{"id":35,"date":"2023-06-27T00:14:40","date_gmt":"2023-06-27T00:14:40","guid":{"rendered":"https:\/\/physigeek.com\/id\/rumus-kekuatan\/"},"modified":"2023-06-27T00:14:40","modified_gmt":"2023-06-27T00:14:40","slug":"rumus-kekuatan","status":"publish","type":"post","link":"https:\/\/physigeek.com\/id\/rumus-kekuatan\/","title":{"rendered":"Rumus kekuatan"},"content":{"rendered":"<p>Artikel ini menjelaskan apa itu rumus gaya dan cara menghitung gaya dengan rumusnya. Selain itu, Anda akan menemukan latihan formula kekuatan yang diselesaikan langkah demi langkah. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFCual-es-la-formula-de-la-fuerza\"><\/span> Apa rumus kekuatan?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Rumus gayanya<\/strong> adalah F=m\u00b7a, jadi rumus gayanya adalah massa benda dikali percepatan benda. Dengan kata lain, untuk menghitung gaya yang diterapkan pada suatu benda atau benda, massa benda harus dikalikan dengan percepatannya. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/formule-de-force.png\" alt=\"rumus kekuatan\" class=\"wp-image-603\" width=\"222\" height=\"221\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/formule-de-force-300x300.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/formule-de-force-150x150.png 150w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/formule-de-force.png 485w\" sizes=\"(max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p> Dalam Sistem Satuan Internasional, gaya diukur dalam newton. Dan satu newton sama dengan satu kilo dikalikan satu meter dibagi satu detik kuadrat:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e7d2d91bb6635880e351a5c152502786_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"N=kg\\cdot \\cfrac{m}{s^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"34\" width=\"90\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p> Oleh karena itu, untuk menghitung nilai gaya dengan rumus tersebut, massa benda harus dikalikan dalam kilogram dan percepatannya harus dalam meter dibagi detik kuadrat. Artinya, massa dan percepatan harus dinyatakan dalam satuan sistem internasional.<\/p>\n<p> Rumus gaya mengikuti hukum kedua Newton, disebut juga prinsip dasar dinamika. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejemplo-de-la-formula-de-la-fuerza\"><\/span> Contoh Rumus Gaya<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Sekarang setelah kita mengetahui rumusan matematis suatu gaya, mari kita selesaikan sebuah contoh untuk memahami sepenuhnya cara menghitung gaya dengan rumus tersebut.<\/p>\n<ul>\n<li> Sebuah kursi guling bermassa 4 kg terletak pada permukaan datar dan licin. Tiba-tiba kursi tersebut didorong dan memperoleh percepatan linier sebesar 6 m\/s <sup>2<\/sup> . Dengan mengabaikan gesekan, hitunglah gaya yang bekerja pada daging.<\/li>\n<\/ul>\n<p> Rumusan masalah sudah memberi kita data yang dinyatakan dalam Sistem Satuan Internasional, sehingga kita bisa langsung menerapkan rumus untuk mencari intensitas gaya:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-99cf37519d1034196143b5a53c677b36_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=m\\cdot a\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"75\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Sekarang kita substitusikan nilai massa daging dan percepatannya ke dalam rumus dan hitung gayanya: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-501d55889e5f24d02031c0a7e4e2928b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=4\\cdot 6=24\\N\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"110\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicios-resueltos-de-la-formula-de-la-fuerza\"><\/span> Latihan rumus gaya yang diselesaikan<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Latihan 1<\/h3>\n<p> Pada permukaan datar kita mempunyai benda yang beratnya 11 kg dalam keadaan seimbang. Pada saat tertentu, sebuah gaya diberikan padanya sehingga percepatannya sebesar 3 m\/s <sup>2<\/sup> . Hitung nilai gaya yang diterapkan (abaikan gesekan). <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Untuk memperoleh nilai gaya yang diterapkan pada benda, kita harus menggunakan rumus gaya umum:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-99cf37519d1034196143b5a53c677b36_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=m\\cdot