{"id":137,"date":"2023-06-25T09:46:18","date_gmt":"2023-06-25T09:46:18","guid":{"rendered":"https:\/\/physigeek.com\/cn\/%e6%af%ab%e7%b1%b3%e6%b1%9e%e6%9f%b1\/"},"modified":"2023-06-25T09:46:18","modified_gmt":"2023-06-25T09:46:18","slug":"%e6%af%ab%e7%b1%b3%e6%b1%9e%e6%9f%b1","status":"publish","type":"post","link":"https:\/\/physigeek.com\/cn\/%e6%af%ab%e7%b1%b3%e6%b1%9e%e6%9f%b1\/","title":{"rendered":"\u6beb\u7c73\u6c5e\u67f1"},"content":{"rendered":"<p>\u672c\u6587\u89e3\u91ca\u4e86 1 \u6beb\u7c73\u6c5e\u67f1\u662f\u4ec0\u4e48\u4ee5\u53ca 1 \u6beb\u7c73\u6c5e\u67f1\u503c\u591a\u5c11\u94b1\u3002\u60a8\u8fd8\u53ef\u4ee5\u627e\u5230\u6beb\u7c73\u6c5e\u67f1\u548c\u5176\u4ed6\u5355\u4f4d\u4e4b\u95f4\u7684\u7b49\u4ef7\u5173\u7cfb\uff0c\u6b64\u5916\uff0c\u60a8\u8fd8\u53ef\u4ee5\u4f7f\u7528\u5728\u7ebf\u8ba1\u7b97\u5668\u8f6c\u6362\u538b\u529b\u5355\u4f4d\u3002 <\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"%C2%BFQue-es-el-milimetro-de-mercurio\"><\/span>\u6beb\u7c73\u6c5e\u67f1\u662f\u591a\u5c11\u6beb\u7c73\uff1f<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><strong>\u6beb\u7c73\u6c5e\u67f1<\/strong>\u662f\u538b\u529b\u5355\u4f4d\u3002\u4e00\u6beb\u7c73\u6c5e\u67f1\u662f\u6307\u4eba\u4f53\u6d78\u5165\u6c34\u94f6\u4e00\u6beb\u7c73\u6df1\u5ea6\u65f6\u6240\u53d7\u5230\u7684\u538b\u529b\u3002\u56e0\u6b64\uff0c\u4e00\u6beb\u7c73\u6c5e\u67f1\u7b49\u4e8e 133.322 Pa\u3002<\/p>\n<p>\u6c5e\u7684\u7b26\u53f7\u662fHg\uff0c\u6240\u4ee5\u6beb\u7c73\u6c5e\u67f1\u7684\u7b26\u53f7\u662fmmHg\u3002<\/p>\n<p>\u5047\u8bbe\u6c5e\u7684\u5bc6\u5ea6\u4e3a 13595.1 kg\/m <sup>3<\/sup> \uff0c\u91cd\u529b\u4e3a 9.80665 m\/s <sup>2<\/sup> \uff0c\u60a8\u53ef\u4ee5\u901a\u8fc7\u5e94\u7528\u6d41\u4f53\u538b\u529b\u516c\u5f0f\u8f7b\u677e\u8ba1\u7b97\u51fa\u4e00\u6beb\u7c73\u6c5e\u76f8\u5f53\u4e8e\u4ec0\u4e48\uff1a<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-fced33095d22fd26e6c15b29f37063c6_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"\\begin{aligned}P&amp;=\\rho \\cdot g \\cdot h\\\\[2ex] &amp;=13595.1\\cdot 9.80665\\cdot 0.001\\\\[2ex] &amp; = 133.322 \\ Pa\\end{aligned }[\/latex ] Gardez \u00e0 l'esprit que le millim\u00e8tre de mercure est en r\u00e9alit\u00e9 une unit\u00e9 qui n'appartient pas au Syst\u00e8me international d'unit\u00e9s (SI). Cependant, dans certains domaines, cette mesure de pression est fr\u00e9quemment utilis\u00e9e, comme en m\u00e9decine. D'un autre c\u00f4t\u00e9, l'unit\u00e9 de pression dans le syst\u00e8me international est le pascal. Par cons\u00e9quent, en physique et en ing\u00e9nierie, la plupart des calculs de pression sont exprim\u00e9s en pascals. Enfin, il convient de noter que c'est une erreur tr\u00e8s courante de consid\u00e9rer qu'un millim\u00e8tre de mercure \u00e9quivaut \u00e0 un torr, mais ce n'est pas exactement le cas. Ci-dessous, nous verrons la diff\u00e9rence entre ces deux unit\u00e9s de pression. <span style=&quot;color:#4fd12f&quot;>\u27a4<\/span> <u style=&quot;text-decoration-color:#4fd12f;&quot;>Vous pouvez utiliser le calculateur en ligne ci-dessous pour convertir entre diff\u00e9rentes unit\u00e9s de pression.