{"id":21,"date":"2023-06-27T12:43:20","date_gmt":"2023-06-27T12:43:20","guid":{"rendered":"https:\/\/physigeek.com\/id\/kondisi-keseimbangan-kedua\/"},"modified":"2023-06-27T12:43:20","modified_gmt":"2023-06-27T12:43:20","slug":"kondisi-keseimbangan-kedua","status":"publish","type":"post","link":"https:\/\/physigeek.com\/id\/kondisi-keseimbangan-kedua\/","title":{"rendered":"Kondisi keseimbangan kedua"},"content":{"rendered":"<p>Artikel ini menjelaskan apa itu kondisi keseimbangan kedua dan apa saja isinya. Anda juga akan menemukan contoh nyata dari kondisi keseimbangan kedua dan, akhirnya, Anda akan dapat berlatih dengan latihan yang diselesaikan selangkah demi selangkah. <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFCual-es-la-segunda-condicion-de-equilibrio\"><\/span> Apa kondisi keseimbangan kedua?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Dalam fisika, <strong>syarat kesetimbangan kedua<\/strong> adalah aturan yang menyatakan bahwa suatu benda berada dalam kesetimbangan rotasi jika jumlah momen yang diterapkan padanya sama dengan nol.<\/p>\n<p> Oleh karena itu, kondisi kesetimbangan kedua terpenuhi bila momen yang dihasilkan sama dengan nol. Secara matematis, kondisi keseimbangan kedua dinyatakan dengan rumus berikut:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-d8a19d84c103481347db47c0b8a6d2a8_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\somme \\vv{M}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"52\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Perhatikan bahwa momen harus dijumlahkan secara vektor, karena momen yang bekerja pada sumbu berbeda tidak dapat dijumlahkan. Kondisi ini tidak menjadi masalah jika bekerja dengan gaya koplanar (dua dimensi) karena momen selalu searah, namun harus diwaspadai ketika bekerja dalam tiga dimensi.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-ec7e37abbe42c976a3809c9e0f2724f2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\displaystyle\\sum\\vv{M_x}=0\\qquad\\sum\\vv{M_y}=0\\qquad\\sum\\vv{M_z}=0\\qquad\" title=\"Rendered by QuickLaTeX.com\" height=\"25\" width=\"336\" style=\"vertical-align: -8px;\"><\/p>\n<\/p>\n<p> Ingatlah bahwa momen (atau torsi) suatu gaya pada suatu titik dihitung dengan mengalikan nilai gaya dengan jarak tegak lurus gaya dari titik tersebut.<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-765ae97c83695144c85bb65446416345_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M=F\\cdot d\" title=\"Rendered by QuickLaTeX.com\" height=\"12\" width=\"79\" style=\"vertical-align: 0px;\"><\/p>\n<\/p>\n<p> Kemudian, untuk memenuhi persamaan kondisi kesetimbangan kedua, benda harus mempunyai percepatan sudut nol, atau dengan kata lain benda dalam keadaan tersebut tidak berputar (dalam keadaan diam) atau berputar dengan kecepatan sudut konstan.<\/p>\n<p> Dengan demikian, kita dapat membedakan jenis-jenis keseimbangan rotasi:<\/p>\n<ul>\n<li> <strong>Kesetimbangan rotasi statis<\/strong> : ketika jumlah momen adalah nol dan kecepatan sudut benda adalah nol.<\/li>\n<li> <strong>Kesetimbangan rotasi dinamis<\/strong> : ketika jumlah momen sama dengan nol dan kecepatan sudut benda konstan (berbeda dari nol). <\/li>\n<\/ul>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejemplos-de-la-segunda-condicion-de-equilibrio\"><\/span> Contoh kondisi keseimbangan kedua<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p> Mengingat pengertian kondisi keseimbangan yang kedua, sekarang kita akan melihat beberapa contoh dari kehidupan sehari-hari untuk menyelesaikan pemahaman konsep tersebut.<\/p>\n<p> Contoh umum dari kondisi keseimbangan kedua adalah skala. Ketika sistem stabil, lengan keseimbangan berhenti berputar sehingga jumlah momennya nol dan sistem berada dalam kesetimbangan rotasi. <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/deuxieme-condition-dequilibre.png\" alt=\"kondisi keseimbangan kedua\" class=\"wp-image-430\" width=\"303\" height=\"303\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/deuxieme-condition-dequilibre-300x300.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/deuxieme-condition-dequilibre-150x150.png 150w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/deuxieme-condition-dequilibre-768x768.png 768w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/deuxieme-condition-dequilibre.png 781w\" sizes=\"(max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p> Contoh nyata lainnya adalah Bumi. Planet terus berputar pada porosnya, namun dianggap berputar dengan kecepatan sudut konstan, sehingga memenuhi syarat kesetimbangan kedua.<\/p>\n<p> Terakhir, ketika kita menggantungkan suatu benda dari langit-langit dan menahannya dalam keadaan diam, benda tersebut memenuhi syarat kesetimbangan kedua dan syarat kesetimbangan pertama, karena berada dalam kesetimbangan translasi dan kesetimbangan translasi. rotasi.