a\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"75\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Jadi kami mengganti data latihan ke dalam rumus dan menghitung nilainya: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0bec1a709df3089b77363f70cded663b_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=11\\cdot 3=33\\N\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"119\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 2<\/h3>\n<p> Jika gaya sebesar 250 N diterapkan pada benda bermassa 15 kg, berapakah percepatan yang dimiliki benda tersebut? <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Untuk mengatasi masalah ini, kita juga perlu menggunakan rumus gaya.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-99cf37519d1034196143b5a53c677b36_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=m\\cdot a\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"75\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dalam hal ini, kita mengetahui nilai gaya yang diterapkan dan massa benda, oleh karena itu kita harus memisahkan percepatan dari rumus untuk mencari nilainya:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fff8770fd096a19b52b29e4827b76130_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a=\\cfrac{F}{m}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"51\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sekarang kita substitusikan nilai gaya dan massa ke dalam ekspresi dan tentukan percepatan yang diperoleh benda. <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6b66e1aacd4f9884ca72fe90792cd62f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a=\\cfrac{250}{15}=16,67 \\ \\cfrac{m}{s^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"153\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 3<\/h3>\n<p> Sebuah mobil melaju dengan kecepatan 40 km\/jam dan pengemudi mobil tersebut melihat ada kecelakaan di depannya. Misalkan mobil tersebut akan mogok dalam waktu 6 sekon dan berat mobil serta pengemudinya adalah 850 kg, berapakah gaya yang harus diberikan oleh rem untuk menghentikan mobil tepat pada waktunya? <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Pertama, kita ubah kecepatan mobil ke satuan Sistem Internasional dengan membuat faktor konversi:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-dc1a6a191f877bda2bff65800cd83a87_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"40 \\ \\cfrac{km}{h} \\cdot \\cfrac{1000 \\ m}{1 \\ km}\\cdot\\cfrac{1 \\ h}{3600 \\ s}=11.11 \\ \\cfrac{m }{ s}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"275\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sekarang kita harus menghitung percepatan yang harus dimiliki mobil untuk berhenti tepat waktu. Untuk melakukan ini, kami menggunakan rumus percepatan:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-1694107fa6e366f66dc20fb7a15ef705_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"a=\\cfrac{v_f-v_i}{t_f-t_i}=\\cfrac{0-11.11}{6-0}=-1.85 \\ \\cfrac{m}{s^2}[\/ latex] Et une fois que l'on conna\u00eet la masse du syst\u00e8me et l'acc\u00e9l\u00e9ration que doit prendre la voiture, on peut obtenir la force que doivent exercer les freins avec la formule de force : [latex]F=m\\cdot a=850\\cdot (-1,85)=-1572,5 \\ N \" title=\"Rendered by QuickLaTeX.com\" height=\"44\" width=\"1945\" style=\"vertical-align: -18px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Gaya resultan mempunyai tanda negatif karena gaya tersebut harus diterapkan berlawanan arah dengan gerak mobil untuk menghentikannya. <\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Formulas-de-otras-fuerzas\"><\/span> Rumus untuk gaya lain<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Dalam fisika, ada banyak jenis gaya dan beberapa di antaranya dihitung menggunakan rumus lain. Di bawah ini adalah rumus gaya-gaya yang paling penting.<\/p>\n<ul>\n<li> <strong>Rumus gaya berat<\/strong> , yaitu gaya yang dikerjakan bumi pada suatu benda, adalah hasil kali gravitasi (g = 9,81 m\/s <sup>2<\/sup> ) dan massa benda tersebut.