<\/u> <\/p>\n<h2 class=&quot;wp-block-heading&quot;><span class=&quot;ez-toc-section&quot; id=&quot;Equivalencias-del-milimetro-de-mercurio&quot;><\/span> \u00c9quivalences du millim\u00e8tre de mercure<span class=&quot;ez-toc-section-end&quot;><\/span><\/h2>\n<p> Dans la section pr\u00e9c\u00e9dente, nous avons vu la d\u00e9finition d&#8217;un millim\u00e8tre de mercure comme unit\u00e9 de pression. Ci-dessous un tableau avec les valeurs des \u00e9quivalences entre un millim\u00e8tre de mercure et d&#8217;autres mesures de pression diff\u00e9rentes.<\/p>\n<figure class=&quot;wp-block-table is-style-stripes&quot;>\n<table>\n<thead>\n<tr>\n<th> Unit\u00e9<\/th>\n<th class=&quot;has-text-align-center&quot; data-align=&quot;center&quot;> Abr\u00e9viation<\/th>\n<th> Equivalence \u00e0 1 mmHg<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td> Pascal<\/td>\n<td class=&quot;has-text-align-center&quot; data-align=&quot;center&quot;> Pennsylvanie<\/td>\n<td> 133 322 Pa.<\/td>\n<\/tr>\n<tr>\n<td> Bar<\/td>\n<td class=&quot;has-text-align-center&quot; data-align=&quot;center&quot;> bar<\/td>\n<td> 0,00133322 bars<\/td>\n<\/tr>\n<tr>\n<td> Baria<\/td>\n<td class=&quot;has-text-align-center&quot; data-align=&quot;center&quot;> baria<\/td>\n<td> 1333,22 barres<\/td>\n<\/tr>\n<tr>\n<td> Atmosph\u00e8re technique<\/td>\n<td class=&quot;has-text-align-center&quot; data-align=&quot;center&quot;> \u00e0<\/td>\n<td> 0,0013595 \u00e0<\/td>\n<\/tr>\n<tr>\n<td> Atmosph\u00e8re<\/td>\n<td class=&quot;has-text-align-center&quot; data-align=&quot;center&quot;> au m<\/td>\n<td> 0,0013158 guichet automatique<\/td>\n<\/tr>\n<tr>\n<td> Torr<\/td>\n<td class=&quot;has-text-align-center&quot; data-align=&quot;center&quot;> Torr<\/td>\n<td> 1 Torr (environ)<\/td>\n<\/tr>\n<tr>\n<td> Livre-force par pouce carr\u00e9<\/td>\n<td class=&quot;has-text-align-center&quot; data-align=&quot;center&quot;> psi<\/td>\n<td> 0,0019337psi<\/td>\n<\/tr>\n<tr>\n<td> m\u00e8tres de colonne d&#8217;eau<\/td>\n<td class=&quot;has-text-align-center&quot; data-align=&quot;center&quot;> mca<\/td>\n<td> 0,0136 mca <\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/figure>\n<h2 class=&quot;wp-block-heading&quot;><span class=&quot;ez-toc-section&quot; id=&quot;Calculadora-para-convertir-unidades-de-presion&quot;><\/span> Calculatrice pour convertir les unit\u00e9s de pression<span class=&quot;ez-toc-section-end&quot;><\/span><\/h2>\n<p> Vous pouvez utiliser le convertisseur suivant pour convertir la valeur d&#8217;une pression exprim\u00e9e dans certaines unit\u00e9s vers d&#8217;autres unit\u00e9s diff\u00e9rentes. Il vous suffit de saisir la valeur de la pression, les unit\u00e9s de conversion et le nombre de d\u00e9cimales souhait\u00e9. Vous devez utiliser le point comme s\u00e9parateur d\u00e9cimal, par exemple 17,53. <\/p>\n<form action=&quot;&quot; method=&quot;post&quot;>\n<div align=&quot;center&quot; style=&quot;line-height:50px; background:#FEF9E7; padding:15px; border:2px