<\/p>\n<p> Jika Anda belum memahami dengan jelas apa saja syarat keseimbangan yang pertama, Anda dapat membaca artikel berikut ini yang dijelaskan secara detail: <\/p>\n<div style=\"background-color:#FFFDE7; padding-top: 10px; padding-bottom: 10px; padding-right: 10px; padding-left: 20px; border: 2.5px dashed #FFB74D; border-radius:20px;\"> <span style=\"color:#ff951b\">\u27a4<\/span> <strong>Lihat:<\/strong> <a href=\"https:\/\/physigeek.com\/id\/kondisi-keseimbangan-pertama\/\">apa kondisi keseimbangan pertama<\/a> <\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Ejercicios-resueltos-de-la-segunda-condicion-de-equilibrio\"><\/span>Latihan terpecahkan dari kondisi keseimbangan kedua<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3 class=\"wp-block-heading\"> Latihan 1<\/h3>\n<p> Hitunglah momen yang harus ditimbulkan oleh tumpuan balok berikut agar balok tersebut berada dalam kesetimbangan rotasi: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-deuxieme-condition-dequilibre.png\" alt=\"menyelesaikan pelaksanaan kondisi keseimbangan kedua\" class=\"wp-image-397\" width=\"237\" height=\"203\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-deuxieme-condition-dequilibre-300x257.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-deuxieme-condition-dequilibre.png 643w\" sizes=\"(max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Agar balok berada dalam kesetimbangan rotasi dan syarat kesetimbangan kedua terpenuhi, tumpuan harus melawan momen puntir yang dihasilkan oleh gaya tersebut, sehingga jumlah momen akan menjadi nol.<\/p>\n<p class=\"has-text-align-left\"> Oleh karena itu kita menghitung momen (atau torsi) yang dihasilkan oleh gaya pada tingkat tumpuan:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-e172a3bbd51bb42bd229d9a88df0a167_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M_{force}=13\\cdot 9 = 117 \\ Nm\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"202\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan sekarang kami mengusulkan persamaan momen kesetimbangan:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fdac8512edbbe2c1b6396ee43a776261_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M_{support}+M_{force}=0\" title=\"Rendered by QuickLaTeX.com\" height=\"18\" width=\"170\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Momen yang menghasilkan gaya lewat di dalam layar, sehingga tandanya negatif:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-b654ae9d3ab78a23e2f7235a7742a503_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M_{support}-117=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"145\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan akhirnya, kita menyelesaikan hal yang tidak diketahui dalam persamaan:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-772409bbbd945be3fc433e503b43e540_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M_{support}=117 \\ Nm\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"152\" style=\"vertical-align: -6px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Denyut nadi yang diperoleh bertanda positif, sehingga arahnya mengarah ke luar layar.<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n<h3 class=\"wp-block-heading\"> Latihan 2<\/h3>\n<p> Seperti terlihat pada gambar berikut, sebuah batang mendatar yang panjangnya 10 m menopang sebuah benda yang massanya 8 kg. Mengetahui jarak antara tumpuan dan benda yang digantung, berapakah besar gaya yang dilakukan oleh tumpuan jika sistem berada dalam keadaan seimbang rotasi dan translasi? <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-de-rotation.png\" alt=\"masalah keseimbangan rotasi\" class=\"wp-image-355\" width=\"339\" height=\"120\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-de-rotation-300x107.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/probleme-dequilibre-de-rotation.png 643w\" sizes=\"(max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<div class=\"wp-block-otfm-box-spoiler-start otfm-sp__wrapper otfm-sp__box js-otfm-sp-box__closed otfm-sp__FFF8E1\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\" data-otfm-spc=\"#FFF8E1\" style=\"text-align:center\">\n<div class=\"otfm-sp__title\"> <strong>lihat solusinya<\/strong><\/div>\n<\/div>\n<p class=\"has-text-align-left\"> Pertama, kita menggunakan rumus gaya gravitasi untuk menghitung berat yang harus ditopang oleh batang horizontal:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-eb480f5d32a9e25cefacd5f89d407580_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"P=m\\cdot g=8\\cdot 9,81 =78,48 \\ N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"244\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Oleh