<\/li>\n<\/ul>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c0cdb663ec9f8fe79fbecd960b50fc39_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=m\\cdot g\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"75\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<ul>\n<li> <strong>Rumus gaya gravitasi<\/strong> yang dihasilkan antara dua benda adalah hasil kali konstanta gravitasi (G=6.672\u00b710 <sup>-11<\/sup> N\u00b7m <sup>2<\/sup> \/kg <sup>2<\/sup> ) dengan massa kedua benda dibagi kuadrat jarak yang memisahkan keduanya. tubuh. bodysuit.<\/li>\n<\/ul>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-09d3ea1c92371cbab38d34c4176304ea_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_G=G\\cdot \\cfrac{m_1\\cdot m_2}{r^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"34\" width=\"135\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<ul>\n<li> Pada <strong>rumus gaya gesek,<\/strong> koefisien gesek dikalikan dengan gaya normal.<\/li>\n<\/ul>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-a865b1cd2e263b944debf58666ec1269_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_R=\\mu\\cdot N\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"86\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<ul>\n<li> <strong>Rumus gaya elastis<\/strong> (atau hukum Hooke) setara dengan konstanta karakteristik pegas dikalikan variasi panjang yang dialami pegas tersebut.<\/li>\n<\/ul>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-9645d4e7fcbb1193a7f5c2f0e2adc18a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_k=k\\cdot \\Delta x\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"91\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<ul>\n<li> <strong>Rumus gaya sentripetal<\/strong> , yaitu gaya yang mendorong suatu benda melewati suatu kurva, adalah massa benda dikalikan kecepatannya dikuadratkan dengan jari-jari kelengkungan.<\/li>\n<\/ul>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-a7005ac8d3236db081a420f52a9eb6b8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_n=m\\cdot \\cfrac{v^2}{r}\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"92\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<ul>\n<li> <strong>Rumus gaya listrik<\/strong> yang menarik atau tolak menolak dua muatan adalah sama dengan konstanta hukum Coulomb (9\u00b710 <sup>9<\/sup> N\u00b7m <sup>2<\/sup> \/C <sup>2<\/sup> ) dikalikan nilai muatan listrik dibagi jarak antara kedua muatan tersebut. kuadrat.<\/li>\n<\/ul>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-66843edf029d1f397f4d4d297844f759_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_E=K\\cdot \\cfrac{q_1\\cdot q_2}{r^2}\" title=\"Rendered by QuickLaTeX.com\" height=\"34\" width=\"123\" style=\"vertical-align: -12px;\"><\/p><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Artikel ini menjelaskan apa itu rumus gaya dan cara menghitung gaya dengan rumusnya. Selain itu, Anda akan menemukan latihan formula kekuatan yang diselesaikan langkah demi langkah. Apa rumus kekuatan? Rumus gayanya adalah F=m\u00b7a, jadi rumus gayanya adalah massa benda dikali percepatan benda. Dengan kata lain, untuk menghitung gaya yang diterapkan pada suatu benda atau benda, &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/id\/rumus-kekuatan\/\"> <span class=\"screen-reader-text\">Rumus kekuatan<\/span> Baca selengkapnya &quot;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 Rumus kekuatan (dengan latihan yang diselesaikan)<\/title>\n<meta name=\"description\" content=\"Kami menjelaskan apa itu rumus gaya dan cara menghitung gaya beserta rumusnya. Dengan latihan khusus dari formula kekuatan.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/physigeek.com\/id\/rumus-kekuatan\/\" \/>\n<meta property=\"og:locale\" content=\"id_ID\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u25b7 Rumus kekuatan (dengan latihan yang diselesaikan)\" \/>\n<meta property=\"og:description\" content=\"Kami menjelaskan apa itu rumus gaya dan cara menghitung gaya beserta rumusnya. Dengan latihan khusus dari formula kekuatan.