solid #4FD12F; border-radius:15px; margin-bottom:20px&quot;><input name=&quot;datos&quot; style=&quot;border:1.5px solid #4FD12F; border-radius:5px;  padding:7px; color:#000000; width: 100px&quot; placeholder=&quot;1&quot; required=&quot;&quot; oninvalid=&quot;this.setCustomValidity('Introduce el valor de la presi\u00f3n aqu\u00ed')&quot; oninput=&quot;this.setCustomValidity('')&quot;><select name=&quot;unidad1&quot; style=&quot;border:1.5px solid #4FD12F; border-radius:5px;  padding:7px; color:#000000; width: 130px&quot;><option value=&quot;mmHg1&quot;> Millim\u00e8tre de mercure (mmHg)<\/option><option value=&quot;pascal1&quot;> Pascal (Pa)<\/option><option value=&quot;bar1&quot;> bar<\/option><option value=&quot;baria1&quot;> Baria (baria)<\/option><option value=&quot;attec1&quot;> Ambiance technique (\u00e0)<\/option><option value=&quot;atm1&quot;> Atmosph\u00e8re (atmosph\u00e8re)<\/option><option value=&quot;torr1&quot;> Torr (Torr)<\/option><option value=&quot;psi1&quot;> Livre-force par pouce carr\u00e9 (PSI)<\/option><option value=&quot;mca1&quot;> M\u00e8tres de colonne d&#8217;eau (mca)<\/option><\/select> <span style=&quot;color:#4FD12F&quot;>\u279c<\/span> <select name=&quot;unidad2&quot; style=&quot;border:1.5px solid #4FD12F; border-radius:5px;  padding:7px; color:#000000; width: 130px&quot;><option value=&quot;pascal2&quot;> Pascal (Pa)<\/option><option value=&quot;bar2&quot;> bar<\/option><option value=&quot;baria2&quot;> Baria (baria)<\/option><option value=&quot;attec2&quot;> Ambiance technique (\u00e0)<\/option><option value=&quot;atm2&quot;> Atmosph\u00e8re (atmosph\u00e8re)<\/option><option value=&quot;torr2&quot;> Torr (Torr)<\/option><option value=&quot;mmHg2&quot;> Millim\u00e8tre de mercure (mmHg)<\/option><option value=&quot;psi2&quot;> Livre-force par pouce carr\u00e9 (PSI)<\/option><option value=&quot;mca2&quot;> M\u00e8tres de colonne d&#8217;eau (mca) <\/option><\/select><select name=&quot;decimales&quot; style=&quot;border:1.5px solid #4FD12F; border-radius:5px;  padding:7px; color:#000000; width: 130px&quot;><option value=&quot;0decimales&quot;> 0 d\u00e9cimales<\/option><option value=&quot;1decimales&quot;> 1 d\u00e9cimale<\/option><option value=&quot;2decimales&quot;> 2 d\u00e9cimales<\/option><option value=&quot;3decimales&quot;> 3 d\u00e9cimales<\/option><option value=&quot;4decimales&quot;> 4 d\u00e9cimales<\/option><option value=&quot;5decimales&quot;> 5 d\u00e9cimales<\/option><option value=&quot;6decimales&quot;> 6 d\u00e9cimales<\/option><option value=&quot;7decimales&quot;> 7 d\u00e9cimales<\/option><option value=&quot;8decimales&quot;> 8 d\u00e9cimales<\/option><option value=&quot;9decimales&quot;> 9 d\u00e9cimales<\/option><option value=&quot;10decimales&quot;> 10 d\u00e9cimales <\/option><\/select><\/p>\n<div style=&quot;text-align:center&quot;><input align=&quot;center&quot; style=&quot;font-size:105%; border-radius:30px; margin-top: 20px; margin-bottom:15px&quot; type=&quot;submit&quot; name=&quot;submit&quot; value=&quot;Convertir&quot;><\/div>\n<\/div>\n<\/form>\n<h2 