{"id":45,"date":"2023-06-26T20:26:33","date_gmt":"2023-06-26T20:26:33","guid":{"rendered":"https:\/\/physigeek.com\/id\/berat-fisik\/"},"modified":"2023-06-26T20:26:33","modified_gmt":"2023-06-26T20:26:33","slug":"berat-fisik","status":"publish","type":"post","link":"https:\/\/physigeek.com\/id\/berat-fisik\/","title":{"rendered":"Berat badan (fisik)"},"content":{"rendered":"<p>Artikel ini menjelaskan pengertian berat dalam fisika. Di sana Anda akan menemukan pengertian berat, cara menghitung berat suatu benda, dan apa perbedaan antara berat dan massa. Terakhir, Anda bisa berlatih dengan latihan binaraga langkah demi langkah. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-el-peso-en-fisica\"><\/span> Apa yang dimaksud dengan berat dalam fisika?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Dalam fisika, <strong>berat<\/strong> suatu benda adalah gaya gravitasi yang bekerja pada benda tersebut. Secara umum, konsep berat mengacu pada gaya gravitasi yang diberikan Bumi pada suatu benda tertentu, namun bisa juga merujuk pada gaya gravitasi planet lain.<\/p>\n<p> Jadi, karena berat adalah gaya, maka berat adalah vektor dengan modulus, arah, arah, dan titik penerapan. Di bawah ini kita akan melihat cara mencari nilai berat, tetapi arahnya akan selalu vertikal, arahnya ke bawah dan titik penerapannya akan sesuai dengan pusat gravitasi benda.<\/p>\n<p> Seperti yang Anda lihat, <strong>dalam fisika kita harus membedakan antara berat dan massa<\/strong> , karena pengertian kedua istilah ini disalahgunakan dalam kehidupan sehari-hari. Di bawah ini telah Anda jelaskan secara detail perbedaan berat dan massa suatu benda.<\/p>\n<p> Lambang berat dalam fisika adalah huruf P, sehingga tanda panah yang melambangkan gaya berat suatu benda ditandai dengan meletakkan huruf P di sebelahnya.<\/p>\n<p> Karena merupakan gaya, maka satuan berat adalah newton dan dinyatakan dengan huruf N. Misalnya, berat seseorang dengan berat 50 kg kira-kira 490 N. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Como-calcular-el-peso-en-fisica\"><\/span> Cara menghitung berat badan dalam fisika<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Dalam fisika, rumus berat suatu benda sama dengan massa benda tersebut dikalikan dengan gravitasi bintang yang memberikan gaya gravitasi. Oleh karena itu, untuk <strong>menghitung gaya berat<\/strong> yang digunakan suatu planet untuk menarik suatu benda, massa benda tersebut harus dikalikan dengan gravitasi planet tersebut.<\/p>\n<p> Jadi, rumus yang digunakan untuk menghitung berat suatu benda adalah: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/poids-physique.png\" alt=\"berat fisik\" class=\"wp-image-814\" width=\"241\" height=\"242\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/poids-physique-300x300.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/poids-physique-150x150.png 150w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/poids-physique.png 483w\" sizes=\"(max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p> Perlu diingat bahwa gravitasi bumi adalah 9,81 m\/ <sup>s2<\/sup> . <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat demonstrasi rumus berat badan<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Untuk mendemonstrasikan rumus gaya berat, kita akan mulai dari ekspresi aljabar yang memungkinkan kita menghitung gaya gravitasi yang dilakukan oleh suatu benda pada benda lain:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-934a1cae402a8b50d0bae2b3910e1874_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=G\\cdot \\cfrac{M\\cdot m}{r^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"114\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Namun rumus gravitasi tepatnya adalah konstanta gravitasi universal (G) dikalikan massa benda langit (M) dibagi kuadrat jarak antara pusat benda langit dan permukaannya (r <sup>2<\/sup> ):<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-278bac151b8b02af9dbca5a377d8823e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"g=\\cfrac{G\\cdot M}{r^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"81\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Jadi, dengan mengganti satu ekspresi dengan ekspresi lainnya, kita sampai pada rumus bobot:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-934a1cae402a8b50d0bae2b3910e1874_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=G\\cdot \\cfrac{M\\cdot m}{r^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"114\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-4ce26d502dae0dc36ae1476ed16a8dd7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=\\cfrac{G\\cdot M}{r^2}\\cdot m\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"113\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-38ec346ff053c03c2ff1249c9b995064_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=g\\cdot m\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"74\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Diferencia-entre-peso-y-masa\"><\/span> Perbedaan antara berat dan massa<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Berat dan massa<\/strong> adalah dua konsep berbeda dalam fisika. Massa adalah jumlah materi yang dimiliki suatu benda dan diukur dalam kilogram (kg), sedangkan berat adalah gaya gravitasi yang diberikan bintang pada suatu benda dan satuan ukurannya adalah newton (N).