{"id":33,"date":"2023-06-27T03:01:24","date_gmt":"2023-06-27T03:01:24","guid":{"rendered":"https:\/\/physigeek.com\/nl\/balancerende-kracht\/"},"modified":"2023-06-27T03:01:24","modified_gmt":"2023-06-27T03:01:24","slug":"balancerende-kracht","status":"publish","type":"post","link":"https:\/\/physigeek.com\/nl\/balancerende-kracht\/","title":{"rendered":"Balancerende kracht"},"content":{"rendered":"<p>In dit artikel wordt uitgelegd wat evenwichtskracht is en hoe deze wordt berekend. Daarnaast kun je oefenen met opgeloste evenwichtskrachtoefeningen. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-la-fuerza-equilibrante\"><\/span> Wat is de evenwichtskracht?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Balancerende kracht<\/strong> is de kracht die het effect van alle krachten in een systeem tegenwerkt, dat wil zeggen, balancerende kracht is de kracht die in staat is een systeem van krachten in evenwicht te brengen.<\/p>\n<p> Daarom heeft de balancerende kracht van een systeem dezelfde grootte, richting en tegengestelde richting als de resulterende kracht.<\/p>\n<p> Bovendien zorgt de balancerende kracht ervoor dat de som van alle krachten in een systeem nul is en daarom is het systeem in evenwicht.<\/p>\n<p> Normale kracht is bijvoorbeeld de kracht die de kracht van het gewicht in evenwicht brengt, omdat het het effect ervan neutraliseert en een lichaam in staat stelt zichzelf op de grond te ondersteunen. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Como-calcular-la-fuerza-equilibrante\"><\/span> Hoe de evenwichtskracht te berekenen<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Om de balancerende kracht op een systeem te berekenen, moet men eerst de resulterende kracht op het systeem vinden en vervolgens de componenten ervan tenietdoen.<\/strong><\/p>\n<p> Omdat de balancerende kracht tegengesteld is aan de resulterende kracht, bestaat het proces om de balancerende kracht af te leiden simpelweg uit het bepalen van de resulterende kracht en het veranderen van het teken van de co\u00f6rdinaten ervan.<\/p>\n<p> Om de evenwichtskracht van een systeem te vinden, is het daarom essentieel dat u weet hoe de resulterende kracht wordt berekend. Als dit niet het geval is, ziet u de volgende uitleg: <\/p>\n<div style=\"background-color:#FFFDE7; padding-top: 10px; padding-bottom: 10px; padding-right: 10px; padding-left: 20px; border: 2.5px dashed #FFB74D; border-radius:20px;\"> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Zie:<\/strong> <a href=\"https:\/\/physigeek.com\/nl\/resulterende-kracht\/\">hoe je de resulterende kracht berekent<\/a><\/div>\n<p> Als de resulterende kracht van een systeem bijvoorbeeld<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-56af5ee7c8addbbb008322d8d7a1b973_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{F_R}=(5,-9) \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"121\" style=\"vertical-align: -5px;\"><\/p>\n<p> , zal de berekening van de balanceringskracht zijn:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-a0d97755676acf9aa70b81c95f2e5812_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{F_E}=-\\vv{F_R}\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"83\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-4b38f36424484cec6c3e0d03a9eaefb2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{F_E}=-(5,-9)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"113\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-ef7fc60f6acc6d952b2318ec8869e316_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{F_E}=(-5,9)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"99\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicios-resueltos-de-la-fuerza-equilibrante\"><\/span> Opgeloste evenwichtskrachtoefeningen<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Oefening 1<\/h3>\n<p> Bereken de balancerende kracht van de volgende drie krachten: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-forces-meme-direction-direction-differente.png\" alt=\"voorbeeld van krachten met dezelfde richting en verschillende richting\" class=\"wp-image-206\" width=\"189\" height=\"150\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-forces-meme-direction-direction-differente-300x238.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-forces-meme-direction-direction-differente.png 452w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Zie de oplossing<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Alle drie de krachten hebben dezelfde richting, dus de richting van de resulterende kracht zal voor deze krachten hetzelfde zijn.<\/p>\n<p class=\"has-text-align-left\"> In deze oefening hebben we twee krachten met dezelfde richting en richting, dus we kunnen ze direct optellen. Aan de andere kant hebben we een andere kracht met dezelfde richting maar een andere richting, dus deze kracht zal de intensiteit aftrekken van de resulterende kracht.<\/p>\n<p class=\"has-text-align-left\"> Bovendien is de waarde van de som van de krachten in de rechterrichting groter dan de waarde van de kracht in de linkerrichting, dus de resulterende kracht moet een rechtse richting hebben. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-de-somme-des-forces-resolues.png\" alt=\"bepaalde uitoefening van de som van de krachten\" class=\"wp-image-208\" width=\"385\" height=\"173\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-de-somme-des-forces-resolues-300x135.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-de-somme-des-forces-resolues-768x346.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-de-somme-des-forces-resolues.png 927w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Omdat de balanceringskracht tegengesteld is aan de resulterende kracht, zal de balanceringskracht daarom een kracht met een waarde van 5 N zijn met dezelfde richting maar naar links.