{"id":242,"date":"2023-06-23T11:17:07","date_gmt":"2023-06-23T11:17:07","guid":{"rendered":"https:\/\/physigeek.com\/id\/energi-potensial-elastis\/"},"modified":"2023-06-23T11:17:07","modified_gmt":"2023-06-23T11:17:07","slug":"energi-potensial-elastis","status":"publish","type":"post","link":"https:\/\/physigeek.com\/id\/energi-potensial-elastis\/","title":{"rendered":"Energi potensial elastis"},"content":{"rendered":"<p>Pada artikel ini Anda akan mengetahui apa itu energi potensial elastis, cara menghitung energi potensial elastis, dan, sebagai tambahan, beberapa latihan diselesaikan selangkah demi selangkah untuk dipraktikkan. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-la-energia-potencial-elastica\"><\/span> Apa yang dimaksud dengan energi potensial elastis?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> <strong>Energi potensial elastis<\/strong> , atau <strong>energi elastis<\/strong> , adalah energi yang terakumulasi di dalam benda yang dapat dideformasi akibat kerja yang dilakukan oleh gaya elastis.<\/p>\n<p> Artinya, energi potensial elastis adalah jenis energi potensial yang berhubungan dengan gaya elastis (atau gaya pemulihan).<\/p>\n<p> Misalnya, ketika pegas dikompresi atau dipanjangkan, energi potensial elastis disimpan. Faktanya, dalam fisika, permasalahan pegas seringkali diselesaikan dengan mempelajari konsep energi potensial elastis. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Formula-de-la-energia-potencial-elastica\"><\/span> Rumus energi potensial elastis<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Energi potensial elastis pegas sama dengan setengah konstanta elastis pegas dikalikan kuadrat perpindahan pegas.<\/p>\n<p> Oleh karena itu, <strong>rumus energi potensial elastis<\/strong> adalah: <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique.png\" alt=\"energi potensial elastis\" class=\"wp-image-4110\" width=\"289\" height=\"289\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique-300x300.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique-150x150.png 150w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique.png 525w\" sizes=\"(max-width: 300px) 100vw, 300px\"><\/figure>\n<p style=\"margin-bottom:5px\"> Emas: <\/p>\n<ul style=\"color:#4fd12f; font-weight: bold;\">\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-09b2ab0fbfe1c76e7f3bf527fc17889c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_p\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"20\" style=\"vertical-align: -6px;\"><\/p>\n<p> adalah energi potensial elastis yang satuannya dalam Sistem Internasional adalah joule (J). <\/span><\/li>\n<li style=\"margin-bottom:8px\"><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d42bc2203d6f76ad01b27ac9acc0bee1_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"k\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"9\" style=\"vertical-align: 0px;\"><\/p>\n<p> adalah konstanta elastis pegas yang satuannya N\/m.<\/span><\/li>\n<li><span style=\"color:#101010;font-weight: normal;\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7e5fbfa0bbbd9f3051cd156a0f1b5e31_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"x\" title=\"Rendered by QuickLaTeX.com\" height=\"8\" width=\"10\" style=\"vertical-align: 0px;\"><\/p>\n<p> adalah jarak ke posisi setimbang, dinyatakan dalam meter. <\/span><\/li>\n<\/ul>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Energia-potencial-elastica-y-trabajo\"><\/span> Energi potensial elastis dan usaha<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Usaha yang dilakukan oleh gaya elastis dihitung dengan mengalikan setengah rumus gaya elastis, yang ditentukan oleh <a href=\"https:\/\/physigeek.com\/id\/hukum-hooke\/\">hukum Hooke<\/a> , dengan perpindahan yang dilakukan. Jadi usaha gaya elastis sama dengan luas segitiga berikut: <\/p>\n<figure class=\"wp-block-image aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elasticite-travail.png\" alt=\"energi potensial elastis dan kerja\" class=\"wp-image-4115\" width=\"313\" height=\"263\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elasticite-travail-300x252.