\" \/>\n<meta property=\"og:url\" content=\"https:\/\/physigeek.com\/id\/rumus-kekuatan\/\" \/>\n<meta property=\"article:published_time\" content=\"2023-06-27T00:14:40+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/formule-de-force.png\" \/>\n<meta name=\"author\" content=\"Jonathan Reynolds\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Jonathan Reynolds\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"3 menit\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/physigeek.com\/id\/rumus-kekuatan\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/physigeek.com\/id\/rumus-kekuatan\/\"},\"author\":{\"name\":\"Jonathan Reynolds\",\"@id\":\"https:\/\/physigeek.com\/id\/#\/schema\/person\/8c80a7450271cac823c1fce889f781ae\"},\"headline\":\"Rumus kekuatan\",\"datePublished\":\"2023-06-27T00:14:40+00:00\",\"dateModified\":\"2023-06-27T00:14:40+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/physigeek.com\/id\/rumus-kekuatan\/\"},\"wordCount\":611,\"commentCount\":0,\"publisher\":{\"@id\":\"https:\/\/physigeek.com\/id\/#organization\"},\"articleSection\":[\"Dinamis\"],\"inLanguage\":\"id\",\"potentialAction\":[{\"@type\":\"CommentAction\",\"name\":\"Comment\",\"target\":[\"https:\/\/physigeek.com\/id\/rumus-kekuatan\/#respond\"]}]},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/physigeek.com\/id\/rumus-kekuatan\/\",\"url\":\"https:\/\/physigeek.com\/id\/rumus-kekuatan\/\",\"name\":\"\u25b7 Rumus kekuatan (dengan latihan yang diselesaikan)\",\"isPartOf\":{\"@id\":\"https:\/\/physigeek.com\/id\/#website\"},\"datePublished\":\"2023-06-27T00:14:40+00:00\",\"dateModified\":\"2023-06-27T00:14:40+00:00\",\"description\":\"Kami menjelaskan apa itu rumus gaya dan cara menghitung gaya beserta rumusnya. Dengan latihan khusus dari formula kekuatan.\",\"breadcrumb\":{\"@id\":\"https:\/\/physigeek.com\/id\/rumus-kekuatan\/#breadcrumb\"},\"inLanguage\":\"id\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/physigeek.com\/id\/rumus-kekuatan\/\"]}]},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/physigeek.com\/id\/rumus-kekuatan\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Rumah\",\"item\":\"https:\/\/physigeek.com\/id\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"Rumus kekuatan\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/physigeek.com\/id\/#website\",\"url\":\"https:\/\/physigeek.com\/id\/\",\"name\":\"Physigeek\",\"description\":\"Pelajari fisika dengan cara mudah!\",\"publisher\":{\"@id\":\"https:\/\/physigeek.com\/id\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/physigeek.com\/id\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"id\"},{\"@type\":\"Organization\",\"@id\":\"https:\/\/physigeek.com\/id\/#organization\",\"name\":\"Physigeek\",\"url\":\"https:\/\/physigeek.com\/id\/\",\"logo\":{\"@type\":\"ImageObject\",\"inLanguage\":\"id\",\"@id\":\"https:\/\/physigeek.com\/id\/#\/schema\/logo\/image\/\",\"url\":\"https:\/\/physigeek.com\/id\/wp-content\/uploads\/2023\/10\/physigeek-logo.png\",\"contentUrl\":\"https:\/\/physigeek.com\/id\/wp-content\/uploads\/2023\/10\/physigeek-logo.png\",\"width\":180,\"height\":42,\"caption\":\"Physigeek\"},\"image\":{\"@id\":\"https:\/\/physigeek.com\/id\/#\/schema\/logo\/image\/\"}},{\"@type\":\"Person\",\"@id\":\"https:\/\/physigeek.com\/id\/#\/schema\/person\/8c80a7450271cac823c1fce889f781ae\",\"name\":\"Jonathan Reynolds\",\"image\":{\"@type\":\"ImageObject\",\"inLanguage\":\"id\",\"@id\":\"https:\/\/physigeek.com\/id\/#\/schema\/person\/image\/\",\"url\":\"http:\/\/physigeek.com\/id\/wp-content\/uploads\/2023\/10\/Jonathan-Reynolds-96x96.jpg\",\"contentUrl\":\"http:\/\/physigeek.com\/id\/wp-content\/uploads\/2023\/10\/Jonathan-Reynolds-96x96.jpg\",\"caption\":\"Jonathan Reynolds\"},\"sameAs\":[\"http:\/\/physigeek.com\/id\"],\"url\":\"https:\/\/physigeek.com\/id\/author\/ind0n35inphys1c\/\"}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"\u25b7 Rumus kekuatan (dengan latihan yang diselesaikan)","description":"Kami menjelaskan apa itu rumus gaya dan cara menghitung gaya beserta rumusnya. Dengan latihan khusus dari formula kekuatan.","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/physigeek.com\/id\/rumus-kekuatan\/","og_locale":"id_ID","og_type":"article","og_title":"\u25b7 Rumus kekuatan (dengan latihan yang diselesaikan)","og_description":"Kami menjelaskan apa itu rumus gaya dan cara menghitung gaya beserta rumusnya. Dengan latihan khusus dari formula kekuatan.","og_url":"https:\/\/physigeek.com\/id\/rumus-kekuatan\/","article_published_time":"2023-06-27T00:14:40+00:00","og_image":[{"url":"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/formule-de-force.png"}],"author":"Jonathan