<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\"> Oefening 2<\/h3>\n<p> Bepaal de evenwichtskracht van het systeem, gevormd door de volgende twee krachten:<\/p>\n<ul>\n<li> Kracht van 10 N met een helling ten opzichte van de horizontale as van 45\u00ba.<\/li>\n<li> Kracht van 7 N met een helling ten opzichte van de horizontale as van 60\u00ba. <\/li>\n<\/ul>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Zie de oplossing<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> De probleemstelling vertelt ons dat de krachten verschillende richtingen hebben, dus om de resulterende kracht te vinden moeten we ze eerst vectorieel ontbinden met behulp van de sinus- en cosinusformules:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d50341bac2e56c0bf8b052e5bdc69ff4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{1x}=10\\cdot \\text{cos}(45\u00ba)=7,71 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"216\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-487172781aca0e78793172956b5615d7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{1y}=10\\cdot \\text{sin}(45\u00ba)=7.71 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"211\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6f8c20f2affa0ed87fbe025c8d05be55_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{2x}=7\\cdot \\text{cos}(60\u00ba)=3,5 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"199\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fa287f252fc5fffdd78b33cc3a642485_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{2y}=7\\cdot \\text{sin}(60\u00ba)=6.06\\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"202\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> En nu voegen we de componenten van de krachten toe die overeenkomen met dezelfde as:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c38ceddd5d93d2d83639cd83b5369e2d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{Rx}=F_{1x}+F_{2x}=7,71+3,5=11,21 \\ N \" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"324\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-441effc100acf5a813f730815eca598c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{Ry}=F_{1y}+F_{2y}=7,71+6,06=13,77 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"331\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> De resulterende kracht is daarom:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-3050740d1257c084c15519680674e21e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{F_R}=(11.21 .13.77) \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"168\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Daarom zal de evenwichtskracht zijn: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-5d0a05a4bd596575b3da12bfaec277ab_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{F_E}=(-11.21 ,-13.77) \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"199\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Oefening 3<\/h3>\n<p> Zoek de evenwichtskracht van het volgende krachtenstelsel: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/sommes-de-forces-vectorielles.png\" alt=\"zijn vectorkrachten\" class=\"wp-image-215\" width=\"331\" height=\"292\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/sommes-de-forces-vectorielles-300x264.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/sommes-de-forces-vectorielles.png 538w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Zie de oplossing<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Om de resulterende kracht van alle vectorkrachten in de grafiek te verkrijgen, moeten we de polygoonmethode toepassen: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/somme-des-forces-graphiquement.png\" alt=\"som van krachten grafisch\" class=\"wp-image-216\" width=\"377\" height=\"292\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/somme-des-forces-graphiquement-300x233.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/somme-des-forces-graphiquement.png 610w\" sizes=\"auto, (max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> De resulterende kracht heeft daarom de volgende componenten:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-39e9675b94809f86add953c33ebddad9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{F_R}=(5,8)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"85\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> De balancerende kracht zal daarom deze kracht zijn met dezelfde componenten maar met een veranderd teken: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-2d5a91e70ece44aa0561f5af13520e94_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\vv{F_E}=(-5,-8)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"113\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>In dit artikel wordt uitgelegd wat evenwichtskracht is en hoe deze wordt berekend. Daarnaast kun je oefenen met opgeloste evenwichtskrachtoefeningen. Wat is de evenwichtskracht? Balancerende kracht is de kracht die het effect van alle krachten in een systeem tegenwerkt, dat wil zeggen, balancerende kracht is de kracht die in staat is een systeem van krachten &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/nl\/balancerende-kracht\/\"> <span class=\"screen-reader-text\">Balancerende kracht<\/span> Weiterlesen &raquo;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"class_list":["post-33","post","type-post","status-publish","format-standard","hentry","category-dynamisch"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.3 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 Evenwichtskracht: definitie, berekening en opgeloste oefeningen<\/title>\n<meta name=\"description\" content=\"We leggen uit wat evenwichtskracht is en hoe deze wordt berekend. 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