<\/p>\n<p> Misalnya, seseorang dengan berat 70 kg memiliki berat di Bumi sebesar 686,7 N. Namun, berat orang yang sama di Bulan adalah 113,4 N meskipun massanya tetap sama.<\/p>\n<p> Oleh karena itu, ketika kita bertanya \u201cBerapa berat badanmu?\u201d \u00bb Untuk mengetahui massa seseorang, kita harus bertanya &#8220;Berapa massamu?&#8221; \u00bb<\/p>\n<p> Perbedaan lain antara berat dan massa adalah instrumen yang diperlukan untuk mengukur properti. Berat diukur dengan menggunakan dinamometer, sedangkan massa diukur dengan timbangan.<\/p>\n<p> Selain itu, massa adalah bilangan sederhana, tetapi berat adalah vektor karena merupakan gaya. Jadi, seperti vektor lainnya, berat mempunyai arah, arti, besaran, dan titik penerapan. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicios-resueltos-del-peso\"><\/span>Latihan Beban Terpecahkan<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Latihan 1<\/h3>\n<p> Hitunglah berat benda di bumi yang massanya 45 kg. Gunakan nilai g=9,81 m\/s <sup>2<\/sup> sebagai gravitasi bumi. <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Untuk menentukan berat suatu benda, cukup terapkan rumus yang sesuai, yaitu:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c0cdb663ec9f8fe79fbecd960b50fc39_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=m\\cdot g\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"75\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sekarang kita substitusikan data massa benda dan gravitasi bumi ke dalam rumus dan hitung beratnya: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-3385b7fd3909025dacf75d3c1d2a533f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=45\\cdot 9,81=441,45 \\N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"178\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 2<\/h3>\n<p> Berat suatu benda di Bumi adalah 650 N, berapakah massa setara dengan berat tersebut di Mars? Fakta: Gravitasi di Mars adalah 3721 m\/s <sup>2<\/sup> . <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Untuk menyelesaikan soal fisika mengenai berat ini, kita harus menggunakan rumus yang dijelaskan di atas:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c0cdb663ec9f8fe79fbecd960b50fc39_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=m\\cdot g\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"75\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dalam hal ini kita mengetahui nilai berat dan gravitasi dan ingin mengetahui massa suatu benda, maka kita selesaikan dulu massanya dengan rumus:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-19aef2a1a6353e9f29b7452f13a42b30_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m=\\cfrac{P}{g}\" title=\"Rendered by QuickLaTeX.com\" height=\"42\" width=\"55\" style=\"vertical-align: -16px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan terakhir, kami mengganti data tersebut ke dalam rumus untuk mencari massa benda seberat 650 N di Mars: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-ebd84d665f96e95fc6b891eb34875db3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m=\\cfrac{650}{3.721}=174,68 \\ kg\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"182\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 3<\/h3>\n<p> Diketahui sebuah benda tegar bermassa 12 kg yang digantung pada dua tali yang sudutnya ditunjukkan pada gambar berikut, hitunglah gaya yang harus dilakukan setiap tali agar benda tetap seimbang. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-de-premiere-condition-dequilibre.png\" alt=\"masalah kondisi keseimbangan pertama\" class=\"wp-image-372\" width=\"243\" height=\"243\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-de-premiere-condition-dequilibre-300x300.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-de-premiere-condition-dequilibre-150x150.png 150w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-de-premiere-condition-dequilibre.png 600w\" sizes=\"(max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Hal pertama yang perlu kita lakukan untuk menyelesaikan masalah jenis ini adalah menggambar diagram benda bebas dari gambar tersebut: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-de-la-premiere-condition-dequilibre.png\" alt=\"menyelesaikan pelaksanaan kondisi keseimbangan pertama\" class=\"wp-image-375\" width=\"282\" height=\"335\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-de-la-premiere-condition-dequilibre-252x300.png 252w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-de-la-premiere-condition-dequilibre.png 600w\" sizes=\"(max-width: 252px) 100vw, 252px\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Perhatikan bahwa sebenarnya hanya ada tiga gaya yang bekerja pada benda yang digantung, yaitu gaya beban P dan tegangan tali T <sub>1<\/sub> dan T <sub>2<\/sub> . Gaya-gaya yang diwakili T <sub>1x<\/sub> , T <sub>1y<\/sub> , T <sub>2x<\/sub> dan T <sub>2y<\/sub> masing-masing merupakan komponen vektor dari T <sub>1<\/sub> dan T <sub>2<\/sub> .