Reynolds","twitter_card":"summary_large_image","twitter_misc":{"Written by":"Jonathan Reynolds","Est. reading time":"3 menit"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/physigeek.com\/id\/rumus-kekuatan\/#article","isPartOf":{"@id":"https:\/\/physigeek.com\/id\/rumus-kekuatan\/"},"author":{"name":"Jonathan Reynolds","@id":"https:\/\/physigeek.com\/id\/#\/schema\/person\/8c80a7450271cac823c1fce889f781ae"},"headline":"Rumus kekuatan","datePublished":"2023-06-27T00:14:40+00:00","dateModified":"2023-06-27T00:14:40+00:00","mainEntityOfPage":{"@id":"https:\/\/physigeek.com\/id\/rumus-kekuatan\/"},"wordCount":611,"commentCount":0,"publisher":{"@id":"https:\/\/physigeek.com\/id\/#organization"},"articleSection":["Dinamis"],"inLanguage":"id","potentialAction":[{"@type":"CommentAction","name":"Comment","target":["https:\/\/physigeek.com\/id\/rumus-kekuatan\/#respond"]}]},{"@type":"WebPage","@id":"https:\/\/physigeek.com\/id\/rumus-kekuatan\/","url":"https:\/\/physigeek.com\/id\/rumus-kekuatan\/","name":"\u25b7 Rumus kekuatan (dengan latihan yang diselesaikan)","isPartOf":{"@id":"https:\/\/physigeek.com\/id\/#website"},"datePublished":"2023-06-27T00:14:40+00:00","dateModified":"2023-06-27T00:14:40+00:00","description":"Kami menjelaskan apa itu rumus gaya dan cara menghitung gaya beserta rumusnya. Dengan latihan khusus dari formula kekuatan.","breadcrumb":{"@id":"https:\/\/physigeek.com\/id\/rumus-kekuatan\/#breadcrumb"},"inLanguage":"id","potentialAction":[{"@type":"ReadAction","target":["https:\/\/physigeek.com\/id\/rumus-kekuatan\/"]}]},{"@type":"BreadcrumbList","@id":"https:\/\/physigeek.com\/id\/rumus-kekuatan\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Rumah","item":"https:\/\/physigeek.com\/id\/"},{"@type":"ListItem","position":2,"name":"Rumus kekuatan"}]},{"@type":"WebSite","@id":"https:\/\/physigeek.com\/id\/#website","url":"https:\/\/physigeek.com\/id\/","name":"Physigeek","description":"Pelajari fisika dengan cara mudah!","publisher":{"@id":"https:\/\/physigeek.com\/id\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/physigeek.com\/id\/?s={search_term_string}"},"query-input":"required name=search_term_string"}],"inLanguage":"id"},{"@type":"Organization","@id":"https:\/\/physigeek.com\/id\/#organization","name":"Physigeek","url":"https:\/\/physigeek.com\/id\/","logo":{"@type":"ImageObject","inLanguage":"id","@id":"https:\/\/physigeek.com\/id\/#\/schema\/logo\/image\/","url":"https:\/\/physigeek.com\/id\/wp-content\/uploads\/2023\/10\/physigeek-logo.png","contentUrl":"https:\/\/physigeek.com\/id\/wp-content\/uploads\/2023\/10\/physigeek-logo.png","width":180,"height":42,"caption":"Physigeek"},"image":{"@id":"https:\/\/physigeek.com\/id\/#\/schema\/logo\/image\/"}},{"@type":"Person","@id":"https:\/\/physigeek.com\/id\/#\/schema\/person\/8c80a7450271cac823c1fce889f781ae","name":"Jonathan Reynolds","image":{"@type":"ImageObject","inLanguage":"id","@id":"https:\/\/physigeek.com\/id\/#\/schema\/person\/image\/","url":"http:\/\/physigeek.com\/id\/wp-content\/uploads\/2023\/10\/Jonathan-Reynolds-96x96.jpg","contentUrl":"http:\/\/physigeek.com\/id\/wp-content\/uploads\/2023\/10\/Jonathan-Reynolds-96x96.jpg","caption":"Jonathan Reynolds"},"sameAs":["http:\/\/physigeek.com\/id"],"url":"https:\/\/physigeek.com\/id\/author\/ind0n35inphys1c\/"}]}},"yoast_meta":{"yoast_wpseo_title":"","yoast_wpseo_metadesc":"","yoast_wpseo_canonical":""},"_links":{"self":[{"href":"https:\/\/physigeek.com\/id\/wp-json\/wp\/v2\/posts\/35"}],"collection":[{"href":"https:\/\/physigeek.com\/id\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/physigeek.com\/id\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/physigeek.com\/id\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/physigeek.com\/id\/wp-json\/wp\/v2\/comments?post=35"}],"version-history":[{"count":0,"href":"https:\/\/physigeek.com\/id\/wp-json\/wp\/v2\/posts\/35\/revisions"}],"wp:attachment":[{"href":"https:\/\/physigeek.com\/id\/wp-json\/wp\/v2\/media?parent=35"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/physigeek.com\/id\/wp-json\/wp\/v2\/categories?post=35"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/physigeek.com\/id\/wp-json\/wp\/v2\/tags?post=35"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}