karena itu, diagram benda bebas sistem adalah: <\/p>\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-rotation-equilibre.png\" alt=\"latihan keseimbangan rotasi teratasi\" class=\"wp-image-356\" width=\"340\" height=\"297\" srcset=\"https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-rotation-equilibre-300x261.png 300w, https:\/\/physigeek.com\/wp-content\/uploads\/2023\/09\/exercice-resolu-rotation-equilibre.png 654w\" sizes=\"(max-width: 300px) 100vw, 300px\"><\/figure>\n<\/div>\n<p class=\"has-text-align-left\"> Rumusan masalah menyatakan bahwa sistem berada dalam keseimbangan gaya-gaya, sehingga jumlah semua gaya-gaya ini haruslah nol. Dengan menggunakan kondisi kesetimbangan ini, kita dapat merumuskan persamaan berikut:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-635096a57ce10781254f283c9807f64c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_A+F_B-P=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"136\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Di sisi lain, pernyataan tersebut juga menyatakan bahwa sistem berada dalam kesetimbangan momentum. Jadi jika kita mempertimbangkan jumlah momen di titik mana pun dalam sistem, hasilnya pasti nol, dan jika kita mengambil titik acuan salah satu dari dua tumpuan, kita akan mendapatkan persamaan dengan hanya satu yang tidak diketahui:<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-f1a6d56c3426e8d6c2e890b5e8f4a873_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"M(A)=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"79\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-922d5ff929e034db7a9e80d732b0b893_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-P\\cdot 6.5+F_B\\cdot (6.5+3.5)=0\" title=\"Rendered by QuickLaTeX.com\" height=\"19\" width=\"233\" style=\"vertical-align: -5px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Sekarang kita dapat menghitung gaya yang diberikan oleh tumpuan B dengan menyelesaikan persamaan yang tidak diketahui: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-95596edf27bb6086c35473f55465416d_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"-78.48\\cdot 6.5+F_B\\cdot 10=0\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"197\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-953185a6ad4824b654b8a40e259bbd71_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_B=\\cfrac{78.48\\cdot 6.5}{10}\" title=\"Rendered by QuickLaTeX.com\" height=\"39\" width=\"125\" style=\"vertical-align: -12px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-c5459080e5aa468fa3d77a16a2b0d9b9_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_B=51.01\\N\" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"87\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-left\"> Dan terakhir, kita dapat mengetahui intensitas gaya yang diterapkan pada tumpuan lain dengan mensubstitusikan nilai yang diperoleh ke dalam persamaan gaya vertikal tinggi: <\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-635096a57ce10781254f283c9807f64c_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_A+F_B-P=0\" title=\"Rendered by QuickLaTeX.com\" height=\"15\" width=\"136\" style=\"vertical-align: -3px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-36325128977806ddaca1436ffb68dcd4_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_A+51,01-78,48=0\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"185\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-5ecd2d608e61435093289d17c242e21f_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"F_A=27,47\\N\" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"90\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<div class=\"wp-block-otfm-box-spoiler-end otfm-sp_end\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Artikel ini menjelaskan apa itu kondisi keseimbangan kedua dan apa saja isinya. Anda juga akan menemukan contoh nyata dari kondisi keseimbangan kedua dan, akhirnya, Anda akan dapat berlatih dengan latihan yang diselesaikan selangkah demi selangkah. Apa kondisi keseimbangan kedua? Dalam fisika, syarat kesetimbangan kedua adalah aturan yang menyatakan bahwa suatu benda berada dalam kesetimbangan rotasi &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/id\/kondisi-keseimbangan-kedua\/\"> <span class=\"screen-reader-text\">Kondisi keseimbangan kedua<\/span> Baca selengkapnya &quot;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"","footnotes":""},"categories":[5],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v21.4 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>\u25b7 Kondisi keseimbangan kedua<\/title>\n<meta name=\"description\" content=\"Kami menjelaskan apa itu kondisi keseimbangan kedua dan terdiri dari apa. 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