<\/p>\n<p class=\"has-text-align-left\"> Jadi, karena kita mengetahui sudut kemiringan tali, kita dapat menemukan ekspresi komponen vektor gaya tarik: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-bc09423d2d10435101c7d6b087add524_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" T_{1x}=T_1\\cdot \\text{cos}(20\u00ba)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"135\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0603d4b02835532dcefe2290484067fb_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" T_{1y}=T_1\\cdot \\text{sin}(20\u00ba)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"133\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0b10a6fc64a1a84b9f4f2c47b7990766_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" T_{2x}=T_2\\cdot \\text{cos}(55\u00ba)\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"135\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-3e7a1dc2ffa7eb20e5e2d9346f0b96a2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" T_{2y}=T_2\\cdot \\text{sin}(55\u00ba)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"133\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Di sisi lain, kita dapat menghitung gaya berat dengan menerapkan rumus gaya gravitasi:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-dab14bd2fa937f39825c5add90b3ae58_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=m\\cdot g=12\\cdot 9,81 =117,72 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"261\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Rumusan masalah menyatakan bahwa benda berada dalam keadaan setimbang, sehingga jumlah gaya vertikal dan jumlah gaya horizontal harus sama dengan nol. Jadi kita dapat menetapkan persamaan gaya dan menetapkannya sama dengan nol: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6532044e76d6b9246f64624159b08c33_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-T_{1x}+T_{2x}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"119\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-52aadf04437252b1f9c17107dfc16a84_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"T_{1y}+T_{2y}-P=0\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"140\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kita sekarang mengganti komponen ketegangan dengan ekspresi yang ditemukan sebelumnya: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-4a4993c55ab7f27b6c0b67793ee5ff8a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-T_1\\cdot\\text{cos}(20\u00ba)+T_2\\cdot \\text{cos}(55\u00ba)=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"239\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-204773c167037418680872592d118315_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"T_1\\cdot \\text{sin}(20\u00ba)+T_2\\cdot \\text{sin}(55\u00ba)-117.72=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"293\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan terakhir, kita selesaikan sistem persamaan untuk mendapatkan nilai gaya T <sub>1<\/sub> dan T <sub>2<\/sub> : <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-8220cbad28a7824cc1d3f06f4dcb7510_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\left.\\begin{array}{l}-T_1\\cdot 0,94+T_2\\cdot 0,57=0\\\\[2ex]T_1\\cdot 0,34+T_2\\cdot 0,82-117 .72=0\\end{array }\\right\\} \\longrightarrow \\ \\begin{array}{c}T_1=69,56 \\ N\\\\[2ex]T_2=114,74 \\ N\\end{array}[\/ latex] \n\n<div class=&quot;wp-block-otfm-box-spoiler-end otfm-sp_end&quot;><\/div>\n<h3 class=&quot;wp-block-heading&quot;> Exercice 4<\/h3>\n<p> Comme le montre la figure suivante, deux objets sont reli\u00e9s par une corde et une poulie de masses n\u00e9gligeables. Si l&#8217;objet 2 a une masse de 7 kg et que l&#8217;inclinaison de la rampe est de 50\u00ba, calculez la masse de l&#8217;objet 1 pour que l&#8217;ensemble du syst\u00e8me soit dans des conditions d&#8217;\u00e9quilibre. Dans ce cas, la force de frottement peut \u00eatre n\u00e9glig\u00e9e. <\/p>\n<div class=&quot;wp-block-image&quot;>\n<figure class=&quot;aligncenter size-full is-resized&quot;><img decoding=&quot;async&quot; loading=&quot;lazy&quot; src=&quot;https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-des-forces.png&quot; alt=&quot;probl\u00e8me d'\u00e9quilibre translationnel&quot; class=&quot;wp-image-295&quot; width=&quot;299&quot; height=&quot;240&quot; srcset=&quot;https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-des-forces-300x241.