{"id":244,"date":"2023-06-23T10:06:26","date_gmt":"2023-06-23T10:06:26","guid":{"rendered":"https:\/\/physigeek.com\/id\/gaya-elastis-atau-gaya-pemulih\/"},"modified":"2023-06-23T10:06:26","modified_gmt":"2023-06-23T10:06:26","slug":"gaya-elastis-atau-gaya-pemulih","status":"publish","type":"post","link":"https:\/\/physigeek.com\/id\/gaya-elastis-atau-gaya-pemulih\/","title":{"rendered":"Gaya elastis (atau gaya pemulih)"},"content":{"rendered":"<p>Artikel ini menjelaskan apa itu gaya elastis (atau gaya restoratif). Dengan demikian, Anda akan menemukan cara menghitung gaya elastis, karakteristiknya, dan latihan gaya elastis yang diselesaikan. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-la-fuerza-elastica\"><\/span> Apa itu gaya elastis?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Gaya elastis<\/strong> , disebut juga <strong>gaya pemulih<\/strong> , adalah gaya yang diberikan oleh bahan elastis ketika bahan tersebut berubah bentuk. Lebih tepatnya, gaya elastis mempunyai besar dan arah yang sama dengan gaya yang merusak benda elastis, namun arahnya berlawanan.<\/p>\n<p> Selanjutnya, semakin besar deformasi yang dialami benda elastis, yaitu semakin memanjang atau tertekannya benda elastis, maka semakin besar pula modulus gaya elastisnya. <\/p>\n<figure class=\"wp-block-image aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elastique.png\" alt=\"kekuatan elastis\" class=\"wp-image-4161\" width=\"640\" height=\"318\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elastique-300x150.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elastique-1024x511.png 1024w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elastique-768x383.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elastique-1536x767.png 1536w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elastique.png 1585w\" sizes=\"(max-width: 300px) 100vw, 300px\"><\/figure>\n<p> Jadi, pegas selalu memberikan gaya elastis dalam arah yang berlawanan dengan gaya luar yang bekerja padanya.<\/p>\n<p> Dalam fisika, permasalahan yang berkaitan dengan pegas sering kali diatasi untuk memahami pengertian gaya elastis. Kita kemudian akan melihat bagaimana gaya elastis dihitung dan bagaimana menyelesaikan soal seperti ini. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Formula-de-la-fuerza-elastica\"><\/span>Rumus gaya elastis<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Gaya elastis yang dilakukan pegas sama dengan dikurangi konstanta elastis pegas dikalikan perpindahannya.<\/p>\n<p> Oleh karena itu, <strong>rumus gaya elastis<\/strong> adalah sebagai berikut:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-b886155aaf78dae4ad0a70c38f91d77f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_e=-k\\cdot \\Delta x\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"104\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p style=\"margin-bottom:5px\"> Emas: <\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-88df03c55e081c7cd9da4e7d74ba7265_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"14\" style=\"vertical-align: 0px;\"><\/p>\n<p> adalah gaya elastis, dinyatakan dalam newton. <\/span><\/li>\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d42bc2203d6f76ad01b27ac9acc0bee1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"k\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"9\" style=\"vertical-align: 0px;\"><\/p>\n<p> adalah konstanta elastis pegas yang satuannya N\/m.<\/span><\/li>\n<li><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e936d3a449e3ecae93ebb5ae1e61feac_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\Delta x\" title=\"Rendered by QuickLaTeX.com\" height=\"13\" width=\"25\" style=\"vertical-align: 0px;\"><\/p>\n<p> adalah perpanjangan yang dialami pegas ketika gaya luar diterapkan, dinyatakan dalam meter.<\/span><\/li>\n<\/ul>\n<p> <strong>Catatan<\/strong> : Tanda negatif hanya untuk menunjukkan bahwa arah gaya elastis berlawanan dengan gaya luar yang bekerja pada pegas. Yang penting modulus gaya elastis setara dengan konstanta elastis dikalikan perpindahan.<\/p>\n<p> Oleh karena itu, rumus gaya elastis ditentukan oleh <a href=\"https:\/\/physigeek.com\/id\/hukum-hooke\/\">hukum elastisitas Hooke<\/a> .