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/force-elasticite-travail.png 454w\" sizes=\"(max-width: 300px) 100vw, 300px\"><\/figure>\n<p> Demikian pula, kerja gaya elastis sama dengan variasi negatif energi potensial elastis:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-b9ec4024e50b6145e2b40308562d3245_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"W_p=-\\Delta E_p \" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"97\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-0534be0cea1bfe9a5658cafa6a63f09f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"W_p=-\\left(E_{p_{final}}-E_{p_{initial}}\\right)\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"209\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p> Akan tetapi, jika pegas mula mula berada pada posisi setimbang, kerja gaya elastis hanya ekuivalen dengan energi potensial elastis akhir, karena energi potensial elastis pada posisi setimbang adalah nol (perpindahan bernilai nol). <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-3410e455493de66bceb6b779165edfe0_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"W_p=-\\left(E_{p_{final}}-\\cancelto{0}{E_{p_{equilibrium}}}\\right) =-E_{p_{final}}\" title=\"Rendered by QuickLaTeX.com\" height=\"22\" width=\"334\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Energia-potencial-elastica-y-energia-cinetica\"><\/span> Energi potensial elastis dan energi kinetik<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Ketika pegas dikompresi atau dipanjangkan dan dilepaskan, pegas memperoleh kecepatan. Oleh karena itu, pegas dapat mempunyai energi potensial elastis dan energi kinetik.<\/p>\n<p> Selain itu, jika gesekan tidak diperhitungkan, energi pegas tidak hilang tetapi diubah (prinsip kekekalan energi). Dengan demikian, energi potensial elastis dapat diubah menjadi energi kinetik dan sebaliknya, namun energi totalnya tidak akan berkurang.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-2aff47ab4f297de9c53f400a9eecd59d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_{p_i}+E_{c_i}=E_{p_f}+E_{c_f}\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"173\" style=\"vertical-align: -7px;\"><\/p>\n<\/p>\n<p> Jadi, ketika energi potensial elastis maksimum, yaitu ketika pegas diregangkan atau dikompresi penuh, energi kinetiknya akan menjadi nol. Begitu pula pada saat energi kinetiknya maksimum, yaitu pada saat pegas berada pada posisi setimbang, maka energi potensial elastisnya akan menjadi nol. <\/p>\n<figure class=\"wp-block-image aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique-energie-cinetique.png\" alt=\"energi potensial elastis dan energi kinetik\" class=\"wp-image-4139\" width=\"437\" height=\"525\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique-energie-cinetique-250x300.png 250w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique-energie-cinetique-852x1024.png 852w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique-energie-cinetique-768x923.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/energie-potentielle-elastique-energie-cinetique.png 920w\" sizes=\"(max-width: 250px) 100vw, 250px\"><\/figure>\n<p> Dengan demikian, pegas bergerak dari posisi maksimum ke posisi minimum secara terus menerus sehingga menghasilkan gerakan osilasi. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicios-resueltos-de-la-energia-potencial-elastica\"><\/span> Latihan soal energi potensial elastis<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Latihan 1<\/h3>\n<p> Hitung energi potensial elastis yang tersimpan dalam pegas yang dikompresi lebih dari 60 cm yang konstanta elastisnya 125 N\/m. <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Dalam hal ini, untuk mencari energi potensial elastis cukup menggunakan rumus yang sesuai, yaitu:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d2f4828b6b0f47984aaa21db09088c1a_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_p=\\cfrac{1}{2}\\cdot k \\cdot x^2\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"108\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Selanjutnya, kita substitusikan data tersebut ke dalam rumus dan hitung energi potensial elastis: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-6cb7cefbfa6fb113024875b9a74c0704_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_p=\\cfrac{1}{2}\\cdot 125 \\cdot 0,6^2=22,5 \\ J\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"217\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\">Latihan 2<\/h3>\n<p> Sebuah benda bermassa 4 kg diikatkan pada konstanta pegas 240 N\/m. Jika pegas diregangkan 35 cm, berapakah kecepatan maksimum yang diperoleh massa tersebut? Dan kapan? Kami mengabaikan gesekan dan massa pegas selama latihan. <\/p>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Seperti yang telah kita lihat dalam teori yang dijelaskan di seluruh artikel, nilai energi kinetik maksimum pegas setara dengan nilai energi potensial elastis maksimumnya. Jadi pertama-tama kita akan menghitung energi potensial elastis maksimum dan dari sana kecepatan maksimumnya.