class=&quot;wp-block-heading&quot;><span class=&quot;ez-toc-section&quot; id=&quot;Diferencia-entre-el-milimetro-de-mercurio-y-el-torr&quot;><\/span> Diff\u00e9rence entre millim\u00e8tre de mercure et torr<span class=&quot;ez-toc-section-end&quot;><\/span><\/h2>\n<p> Le millim\u00e8tre de mercure et le torr sont deux unit\u00e9s de pression. Bien qu&#8217;au d\u00e9but les deux unit\u00e9s \u00e9taient consid\u00e9r\u00e9es comme \u00e9quivalentes, actuellement <strong>la diff\u00e9rence entre la valeur du millim\u00e8tre de mercure et la valeur du torr est de 0,0000143 %.<\/strong> La raison de cette diff\u00e9rence est expliqu\u00e9e ci-dessous. \u00c0 l&#8217;origine, le torr \u00e9tait d\u00e9fini comme une unit\u00e9 de pression exactement \u00e9gale \u00e0 la pression exerc\u00e9e par un millim\u00e8tre de mercure \u00e0 0\u00baC. Cependant, cette description n&#8217;\u00e9tait pas assez rigoureuse puisque la gravit\u00e9 change l\u00e9g\u00e8rement en fonction de la position de la Terre (du fait qu&#8217;elle n&#8217;est pas compl\u00e8tement sph\u00e9rique et du fait de sa rotation). Ainsi, en 1954, lors de la 10e Conf\u00e9rence g\u00e9n\u00e9rale des poids et mesures, le torr fut red\u00e9fini. Depuis, le torr est \u00e9gal \u00e0 1\/760 de la pression atmosph\u00e9rique normale, soit 133,322368421 pascals. [latex]1 \\ Torr = 133,322368421 \\ Pa &#8221; title=&#8221;Rendered by QuickLaTeX.com&#8221; height=&#8221;766&#8243; width=&#8221;807&#8243; style=&#8221;vertical-align: 0px;&#8221;><\/p>\n<\/p>\n<p>\u53e6\u4e00\u65b9\u9762\uff0c\u4e00\u6beb\u7c73\u6c5e\u67f1 (mmHg) \u6b63\u597d\u662f 133.322387415 Pa\u3002<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-303ab3dc6c1d6fb97e85999ee08d1488_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"1 \\ mmHg = 133,322387415 \\ Pa \" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"237\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p>\u7b80\u800c\u8a00\u4e4b\uff0c\u6beb\u7c73\u6c5e\u67f1\u548c\u6258\u5e76\u4e0d\u5b8c\u5168\u76f8\u540c\uff0c\u800c\u662f\u5b83\u4eec\u7684\u6570\u503c\u7565\u6709\u4e0d\u540c\u3002\u7136\u800c\uff0c\u7531\u4e8e\u5b83\u4eec\u7684\u503c\u975e\u5e38\u76f8\u4f3c\u5e76\u4e14\u5728\u5386\u53f2\u4e0a\u662f\u76f8\u540c\u7684\uff0c\u56e0\u6b64\u5b83\u4eec\u901a\u5e38\u88ab\u8ba4\u4e3a\u662f\u76f8\u540c\u7684\u5355\u4f4d\u3002\u5982\u4e0b\u6240\u793a\uff0c\u5047\u8bbe\u8fd9\u4e24\u4e2a\u538b\u529b\u6d4b\u91cf\u503c\u76f8\u7b49\u6240\u4ea7\u751f\u7684\u8bef\u5dee\u51e0\u4e4e\u4e3a\u96f6\uff1a<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-cb878c0e6d86c7bc56c4eae10597ad72_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"1 \\ mmHg = 1,000000142466321 \\ Torr \" title=\"Rendered by QuickLaTeX.com\" height=\"16\" width=\"287\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<p class=\"has-text-align-center\">\n<p class=\"has-text-align-center\"><img decoding=\"async\" loading=\"lazy\" src=\"https:\/\/physigeek.com\/wp-content\/ql-cache\/quicklatex.com-835cda73f01fe3bb1d3e6b752c45a2e2_l3.png\" class=\"ql-img-inline-formula