<\/p>\n<p> Sebaliknya, ketika pegas diregangkan atau dikompresi, energi potensial akan tersimpan. Jadi rumus menghitung energi potensial elastis adalah sebagai berikut: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-3bd6ff61b959af0bf6c8061037ba754e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_p=\\cfrac{1}{2}\\cdot k \\cdot \\Delta x^2\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"123\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejemplo-de-la-fuerza-elastica\"><\/span>Contoh gaya elastis<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Setelah kita melihat definisi gaya elastis, kita akan melihat contoh penyelesaian tentang cara menghitung jenis gaya ini.<\/p>\n<ul>\n<li> Sebuah pegas yang mempunyai konstanta elastis 170 N\/m ditarik sejauh 45 cm. Berapakah gaya elastis yang dihasilkan pegas?<\/li>\n<\/ul>\n<p> Untuk menentukan gaya elastis, kita harus menggunakan rumus yang kita lihat di atas:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-b886155aaf78dae4ad0a70c38f91d77f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_e=-k\\cdot \\Delta x\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"104\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p> Namun, sebelum menggunakan rumus ini, Anda perlu mengubah panjang offset menjadi meter:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-311621c96c01a4535b15801b7164ee17_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"45 \\ cm \\div 100 =0,45 \\ m\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"174\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p> Terakhir, kita substitusikan data konstanta elastis dan perpindahan pegas ke dalam rumus dan hitung gaya elastis: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-f6aa371674edfdd6c42d7e3bcb64383e_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_e=-170\\cdot 0,45=-76,5 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"224\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicios-resueltos-de-la-fuerza-elastica\"><\/span> Latihan soal gaya elastis<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Latihan 1<\/h3>\n<p> Sebuah benda bermassa 8 kg digantung pada sebuah pegas vertikal. Berapa besar regangan pegas jika konstanta elastisnya 350 N\/m? (g=10 m\/s <sup>2<\/sup> ) <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-de-la-loi-de-hooke.png\" alt=\"contoh penyelesaian hukum Hooke\" class=\"wp-image-4066\" width=\"118\" height=\"229\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-de-la-loi-de-hooke-154x300.png 154w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exemple-de-la-loi-de-hooke.png 283w\" sizes=\"(max-width: 154px) 100vw, 154px\"><\/figure>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Pertama, kita perlu menghitung gaya beban yang diberikan oleh massa pada pegas. Untuk melakukannya, cukup kalikan massa dengan gravitasi:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-21b4daa2a5826fe5c1bffc3d93cb084a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=m\\cdot g = 8\\cdot 10=80 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"201\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan setelah kita mengetahui gaya yang diterapkan pada pegas, kita dapat menggunakan rumus gaya elastis:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d289d95f4fbd3eaaa673f0217091347c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_e=k\\cdot \\Delta x\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"90\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Kami memecahkan ekstensi formula:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-dd49ebc50db3810f4c2d06bf3716663d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\Delta x=\\cfrac{F_e}{k}\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"69\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Terakhir, kami mengganti nilainya ke dalam rumus dan menghitung perpanjangan pegas: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-82d67ff2ea6c812a73f07308c0600014_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\Delta x=\\cfrac{F_e}{k}=\\cfrac{80}{350} =0,23 \\ m = 23 \\ cm\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"271\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 2<\/h3>\n<p> Sebuah pegas diberi gaya sebesar 50 N, sehingga pegas tersebut meregang sejauh 12 cm. Berapa besar regangan pegas jika diberi gaya sebesar 78 N? <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Untuk