"https:\/\/physigeek.com\/pt\/#organization"},"articleSection":["Din\u00e2mico"],"inLanguage":"pt-BR","potentialAction":[{"@type":"CommentAction","name":"Comment","target":["https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/#respond"]}]},{"@type":"WebPage","@id":"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/","url":"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/","name":"\u25b7 Como calcular os componentes de uma for\u00e7a (exemplos)","isPartOf":{"@id":"https:\/\/physigeek.com\/pt\/#website"},"datePublished":"2023-06-27T19:33:24+00:00","dateModified":"2023-06-27T19:33:24+00:00","description":"Explicamos o que s\u00e3o os componentes de uma for\u00e7a e como s\u00e3o calculados (f\u00f3rmula). Com exemplos resolvidos de componentes de for\u00e7a.","breadcrumb":{"@id":"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/#breadcrumb"},"inLanguage":"pt-BR","potentialAction":[{"@type":"ReadAction","target":["https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/physigeek.com\/pt\/componentes-de-uma-forca\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Lar","item":"https:\/\/physigeek.com\/pt\/"},{"@type":"ListItem","position":2,"name":"Componentes de uma for\u00e7a"}]},{"@type":"WebSite","@id":"https:\/\/physigeek.com\/pt\/#website","url":"https:\/\/physigeek.com\/pt\/","name":"Physigeek","description":"Aprenda f\u00edsica da maneira mais f\u00e1cil!","publisher":{"@id":"https:\/\/physigeek.com\/pt\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/physigeek.com\/pt\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"pt-BR"},{"@type":"Organization","@id":"https:\/\/physigeek.com\/pt\/#organization","name":"Physigeek","url":"https:\/\/physigeek.com\/pt\/","logo":{"@type":"ImageObject","inLanguage":"pt-BR","@id":"https:\/\/physigeek.com\/pt\/#\/schema\/logo\/image\/","url":"https:\/\/physigeek.com\/pt\/wp-content\/uploads\/2023\/10\/physigeek-logo.png","contentUrl":"https:\/\/physigeek.com\/pt\/wp-content\/uploads\/2023\/10\/physigeek-logo.png","width":180,"height":42,"caption":"Physigeek"},"image":{"@id":"https:\/\/physigeek.com\/pt\/#\/schema\/logo\/image\/"}},{"@type":"Person","@id":"https:\/\/physigeek.com\/pt\/#\/schema\/person\/dbb0dcefd6128273c4dc80a663ede0f7","name":"Jonathan Reynolds","image":{"@type":"ImageObject","inLanguage":"pt-BR","@id":"https:\/\/physigeek.com\/pt\/#\/schema\/person\/image\/","url":"http:\/\/physigeek.com\/pt\/wp-content\/uploads\/2023\/10\/Jonathan-Reynolds-96x96.jpg","contentUrl":"http:\/\/physigeek.com\/pt\/wp-content\/uploads\/2023\/10\/Jonathan-Reynolds-96x96.jpg","caption":"Jonathan Reynolds"},"sameAs":["http:\/\/physigeek.com\/pt"]}]}},"yoast_meta":{"yoast_wpseo_title":"","yoast_wpseo_metadesc":"","yoast_wpseo_canonical":""},"_links":{"self":[{"href":"https:\/\/physigeek.com\/pt\/wp-json\/wp\/v2\/posts\/14","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/physigeek.com\/pt\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/physigeek.com\/pt\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/physigeek.com\/pt\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/physigeek.com\/pt\/wp-json\/wp\/v2\/comments?post=14"}],"version-history":[{"count":0,"href":"https:\/\/physigeek.com\/pt\/wp-json\/wp\/v2\/posts\/14\/revisions"}],"wp:attachment":[{"href":"https:\/\/physigeek.com\/pt\/wp-json\/wp\/v2\/media?parent=14"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/physigeek.com\/pt\/wp-json\/wp\/v2\/categories?post=14"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/physigeek.com\/pt\/wp-json\/wp\/v2\/tags?post=14"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}