quicklatex-auto-format\" alt=\"1 \\ Torr = 0,999999857533699 \\ mmHg \" title=\"Rendered by QuickLaTeX.com\" height=\"17\" width=\"288\" style=\"vertical-align: -4px;\"><\/p>\n<\/p>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Historia-del-milimetro-de-mercurio\"><\/span>\u6beb\u7c73\u6c5e\u67f1\u7684\u5386\u53f2<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>\u6beb\u7c73\u6c5e\u67f1\u4f5c\u4e3a\u538b\u529b\u5355\u4f4d\u7684\u8d77\u6e90\u5728\u4e8e\u7269\u7406\u5b66\u5bb6 Evangelista Torricelli \u4e8e 1643 \u5e74\u53d1\u660e\u7684\u6c34\u94f6\u6c14\u538b\u8ba1\u3002<\/p>\n<p>\u8be5\u4eea\u5668\u5305\u62ec\u5c06\u4e00\u7aef\u5bc6\u5c01\u7684\u88c5\u6709\u6c5e\u7684\u7ba1\u5b50\u6d78\u5165\u4e5f\u88c5\u6709\u6c5e\u7684\u5f00\u53e3\u5bb9\u5668\u4e2d\u3002\u56e0\u6b64\uff0c\u7ba1\u5185\u7684\u6c5e\u6839\u636e\u7a7a\u6c14\u65bd\u52a0\u5728\u5f00\u53e3\u5bb9\u5668\u4e2d\u7684\u6db2\u4f53\u4e0a\u7684\u538b\u529b\uff08\u5373\u6839\u636e\u5927\u6c14\u538b\u529b\uff09\u800c\u589e\u52a0\u6216\u51cf\u5c11\u3002\u8fd9\u6837\uff0c\u5c31\u53ef\u4ee5\u6839\u636e\u6c5e\u4f4d\u79fb\u7684\u6beb\u7c73\u6570\u6765\u6d4b\u91cf\u73af\u5883\u538b\u529b\u3002<\/p>\n<p>\u7136\u800c\uff0c\u6c34\u94f6\u7684\u5bc6\u5ea6\u53d6\u51b3\u4e8e\u6e29\u5ea6\uff0c\u53e6\u4e00\u65b9\u9762\uff0c\u91cd\u529b\u4e5f\u6839\u636e\u4f4d\u7f6e\u7565\u6709\u4e0d\u540c\u3002\u8fd9\u610f\u5473\u7740\u4e00\u6beb\u7c73\u6c5e\u67f1\u4e0e\u53e6\u4e00\u4e2a\u538b\u529b\u5355\u4f4d\u7684\u5f53\u91cf\u6839\u636e\u8fd9\u4e24\u4e2a\u56e0\u7d20\u800c\u53d8\u5316\u3002<\/p>\n<p>\u56e0\u6b64\uff0c\u51b3\u5b9a\u5c06\u6beb\u7c73\u6c5e\u67f1\u5b9a\u4e49\u4e3a\u57280\u2103\u6e29\u5ea6\u4e0b\uff0c\u65bd\u52a0\u57281\u6beb\u7c73\u9ad8\u7684\u6c5e\u67f1\u5e95\u90e8\u7684\u538b\u529b\uff0c\u5176\u4e2d\u6c5e\u7684\u5bc6\u5ea6\u4e3a13595.1 kg\/m <sup>3<\/sup> \uff0c\u91cd\u529b9.80665 m\/s <sup>2<\/sup> \u3002\u56e0\u6b64\uff0c1\u6beb\u7c73\u6c5e\u67f1\u7684\u503c\u76f8\u5f53\u4e8e\u4ee5\u4e0b\u8868\u8fbe\u5f0f\uff1a<\/p>\n<p class=\"has-text-align-center\"> [latex]\\begin{\u5bf9\u9f50}P&amp;=\\rho \\cdot g \\cdot h\\\\[2ex] &amp;=13595.1\\cdot 9.80665\\cdot 0.001\\\\[2ex] &amp; = 133.322 \\Pa\\end{\u5bf9\u9f50}[\/latex ]<\/p>\n<p>\u8fd9\u6837\uff0c\u6beb\u7c73\u6c5e\u67f1\u5c31\u88ab\u6570\u5b57\u5316\u4e86\uff0c\u5e76\u4e14\u603b\u662f\u53d6\u76f8\u540c\u7684\u503c\u3002<\/p>\n","protected":false},"excerpt":{"rendered":"<p>\u672c\u6587\u89e3\u91ca\u4e86 1 \u6beb\u7c73\u6c5e\u67f1\u662f\u4ec0\u4e48\u4ee5\u53ca 1 \u6beb\u7c73\u6c5e\u67f1\u503c\u591a\u5c11\u94b1\u3002\u60a8\u8fd8\u53ef\u4ee5\u627e\u5230\u6beb\u7c73\u6c5e\u67f1\u548c\u5176\u4ed6\u5355\u4f4d\u4e4b\u95f4\u7684\u7b49\u4ef7\u5173\u7cfb\uff0c\u6b64\u5916\uff0c &hellip;<\/p>\n<p class=\"read-more\"> <a class=\"\" href=\"https:\/\/physigeek.com\/cn\/%e6%af%ab%e7%b1%b3%e6%b1%9e%e6%9f%b1\/\"> <span class=\"screen-reader-text\">\u6beb\u7c73\u6c5e\u67f1<\/span> \u67e5\u770b\u5168\u6587 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