menghitung perpanjangan pegas, pertama-tama kita harus menentukan konstanta elastisnya. Oleh karena itu, kita mencari konstanta elastis dari rumus gaya elastis: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c0583a84bd59386c9674aaa94aa7d6ba_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=k\\cdot \\Delta x \\quad \\longrightarrow \\quad k=\\cfrac{F}{\\Delta x}=\\cfrac{50}{0.12} =416.67 \\ \\cfrac{N} {m}[ \/latex] Maintenant que nous connaissons la valeur de la constante d'\u00e9lasticit\u00e9, nous pouvons calculer l'allongement du ressort en utilisant la loi de Hooke : [latex]F=k\\cdot \\Delta x \\quad \\longrightarrow \\quad \\Delta x=\\cfrac{F}{k}=\\cfrac{78}{416.67} =0,19 \\ m = 19 \\ cm \" title=\"Rendered by QuickLaTeX.com\" height=\"124\" width=\"1208\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 3<\/h3>\n<p> Kita mempunyai sebuah bola bermassa m=7 kg yang diletakkan di sebelah pegas dengan posisi mendatar yang konstanta elastisitasnya 560 N\/m. Jika kita mendorong bola dan menekan pegas sebesar 8 cm, maka bola akan terdorong dan kembali ke kedudukan semula. Dengan percepatan berapa bola akan meninggalkan kontak dengan pegas? Abaikan gesekan selama latihan. <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-loi-du-crochet.png\" alt=\"pelaksanaan hukum Hooke yang tegas\" class=\"wp-image-4074\" width=\"295\" height=\"328\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-loi-du-crochet-270x300.png 270w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-loi-du-crochet.png 745w\" sizes=\"(max-width: 270px) 100vw, 270px\"><\/figure>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>Lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Pertama, kita harus menghitung gaya yang dilakukan dengan mendorong bola dan menekan pegas. Untuk melakukan ini, kami menerapkan rumus dari hukum Hooke:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-02824e33202a9d71a6964aba33e74849_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F=k\\cdot \\Delta x=560 \\cdot 0,08 = 44,8 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"263\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Untuk memahami bagian ini dengan baik, Anda harus memahami konsep gaya elastis. Apabila suatu gaya diberikan pada pegas maka akan timbul pula gaya reaksi yang besar dan arahnya sama tetapi arahnya berlawanan (prinsip aksi-reaksi). Jadi, gaya yang dikerjakan pegas pada bola sama besarnya dengan gaya yang dihitung di atas:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6b258ef25c5afc79b6401649152de803_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"|F_{ressort\\\u00e0 balle}|=|F|=44,8 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"219\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Terakhir, untuk menentukan percepatan bola, kita harus menerapkan hukum kedua Newton:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-3121171800c187fa5cf1a980aa5e80cc_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_{spring\\to ball}=m_{ball}\\cdot a_{ball}\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"193\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Jadi kita selesaikan percepatan dari rumus dan substitusikan datanya untuk mencari nilai percepatan bola: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-f4dfeca33dce4b76e142d1a6e41f26f3_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\" a_{ball}=\\cfrac{F_{spring\\to ball}}{m_{ball}}=\\cfrac{44,8}{7}=6,4 \\ \\cfrac{m}{s^2 }\" title=\"Rendered by QuickLaTeX.com\" height=\"41\" width=\"279\" style=\"vertical-align: -15px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Artikel ini menjelaskan apa itu gaya elastis (atau gaya restoratif). Dengan demikian, Anda akan menemukan cara menghitung gaya elastis, karakteristiknya, dan latihan gaya elastis yang diselesaikan. Apa itu gaya elastis? Gaya elastis , disebut juga gaya pemulih , adalah gaya yang diberikan oleh bahan elastis ketika bahan tersebut berubah bentuk. Lebih tepatnya, gaya elastis mempunyai &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/id\/gaya-elastis-atau-gaya-pemulih\/\"> <span class=\"screen-reader-text\">Gaya elastis (atau gaya pemulih)<\/span> Baca selengkapnya &quot;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 Gaya 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