<\/p>\n<p class=\"has-text-align-left\"> Energi potensial maksimum yang dicapai pegas adalah pada perpindahan maksimumnya, yaitu pada saat pegas diregangkan sebesar 35 cm. Oleh karena itu kami menghitung energi potensial elastis dalam situasi ini:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-08e679b77dab99372b927bdf9e1ef672_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_{p_{m\\'ax}}=\\cfrac{1}{2}\\cdot k \\cdot x^2=\\cfrac{1}{2}\\cdot 240\\cdot 0,35^2= 14,7\\ J\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"338\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dengan demikian, energi kinetik maksimum akan tercapai di titik lain, tepatnya pada saat pegas melewati posisi setimbangnya. Tetapi nilainya akan sama dengan energi potensial elastis maksimum:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-4ef529c89fa2f18832b3326e13fe9b8d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_{c_{m\\'ax}}=E_{p_{m\\'ax}}=14,7 \\ J\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"190\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Terakhir, cukup menghitung kecepatan yang sesuai dengan energi kinetik ini menggunakan rumus yang sesuai: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d2ce3408631a61e46a1805d12f3ec1d7_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle E_{c_{m\\'ax}}=\\cfrac{1}{2}\\cdot m \\cdot v_{m\\'ax}}^2 \\ \\longrightarrow \\ v_{m\\'ax} } =\\sqrt{\\frac{2\\cdot E_{c_{m\\'ax}}}{m}}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"356\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-3d39d86532e99274a7b3e8812aec2d16_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle v_{m\\'ax}} =\\sqrt{\\frac{2\\cdot E_{c_{m\\'ax}}}{m}}=\\sqrt{\\frac{2\\cdot 14, 7}{4}}=2,71 \\ \\frac{m}{s}\" title=\"Rendered by QuickLaTeX.com\" height=\"43\" width=\"332\" style=\"vertical-align: -14px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Singkatnya, kecepatan maksimum yang diperoleh massa adalah 2,71 m\/s dan akan mencapai kecepatan tersebut setiap kali melewati posisi setimbang.<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\"> Latihan 3<\/h3>\n<p> Sebuah benda bermassa m=2kg digantungkan pada sebuah pegas yang dipasang pada langit-langit. Pegas segera ditarik \u0394X=50 cm hingga diperoleh posisi setimbang baru pada ketinggian h=3 m dari tanah. Berapa total energi potensial yang tersimpan? Data: k=40 N\/m; g = 10 m\/s. <\/p>\n<figure class=\"wp-block-image aligncenter size-large is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-energie-resolue-potentiel-elastique-ressort-ressort.png\" alt=\"menyelesaikan masalah energi daya elastis\" class=\"wp-image-4142\" width=\"133\" height=\"489\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-energie-resolue-potentiel-elastique-ressort-ressort-82x300.png 82w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-energie-resolue-potentiel-elastique-ressort-ressort-279x1024.png 279w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-energie-resolue-potentiel-elastique-ressort-ressort.png 358w\" sizes=\"(max-width: 82px) 100vw, 82px\"><\/figure>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Energi potensial elastis total merupakan jumlah energi potensial elastis pegas ditambah energi potensial gravitasi massa.<\/p>\n<p class=\"has-text-align-left\"> Jadi, pertama-tama kita menghitung energi potensial elastis dengan menerapkan rumus yang dijelaskan di artikel:<\/p>\n<\/p>\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-7f1c525a7629730f7f6094e12ac7bb1d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_{p_{el\\'astica}}=\\cfrac{1}{2}\\cdot k \\cdot x^2=\\cfrac{1}{2}\\cdot 40\\cdot 0.5^2= 5 \\ J\" title=\"Rendered by QuickLaTeX.com\" height=\"38\" width=\"311\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Selanjutnya, kita menghitung energi potensial gravitasi menggunakan rumus yang sesuai:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-f16585ff1c7650cc38f0e69fa53e6034_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_{p_{hauteur}}=m\\cdot g \\cdot h =2 \\cdot 10 \\cdot 3 =60 \\ J\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"294\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Oleh karena itu, energi potensial total adalah jumlah dari dua energi potensial yang dihitung: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-a60ec0c6fe0591fb20033ec30a2a4ffa_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"E_{p_{Total}}=E_{p_{el\\'astica}}+E_{p_{hauteur}}=5+60=65 \\ J\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"358\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Pada artikel ini Anda akan mengetahui apa itu energi potensial elastis, cara menghitung energi potensial elastis, dan, sebagai tambahan, beberapa latihan diselesaikan selangkah demi selangkah untuk dipraktikkan. Apa yang dimaksud dengan energi potensial elastis? Energi potensial elastis , atau energi elastis , adalah energi yang terakumulasi di dalam benda yang dapat dideformasi akibat kerja yang &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/id\/energi-potensial-elastis\/\"> <span class=\"screen-reader-text\">Energi potensial elastis<\/span> Baca selengkapnya &quot;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - 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