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-des-forces.png 718w&quot; sizes=&quot;(max-width: 300px) 100vw, 300px&quot;><\/figure>\n<\/div>\n<div class=&quot;wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1&quot; role=&quot;button&quot; tabindex=&quot;0&quot; aria-expanded=&quot;false&quot; data-otfm-spc=&quot;#FFF8E1&quot; style=&quot;text-align:center&quot;>\n<div class=&quot;otfm-sp__title&quot;> <strong>Voir la solution<\/strong><\/div>\n<\/div>\n<p> Le corps 1 est sur une pente inclin\u00e9e, donc la premi\u00e8re chose \u00e0 faire est de vectoriser la force de son poids pour avoir les forces sur les axes de la pente : [latex]P_{1x}=P_1\\cdot \\text{sin}(\\alpha)&#8221; title=&#8221;Rendered by QuickLaTeX.com&#8221; height=&#8221;340&#8243; width=&#8221;2918&#8243; style=&#8221;vertical-align: 0px;&#8221;><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-1a0b77602980cc17cce9b3baef744df8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_{1y}=P_1\\cdot \\text{cos}(\\alpha)\" title=\"Rendered by QuickLaTeX.com\" height=\"20\" width=\"130\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Jadi, himpunan gaya yang bekerja pada keseluruhan sistem adalah: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-equilibre-des-forces.png\" alt=\"latihan keseimbangan translasi terselesaikan\" class=\"wp-image-296\" width=\"338\" height=\"272\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-equilibre-des-forces-300x241.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-equilibre-des-forces.png 718w\" sizes=\"(max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Rumusan masalah menyatakan bahwa sistem gaya-gaya berada dalam keadaan setimbang, sehingga kedua benda harus berada dalam keadaan setimbang. Dari informasi ini kita dapat mengajukan persamaan kesetimbangan kedua benda: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-ed082b4f064316ab20fb0d26054d3010_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"1\\ \\rightarrow \\ \\begin{cases}P_{1x}=T\\\\[2ex]P_{1y}=N\\end{cases} \\qquad\\qquad 2 \\ \\rightarrow \\ T=P_2[\/latex ] Ainsi, la composante du poids de l'objet 1 inclin\u00e9 dans le sens de la pente doit \u00eatre \u00e9gale au poids de l'objet 2 : [latex]P_{1x}=P_2\" title=\"Rendered by QuickLaTeX.com\" height=\"87\" width=\"1160\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-4e1b75b6ba5d7bbe88d23e014eb011c5_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P_1\\cdot \\text{sin}(\\alpha)=P_2\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"120\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sekarang kita terapkan rumus gaya gravitasi dan sederhanakan persamaannya: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-06a53a846ad5bc034f69fa05488404c4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_1\\cdot g \\cdot \\text{sin}(\\alpha) =m_2 \\cdot g\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"174\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-802fde26f3388538d766a709d60cf48b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_1 \\cdot \\text{sin}(\\alpha) =m_2\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"130\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Terakhir, kita substitusikan datanya dan selesaikan massa benda 1: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0457f85ca65afde96b2e575ce54869dd_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_1 \\cdot \\text{sin}(50\u00ba) =7\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"122\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-9a26d132815a0ce878a6ad874c8b40b0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_1 =\\cfrac{7}{\\text{sin}(50\u00ba)}\" title=\"Rendered by QuickLaTeX.com\" height=\"44\" width=\"103\" style=\"vertical-align: -17px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6e80f0daabb2167ec2f6622b08001a97_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"m_1=9,14 \\ kg\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"106\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Artikel ini menjelaskan pengertian berat dalam fisika. Di sana Anda akan menemukan pengertian berat, cara menghitung berat suatu benda, dan apa perbedaan antara berat dan massa. Terakhir, Anda bisa berlatih dengan latihan binaraga langkah demi langkah. Apa yang dimaksud dengan berat dalam fisika? Dalam fisika, berat suatu benda adalah gaya gravitasi yang bekerja pada benda &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/id\/berat-fisik\/\"> <span class=\"screen-reader-text\">Berat badan (fisik)<\/span> Baca selengkapnya &quot;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 Berat (fisika): definisi, rumus, latihan yang diselesaikan,...<\/title>\n<meta name=\"description\" content=\"Kami menjelaskan apa arti berat dalam fisika. 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